$425, but everything is on sale for 20% off. What is the amount of the discount? What is the cost of the table after the discount?

Answer: m=-3/2

Step-by-step explanation:

To find the slope, we use the formula [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]. With our given points, we can directly plug them into the formula.

[tex]m=\frac{9-6}{-5-(-3)} =\frac{3}{-2}[/tex]

Our slope is m=-3/2.

Answer:

[tex]cos \beta = -\sqrt\dfrac{2}{3}[/tex]

Step-by-step explanation:

It is given that [tex]\angle \beta[/tex] lies in the third quadrant.

In 3rd quadrant, sine and cosine both are negative.

Also given that:

[tex]sin \beta =-\dfrac{\sqrt3}{3}[/tex]

We know that identity between sine and cosine as:

[tex]sin^2\theta + cos^2\theta = 1[/tex]

Here, [tex]\angle \theta\ is\ \angle \beta[/tex]

Therefore, the identity can be written as:

[tex]sin^2\beta + cos^2\beta= 1[/tex]

Putting the value of [tex]sin\beta[/tex]:

[tex](-\dfrac{\sqrt3}{3})^2+ cos^2\beta= 1\\\Rightarrow cos^2\beta = 1 -\dfrac{3}{9}\\\Rightarrow cos^2\beta = \dfrac{9-3}{9}\\\Rightarrow cos^2\beta = \dfrac{6}{9}\\\Rightarrow cos\beta = \pm \sqrt{\dfrac{6}{9}}\\\Rightarrow cos\beta = \pm \sqrt{\dfrac{2}{3}}[/tex]

But, it is given that [tex]\beta[/tex] is in 3rd quadrant. That means, value of cos[tex]\beta[/tex] will be negative.

Therefore, the correct answer is:

[tex]cos \beta = -\sqrt\dfrac{2}{3}[/tex]

Answer:

[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]

And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:

[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]

And from the previous result we got:

[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]

And solving we got:

[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]

And then we can find the mean with this formula:

[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

[tex] \bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8[/tex]

Where [tex] w_i[/tex] represent the number of credits and [tex]X_i[/tex] the grade for each subject. From this case we can find the following sum:

[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]

And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:

[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]

And from the previous result we got:

[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]

And solving we got:

[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]

And then we can find the mean with this formula:

[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Answer:

0.8397

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the cards are chosen is not important. Also, they are drawn without replacement. So we use the combinations formula to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

What is the probability that at least one of the cards drawn is a spade?

Either none is a spade, or at least one is a spade. The sum of the probabilities of these outcomes is 1.

The standard deck has 52 cards, of which 13 are spades. So

Probability that none are spades:

Desired outcomes:

6 cards from a set of 52 - 13 = 39. So

[tex]D = C_{39,6} = \frac{39!}{6!33!} = 3262623[/tex]

Total outcomes:

6 cards from a set of 52. So

[tex]T = C_{52,6} = \frac{52!}{6!46!} = 20358520[/tex]

Probability:

[tex]p = \frac{D}{T} = \frac{3262623}{20358520} = 0.1603[/tex]

Probability that at least one is a spade:

1 - 0.1603 = 0.8397

The answer is 0.8397

Answer:

[tex]Perimeter = 11 + \sqrt{13}[/tex]

Step-by-step explanation:

To find the perimeter of WXYZ we need to find the length of all four sides: WX, XY, YZ and WZ.

To find the length of each side, we can use the formula for the distance of two points:

[tex]distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

So we have that:

[tex]WX = \sqrt{(2 - 4)^2 + (3 - 6)^2} = \sqrt{13}[/tex]

[tex]XY = \sqrt{(4 - 7)^2 + (6 - 6)^2} = 3[/tex]

[tex]YZ = \sqrt{(7 - 7)^2 + (6 - 3)^2} = 3[/tex]

[tex]WZ = \sqrt{(2 - 7)^2 + (3 - 3)^2} = 5[/tex]

The perimeter is:

[tex]Perimeter = WX + XY + YZ + WZ[/tex]

[tex]Perimeter = \sqrt{13} + 3 + 3 + 5 =11 + \sqrt{13}[/tex]

Answer:

  6 × 5 × 5 square inches

Step-by-step explanation:

The area of one of the figure's 6 squares is the product of its side length, so is ...

