Why would it be difficult to experimentally calculate the speed of sound in the classroom with a stopwatch and meter stick?

Answers

Answer 1

Answer:

Sound travels quite fast and sound wave must pass through a medium, such as air.

To measure a sound in classroom you will require to measure the time it takes a sound to travel a measured distance using stopwatch and meter stick but it would be difficult because walls of classroom will create echos echos.

Echos are reflections of sounds which causes timing errors and make difficult to meausre the speed of sound.


Related Questions

Dominic made the table below to organize his notes about mixtures.
Properties of Mixtures
has no set composition
must have more than one state of matter
must have more than one substance
What mistake did Dominic make?
The title should read "Properties of Solutions" because some mixtures do not have all of the properties listed.
There is a definite recipe to make each mixture, so the composition of a mixture is set.
Although it is possible to have more than one state, it is also possible to have only one state.
A single substance can be used to make a mixture if the substance is composed of more than one element.

Answers

Answer:

Althought it us possible to have more then one state, it's also possible to have only one state of matter

Explanation:

You can make solutions of only one state if matter, for example , it two liquids can be mixed to form a solution they are called miscible.

Answer:

The correct answer is C.) Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

I just did the test on edge and got it right

0.0000302 in scientific notation

Answers

The answer is 3.02 x 10^-5

Answer:

3.02x10^-5

Explanation:

A scientific notation consists of

c x 10^n

the c must be a number between 1-9, while n must be an integer.

it indicates the c being multiplied by the nth power of 10.

From 0.0000302, we need to move the decimal to after 3 so that 3.02 can be a number between 1-9. When moving the decimal point to the right side, each digit moved counts as -1 power of 10.

So, to give 3.02, we need to move the decimal by 5 digits. hence, we can conclude n = -5.

0.0000302 = 3.02x10^-5

A 28-turn circular coil of radius 4.40 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression B = 0.010 0t + 0.040 0t2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t = 4.20 s.

Answers

Answer:

ε = -0.0589V = -58.9mV

Explanation:

In order to calculate the induced emf in the coil, you use the following formula:

[tex]\epsilon=-N\frac{d\Phi_B}{dt}=-N\frac{d(SBcos\alpha)}{dt}[/tex]         (1)

ε: induced emf = ?

N: turns of the coil = 28

ФB: magnetic flux trough the coil

S: cross sectional area of the circular coil = π.r^2

r: radius of the cross sectional area of the coil = 4.40cm = 0.044m

B: magnetic field

α: angle between the direction of the magnetic field and the direction of the normal to the cross area of the coil = 0°

You take into account that the area is constant respect to the magnetic field that cross it. Only the magnetic field is changing with time. The magnetic field depends on time as follow:

[tex]B(t)=0.010t+0.040t^2[/tex]           (2)

You replace the expression (2) into the equation (1), evaluate the derivative, and replace the values of the other parameters for t =4.20s:

[tex]\epsilon=-NS\frac{dB}{dt}=-NS\frac{d}{dt}[0.010t+0.040t^2]\\\\\epsilon(t)=-NS(0.010+0.080t)\\\\\epsilon(t)=-(28)(\pi(0.044m)^2)(0.010T/s+0.080T/s^2(4.20s))\\\\\epsilon(t)=-0.0589V=-58.9mV[/tex]

The induced emf in the coil is -58.9mV

differences between concave and convex meniscus​

Answers

Explanation:

A concave meniscus,(normally seen) occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.

Answer:

there are differences between concave and convex menuscus

Explanation:

A concave meniscus, which is what you normally will see, occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.

The vibrations of a string fixed at both ends are represented by y=16sin(πx/15 )cos(96πt). Where x and y are in cm and t in seconds. Then the phase difference between the points at x=13cm and x=16 in radian​

Answers

Answer:

Explanation:

y = 16 sinπx/15 cos(96πt)

When t = 0

y = 16 sinπx/15

here πx/15 is phase of the point at x

if x = 13

Phase = 13π/15

if x = 16

Phase = 16π/15

Phase difference

= 16π/15 - 13π/15

= 3π/15

= π/5 radian .

an object experiences buoyant force of 15.9 n when immersed in a fluid of density 917 kg/m^3. what is the volume of the object?

Answers

Answer:

0.00176

Explanation:

Credit to the person above.

Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.

Answers

Answer:

6.67×10⁻⁸ cm³/g/s²

Explanation:

6.67×10⁻¹¹ Nm²/kg²

= 6.67×10⁻¹¹ (kg m/s²) m²/kg²

= 6.67×10⁻¹¹ m³/kg/s²

= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)

= 6.67×10⁻⁸ cm³/g/s²

WILL GIVE BRANLIET PLS HELP!!!!! AT LEAST TAKE A LOOK!!!!! I REALLY COULD USE THE HELP!!! SHARE YO SMARTNESSS!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.

