Answer:
a) Null and alternative hypothesis
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
b) Test statistic t=-1.565
P-value = 0.0612
NOTE: the sample size is n=65.
c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
d) Null and alternative hypothesis
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
Test statistic t=-1.565
Critical value tc=-1.669
t>tc --> Do not reject H0
Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
The significance level is 0.05.
The sample has a size n=65.
The sample mean is M=30.15.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=65-1=64[/tex]
This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-1.565)=0.0612[/tex]
As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Critical value approach
At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.
As the test statistic is greater than the critical value, it falls in the acceptance region.
The null hypothesis failed to be rejected.
Consider the accompanying matrix as the augmented matrix of a linear system. State in words the next two elementary row operations that should be performed in the process of solving the system.
(1 -4 4 0 -2
0 2 -6 0 5
0 0 1 2 - 4
0 0 4 5 -1]
(Type an integer or a simplified fraction)
A. Replace row 4 by its sum with - 4 times row 3.
(Type an integer or a simplified fraction)
B. Replace row 2 by its sum with times row 4.
(Type an integer or a simplified fraction.)
C. Interchange row 3 and row 2.
Answer:
The correct option is (A)
A. Replace row 4 by its sum with - 4 times row 3.
[tex]\left[\begin{array}{ccccc}1&-4&4&0&-2\\0&2&-6&0&5\\0&0&1&2&-4\\0&0&0&-3&15\end{array}\right][/tex]
w = 8
x = 17/2
y = 6
z = -5
Step-by-step explanation:
The given matrix is
[tex]\left[\begin{array}{ccccc}1&-4&4&0&-2\\0&2&-6&0&5\\0&0&1&2&-4\\0&0&4&5&-1\end{array}\right][/tex]
To solve this matrix we need to create a zero at the 4th row and 3rd column which is 4 at the moment.
Multiply 3rd row by -4 and add it to the 4th row.
Mathematically,
[tex]R_4 = R_4 - 4R_3[/tex]
So the correct option is (A)
A. Replace row 4 by its sum with - 4 times row 3.
So the matrix becomes,
[tex]\left[\begin{array}{ccccc}1&-4&4&0&-2\\0&2&-6&0&5\\0&0&1&2&-4\\0&0&0&-3&15\end{array}\right][/tex]
Now the matrix may be solved by back substitution method.
Bonus:
The solution is given by
Eq. 1
-3z = 15
z = -15/3
z = -5
Eq. 2
y + 2z = -4
y + 2(-5) = -4
y - 10 = -4
y = -4 + 10
y = 6
Eq. 3
2x - 6y + 0z = 5
2x - 6(6) = 5
2x - 12 = 5
2x = 12 + 5
2x = 17
x = 17/2
Eq. 4
w - 4x + 4y + 0z = -2
w - 4(17/2) + 4(6) = -2
w - 34 + 24 = -2
w - 10 = -2
w = -2 + 10
w = 8
What is the greatest common factor of 36 and 44?
Answer:
GCF - 4
Step-by-step explanation:
36 - 1, 2, 3, 4, 6, 9, 12, 18, 36
44 - 1, 2, 4, 11, 44
Hope this helps! :)
The valve was tested on 250 engines and the mean pressure was 7.3 pounds/square inch (psi). Assume the population standard deviation is 0.8. The engineer designed the valve such that it would produce a mean pressure of 7.2 psi. It is believed that the valve does not perform to the specifications. A level of significance of 0.05 will be used. Find the value of the test statistic. Round your answe
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ = 7.2
For the alternative hypothesis,
H1: µ ≠ 7.2
This is a two tailed test.
Since the population standard deviation is given, the test statistic would be the z score determined from the normal distribution table. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 7.2
x = 7.3
σ = 0.8
n = 250
z = (7.3 - 7.2)/(0.8/√250) = 1.976
Test statistic is 1.976
The sum of Joe's and Sheila's ages is 115. Fourteen years ago, Joe was twice as old as Sheila. How old is Sheila now?