  5 × 5 square inches

The area of all 6 of those squares is 6 times this, or ...

  6 × 5 × 5 square inches

Answer:

b. Skewed-left

Step-by-step explanation:

The histogram will be expressed with the x-axis representing the salaries, in growing amount to the right. The y-axis will represent the relative or absolute frequency.

We know that most of the players earn the minimum league wage. Then, we will have a high frequency in the low salaries classes, at the left of the histogram. A few players earn very high salaries, so we will have a right tail with high values for the salaries a little frequency.

There is no symmetry in this histogram and it is not uniform, as there is no representative mean salary.

As most of the data will be close to the left side, we can conclude that the histogram will be skewed-left.

The Histogram of salary data, with most having less salary is RIGHT Skewed

Given : Data of players' salary is concentrated towards towards most players having less ( minimum ) salary.

Right Skewness denotes a distribution where Tail is on the right side. This implies data is highly concentrated toward left side, ie lower independent variable (x - here 'salary') values.

Left Skewness denotes a distribution where Tail is on the left side. This implies data is highly concentrated towards right side, ie higher independent variable (x - here 'salary') values.

In this case : As more players have lower values of independent variable ie salary, so the data will be concentrated at left - having tail at right.

Hence, it will be Skewed Right

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Answer:

1. tan J

2. D. tan(∠x) = yz/xy

Step-by-step explanation:

1. Remember that tangent is opposite over hypotenuse. So 12 has to be opposite of x point. The only point suitable would be point J. Therefore, your answer is for tan∅ is tan J.

2. Same concept here as in 1. Extra: If tan is sin∅/cos∅ on the unit circle, that means yz would have to be sin and yx would have to be cos.

Answer:

1  3/10

Step-by-step explanation:

9/8  +7/40

Get a common denominator of 40

9/8 *5/5 + 7/40

45/40 + 7/40

52/40

Rewriting as

40/40 +12/40

1 + 3/10

1  3/10

Answer:

1 3/10

Step-by-step explanation:

First, you need to get a common denominator:

8x5=40 <-- common denominator

45/40+7/40= 52/40

yes you can simplify it.

your final answer will be: 1 3/10

Answer:

It's D: No, there is not enough information given.

Step-by-step explanation:

just took the quiz

The correct answer option D which is No, there is not enough information given.

A parallelogram is a quadrilateral having four sides with two opposite sides parallel to each other. The sum of the angles suspended by all the four sides of the parallelogram is 360.

Using VX = WZ and m∠ZVX = m∠XWZ, we have a side and an angle. In order to prove the triangles congruent by SAS, we must have two sides and the angle between them. With the information we have now, we would have to have VZ = WX. However, we are not given that information.

We do have that ZX = ZX by the reflexive property, but this is not SAS, as the angle we have is not between the two sides.

Therefore correct answer option D which is No, there is not enough information given.

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Answer:

-2x² + 15

Step-by-step explanation:

Step 1: Add like terms

4x² - 6x² = -2x²

-10x + 10x = 0

12 + 3 = 15

Step 2: Rewrite

-2x² + 15

[tex](8 - 10x + 3) + ( - 12 + 10x + 12)[/tex]

[tex](11 - 10x) + (10x)[/tex]

[tex] 11 - 10x + 10x[/tex]

[tex] = 11[/tex]

Answer:

36

Step-by-step explanation:

Answer:

Dear User

Answer to your query is provided below

X = 2/7 or X = -3/2

Step-by-step explanation:

Explanation for the same is attached in image

Answer:

Step-by-step explanation:

Hello!

Since you didn't upload the data, I'll use my own data to solve the example. The steps will be the same, only the results will change. (see attachment) The hypothesis test will be made using a 5% significance level.

The objective of this exercise is to test if there is an association between two variables:

X₁: The subject is vaccinated, categorized "Yes" and "No"

X₂: The subject got the disease, categorized "Yes" and "No"

These two variables of interest are qualitative categorical and each one of them has two categories.

