Write the MIPS assembly code to find the area of a given shape. Your program must take a floating-point value and shape (Circle - 1, Triangle - 2, Square - 3) as input and return the circumference/perimeter and area of the shape. Assume the floating-point value units are meters and the triangle is an equilateral triangle. [Note: you can search for the expression to calculate the area and circumference/perimeter of these shapes]

Answers

Answer 1

Answer:

Explanation:

.data

msg1: .asciiz "Enter the floating point value = "

msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "

msg3: .asciiz "\nThe perimeter of the triangle with side = "

msg4: .asciiz " meters is "

msg5: .asciiz " meters.\n"

msg6: .asciiz "\nThe area of the triangle with side = "

msg7: .asciiz " square meters.\n"

msg8: .asciiz "\nThe circumference of the circle with radius = "

msg9: .asciiz "\nThe area of the circle with radius = "

msg10: .asciiz "\nThe perimeter of the square with side = "

msg11: .asciiz "\nThe area of the square with side = "

pi: .float 3.1415816

eq_tr_area: .float 0.43305186

two: .float 2

three: .float 3

four: .float 4

.text

li $v0,4           # system call code for printing string = 4

la $a0,msg1       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0,6           # system call code for reading floating point number

syscall           # call operating system to perform read operation

li $v0,4           # system call code for printing string = 4

la $a0,msg2       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0,5           # system call code for reading integer

syscall           # call operating system to perform read operation

move $t0,$v0

IF:

bne $t0,1,ELSE_IF   #if not 1 then goto elseif

li $v0,4           # system call code for printing string = 4

la $a0,msg8       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

l.s $f1,pi

l.s $f3,two

mul.s $f3,$f3,$f1   #calculate 2*pi*radius

mul.s $f3,$f3,$f0

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f3       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg5       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg9       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

mul.s $f2,$f0,$f0   #calculate radius *radius

mul.s $f2,$f2,$f1   #calculate pi *r^2

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f2       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg7       # load address of string to be printed into $a0

syscall  

ELSE_IF:

bne $t0,2,ELSE       #if not 2 then check else

li $v0,4           # system call code for printing string = 4

la $a0,msg3       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

l.s $f3,three

mul.s $f3,$f3,$f0   #calculate 3*side

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f3       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4            

la $a0,msg5        

syscall            

li $v0,4            

la $a0,msg6        

syscall          

li $v0, 2        

mov.s $f12,$f0        

syscall            

li $v0,4            

la $a0,msg4      

syscall            

l.s $f3,eq_tr_area    

mul.s $f2,$f0,$f0    

mul.s $f2,$f2,$f3    

li $v0, 2      

mov.s $f12,$f2      

syscall            

li $v0,4            

la $a0,msg7        

syscall  

ELSE:

bne $t0,3,END        

li $v0,4            

la $a0,msg10        

syscall            

li $v0, 2        

mov.s $f12,$f0        

syscall            

li $v0,4            

la $a0,msg4        

syscall            

l.s $f3,four      

mul.s $f3,$f3,$f0    

li $v0, 2        

mov.s $f12,$f3      

syscall            

li $v0,4          

la $a0,msg5        

syscall            

li $v0,4          

la $a0,msg11      

syscall            

li $v0, 2        

mov.s $f12,$f0      

syscall            

li $v0,4          

la $a0,msg4        

syscall          

mul.s $f2,$f0,$f0    

li $v0, 2        

mov.s $f12,$f2      

syscall            

li $v0,4            

la $a0,msg7        

syscall  

END:

li $v0,10        

syscall          

Answer 2

Code is as follows:

.data

msg1: .asciiz "Enter the floating point value = "

msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "

msg3: .asciiz "\nThe perimeter of the triangle with side = "

msg4: .asciiz " meters is "

msg5: .asciiz " meters.\n"

msg6: .asciiz "\nThe area of the triangle with side = "

msg7: .asciiz " square meters.\n"

msg8: .asciiz "\nThe circumference of the circle with radius = "

msg9: .asciiz "\nThe area of the circle with radius = "

msg10: .asciiz "\nThe perimeter of the square with side = "

msg11: .asciiz "\nThe area of the square with side = "

pi: .float 3.1415816

eq_tr_area: .float 0.43305186

two: .float 2

three: .float 3

four: .float 4

.text

li $v0,4           # system call code for printing string = 4

la $a0,msg1       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0,6           # system call code for reading floating point number syscall           # call operating system to perform read operation

li $v0,4           # system call code for printing string = 4 la $a0,msg2       # load address of string to be printed into $a0 syscall           # call operating system to perform print operation

li $v0,5           # system call code for reading integer syscall           # call operating system to perform read operation move $t0,$v0

