write the chemical formulae for; nitrogen monoxide, hydrochloric acid, barium phosphate, ammonium hydroxide,nitric acid​

Answers

Answer 1

Answer:

Nitrogen Monoxide = NOHydrochloric Acid = HCLBarium Phosphate = (Ba) 3{(Po)4}Ammonium Hydroxide = (NH) 4(OH) Nitric Acid = H(NO)3

Write The Chemical Formulae For; Nitrogen Monoxide, Hydrochloric Acid, Barium Phosphate, Ammonium Hydroxide,nitric
Write The Chemical Formulae For; Nitrogen Monoxide, Hydrochloric Acid, Barium Phosphate, Ammonium Hydroxide,nitric

Related Questions

Study the image of earths layer which statement correctly compares the thicknesses of earths layers

Answers

This question is incomplete because the options are missing; here is the complete question:

Study the image of the Earth's layer which statement correctly compares the thicknesses of earths layers

A. Earth’s mantle is thinner than its oceanic crust.

B. Earth’s outer core is thicker than its mantle.

C. Earth’s continental crust is thicker than its lithosphere.

D. Earth’s lithosphere is thinner than its asthenosphere.

The answer to this question is D. Earth’s lithosphere is thinner than its asthenosphere.

Explanation:

The image shows the different layers that are part of Earth, as well as the thickness of each layer, in kilometers. In this, the thickest layer is the Mantle that is almost 2900 kilometers; this is followed in thickness by the outer and the inner core.

Additionally, other layers such as the continental/oceanic crust, the asthenosphere, and the lithosphere that are near the surface are thinner. About this, it can be concluded the lithosphere is thinner than the asthenosphere because the lithosphere has a thickness of 100 km, while the asthenosphere thickness is 660km. This makes option D the correct.

The density of an object is .835 g/cm3. If its volume is 34 cm3, what is the mass of the object? (Density: D = )

.02 g
.41 g
28.39 g
40.72 g

Answers

Answer:

28.39 g

Explanation:

D= m ÷ v

So, M= D × V

0.835 × 34= 28.39

Answer:

C. 28.39 g

Explanation:

took the test<3

Distinguish between homogeneous and heterogeneous mixture with 2 example each. Do not use the examples give above​

Answers

homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. While, heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture.
Example of heterogeneous :
Oil and water
Smog

Example of homogeneous:
Salt water
Air

how does enormous energy get released from the sun​

Answers

Answer:

By nuclear fission

Explanation:

The sun generates enormous energy through the process of nuclear fusion.

The core or the innermost part of the sun is characterized by high temperature and pressure. These two factors cause the separation of nuclei from electrons and the fusion of hydrogen nuclei to form a  helium atom.

During the fusion process, energy is released.

please help


The statement "46 m, East" refers to the
of an object.
velocity
distance
displacement
speed
acceleration

Answers

Answer:

Displacement

Explanation:

Displacement is a vector quantity i.e it has both magnitude and direction. The direction is indicated with compass bearing i.e North, South, East or West or you could have North East, North West, South West, South East.

A toaster oven draws 300.0 watts of power. If it is plugged into an outlet with a voltage of 115 volts, what current is in the toaster's circuit?
OA 3.45 10% amps
ОВ.
415 amps
Ос.
285 amps
OD
2.61 amps

Answers

Answer:

I = 2.61 A

Explanation:

It is given that,

Power of a toaster is 300 watts

It is plugged into an outlet with a voltage of 115 volts

We need to find the current in the toaster's circuit.

The electrical power is given by the formula as follows :

P = V I

I is electric current

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{300}{115}\\\\I=2.61\ A[/tex]

So, 2.61 A of current is in the toaster's circuit.

Answer: D.

2.61 amps

Explanation: edmentum

What is the kinetic energy of a 200kg boat moving at 2.7m/s?