To test if the variables are associated, considering the type of variables they are, you have to apply a Chi Square test of Independence, where the statistic hypotheses are:

H₀: [tex]P_{ij}= P_{i.} * P_{.j}[/tex] ∀ i= 1, 2 and j= 1, 2

H₁: The variables, vaccination and disease status, are not independent.

α: 0.05

The statistic is

X²= [tex]{r} \atop {i=1} \right.[/tex]∑[tex]{c} \atop {j=1} \right.[/tex]∑[tex]\frac{(O_{ij}-E_{ij})^2}{E_{ij}}[/tex]≈[tex]X^2_{(r-1)(c-1)}[/tex]

i= values in rows

j= values in columns

r= total number of rows

c= total number of columns

This type of test is always one-tailed to the right, meaning that you will reject the null hypothesis to high values of Chi Square. There is only one critical value:

[tex]X^2_{(r-1)(c-1);1-\alpha }= X^2_{(2-1)(2-1);1-0.05}= X^2_{1*1;0.95}= 3.841[/tex]

The decision rule will be:

If [tex]X^2_{H_0}[/tex] ≥ 3.841, reject the null hypothesis.

If [tex]X^2_{H_0}[/tex] < 3.841, do not reject the null hypothesis.

Using the p-value approach, the decision rule is always the same:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

Before calculating [tex]X^2_{H_0}[/tex], you have to calculate the expected frequencies for all categories using the formula:

Ê[tex]_{ij}[/tex]= [tex]\frac{O_{i.}*O_{.j}}{n}[/tex]

Ê₁₁= [tex]\frac{O_{1.}*O_{.1}}{n}= \frac{82*100}{200} = 41[/tex]

Ê₁₂= [tex]\frac{O_{1.}*O_{.2}}{n}= \frac{82*100}{200} = 41[/tex]

Ê₂₁= [tex]\frac{O_{2.}*O_{.1}}{n}= \frac{118*100}{200} = 59[/tex]

Ê₂₂= [tex]\frac{O_{2.}*O_{.2}}{n}= \frac{118*100}{200} = 59[/tex]

[tex]X^2_{H_0}= \frac{(42-41)^2}{41} + \frac{(40-41)^2}{41} + \frac{(58-59)^2}{59} + \frac{(60-59)^2}{59}= 0.0827[/tex]

The p-value for this test is the probability of obtaining a value as extreme as [tex]X^2_{H_0}[/tex]= 0.0827:

P(X₁² ≥ 0.0827)= 1 - P(X₁² < 0.0827)= 1 - 0.2264= 0.7736

Ata 5% significance level, the decision is to not reject the null hypothesis. You can conclude that the vaccination and the disease status of the subjects are not related. The new vaccine does not affect the chances of the subjects getting the disease.

I hope this helps!

Answer:

D.

Step-by-step explanation:

Deus ex machina is the plot device of using something very improbable to resolve a situation.

Answer:

The explanation is:

All interior angles in an equilateral triangle are congruent, making them all 60° by the sum of angles in a triangle. Because alternate interior angles of parallel lines are congruent, x = 60°.

Answer: The mean difference is between 799586.3 and 803257.9.

Step-by-step explanation: To estimate the mean difference for confidence interval:

Find the statistic sample:

For the traffic count, mean = 1835.8 and s = 1382607.3

The confidence interval is 90%, so:

α = [tex]\frac{1-0.9}{2}[/tex]

α = 0.05

The degrees of dreedom are:

df = n - 1

df = 10 - 1

df = 9

Using a t-ditribution table, the t-score for α = 0.05 and df = 9 is: t = 1.833.

Error will be:

E = [tex]t.\frac{s}{\sqrt{n} }[/tex]

E = 1.833.([tex]\frac{1382607.3}{\sqrt{10} }[/tex])

E = 801422.1

The interval is: mean - E < μ < E + mean

1835.8 - 801422.1 < μ < 1835.8+801422.1

-799586.3 < μ < 803257.9

The estimate mean difference in trafic count between 6th and 13th using 90% level of confidence is between 799586.3 and 803257.9.