IF:

bne $t0,1,ELSE_IF   #if not 1 then goto elseif

li $v0,4           # system call code for printing string = 4

la $a0,msg8       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2 mov.s $f12,$f0       #move the single precision f2 in f12 syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4 la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

l.s $f1,pi l.s $f3,two

mul.s $f3,$f3,$f1   #calculate 2*pi*radius

mul.s $f3,$f3,$f0

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f3       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg5       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg9       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

mul.s $f2,$f0,$f0   #calculate radius *radius

mul.s $f2,$f2,$f1   #calculate pi *r^2

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f2       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg7       # load address of string to be printed into $a0

syscall  

ELSE_IF:

bne $t0,2,ELSE       #if not 2 then check else

li $v0,4           # system call code for printing string = 4 la $a0,msg3       # load address of string to be printed into $a0 syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f2 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

l.s $f3,three

mul.s $f3,$f3,$f0   #calculate 3*side

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f3       #move the single precision f2 in f12

syscall  

bne $t0,3,END       #if not 3 then end

li $v0,4           # system call code for printing string = 4

la $a0,msg10       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f0       #move the single precision f0 in f12

syscall           # call operating system to perform print operation

li $v0,4           # system call code for printing string = 4

la $a0,msg4       # load address of string to be printed into $a0

syscall           # call operating system to perform print operation

l.s $f3,four       # multilply by 4

mul.s $f3,$f3,$f0   #calculate 4*side

li $v0, 2       # system call code for printing float = 2

mov.s $f12,$f3       #move the single precision f3 in f12

syscall           # call operating system to perform print operation

END:  

li $v0,10       # system call code for printing exit (end of program)

syscall           # call operating system to perform print operation

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Write The MIPS Assembly Code To Find The Area Of A Given Shape. Your Program Must Take A Floating-point
Write The MIPS Assembly Code To Find The Area Of A Given Shape. Your Program Must Take A Floating-point
Write The MIPS Assembly Code To Find The Area Of A Given Shape. Your Program Must Take A Floating-point
Write The MIPS Assembly Code To Find The Area Of A Given Shape. Your Program Must Take A Floating-point
Write The MIPS Assembly Code To Find The Area Of A Given Shape. Your Program Must Take A Floating-point

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1. Create a (3,3) array where row 0 is [0, 0, 0], row 1 is [2, 2, 2], row 2 is [-2, -2, -2]. Print the array.
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In [ ]: # Your codes for 2.
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Answer:

(1) The program in Python is as follows:

rows, cols = (3, 3)

arr =[[0,0,0],[2,2,2],[-2,-2,-2]]

print(arr)

arr[0][0] = 10

arr[2][2] = -10

print(arr)

for i in range(rows):

   for j in range(cols):

       arr[i][j]-=2

   

print(arr)

for i in range(rows):

   for j in range(cols):

       if arr[i][j]< 0:

           print(arr[i][j], end = ", ")

(2) The program in Python is as follows:

import numpy as np

x = [10000, 1000, 100, 10, 1, 0, -10, -100]

p = [0.05, 0.05, 0.20, 0.20, 0.1, 0.1, 0.1, 0.2]

q = np.dot(x,p)

print(q)

Explanation:

(1)

This initializes the rows and columns of the array to 3

rows, cols = (3, 3)

1. This creates and array and also populates it with the given data

arr =[[0,0,0],[2,2,2],[-2,-2,-2]]

Print the array

print(arr)

2. This changes index 0,0 to 10 and index 2,2 to -10

arr[0][0] = 10

arr[2][2] = -10

Print the array

print(arr)

This iterates through the rows and the columns of the array

for i in range(rows):

   for j in range(cols):

3. This subtracts 2 from each array element

       arr[i][j]-=2

Print the array    

print(arr)

This iterates through the rows and the columns of the array

for i in range(rows):

   for j in range(cols):

If array element is negative

       if arr[i][j]< 0:

4. Print the array element

           print(arr[i][j], end = ", ")

(2)