Answer: Sheila today = [tex]46\dfrac{1}{3}[/tex] yrs old
Step-by-step explanation:
J + S = 115 v⇒ J = 115 - S
Current Ages Ages 14 years ago
Joe (J) = 115 - S J - 14 = 2(S - 14)
Sheila (S) = S
Substitute J = 115 - S into the "14 years ago" equation
J - 14 = 2(S - 14)
(115 - S) - 14 = 2(S - 14)
111 -S = 2S - 28
111 = 3S - 28
139 = 3S
46 [tex]\frac{1}{3}[/tex] = S
It is odd that the result was not an integer. I wonder if you meant to type "Joe was twice as old as Sheila is today. That would change the equation to:
J - 14 = 2S
111 - S = 2S
111 = 3S
37 = S
The voltage in a circuit is the product of two factors, the resistance and the current. If the voltage is 6ir + 15i + 8r+20, find the expressions for the current and resistance
Answer:
resistance: (2r +5)current: (3i +4)Step-by-step explanation:
The factors of the given expression are ...
6ir +15i +8r +20 = (3i +4)(2r +5)
Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...
resistance: (2r +5)
current: (3i +4)
The average daily rainfall for the past week in the town of Hope Cove is normally distributed, with a mean rainfall of 2.1 inches and a standard deviation of 0.2 inches. If the distribution is normal, what percent of data lies between 1.9 inches and 2.3 inches of rainfall? a) 95% b) 99.7% c) 34% d) 68%
Answer:
D
Step-by-step explanation:
We calculate the z-score for each
Mathematically;
z-score = (x-mean)/SD
z1 = (1.9-2.1)/0.2 = -1
z2 = (2.3-2.1)/0.2 = 1
So the proportion we want to calculate is;
P(-1<x<1)
We use the standard score table for this ;
P(-1<x<1) = P(x<1) -P(x<-1) = 0.68269 which is approximately 68%
Answer:
68
Step-by-step explanation:
If x=3 then what is y the equation is 2x -y=5 if you have the answer lets d a t e I m f e m a l e. T a n g ie_man 18 snap without spaces.
Answer:
y = 1Step-by-step explanation:
Given the equation, 2x- y = 5, if x = 3, to get y we will simply substitute the value of x into the expression given as shown;
[tex]2x - y = 5\\\\Substituting \ x = 3\ into \ the \ equation\\\\2(3) - y = 5\\\\6 - y = 5\\\\subtracting\ 6\ from\ both\ sides\\\\6-6-y = 5- 6\\\\-y = -1\\\\multiplying\ both\ sides\ by \ -1\\-(-y) = -(-1)\\\\y = 1[/tex]
Hence, the value of y is 1
Please help meeeeeeeee
Answer:
The lines will intersect infinitely many times, because they are identical.
Step-by-step explanation:
Let's change the equations of the lines into (y=mx+b) form.
6x-4y=2 Divide by 2.
3x-2y=1 Move x and divide by -2.
-2y=1-3x ---> y= -1/2+3/2x
The equation of the first line is y=3/2x- 1/2
-2y+3x=1
-2y=1-3x
y = 3/2x -1/2
The equation of the second line is y = 3/2x- 1/2.
The lines are identical- infinitely many intersections.
Step-by-step explanation:
I think the answer is third because it doesn't has a solution.
Solve the quadratic equation x2 + 14x = 51 by completing the square.
Question 3 options:
A)
x = –17, x = –3
B)
x = –17, x = 3
C)
x = 3, x = 17
D)
x = –3, x = 17
Answer:
B
Step-by-step explanation:
Given
x² + 14x = 51
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(7)x + 49 = 51 + 49 , that is
(x + 7)² = 100 ( take the square root of both sides )
x + 7 = ± [tex]\sqrt{100}[/tex] = ± 10 ( subtract 7 from both sides )
x = - 7 ± 10
Thus
x = - 7 - 10 = - 17
x = - 7 + 10 = 3
Help me pls I need help
Answer:
C
Step-by-step explanation:
If two lines are parallel, their slopes are the same.
Since the slope of line l is 4/9, this means that the slope of line m must also be 4/9.
Answer:
C. 4/9
Step-by-step explanation:
Parallel lines have equal slopes.
Since line l and line m are parallel, then their slopes must be the same.
[tex]m_{l} =m_{m}[/tex]
We know that the slope of line l is 4/9
[tex]\frac{4}{9} = m_{m}[/tex]
Line l has a slope of 4/9, therefore line m must also have a slope of 4/9.