Answers

Answer:

729 Joules

Explanation:

Kinetic energy is 1/2mv²

where m is the mass of the object

v is the velocity

From the question

m = 200kg

v = 2.7m/s

Kinetic energy is

1/2 × 200 × 2.7²

= 729 Joules

Hope this helps you

729 joules is what I think is right

Using the formula W = mg, how many milliliters of water with a density of 1g/mL are required to weigh 0.75 newtons and g = 9.81 m/s2? Round to the nearest tenth. (Note: The mass will be in kg in your answer, thus convert to g and then to mL.) Answer: mL

Answers

Given that,

Weight = 0.75 N

Acceleration due to gravity = 9.81 m/s²

Density of water = 1 g/ml

We need to calculate the volume of water

Using formula of weight

[tex]W=mg[/tex]

[tex]W=\rho Vg[/tex]

[tex]mg=\rho\times V\times g[/tex]

Where, V = volume

g = acceleration

m = mass

Put the value into the formula

[tex]0.076\times 9.8\times10^3=1\times V\times9.8[/tex]

[tex]V= \dfrac{0.076\times 9.8\times10^3}{1\times9.8}[/tex]

[tex]V=76\ ml[/tex]

Hence, The volume of water is 76 mL.

Answer:

76.5mL

Explanation:

w = mg

0.75N = m * 9.81

m = 0.75 / 9.81 = 0.0765 kg

The mass in grams is 0.0765 * 1000 = 76.5g

At a density of 1 g/mL,

76.5g ÷ 1g/ml = 76.5mL

A ball is moving up an inclined plane, when it's velocity changes from 15m/s to 7m/s in 3 seconds . What is the acceleration.​

Answers

Explanation:

[tex]a = \frac{change \: in \: velocity}{change \: in \: time} [/tex]

[tex]a = \frac{v - u}{t} [/tex]

[tex]v = 7 {ms}^{ - 1} [/tex]

[tex]u = 15 {ms}^{ - 1} [/tex]

[tex]t = 3 \: seconds[/tex]

[tex]a = \frac{7 - 15}{3} [/tex]

[tex]a = \frac{ - 8}{3} [/tex]

[tex]a = - 2.67 \: {ms}^{ - 2} [/tex]

helppppp me it's urgent please

the last one is the light will move in some manner not determined by the information here. ​

Answers

Light bends away from the normal, because it's moving from higher to lower refractive index.

Same bend-direction as when it goes from water into air.

21. A toy car starts from rest and accelerates at 1.50 m/s’ [E] for 5.25 s. What is the final
velocity, V, of the car? Show your work.

Answers

Answer: The final Velocity, V, of the car is 7.9m/s

Explanation:

Given the following :

Toy car starts from rest, therefore,

Initial Velocity (u) = 0

Acceleration (a) = 1.5m/s^2 E for time, t = 5.25s

Final velocity (V) of the car =?

Using the motion equation:

v = u + at

Where v = final Velocity

u = Initial Velocity

a = acceleration

t = time

v = 0 + 1.5(5.25)

v = 0 + 7.875

v = 7.875m/s

v = 7.9m/s

An airplane on a runway has an initial speed of 15 meters/second. What is its final velocity when it travels 600 meters on the runway with a constant acceleration of 6 meters/second2?

Answers

Answer:

86.17m/s

Explanation:

Since the motion is of constant acceleration, we can use one of the equations of motion as follows;

v² = u² + 2as

Where;

v = final velocity of the airplane

u = initial velocity of the airplane

s = distance covered by the plane

a = acceleration

From the question,

u = 15m/s

s = 600m

a = 6m/s²

Substitute these values into the equation above as follows;

v² = 15² + 2(6)(600)

v² = 225 + 7200

v² = 7425

v = √7425

v  = 86.17m/s

Therefore, the final velocity of the airplane is 86.17m/s

Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which the air temperature is 20 C and the convection coefficient at the outer tube surface is 11 W/m2 K. Estimate the heat loss per unit length of tube.

