Explanation:
matter is a substance that has mass and it takes up space.
hope this helps!!
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g
13.Which shows the order of increasing ionization energy?
a.Si, Al, Mg, Na
b.Ga, Ge, As, Se
c.Be, Mg, Ca, Sr
d.F, Cl, Br, I
If you have 15g of sodium carbonate, what
mass of sodium is present in that sample?
Answer: 6.75 g
Explanation:
Which types of changes must follow the law of conservation of mass?
Both physical and chemical changes
Neither physical nor chemical changes
Only physical changes
Only chemical changes
Answer: both
Explanation:
why is productivity greatest near the ocean's surface?
Answer:
Sunlight penetrates the top layers of the ocean, so photosynthesis occurs there. ... Upwelling brings nutrients to the surface.
Heat from the sun moves through space by the process of
es
A)
circulation.
B)
conduction
C)
convection.
D)
radiation
A cylinder of an ideal gas contains 1.2 moles of gas and occupies a volume of 5.0L. If 0.5 moles of a second gas are added to the cylinder, and the cylinder is allowed to expand until it reaches the same temperature and pressure as before, what is the final volume of gas, in liters, that occupies the cylinder?
Answer:
7.08 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.2 + 0.5 = 1.7 moles
Final volume (V₂) =?
From ideal gas equation,
PV = nRT
Divide both by n
PV / n = RT
Divide both side by P
V / n = RT/P
RT/P => constant
Therefore,
V₁ / n₁ = V₂ / n₂
With the above formula i.e
V₁/n₁ = V₂/n₂
We can obtain the final volume of the gas as follow:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.7 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
5 / 1.2 = V₂ / 1.7
Cross multiply
5 × 1.7 = 1.2 × V₂
8.5 = 1.2 × V₂
Divide both side by 1.2
V₂ = 8.5 / 1.2
V₂ = 7.08 L
Therefore, the final volume of the gas is 7.08 L
New rocks are heavier than old rocks.
what is the name of the compoud H2Co2
Wine goes bad soon after opening because the ethanol ch3ch2oh in it reacts with oxygen gas o2 from the air to form water h2o and acetic acid ch3cooh , the main ingredient of vinegar. Calculate the moles of ethanol needed to produce 0.055mol of acetic acid. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Answer:
For producing 0.55 mole of acetic acid, 0.55 mole of ethanol is required.
Explanation:
The balanced equation for this reaction is
CH3CH2OH + O2 --> CH3COOH + H2O
As we can see in this equation, the ration of number of moles of acetic acid to the number of moles of ethanal is equal to [tex]1 : 1[/tex]
Hence, in order to produce one mole of acetic acid, 1 mole of ethanol is required.
Thus, for producing 0.55 mole of acetic acid, 0.55 mole of ethanol is required.
An atom absorbs radiation. Select the possible changes this could have on the atom:
*it can change the atomic mass
*it can cause the atom to lose an electron
*it can cause the atom to become and ion
*it cause the atom to change element
Answer:
*it can cause the atom to become and ion
Suppose you have a mixture of iron filings, sand, and sugar and you want to separate the three. Fill in the materials you expect to see at each step as you perform the actions shown to separate them. The materials you may expect to see are: iron filings, sand, sugar, and sugar water.
Answer:
Explanation:
mixture of iron filings, sand, and sugar
First Step - Iron Fillings
Use a magnet to separate the iron fillings from the mixture. Due to magnetic properties of the iron fillings, the magnets would attract the iron fillings and separate it from the mixture.
Second step - Sand
Place the sand and sugar mixture in water. The sugar would dissolve in water and the sand easily separated by filtration.
Third step - Sugar and Sugar water
Boil the sugar water to remove the water and place in the refrigerator for crystallization of the sugar.
how many lbs are in 60 oz
Answer:
3 pounds 13 ounces
Explanation:
Math
Answer:
3.75
Explanation:
2) Which liberates the most energy?
A) F(g) + e ➡️ F-(g)
B) N(g) +e- ➡️ N-(g)
C) O(g) +e ➡️ O-(g)
D) C(g) +e ➡️ C-(g)
Answer: [tex]F(g)+e^-\rightarrow F^-(g)[/tex]
Explanation:
Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.
The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.
[tex]F(g)+e^-\rightarrow F^-(g)[/tex]
whats the balance to Sr + O, SrO
Answer:
SrO = Sr + O - Chemical Equation Balancer.