The correct answer is C. 4/9
Question 1 of 16,
The area of a trapezoid is 189 cm . The height is 14 cm and the length of one of the parallel sides is 8 cm. Find the length of the second parallel side.
Answer:
19cm
Step-by-step explanation:
The area of a trapezoid [tex]=\dfrac12(a+b)h[/tex] (where a and b are the parallel sides).
Given:
Area = 189 Square cm
Height, h=14cm
a=8cm
We want to find the value of the other parallel side, b.
Substitution of the given values gives:
[tex]189=\dfrac12(8+b)14\\189=7(8+b)\\$Divide both sides by 7\\8+b=27\\Subtract 8 from both sides\\b+8-8=27-8\\b=19cm[/tex]
The length of the second parallel side is 19cm.
How do you write 0.0026 in scientific notation? ___× 10^____
Answer:
It's written as
[tex]2.6 \times {10}^{ - 3} [/tex]
Hope this helps you
Answer:
2.6 × 10⁻³
Step-by-step explanation:
To write a number in scientific notation, move the decimal to the right or left until you reach a number that is 1 or higher.
In the decimal 0.0026, the first number that is 1 or higher is 2.
0.0026 ⇒ 2.6
When trying to figure out the exponent, here are some things to keep in mind:
- when you move the decimal to the right, the exponent is negative
- when you move the decimal to the left, the exponent is positive
You moved the decimal to the right three places. So the exponent will be -3.
The result is 2.6 × 10⁻³.
Hope this helps. :)
What is the value of x?
Enter your answer in the box.
X=
Answer:
3
Step-by-step explanation:
Triangle ABC is an isosceles triangle, so
[tex]x^2+x^2=(6\sqrt{2} )^2\\2x^2=6^2*2\\x^2=6^2\\x=6.[/tex]
Triangle BCD is a notable triangle and the sides are
BD=x, CD=[tex]x\sqrt{3}[/tex],BC=2x=6
2x=6
x=3
A concession-stand manager buys bottles of water and soda to sell at a football game. The manager needs to buy a total of 4,500 drinks and have 25% more water than soda. Let w be the number of bottles of water and let s be the number of bottles of soda. Create a system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to bu
Answer: The equations are
w + s = 4500
2.25s = 4500
Step-by-step explanation:
Let w represent the number of bottles of water that the football manager bought.
Let s represent the number of bottles of soda that the football manager bought.
The manager needs to buy a total of 4,500 drinks. This means that
w + s = 4500
He also needs to have 25% more water than soda.
25% of soda = 25/100 × s = 0.25s
25% more of water than soda = s + 0.25s = 1.25s
The equation would be
1.25s + s = 4500
2.25s = 4500
pls help help help hepl
Answer:
C
Step-by-step explanation:
undefined slope means tat the denominator=0 in the equation
m=y2-y1/x2-x1
A: m=-1-1/1+1=-2
B;2-2/2+2=0
C: 3+3/-3+3 = 6/0 undefined
D: 4+4/4+4=1
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]
Answer:
Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]
Step-by-step explanation:
We are given that a function
[tex]f(x)=ln(x)[/tex]
Interval [1,5]
The given function is defined on this interval.
Hypothesis of Mean Value Theorem:
(1) Function is continuous on interval [a,b]
(2)Function is defined on interval (a,b)
From the graph we can see that
The function is continuous on [1,5] and differentiable at(1,5).
Hence, the function satisfies the hypothesis of the Mean Value Theorem.
