A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped into a container of boiling water (100oC). If the temperature of the sphere increases 10o in 9 seconds, find the temperature of the ball after 18 seconds in the boiling water. (Assume the sphere obeys Newton's Law of Cooling.)

Answers

Answer 1

Answer:

38.71°C

Step-by-step explanation:

Given :

Initial temp, T0 = 20°C

Final temperature, T = 20 + 10 = 30°C

Time, t = 9 seconds

Surrounding temperature, Ts = 100°C

Newton's Law of cooling :

T = Ts + (T0 - Ts) * e^-kt

Obtain the value of k

30 = 100 + (20 - 100) * e^-9k

30 - 100 = - 80e^-9k

-70 = - 80e^-9k

-70 / - 80 = e^-9k

0.875 = e^-9k

Take the In of both sides

In(0.875) = - 9k

−0.133531 = - 9k

k = 0.133531 / 9

k = 0.0148

Hence,

t = 18

T = Ts + (T0 - Ts) * e^-kt

T = 100 + (20 - 100) * e^-0.0148(18)

T = 100 - 80 * e^-0.0148(18)

T = 100 - 80 * 0.7661326

T = 38.709392

T = 38.71°C


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You have to explain the answer

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Answer:

D the last expression

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Answer:

a=6/25b+-2/5

Step-by-step explanation:

17b+a−23b+24a=−10

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Step-by-step explanation:

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plssssss help fast!!!!Launching From a Tower
Suppose a projectile is launched from a tower into the air with an initial velocity of 48 feet per
second. Its height, h, in feet, above the ground is modeled by the function
h = -16t2 + vot + 64
where t is the time, in second, since the projectile was launched and v, is the initial velocity.
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Answers

Answer:

A. h = 64

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E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

  = -16(t^2 - 3t -  4)

 = -16(t - 4)(t + 1)

t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

The maximum height is 100 feet at a time of about 1.5 seconds.

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

h = -16t² + vt + 64

-16t² + 48t + 64 = h

h is the height, v is the initial velocity and t is the time.

a) The tower height is about 64 feet from the equation

b) The time is at h = 0, hence:

-16t² + 48t + 64 = 0

t = 4 seconds

c) Maximum height is at h' = 0

h' = -32t + 48

-32t + 48 = 0

t = 1.5 seconds

d) h(1.5) = -16(1.5)² + 48(1.5) + 64 = 100 feet

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Answers

Answer:

The answer is 7 because if we write 7 - 8 = -1, then we could see that the answer would be -1 since 7 is 1 value lower than 8, and 8 - 8 = 0, so if 7 is lower than 8 by 1, then you would go one value lower from 0, which is -1. You can also figure this out by looking at a number line and starting from 7 and then going backwards 8 times and whatever number you land on after going back 8 times is your answer.

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Answers

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Answer:

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WANT MORE THEN FOLLOW ME, LIKE & MARK MY ANSWER AS BRAINLIST ANSWER

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let's solve your equation step-by-step.

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Step 2: Divide both sides by 1/3.

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