Answers

Answer:

1.01 W/m

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above, we assumed that the pipe wall and the oil are in thermal equilibrium.

area of the pipe per unit length A = [tex]\pi r ^{2}[/tex] = [tex]7.069*10^{-4}[/tex] m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = 1.01 W/m

The heat loss per unit length of tube should be considered as the 1.01 W/m.

Calculation of the heat loss:

Since

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

Now

area of the pipe per unit length A should be

= πr^2

 = 7.069*10^-4 m^2/m

Now

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130

= 1.01 W/m

hence, The heat loss per unit length of tube should be considered as the 1.01 W/m.

Learn more about heat here: https://brainly.com/question/15170783

Example
Rain appears to fall vertically to a man walking at a rate of 3km/h. At
a speed of 6 km/h, it appears to meet him at an angle of 45° of vertical.
Find out the speed of rain.​

Answers

Answer:

4.24 km/h

Explanation:

When the man walks at a rate of 3 km/h, the rain appears to fall vertically, which means it has the same horizontal rate, 3 km/h.

When the man walks at a rate of 6 km/h, the rain's horizontal velocity relative to the man is now 6 km/h − 3 km/h = 3 km/h.  The rain meets the man at a 45 degree angle, so the vertical velocity is also 3 km/h.

Therefore, the total speed is:

v = √((3 km/h)² + (3 km/h)²)

v = 4.24 km/h

A light, rigid rod is 51.4 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at rest with a small, massive ball attached to its bottom end. You strike the ball, suddenly giving it a horizontal velocity so that it swings around in a full circle. What minimum speed at the bottom is required to make the ball go over the top of the circle?

Answers

Answer:

4.489 m/s

Explanation:

We are given;

Length of rod;L = 51.4 cm = 0.514 m

When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.

Thus; ½mv² = mgh

m will cancel out to give;

v² = 2gh

Where:

g is acceleration due to gravity = 9.8 m/s²

h is the maximum height of the ball which is equal to twice the length of the rod.

Thus, h = 2(0.514) = 1.028 m

v² = 2 × 9.8 × 1.028

v = √20.1488

v = 4.489 m/s

If an object of 3.5 cm heitght is kept at a distance of 12 cm from the convex lens of focal length 8 cm. Find the position,nature and height of the height

Answers

Answer: The image is at a distance of 24 cm on the right of the lens, it will be an inverted, real image and has a height of 7 cm.

Explanation: To determine the position of the image of the object, use the Lens Equation, which is described by:

[tex]\frac{1}{f} = \frac{1}{u} +\frac{1}{v}[/tex]

where

f is focal length;

u is distance of the object from the lens;

v is distance of the image of the pbject from the lens;

Calculating the position of the image will be:

[tex]\frac{1}{v} =\frac{1}{f} - \frac{1}{u}[/tex]

[tex]\frac{1}{v} = \frac{1}{8} - \frac{1}{12}[/tex]

[tex]\frac{1}{v} = \frac{1}{24}[/tex]

v = 24 cm

Note that the distance of the image from the lens is positive. This means that the formed image is positioned at the right of the lens and is inverted.

For the height of the image, it can be used the Magnification (M) of an image:

M = [tex]\frac{h_{i}}{h_{o}} = \frac{v}{u}[/tex]

where:

[tex]h_{i}[/tex] is the height of the image

[tex]h_{o}[/tex] is the height of the object

For this image:

[tex]\frac{h_{i}}{3.5} = \frac{24}{12}[/tex]

[tex]h_{i} =[/tex] 2 * 3.5

[tex]h_{i}[/tex] = 7 cm

The image formed for this lens is 24 cm on the right of the lens, inverted related to the object and has height of 7 cm.

Mt Everest is at the height of 8850 m; its base is at an elevation of 5400m. The temperature here drops at the rate of 1 degree per 100m. If temperature at the base is -5, what will be the temperature at the top?