In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the population standard deviation is 5.8 hours. Find the 98% confidence interval for the population mean.
a. (17.5, 21.7)
b. (14.1, 23.2)
c. (18.3, 20.9)
d. (19.1, 20.4)
Answer:
[tex]19.6-2.42\frac{5.8}{\sqrt{42}}=17.43[/tex]
[tex]19.6+2.42\frac{5.8}{\sqrt{42}}=21.77[/tex]
And the best option for this case would be:
a. (17.5, 21.7)
Step-by-step explanation:
Information given
[tex]\bar X= 19.6[/tex] represent the sample mean
[tex]\mu[/tex] population mean
[tex]\sigma= 5.8[/tex] represent the population deviation
n=42 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The degrees of freedom, given by:
[tex]df=n-1=42-1=41[/tex]
Since the Confidence is 0.98 or 98%, the significance would be [tex]\alpha=0.02[/tex] and [tex]\alpha/2 =0.1[/tex], and the critical value would be [tex]t_{\alpha/2}=2.42[/tex]
Replacing we got:
[tex]19.6-2.42\frac{5.8}{\sqrt{42}}=17.43[/tex]
[tex]19.6+2.42\frac{5.8}{\sqrt{42}}=21.77[/tex]
And the best option for this case would be:
a. (17.5, 21.7)
Answer:
The 98% confidence interval for the population mean is between 17.5 hours and 21.7 hours.
divide 15 root 20 by 6 root 125
Answer:
15√20/6√125
=√20/√5
=2
Step-by-step explanation:
Can somebody please help me with this question?
Answer: 6x^2
Step-by-step explanation:
The area of a triangle is 1/2bh
Thus, simply multiply 2x*3x = 6x^2
Hope it helps <3
Answer:
[tex]3 {x}^{2} [/tex]Solution,
Base(b)= 3x
Height(h) = 2x
Now,
Finding the area of triangle:
[tex] \frac{1}{2} \times b \times h[/tex]
[tex] \frac{1}{2} \times 3x \times 2x[/tex]
[tex] \frac{1}{2} \times 6 {x}^{2} [/tex]
[tex]3 {x}^{2} [/tex]
Hope this helps....
Good luck on your assignment....
Follow the properties of the equality given for the steps to solve the following equation:
-3(x-4)+5=-x-3
(answers and steps in photo)
Answer:
Step-by-step explanation:
-3x+12+5= -x-3 -3x+17 = -x-317 = 2x-320 =2xx=10The FDA regulates that a fish that is consumed is allowed to contain at most 1 mg/kg of mercury. In Florida, bass fish were collected in 53 different lakes to measure the amount of mercury in the fish from each of the 53 lakes. Do the data provide enough evidence to show that the fish in all Florida lakes have different mercury than the allowable amount?
Required:
State the random variable, population parameter, and hypotheses.
Answer:
Yes. At a significance level of 0.05, there is enough evidence to support the claim that the fish in all Florida lakes have different mercury than the allowable amount.
The random variable is the sample mean amount of mercury in the bass fish from the lakes of Florida.
The population parameter is the mean amount of mercury in the bass fish of Florida lakes.
The alternative hypothesis (Ha) states that the amount of mercury significantly differs from 1 mg/kg.
The null hypothesis (H0) states that the amount of mercury is not significantly different from 1 mg/kg.
[tex]H_0: \mu=1\\\\H_a:\mu\neq 1[/tex]
Step-by-step explanation:
The question is incomplete.
There is no data provided.
We will work with a sample mean of 0.95 mg/kg and sample standard deviation of 0.15 mg/kg to show the procedure.
This is a hypothesis test for the population mean.
The claim is that the fish in all Florida lakes have different mercury than the allowable amount (1 mg of mercury per kg of fish).
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=1\\\\H_a:\mu\neq 1[/tex]
The significance level is assumed to be 0.05.
The sample has a size n=53.
The sample mean is M=0.95.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.15.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.15}{\sqrt{53}}=0.0206[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.95-1}{0.0206}=\dfrac{-0.05}{0.0206}=-2.427[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=53-1=52[/tex]
This test is a two-tailed test, with 52 degrees of freedom and t=-2.427, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=2\cdot P(t<-2.427)=0.019[/tex]
As the P-value (0.019) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
At a significance level of 0.05, there is enough evidence to support the claim that the fish in all Florida lakes have different mercury than the allowable amount.
At work, Brett must check and record the internal temperature of the freezer on an hourly basis. When working properly, the temperature should remain constant over time. What word describes the slope of a line showing the temperature of the freezer as a function of time in hours when the freezer is working properly?
a.positive
b.zero
b.negative
c.undefined
Answer:
B. zero
Step-by-step explanation:
If the temperature is supposed to remain constant over time (the same) when working properly, then this means that there is no increase or decrease over time.