Explanation:
Calculate the number of moles in 2.67 g of carbon trihydride
Answer:0.178 moles
Explanation: carbon trihydride seems to be an unusual name for the methyl group CH3–
ionic wt 15
moles = 2.67/15 = 0.178
write the balanced equation for the formation of carbon dioxide.
how many moles are in 6.31x10^24 C atoms
Answer:
Explanation:
1 mol of any chemical is 6.02 * 10^23
x mol of any chemical is 6.31 * 10^24
You should look at this before you put it in your calculator. You should think roughly 10.
Now you can set it up as a proportion
1/x = 6.02 * 10^23/6.31 * 10^24 Cross multiply
6.02 * 10^23 x = 1 * 6.31 * 10^24 Divide by 6.02 * 10^23
x = 6.31 * 10^24 / 6.02 * 10^23
x = 10.48 mols.
I gave brainlest:: answer this .....
answers this...i gave brainlest!!
Answer:
I hope I can help
Explanation:
I hope I can help you
A __________________ chemical equation shows that the same number of atoms in the reactants are also in the product.
balanced
rearranged
transferred
beautiful
1 point
If the element Lithium (Li) were to bond with the element Sulfur (s), what
type of bond can you predict will be formed and why?*
A. Covalent-Li and S are two nonmetals
B. Covalent-Li is a metal and S is a nonmetal
C. Ionic-Li and S are two nonmetals
D. Ionic-Li is a metal and S is a nonmetal
Answer:
C. Ionic-Li and S are two nonmetals
Which of the following is a nonelectrolyte?
HCI
Rb2SO4
CH3CH2OH
KOH
NaCl
write and balance the cellular respiration equation of glucose compared with the photosynthesis reaction in the terms of reactants products energy flow in the significance of each.
Answer:
Explanation:
.
How many grams are there in 3.4 x 10^24 atoms of He?
Group of answer choices
2.07
5.7 g
0.57 g
20.7
Given :
Number of He atoms, [tex]n = 3.4\times 10^{24}[/tex] atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are [tex]6.022 \times 10^{23}[/tex] atoms in 4 g of He.
Let, number of gram He in [tex]3.4\times 10^{24}[/tex] atoms is x , so :
[tex]x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g[/tex]
Therefore, grams of He atoms is 22.58 g .
An increase in the volume of a substance because of an increase in temperature is called
Answer:
Its called contraction.
Explanation:
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of [tex]CH_4[/tex] is burned in excess oxygen gas
Given: [tex]CH _4 +2O_2\rightarrow CO_2+2H_2O[/tex] ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] weighs = 16 g
Thus we can say:
16 g of [tex]CH_4[/tex] on combustion releases heat = 802 kJ
Thus 24.8 g of [tex]CH_4[/tex] on combustion releases =[tex]\frac{802}{16}\times 24.8=1243.1kJ[/tex]
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.
Answer:
[tex]1.936\times 10^{-18}\ \text{J}[/tex]
Explanation:
[tex]R_h[/tex] = Rydberg constant = [tex]2.178\times 10^{-18}\ \text{J}[/tex]
[tex]n_i[/tex] = Initial shell = 3
[tex]n_f[/tex] = Final shell = 1
We have the relation
[tex]\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}[/tex]
The energy of the photon emitted here is [tex]1.936\times 10^{-18}\ \text{J}[/tex].
If 1 g of radium-226 has an activity of 1 curie, what is the activity of 2 g of radium-226? 1 curie 2 curies 4 curies 10 curies
Answer:
2 curies
Explanation:
This is actually pretty easy to explain.
The Radium-226 which is an isotope of the radium, have an activity of curie. This is basically used in radioactivity of certain elements.
As in both cases we have Radium -226 and we are only varying the mass of the Radium, then, we can just do a rule of 3 to calculate this:
1 g Ra-226 --------> 1 Curie
2 g Ra-226 --------> X Curie
Solving for X:
X = 2 g * 1 Curie / 1 g
X = 2 Curies.You can also see this by taking 2 grams of Ra per separate. On one side you have 1 g of Ra-226 and on the other side, you have another 1 g of Ra-226. Both have 1 Cury of activity. If you put both on the same side, you will have 1 Cury of 1 isotope plus 1 cury of the other isotope, final result? 2 curies.
Hope this helps
2
Convert -27°C to Kelvin.
Answer:
-27 C converted to Kelvin is 246.15 Kelvin.
Explanation:
Hope this helps
Answer:
246.15K
Explanation:
Formula: (-27°)C + 273.15 = 246.15K