Answers

Answer:

The temperature at the top is -39.5 degree

Explanation:

The height of Mt Everest = 8850 m

The base is at the elevation of = 5400 m

The drop in temperature = 1 degree per 100 m

At the base, the temperature = -5

Since every 100 meter rise in height results in the one degree drop of temperature. Therefore, first find the difference between the base and height. Multiply with negative one.

Difference in heights = 8850 – 5400 = 3450

The temperature at the top = (3450 / 100) + 5 = -39.5 degree

Since there is fall in temperature so we use negative sign.

Two teams are playing tug-of-war. Team A, on the left, is pulling on the rope with an effort of 5000 N. If the rope is moving at a constant velocity, how hard and in which direction is team B pulling?
A. 2500 N to the left
B. 5000 N to the right
C. 2500 N to the right
D. 5000 N to the left

Answers

Explanation:

If Team A is on the left, B is on the right

if the force is constant, it means that the effort applied is equal.

So Team B is pulling 5000N to the right.

It has been suggested, and not facetiously, that life might have originated on Mars and been carried to Earth when a meteor hit Mars and blasted pieces of rock (perhaps containing primitive life) free of the surface. Astronomers know that many Martian rocks have come to Earth this way. One objection to this idea is that microbes would have to undergo an enormous, lethal acceleration during the impact. Let us investigate how large such an acceleration might be. To escape Mars, rock fragments would have to reach its escape velocity of 5.0 km/s, and this would most likely happen over a distance of about 4.0m during the impact.
1) What would be the acceleration, in m/s, of such a rock fragment?
2) What would be the acceleration, in g's, of such a rock fragment?
3) How long would this acceleration last?
4) In tests, scientists have found that over 40% of Bacillius subtilis bacteria survived after an acceleration of 450000g. In light of your answer to part A, can we rule out the hypothesis that life might have been blasted from Mars to Earth?

Answers

Answer and Explanation:

Given that

v_f = 5 km/s = 5,000 m/s

d = 4 m

v_i = 0 m/s

The computation is shown below:

1. The acceleration in m/s is

Here we use the motio third equation which is

[tex]v_f^2 = v_i^2 + 2ad[/tex]

5000^2 = 0^2 + 2 (a) (4)

So

[tex]a = 3.125 \times 10^{6} m/s^2[/tex]

2. Now acceleration in g is

[tex]= \frac{3.125 \times 10^{6} m/s^2}{9.81}[/tex]

[tex]= 3.18 \times 10^{5}g[/tex]

3. The long of acceleration last is

[tex]t = \frac{v-u}{a}[/tex]

[tex]= \frac{5000 - 0}{3.125 \times 10^{6}}[/tex]

[tex]= 1.6 \times 10^{-3}s[/tex]

4.As we can see that

[tex]3.18 \times 10^{5}[/tex] is smaller than the [tex]4.5 \times 10^{5}g[/tex]

So, it should not be ruled out

Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.

Answers

Answer:

i took g = 9.8m/s

A. 1.16secs

B. 2.32secs

C. 6.57m

D. 57.91m

Explanation:

A. How long does the Missile take to reach ot peak?

Time taken (t) =( U²Sin (angle) )/g

u = initial velocity = 25m/s

angle given = 30°

g = acceleration due to gravity = 9.8m/s²

t = U² x Sin (angle) / g

t = 25² x Sin(30)/9.8

t = 1.61secs

B. How long is the missile in the air in total?

T = 2t

T = 2 x 1.61 = 2.32 secs

C. what maximum Height does the missile reach?

Maximum height = U²Sin²(angle) / 2gM.H =25² x Sin(30)² / 2 x 9.8M.H=6.57mMaximum height= 6.57m

D. How far does the missile travel Horizontally?

Range = U²2Sin(angle)/gRange = 25² x 2 x Sin(30) / 9.8Range = 57.91m

Consider a satellite in a circular orbit around the earth. Why is it important to give a satellite a horizontal speed when placing it in orbit? What will happen if the horizontal speed is too small? What will happen if the speed is too large?

