Answer:
Explanation:
The following class code is written in Java and includes all of the required methods as requested in the question...
package sample;
class GasTank {
private double amount = 0;
private double capacity;
public GasTank(double initialAmount) {
this.capacity = initialAmount;
}
public void addGas(double addAmount) {
this.amount += addAmount;
if (amount > capacity) {
amount = capacity;
}
}
public void useGas(double subtractAmount) {
this.amount -= subtractAmount;
if (amount < 0) {
amount = 0;
}
}
public boolean isEmpty() {
return (amount < 0.1);
}
public boolean isFull() {
return (amount > capacity - 0.1);
}
public double getGasLevel() {
return amount;
}
public double fillUp() {
double difference = capacity - amount;
amount = capacity;
return difference;
}
}
C++ "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length.
Ex: The following patterns yield a userScore of 4:
Ex: The following patterns yield a userScore of 9:
simonPattern: RRGBRYYBGY
userPattern: RRGBBRYBGY
Result: Can't get test 2 to occur when userScore is 9
Testing: RRGBRYYBGY/RRGBBRYBGY
Your value: 4
Testing: RRRRRRRRRR/RRRRRRRRRY
Expected value: 9
Your value: 4
Tests aborted.
Answer:
In C++:
#include <iostream>
using namespace std;
int main(){
int userScore = 0;
string simonPattern, userPattern;
cout<<"Simon Pattern: "; cin>>simonPattern;
cout<<"User Pattern: "; cin>>userPattern;
for (int i =0; i < simonPattern.length();i++){
if(simonPattern[i]== userPattern[i]){
userScore++; }
else{ break; }
}
cout<<"Your value: "<<userScore;
return 0;
}
Explanation:
This initializes user score to 0
int userScore = 0;
This declares simonPattern and userPattern as string
string simonPattern, userPattern;
This gets input for simonPattern
cout<<"Simon Pattern: "; cin>>simonPattern;
This gets input for userPattern
cout<<"User Pattern: "; cin>>userPattern;
This iterates through each string
for (int i =0; i < simonPattern.length();i++){
This checks for matching characters
if(simonPattern[i]== userPattern[i]){
userScore++; }
This breaks the loop, if the characters mismatch
else{ break; }
}
This prints the number of consecutive matches
cout<<"Your value: "<<userScore;
Which of the statements below describe how to print a document?
Description
Military time uses 24 hours for the entire day instead of 12 for am/pm separately. Military time is a 4 digit (base-10) integer with the following rules:
The first two digits show the hour (between 00 and 23) and
The last two digits show the minutes (between 00 and 59)
There is no colon separating hours from minutes.
Military time starts at 0000 in the morning and counts up
When we get to the afternoon, we use 1300 for 1:00 PM and 2300 for 11:00 PM.
When we get to midnight, the hour is 00 (not 24).
TASK: Write a program that reads two times in military format and prints the number of hours and minutes between the two times (See example below).
NOTE: Your program should consider the difference between the times IN THE SAME DAY. For example: The time difference between 2359 and 0000 is 23 hours and 1 minute (NOT 1 minute).
Detailed Requirements
• Compose a written document (MS Word Document) describing your algorithm, feel free include a diagram if you like
• The program should prompt for two times separately, then print the duration of time between (see sample output below).
• The program should check the input for the correct military time format:
. Make sure the hours are between 00 and 23.
. Make sure the minutes are between 00 and 59
. If the validity check fails, it should print an appropriate error and prompt again.
• Your program should use io manipulators to produce military time with leading zeroes. e.g. 9 am should be printed 0900 (not 900).
• More points will be awarded to an implementation that can produce an accurate result regardless of the order of the inputs.
• Do not produce runtime errors that abruptly end your program (crash)
• Include descriptive comments, neat indentation, proper spacing for good readability, and appropriate and consistently named variables.
• Program source should have a comment block at the top with the student name, section, and description of your program.
Please enter a time: 1sykdf
Military Tine Format Required: Bad input, try again.
Please enter a time: 2580
Military Tine Format Required: Hours must be between 2 and 23, try again
Please enter a time: 2365
Military Tine Format Required: Minutes must be between me and 59, try again
Please enter a time: 0900 First time 0900 accepted.
Please enter a time: jdkjs
Military Time Forest Required: Bad input, try again.
Please enter a time: 39573
Military Tine Format Required: Hours must be between 28 and 23, try again
Please enter a time: 1799
Military Tine Format Required: Minutes must be between me and 59, try again
Please enter a time: 1730 Second time: 1738 accepted.
Time difference between 1988 and 1732 ts 8 hours and 30 minutes Dismissed solder!
Note! When I change the order of the time inputs. I get the same result!
Answer:
from datetime import time, datetime, timedelta, date
for _ in iter(list, 0):
t1 = input("Please enter time one: ")
t2 = input("Please enter time two: ")
if t1.isdigit() == True and (int(t1[:2])<=23 and int(t1[2:]) <= 59)\
and t2.isdigit() == True and (int(t2[:2])<= 23 and int(t2[2:])<=59):
time_1 = time(hour=int(t1[:2]), minute=int(t1[2:]))
time_2 = time(hour= int(t2[:2]), minute=int(t2[2:]))
if time_1 > time_2:
diff = datetime. combine (date. today( ), time_1) - datetime. combine(date. today ( ), time_2)
else:
diff = datetime. combine (date. today( ), time_2) -datetime. combine(date. today ( ), time_1)
diff_list = str(diff).split(":")
del diff_list[2]
diff_t = "". join (diff_list)
print(diff_t)
break
if t1.isdigit() == False or t2.isdigit() == False:
print("Military Time Forest Required: Bad input, try again.")
continue
elif int(t1[:2])> 23 or int(t2[:2])> 23:
print("Military Tine Format Required: Hours must be between 00 and 23, try again")
continue
elif int(t1[2:])> 59 or int(t2[2:])> 59:
print("Military Tine Format Required: Minutes must be between me and 59, try again")
continue
Explanation:
The python Datetime package is used to manipulate date and time, creating immutable Datetime objects from the various python data types like integer and string. The block of code above is a conditional for-loop statement that gets two user time value inputs and prints out the difference as a string in Military forest time format.
identify and explain 3 methods of automatically formatting documents
Answer:
Three common automatic formatting for documents are...
Margin justification- where text is aligned to both the left and right margin- producing a neat page
Paragraph justification- where paragraphs are not split as they go over the page- but are moved to the next page in one piece.
Tabular justification- where text is indented or aligned at a 'tab stop'. - to emphasise a paragraph.
The 3 methods used in Microsoft word to auto format are; Margin Justification, Tabular Justification, Paragraph Justification
What is formatting in Microsoft Word?In Microsoft word, there are different ways of formatting a text and they are;
Margin justification; This is a type of formatting where all the selected text are aligned to either the left or right margin as you go to a new page as dictated by the user.Paragraph justification; This a type of auto formatting where paragraphs are not split as they go to a new page but simply continue from where they left off.Tabular justification; This is a type that the text is indented or aligned at a 'tab stop' to possibly show a paragraph.Read more about Formatting in Microsoft Word at: https://brainly.com/question/25813601