Line 1 and 2 are given as part of the program

x = [10000, 1000, 100, 10, 1, 0, -10, -100]

p = [0.05, 0.05, 0.20, 0.20, 0.1, 0.1, 0.1, 0.2]

This uses np dot to multiply x and p

q = np.dot(x,p)

This prints the result of the product

print(q)

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Answer:

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age = int(input("Age: "))

carryOn = int(input("Carry on Bags [0 or 1]: "))

checkedBags = int(input("Checked Bags [0 or greater]: "))

airFare = 300

if age >= 60:

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   airFare = 0

if carryOn ==  1:

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if checkedBags ==  2:

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Explanation:

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This gets input for carry on bags

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This gets input for checked bags

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This initializes the base cost to 300

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   airFare = 290

This updates the base cost to 0 for children 2 years or younger

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This updates the airFare if carryOn bag is 1

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This updates the airFare if checkedBags is 2. The first bag is free; so, only the second is charged

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   def __init__(self, first, last) :

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Answer:

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The program written in C++, where comments are used to explain each action is as follows:

#include<bits/stdc++.h>

using namespace std;

//This defines the SortVector function

void SortVector(vector <int>& myVec){

   //This sorts the vector elements in ascending order

   sort(myVec.begin(), myVec.end());

   //This iterates through the sorted vector, and print each element

for (auto x : myVec)

 cout << x << " ";

}

//The main begins here

int main(){

   //This declares all the variables

   int num, numInput; vector<int> v;

   //This gets the length of the vector

   cin>>num;

   //The following iteration gets input for the vector

   for(int i = 0; i<num;i++){

       cin>>numInput;

       v.push_back(numInput);

   }

   //This calls the SortVector function

   SortVector(v);

return 0;

}

Read more about functions at:

https://brainly.com/question/24833629

arrange the following numbers in ascending order -2/3, 7/-18 , 5/-19​

Answers

Answer:

2/3 5/19 7/18

Explanation:

Write a function that simulates the roll of a six-sided dice. The name of the function is rollDice. The function accepts no parameters and returns a pseudorandom int: 1, 2, 3, 4, 5, or 6. Write only the function, not the main program. You may assume that srand() was invoked in the main function. There should not be any cin or cout statements in the function.

Answers

Answer:

int rollDice(){

  return 1 + rand() % 6;

}

Explanation:

What technique is used to store sound waves as binary numbers?

Answers

Answer:

Sound waves are analogue and therefore they need to be converted into binary in order for a computer to be able to process them. To do this, the computer must convert the waveform into a numerical representation so that the waveform can be stored digitally. For this, we use an Analogue-to-Digital Convertor (ADC).

Explanation:

Sound waves aren’t a digital standard so they used conversion

Who takes Mindtap Web Design

Answers

Answer:

MindTap is a new personalized program of digital products and services that engages students with interactivity while also offering students and instructors choice in content, platform, devices, and learning tools. ... The customizable, cloud-based system is a web portal students log into to navigate via a dashboard.

Explanation:

MindTap for Minnick's Responsive Web Design with HTML 5 & CSS, 9th Edition is the digital learning solution that powers students from memorization to mastery. It gives you complete control of your course—to provide engaging content, to challenge every individual, and to build their confidence.

why does a computer system need memory​

Answers

Explanation:

Computer memory is a temporary storage area. It holds the data and instructions that the Central Processing Unit (CPU) needs.

Lucy wants to add some notes in her research paper that provide additional information to the reader. She also wants to display her university logo on all the pages as part of the title. What formatting can she apply to her document to include these details?

Answers

She can use a header

Which is true regarding pseudocode?
It uses simple words and symbols to communicate the design of a program,
It compiles and executes code.
It expresses only complex processes.
O It gives a graphical representation of a set of instructions to solve a problem.

Answers

Answer:

It uses simple words and symbols to communicate the design of a program

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are seven (7) main stages in the creation of a software and these are;

1. Planning.

2. Analysis.

3. Design.

4. Development (coding).

5. Testing.

6. Implementation and execution.

7. Maintenance.

A pseudocode refers to the description of the steps contained in an algorithm using a plain or natural language. Also, a pseudocode gives a summary of the steps adopted during a software development process using simple (concise) words and symbols.

This ultimately implies that, a pseudocode uses simple words and symbols to communicate the design of a program.

Answer:

A: It uses simple words and symbols to communicate the design of a program

Explanation:

Credit to the person above me.