Answers

Answer:

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,

Explanation:

When a satellite is in orbit the most important force is the docking of gravity with the Earth

             F = m a

where the acceleration is centripetal and F is the force of universal attraction

centripetal acceleration is

             a = v² / r

             

             F = m v² / r

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero, the force also drops to serious and the satellite steels to Earth.

The speed of the satellite is provides the speed, by local for smaller speeds in satellite, it descends in its orbits and when the speed is amate you have the energy to stop an orb to go to a higher orbit.

6. While standing on an ice surface (assume no friction), a 60 kg skater pushes against
a wall with an average force of 240 N east for 0.360 s. Calculate the velocity
(magnitude and direction) of this student at 0.360 s.

Answers

Answer: 1.44m/s West

Explanation:

Given the following :

Mass of skater = 60kg

Average force = 240N east

Time of = 0.360 seconds

The Velocity after 0.360seconds

Recall the relation:.

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)

Ft = mV

240 × 0.360 = 60 × V

60 × V = 86.4

V = 86.4 / 60

V = 1.44m/s

According to Newton's third law, to every action, there is an equal and opposite reaction.

The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force

Therefore, velocity is 1.44ms West

SPEAR is a storage ring at the Stanford Linear Accelerator which has a circulating beam of electrons that are moving at nearly the speed of light (2.998 108 m/s). If a similar ring is about 80.0 m in diameter and has a 0.59 A beam, how many electrons are in the beam

Answers

Answer:

n = 3.1x10¹²

Explanation:

To find the number of electrons we need to find first the charge (q):

[tex] I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t [/tex]    (1)

Where:

I: is the electric current = 0.59 A

t: is the time

The time t is equal to:

[tex]v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}[/tex]   (2)

Where:

x: is the displacement

v: is the average speed = 2.998x10⁸ m/s

The displacement is equal to the perimeter of the circumference:

[tex] \Delta x = 2\pi*r = \pi*d [/tex]     (3)

Where d is the diameter = 80.0 m

By entering equations (2) and (3) into (1) we have:

[tex]q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C[/tex]      

Now, the number of electrons (n) is given by:

[tex] n = \frac{q}{e} [/tex]

Where e is the electron's charge = 1.6x10⁻¹⁹ C  

[tex] n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} [/tex]

Therefore, the number of electrons in the beam is 3.1x10¹².

I hope it helps you!

An electromagnetic wave has a frequency of 1.0 < 1014 Hz. What is the
wavelength of the wave? Use the equation 1 = and the speed of light as
V
f
3.0 x 108 m/s.
O A. 3.3 x 10-8 m
B. 3.0 x 1022 m
C. 3.3 x 105 m
0
D. 3.0 x 10-6 m

Answers

Answer:

  D. 3.0 × 10^-6 m

Explanation:

Wavelength is found by dividing the speed of light by the frequency:

  λ = c/f = (3·10^8 m/s)/(1.0·10^14 Hz) = 3.0·10^-6 m

as the mass of the cart increases, the acceleration of the cart

Answers

Answer:

decrease

Explanation:

as the mass of the cart increase the acceleration of the cart decrease

Los primeros vuelos de prueba del transbordador espacial usaban un "planeador" (con masa de 980 kg incluyendo el piloto). Después de un lanzamiento horizontal a 480 km/h a una altitud de 3500 m, el planeador finalmente aterrizaba con una rapidez de 210 km/h ¿Cuál era la fuerza promedio que la resistencia del aire ejercía sobre él cuando entraba con un ángulo de planeo constante de 12° con respecto a la Tierra?

Answers

Answer:

La fuerza promedio que ejerce la resistencia del aire sobre el planeador cuando ingresa con un ángulo de planeo constante de 12 ° con respecto a la Tierra es 9613.8 N

Explanation:

Los parámetros dados son;

Masa del planeador = 980 kg.

Velocidad de lanzamiento horizontal = 480 km / h

Altitud de lanzamiento = 3500 m.