If there were a line to represent this, then it would be a straight line with a slope of 0 because the temperature would remain the same.
The CEO of Millennium Dairy Product, a small venture among 10 partners each having 100,000 shares, sought to raise an additional Rs.50 million in a private placement of equity in his early stage dairy product company. The CEO conservatively projected net income of Rs.50 million in year 5, and knew that the comparable companies traded at a price earnings ratio of 20X. She approached SBI caps, a venture capitalist with her proposal to seek funds. (10) a) What share of the company would SBI caps require today if their required rate of return was 50%? b) If the company had 1000,000 shares outstanding before the private placement, how many shares should SBI caps purchase? c)What price per share should she agree to pay if her required return was 50%? d)What are the pre money and post valuations? e) What are the Carried interests of the VC and the promoters?
Answer:
Millennium Dairy Product
a) Share of the company that SBI Caps should require today to get a required rate of return of 50%.
= 50%
b) If the company had 1,000,000 (100,000 x10) shares outstanding before the private placement, SBI Caps should purchase
1,000,000 shares = 50% of (1,000,000 + 1,000,000) shares
Assuming the founding promoters are not giving up their shares, instead, new equity shares are being issued.
c) The price per share SBI Caps should agree to pay, if her required return was 50% is
Rs.50 per share, which will provide the required additional equity financing of (Rs.50 million) since Rs.50 x 1,000,000 equals Rs.50 million.
d) Pre money and post money valuations:
These are based on the calculated Market Price of Rs.1,000 per share from the Price/Earnings Ratio.
Pre money valuation will be Rs.1,000 x 1,000,000 shares = Rs.1 billion
Post money valuation will be Rs.1,000 x 2,000,000 shares = Rs.2 billion
e) Carried interests of the VC and the promoters
VC's carried interest = share of profits = 50% xRs.50 million = Rs.25 million
Promoters' carried interest = Rs.25 million
Step-by-step explanation:
a) Calculation of share in the company:
SBI Cap's required rate of return is 50%
If she invests Rs.50 million today, her expected return will be equal to Rs.50 million x 50% = Rs.25 million
Since rate of return = Net Income/Initial Investment or (Current value of investment - Initial Investment)/Initial Investment.
This return will be equal to 50% of the total net income of Rs.50 million
b) Price/Earnings P/E ratio = Market price per share/Earnings per share (EPS)
Since P/E ratio of similar companies = 20 times,
The company's P/E = 20 times x EPS
With calculated EPS = Rs.50 million /1,000,000 = Rs.50
Therefore, price per share = 20 x Rs.50 = Rs.1,000
Pre money valuation = Rs.1,000 x 1 million shares = Rs.1 billion
Post money valuation = Rs.1,000 x 2 million shares = Rs.2 billion
c) The carried interest is the share of profits to which the promoters and the Venture Capitalists are entitled. Their respective shares are 50% of the net income = Rs.25 million each.
d) The pre money and post money valuations: The pre money valuation is the valuation of the company before the additional equity financing. The post money valuation is the valuation of the company after the additional equity financing. There are many ways to value a company. In this case, we have used the P/E ratio as a basis for the valuation. However, we did not dilute the earnings per share post money, for simplicity.
Please help asap!!!!!!!
Answer:Yes indeed!
Step-by-step explanation:
Your right!
Need Help With This
Answer/Step-by-step explanation:
Let x = 4 (you and 3 friends)
Ticket cost per head = $5.50
Drink cost per head = $2.50
Popcorn cost per head = $4.00
Expression representing total amount of money spent = $5.50(x) + $2.50(x) + $4.00(x)
Evaluate the expression by plugging in the value of x = 4
Total amount of money spent = $5.50(4) + $2.50(4) + $4.00(4)
= $22 + $10 + $16 = $48
Total amount of money spent = $48
The time to assemble the first unit on a production line is 8 hours. The learning rate is 0.81. Approximately how long will it take for the seventh unit to be assembled?