Answer:

[tex]\cos (\theta)[/tex]

Step-by-step explanation:

[tex]\dfrac{\tan (\theta) \cot (\theta)}{\sec (\theta)}= \\\\\\\dfrac{\dfrac{\sin (\theta)}{\cos (\theta)}\cdot \dfrac{\cos (\theta)}{\sin (\theta)}}{\dfrac{1}{\cos (\theta)}}= \\\\\\1\cdot \cos (\theta)=\\\\\\\boxed{\cos (\theta)}[/tex]

Hope this helps!

Answer:

csc 270° is the answer.

Answer:

None

Step-by-step explanation:

The answers are:

1. g(10) -31

2. x= -17/3

3. f(3)= 2

4.x= √30

5. h(-2)= 1

6. x= 0

7. h(a)= 1

In mathematics, a function is represented as a rule that produces a distinct result for each input x. In mathematics, a function is indicated by a mapping or transformation. Typically, these functions are identified by letters like f, g, and h. The collection of all the values that the function may input while it is defined is known as the domain. The entire set of values that the function's output can produce is referred to as the range. The set of values that could be a function's outputs is known as the co-domain.

Given:

f(x) = x² – 7

g(x) = -3x - 1

j(x)= 2x-9

h(x) = 1

1. g(10)= -3(10) -1 = -30 - 1= -31

2. g(x) = 16

-3x- 1= 16

-3x = 17

x= -17/3

3. f(3)= (3)² – 7 = 9- 7= 2

4. f(x)= 23

x² – 7=  23

x² = 30

x= √30

5. h(-2)= 1

6. x= 0

7. h(a)= 1

8. S(-1) = 3

The value of function s(a) at a=-1 is 3.

10. g(4) = -1

The value of function g(a) at a=4 is -1.

11. h(2) = 8

The value of function h(a) at a=2 is 8.

12. k(2) = 9​

The value of function k(a) at a= 2 is 9.

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Answer:

(a)650 ways

(b)650 ways

(c)676 ways

Step-by-step explanation:

There are 26 red and 26 black cards.

If a card is dealt to each of 2 players, we want to find out how many different ways this can be done.

(a)Both cards are red

If both cards are red:

The first red card can be dealt in 26 ways.

The second red card can be dealt in 25 ways.

Therefore: Both Red cards can be dealt in: 26 X 25 = 650 ways

(b)Both cards are black

If both cards are black:

The first black card can be dealt in 26 ways.

The second black card can be dealt in 25 ways.

Therefore: Both black cards can be dealt in: 26 X 25 = 650 ways

(c)One card is black and the other is red.

The red card can be dealt in 26 ways.

The black card can be dealt in 26 ways.

Therefore: Both cards can be dealt in: 26 X 26 = 676 ways

Answer:

  a = -2; b = 5

Step-by-step explanation:

Expanding the right side of the given equation, we have ...

  x^2 -4x +9 = x^2 +2ax +a^2 +b

Comparing coefficients, we see ...

  -4 = 2a . . . . . coefficient of x term

  9 = a^2 +b . . . constant term

The first of these tells us ...

  -2 = a . . . . divide by 2

The second of these tells us ...

  9 = (-2)^2 +b . . . substitute for a

  5 = b . . . . subtract 4

The values of a and b are (a, b) = (-2, 5).

Answer:

a=-2

b=5

Step-by-step explanation:

type this on mathswatch and you will get it right

Answer:

[tex] P(X>1)= 1-P(X \leq 1)= 1- [P(X=0) +P(X=1)][/tex]

And if we use the probability mass function we got:

[tex]P(X=0)=(4C0)(0.6)^0 (1-0.6)^{4-0}=0.0256[/tex]  

[tex]P(X=1)=(4C1)(0.6)^1 (1-0.6)^{4-1}=0.1536[/tex]  

And replacing we got:

[tex] P(X>1) =1- [0.0256 +0.1536]= 0.8208[/tex]

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=4, p=0.6)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

We want to find the following probability:

[tex] P(X >1)[/tex]

And for this case we can use the complement rule and we got:

[tex] P(X>1)= 1-P(X \leq 1)= 1- [P(X=0) +P(X=1)][/tex]

And if we use the probability mass function we got:

[tex]P(X=0)=(4C0)(0.6)^0 (1-0.6)^{4-0}=0.0256[/tex]  

[tex]P(X=1)=(4C1)(0.6)^1 (1-0.6)^{4-1}=0.1536[/tex]  

And replacing we got:

[tex] P(X>1) =1- [0.0256 +0.1536]= 0.8208[/tex]

Answer:

  C.  (5, 3)

  D.  (7, -1)

Step-by-step explanation:

The requirement that y < 4 eliminates points A, E, F. None of 7, 4, 5 are less than 4.

The requirement that x+y ≥ 6 eliminates point B. 1-1 = 0 is not at least 6.

Points C and D satisfy both inequalities.

Answer:

The number of games must a store sell in order to be eligible for a reward is 135.

Step-by-step explanation:

Let the random variable X represent the number of video games sold in a month by the sores.

The random variable X has a mean of, μ = 132 and a standard deviation of, σ = 9.

It is provided that the company is looking to reward stores that are selling in the top 7%.

That is, [tex]P (\bar X > \bar x) = 0.07[/tex].

The z-score related to this probability is, z = 1.48.

Compute the number of games must a store sell in order to be eligible for a reward as follows:

[tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}[/tex]

[tex]\bar x=\mu+z\cdot \sigma/\sqrt{n}[/tex]

   [tex]=132+1.48\times (9/\sqrt{36})\\\\=132+2.22\\\\=134.22\\\\\approx 135[/tex]

Thus, the number of games must a store sell in order to be eligible for a reward is 135.

Answer:

1.48

1.5

135

Step-by-step explanation:

Answer:

543

Step-by-step explanation:

let x= total salary

0.25x=135.75

x=543

Answer:

[tex]\$ \: 543.00[/tex]

Step-by-step explanation:

[tex]25\% \times x =135.75[/tex]

[tex]1/4 \times x =135.75[/tex]

[tex]0.25 \times x =135.75[/tex]

[tex]x=135.75 \times 4[/tex]

[tex]x=543[/tex]

Answer:

Step-by-step explanation:

Using the one sample proportion test:

z = (p-P) / √{P (1-P)/n}

Where p = 709/2640= 0.27, P = 0.29, n= 2640

Thus z = (0.27-0.29) / √{0.29 (1-0.29) / 2640}

z = (-0.02) / √{0.29(0.71) /2640}

z = (-0.02) / √0.00007799

z = (0.02) / 0.0088

z = 2.27

To be able to draw a conclusion, lets find the p value at the 0.1 level of significant: p value is 0.2327. The result is significant as the p value is greater than 0.1 thus we will fail to reject the null and conclude that there is not enough statistical evidence to prove that the true percentage of all firms that announced one or more acquisitions during the year 2000 is less than 29%

Answer:

  f^-1(x) = (4x +3)/(1 -x)

Step-by-step explanation:

Solve for y:

  f(y) = x

  (y -3)/(y +4) = x

  y -3 = xy +4x . . . . . . multiply by y+4

  y -xy = 4x +3 . . . . . . add 3-xy

  y(1 -x) = 4x +3 . . . . . factor out y

  y = (4x +3)/(1 -x) . . . divide by the coefficient of y

The inverse function is ...

  f^-1(x) = (4x +3)/(1 -x)

Answer:

Haha proofs are an interesting thing. Usually, nothing is to scale, which is why you can't measure anything. They are pretty annoying, but it helps to know why certain things are the way that they are and develop justification skills for higher level math.

Sorry to discourage you, but you're going to see "Justify" quite a lot in calculus and beyond which is basically a more informal version of a proof

you can never escape it tbh lol

We can't just measure the two figures to see if they are congruent as congruence is about shape and size.

It should be noted that congruence simply means that the shapes have identical length, angles, and size.

Therefore, we can't just measure the two figures to see if they are congruent as congruence is about shape and size.

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Answer:

poop

Step-by-step explanation:

poop