Velocidad de aterrizaje final = 210 km / h

Ángulo de deslizamiento, θ = 12 °

La ecuación para el equilibrio de fuerzas.

L · cos (θ) + D · sin (θ) = W

L · sin (θ) + D · cos (θ)

Dónde:

L = fuerza de elevación

D = fuerza de arrastre

W = Peso del "planeador"

W = Masa del "planeador" × Aceleración debido a la gravedad = 980 kg × 9.81 m / s²

W = 9613.8 N

Por lo tanto, tenemos;

L · cos (12) + D · sin (12) = 9613.8 ,,,,,,,,,,,,, (1)

L · sin (12) = D · cos (12) ,,,,,,,,,,,,, (2)

De la ecuación (2), tenemos;

L = D · (cos (12)/sin (12))

Sustituyendo el valor de L = D · (cos (12) / sin (12)) en la ecuación (1), se obtiene;

D · (cos (12)/sin (12)) · cos (12) + D · sin (12) = 9613.8

D = 9613.8/((cos (12)/sin (12)) · cos (12) + sin (12)) = 1998.82 N

L = D · (cos (12)/sin (12)) = 1998.82 · (cos (12)/sin (12)) = 9403.72 N

Por lo tanto, la fuerza da la fuerza promedio que la resistencia del aire ejerce sobre el planeador cuando ingresa con un ángulo de planeo constante de 12 ° con respecto a la Tierra;

F = √ (L² + D²) = √ (9403.72² + 1998.82²) = 9613.8 N.

Which two substances could be produced in a combustion reaction?


A. Carbon dioxide and oxygen

B. Carbon dioxide and water

C. Heptane and water

D. Heptane and oxygen

Answers

Answer: B. Carbon dioxide and water

Explanation: Combustion simply refers to burning. A combustion reaction may thus be explained as a chemical process which involves the reaction between a substance and an oxidizer usually oxygen gas. The combustion reaction in most cases involves the reaction between hydrocarbons which are combustible compounds and oxygen gas. The reaction between the combustible compound and oxygen gas is then followed by the release of energy, with the product being carbondioxid and water. Below is an example of combustion reaction.

Combustion the Methane CH4.

Here, CH4 reacts with oxygen gas(O2) to produce carbondioxide and water.

CH4 + 2O2 ------> CO2 + 2H2O

Answer:

Correct answer B

Explanation:

Just took quiz

Question 1 of 10
2 Points
What is the SI unit for gravitational potential energy?
A. Newton
B. Joule
C. Meter
D. Watt

Answers

Answer:

Joule

Explanation:

As any unit of energy (kinetic, potential, etc.), the gravitational potential energy has SI units of Joule. This s the work done by a force of 1 Newton to displace an object 1 meter in the direction of application of the force.

A high diver of mass 74.0 kg jumps off a board 9.00 m above the water. If his downward motion is stopped 2.50 seconds after he enters the water, what average upward force did the water exert on him​

Answers

Answer:

1120 N

Explanation:

The velocity with which he hits the water can be found with kinematics:

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)

v = -13.3 m/s

Or it can be found with conservation of energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × -9.8 m/s² × -9.00 m)

v = -13.3 m/s

Sum of forces on the diver after he hits the water:

∑F = ma

F − mg = m Δv/Δt

F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)

F = 1120 N

whats the texture of copper wire​

Answers

Copper is a reddish orange, soft metal with a bright metallic luster. It is an excellent conductor of heat and electricity. Copper surfaces when exposed to air gradually turns to a dull, brownish color.