Answer:
4.428 hours
Step-by-step explanation:
If the learning rate is 0.81, the slope of the learning curve is:
[tex]b=\frac{ln(0.81)}{ln(2)} \\b=-0.304[/tex]
The time it takes to produce the n-th unit is:
[tex]T_n=T_1*n^b[/tex]
If T1 = 8 hours, the time required to produce the seventh unit will be:
[tex]T_n=8*7^{-0.304}\\T_n=4.428\ hours[/tex]
It will take roughly 4.428 hours.
Suppose you invest $ 2,000 at 45% Interest
compounded daily. F(t) represents value of investments
in t years
A) Find equation For F(+)
B) use equation to find how much account will
be worth in 30 years round to nearest cent
C) How much you should invest now in
order to have 14.000 in 9 years round to the nearest cent
Answer:
You will have $29,000 in 30 years, and you need to start with about $2,772.28 to make $14,000 in 9 years
Step-by-step explanation:
To find the total investment use the equation [tex]A = P(1 + rt)[/tex]
Where A equals total investment, P is your start investment, r is your rate, and t is time.
[tex]A=2,000(1+(0.45 * 30))[/tex]
[tex]A=2,000(1+13.5)[/tex]
[tex]A=2,000*14.5[/tex]
[tex]A=29,000[/tex]
To find the start investment use the equation [tex]P = A / (1 + rt)[/tex]
[tex]P=14,000/(1+(0.45*9))[/tex]
[tex]P=14,000/(1+4.05)[/tex]
[tex]P=14,000/5.05[/tex]
[tex]P=2,772.28[/tex]
Identify the parts (include: terms, coefficients, variables and
constants) of the following expression and translate it into a
verbal expression:
2(3x - 2y) + 7
Answer:
x=9
Step-by-step explanation:
3x subtracted by 2y
is 1 then 1 multiplied by 2 is 2 then 7 + 2 is 9
PEMDAS
As part of a larger project to study the behavior of stressed-skin panels, a structural component being used extensively in North America, an article reported on various mechanical properties of Scotch pine lumber specimens. Data on the modulus of elasticity (MPa) obtained 1 minute after loading in a certain configuration and 4 weeks after loading for the same lumber specimens is presented here.
Observatio 1 min 4 Week Difference
1 16,620 9,110 1380
2 17,300 13,250 3370
3 15,480 14,720 2580
4 12,970 12,740 2740
5 17,260 10,120 2850
6 13,400 14,570 2690
7 13,900 11,220 2180
8 13,630 11,100 2800
9 13,260 11,420 2210
10 14,370 10,910 2350
11 11,700 12,110 2260
12 15,470 8,620 3080
13 17,840 12,590 2880
14 14,070 15,090 2750
15 14,760 10,550 3520
Required:
Calculate and interpret an upper confidence bound for the true average difference between 1-minute modulus and 4-week modulus; first check the plausibility of any necessary assumptions. (Use α = 0.05. Round your answer to the nearest whole number.)
Answer:
The upper confidence bound for the true average difference between 1-minute modulus and 4-week modulus is 2933.82.
Step-by-step explanation:
Compute the mean difference and standard deviation of the difference as follows:
[tex]\bar d=\frac{1}{n}\sum d_{i}=\frac{1}{15}\times [1380+3370+2580+...+3520]=2642.67\\\\S_{d}=\sqrt{\frac{1}{n-1}\sum (d_{i}-\bar d)^{2}}\\=\sqrt{\frac{1}{15-1}[(1380-2642.67)^{2}+(3370-2642.67)^{2}+...}=525.69[/tex]
The degrees of freedom is:
df = n - 1
= 15 - 1
= 14
Th critical value of t is:
[tex]t_{\alpha/2, (n-1)}=t_{0.05/2, 14}=2.145[/tex]
*Use a t-table.
Compute the upper confidence bound for the true average difference between 1-minute modulus and 4-week modulus as follows:
[tex]\text{Upper Confidence Bound}=\bar d+t_{\alpha/2, (n-1)}\cdot \frac{S_{d}}{\sqrt{n}}[/tex]
[tex]=2642.67+2.145\cdot \frac{525.69}{\sqrt{15}}\\\\=2642.67+291.15\\\\=2933.82[/tex]
Thus, the upper confidence bound for the true average difference between 1-minute modulus and 4-week modulus is 2933.82.
can someone help me with this please?!?
Answer:
The answer is 60cm^2.
hope it helps..