Which problem does IPv6 (Internet Protocol version 6) help to solve?

Answers

Answer:

Address space exhaustion

Explanation:

IPv6 (Internet Protocol version 6) was introduced in 1995. This model is faster and safer than the previous models due to the modifications done on it.

It was however introduced with the main aim of addressing space exhaustion. IPv4 addresses were already getting scarce and a new model had to be introduced to bridge the gap. IPv4 has billions of addresses however IPv6 has multiples of trillions addresses to take care of current and future needs.

**GIVING ALL POINTS** 4.02 Coding With Loops
I NEED THIS TO BE DONE FOR ME AS I DONT UNDERSTAND HOW TO DO IT. THANK YOU

Output: Your goal

You will complete a program that asks a user to guess a number.


Part 1: Review the Code

Review the code and locate the comments with missing lines (# Fill in missing code). Copy and paste the code into the Python IDLE. Use the IDLE to fill in the missing lines of code.


On the surface this program seems simple. Allow the player to keep guessing until he/she finds the secret number. But stop and think for a moment. You need a loop to keep running until the player gets the right answer.


Some things to think about as you write your loop:


The loop will only run if the comparison is true.

(e.g., 1 < 0 would not run as it is false but 5 != 10 would run as it is true)

What variables will you need to compare?

What comparison operator will you need to use?

# Heading (name, date, and short description) feel free to use multiple lines


def main():


# Initialize variables

numGuesses = 0

userGuess = -1

secretNum = 5


name = input("Hello! What is your name?")


# Fill in the missing LOOP here.

# This loop will need run until the player has guessed the secret number.


userGuess = int(input("Guess a number between 1 and 20: "))


numGuesses = numGuesses + 1


if (userGuess < secretNum):

print("You guessed " + str(userGuess) + ". Too low.")


if (userGuess > secretNum):

print("You guessed " + str(userGuess) + ". Too high.")


# Fill in missing PRINT statement here.

# Print a single message telling the player:

# That he/she guessed the secret number

# What the secret number was

# How many guesses it took


main()

Part 2: Test Your Code

Use the Python IDLE to test the program.

Using comments, type a heading that includes your name, today’s date, and a short description.

Run your program to ensure it is working properly. Fix any errors you observe.

Example of expected output: The output below is an example of the output from the Guess the Number game. Your specific results will vary based on the input you enter.


Output


Your guessed 10. Too high.

Your guessed 1. Too low.

Your guessed 3. Too low.

Good job, Jax! You guessed my number (5) in 3 tries!




When you've completed filling in your program code, save your work by selecting 'Save' in the Python IDLE.


When you submit your assignment, you will attach this Python file separately.


Part 3: Post Mortem Review (PMR)

Using complete sentences, respond to all the questions in the PMR chart.


Review Question Response

What was the purpose of your program?

How could your program be useful in the real world?

What is a problem you ran into, and how did you fix it?

Describe one thing you would do differently the next time you write a program.

Answers

Answer:

sorry man

Explanation:

How many binary digits does a single hexadecimal digit represent?

Answers

Four binary digits

A single hexadecimal digit can represent four binary digits.

What is the output of the following code segment?

String[] cs = "Elon Musk founded SpaceX on May 6, 2002.".split(" ");

System.out.println(cs.length);

Answers

Answer:

8

Explanation:

paki sagot po kailangan ko na po Kasi Yan ngayon and I follow po Kita f ma answer mo nang Tama!❤️​

Answers

Answer:

1. Mali

2. Tama

3.tama

4. Tama

5. tama

Answer:

1. Mali

2. Tama

3.tama

4. Tama

5. tama

Explanation:

other person got it ;)

what are the qualitative data items about text book​

Answers

Answer:

Qualitative data is defined as the data that approximates and characterizes. Qualitative data can be observed and recorded. ... This type of data is collected through methods of observations, one-to-one interviews, conducting focus groups, and similar methods.

21. The most overlooked people in information security are:
A consultants and temporary hires.
B. secretaries and consultants.
C. contract laborers and executive assistants.
D. janitors and guards.
E. executives and executive secretaries.

Answers

Answer: D. janitors and guards

Explanation:

Information security simply means the protection of information from an unauthorized use or access.

The most overlooked people in information security are the janitors and the guards. Due to the fact that they're at the bottom of the organizational chart, they tend to be overlooked and not given the respect that they deserve.

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