Other Questions
Homolysis, or homolytic bond dissociation, produces a very specific type of product under certain reaction conditions. In Part 1, select all the products (in formulae and general chemical terms) that could result from homolysis. In Part 2, select the reaction conditions that are most likely to promote homolysis. Part 1. Choose all that may occur as possible products of a homolysis reaction. Choose one or more:_______. a. hydride ion b. R3CO c. Br2 d. H e. a carbocation f. H3C g. H3CO- h. hydrogen ion i. a carbon free radical Part 2. Choose the conditions under which homolysis is likely to occur. Choose one or more:_______. a. strong base b. ultraviolet irradiation c. high temperature d. strong acid e. infrared irradiation f. low temperature What does the perimeter of this figure consist of?A.) one semicircle and one line segmentB.) one semicircle and two line segmentsC.) one semicircle and three line segmentsD.) two semicircles and two line segmentsI hope you can help! One way the president can influence economic foreign policy is by I need help please! Simplify: ( ++)2 + ( +)2 + ( +)2 When you take your first job, you decide to start saving right away for your retirement. You put $5,000 per year into a saving plan, which interest rate 10% per year. Five years later, you move to another job and stop making contributions to the saving plan. If the first plan continued to earn interest for another 35 years, determine the future worth in year 40. Which pair of terms best describes a wooden table?biotic and nonlivingbiotic and livingabiotic and nonlivingabiotic and living HELP!!! How far have I travelled if I biked at 10mph for hhrs, I walked at 3mph for twice as long as I biked, and ran at 10mph for one quarter as long as I walked? Elizabeth has been receiving harassing text messages. What is the first step she should take if the text messages make her uncomfortable? Call the police. Post the message on social media. Block the person sending the message. Forward the message to a friend and ask for help. Find the next 4 terms of this Fibonacci sequence -x, x+y, y Which one is it?Radical Republicans lost power in Congress for all of the following reasons exceptA. northerners had grown weary of efforts to change the South.B. northerners had lost faith in Republicans because of corruption.C. all the goals of the Radical Republicans had been achieved by 1876.D. Charles Sumner and Thaddeus Stevens had both died by 1874. Yvette exercises 14 days out of 30 in one month. What is the ratio of the number of days she exercises to the number of days in the month? Simplify the ratio. please hellp please hellp fast. rewrite the rational exponent as a radical by extending the properties of integer exponents A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = 16t2 + 48t + 190. Approximately when will the projectile hit the ground? 1.5 seconds 3.2 seconds 5.3 seconds 6.2 seconds PLEASE HELP WITH PART 2!!!!!Examine the map below and use it, along with your understanding or early rivervalley civilizations, to answer the following questions.BPart 1: What is the name of the region labeled 'A' on the map? Name one majorcivilization that arose from this river valley region.. What is the name of the region labeled "B" on the map? Name one majorcivilization that arose from this river valley region.Part II: Imagine you are a farmer living in the region labeled "B" on the map during theBronze Age. Describe your everyday life in as much detail as possible. Be sure todiscuss how you make a living, how you relate with other members of yoursociety, and your thoughts on how your society is governed. What are some of the Flemish and Dutch traditions the artist used in the image above?a use of bright colors mixed with neutral colors such as white, brown, and creamo plain background coupled with everyday objectsmaximum contrast of textures within a color scheme of white, grays, and brownsd all of the aboveWhat are some of the Flemish and Dutch traditions the artists used in the image? 9. A water glass can hold 2/9 of a litre of water. How many glasses of water can be filled with a 3 litre bottle? 9.A 0.060 kg tennis ball hits the wall horizontally. The moment the ball hits the wall it accelerates at a rate of 752 m/s2. What is the force that the ball applied to the wall? According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 65 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively.(a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for as needed.)H0:Ha:(b) Using the sample from the 60 bottles, what is the test statistic? (Round your answer to three decimal places.)Using the sample from the 60 bottles, what is the p-value? (Round your answer to four decimal places.)p-value =(c) At = 0.05, what is your conclusion?Do not reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.(d) Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses. (Enter != for as needed.)H0:Ha:Find the value of the test statistic. (Round your answer to three decimal places.)State the critical values for the rejection rule. Use = 0.05.(Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistic test statistic State your conclusion.Do not reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.Reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.