Answers

Answer:

λ = 6,108 10⁻⁷ m = 610.8 nm

λ = 5.513 10⁻⁷ m = 551.3 nm

Explanation:

Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression

          d sin θ = m λ

where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference

In this exercise they give us several conditions

The first

the angle is 1.12º to the maximum m = 8

the distance between the slits d = 0.000250 m

of the initial equation

           λ = d sin θ / m

           λ = 0.000250 sin 1.12 / 8

           λ = 6,108 10⁻⁷ m = 610.8 nm

The second

the distance from the slits to the screen is L = 302.0 cm = 3.020 m

the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5

in this case we use that the angle in the experiment is small

      tan θ = y / L

      tan θ = sin θ / cos θ = sin θ

we substitute

       sin θ = y / L

       d y / L = m λ

       λ = d y / L m

 

we calculate

       λ = 0.000250 0.0333 / (3,020 5)

       λ = 5.513 10⁻⁷ m = 551.3 nm

A 0.675 kg mass is attached to a
spring of spring constant 42.4 N/m,
pulled, and released. What is the
frequency of the resulting
oscillation?
(Unit = Hz)

Answers

Answer:

1.26

Explanation:

f=1/(2pi) square root k/m

f=1/(2pi) square root 42.4/.675

f=1.26 I just did this question and found this right

If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.

Answers

Answer:

a. It would shrink

b. It would expand

Explanation:

a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.

The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out

b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.

The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out

A body is acted upon by a force of 4N.
As a result, the velocity of the body has
changed from 0.3 m/s to 0.1 m/s passing
through a certain distance. If the mass
of the body is 1 kg, find the distance travelled.

Answers

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Kinematics.

so here we get as,

V^2 = U^2 + 2as

so here, a = -0.2 m/s^2

(0.1)^2 = (0.3)^2 + (-0.2)(s)

=> 0.01 = 0.09 - 0.2s

=> 0.2s = 0.08

=> s = 0.08/0.2

=> s = 0.4 m

help fast I want the correct answer please does spectral diffusion cause light to scatter ​

Answers

Answer: No

Explanation:

Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.

Scattering of light occurs when light passes through a rough path or a diffused surface.

But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.

Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.

Fluctuation in frequency does not mean diffraction of light or particles

Therefore, spectral diffusion does not cause light to scatter.

The coil of wire in the center of the screen encompasses an area through which magnetic field lines pass, so there is a magnetic flux through those coils. With the magnet stationary, is this magnetic flux producing any flow of current or potential difference?

Answers

Answer:

No, the coil will produce no flow of current or potential difference.

Explanation:

Magnetic field flux is the number of magnetic field line passing through a given area. It depends on the area and the magnetic field strength through this area. For electromagnetic induction to occur, there must be a constantly changing magnetic field. This is according to Faraday's law of electromagnetic induction that states that the induced EMF is directly proportional to the rate of change in flux ΔФ/Δt, and is also proportional to the number of turns on the coil. A changing magnetic field will lead to a break in the flux linkage, which induces current or potential difference on the coil. A stationary coil through a magnetic filed will therefore produce no electric flow of current or potential difference on the coil.

A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity​

Answers

Answer:

[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]

Given:

Initial velocity (u) = 0 m/s

Acceleration (a) = 2 m/s²

Time taken (t) = 10 seconds

To Find:

Final velocity (v)

Explanation:

[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]

A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.

Answers

Answer:

Speed of the satellite V = 6.991 × 10³ m/s

Explanation:

Given:

Force F = 3,000N

Mass of  satellite m = 500 kg

Mass of earth M = 5.97 × 10²⁴

Gravitational force G = 6.67 × 10⁻¹¹

Find:

Speed of the satellite.

Computation:

Radius r = √[GMm / F]

Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)

Radius r = 8.146 × 10⁶ m

Speed of the satellite V = √rF / m

Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500

Speed of the satellite V = 6.991 × 10³ m/s

Which object has the most gravitational potential energy?
O A. A 5 kg book at a height of 2 m
B. An 5 kg book at a height of 3 m
C. An 8 kg book at a height of 3 m
O D. A 8 kg book at a height of 2 m
SUBARU

Answers

Answer:

D

Explanation:

its the heaviest so i would assume its D

what is acceleration???​

Answers

Answer:

The rate at which velocity changes.

Explanation:

Acceleration is when motion changes, it is the rate at which velocity changes.

Answer:

Acceleration is defined as change in velocity per unit time.The increase in velocity per unit time is called acceleration.

Hope this is helpful for you.

Pluto was first observed in 1930, and its largest moon, Charon, was discovered in 1978. A few years after Charon’s discovery, astronomers were able to observe a series of eclipses as Pluto and Charon passed in front of one another. By studying how the brightness of Pluto and Charon changed as they eclipsed each other, astronomers were able to measure the masses and radii of both Pluto and its moon. What did these measurements imply about the average densities of Pluto and Charon?

Answers

Answer:

The average densities of both matches the expected density for objects made from water ice.

Explanation:

Charon's density is 1.2 to 1.3 g / cm3, while Pluto's density is 1.8 to 2.1 g / cm3. This was discovered in many researches and measurements of these two celestial bodies, with the objective of understanding them and promoting efficient scientific knowledge.

With the measurements of the average densities between pluto and Charon it was possible to conclude several statements about them. Firstly, it is possible to see that the two formed independently and at different times, in addition to indicating the existence of few rocks in charon, which is consistent with the average density of objects made mostly of water ice.

1-D Kinematics
A car starts at a position of -153 m
and undergoes a displacement of
512 m. What is its final position?
(Unit = m)​

Answers

Answer:

hope it helps you...........

A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)

Answers

Options:

a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.

b)  An arrow of magnitude 6.50 N points down the slope of the hill.    

c)  An arrow of magnitude 78.5 N points down the slope of the hill.

d)  An arrow of magnitude 852.6 N points straight down.

Answer:

d)  An arrow of magnitude 852.6 N points straight down.

Explanation:

The total mass of the two riders, m = 87.0 kg

The free body diagrams of the situation described are drawn and contained in the files attached to this solution.

Note that the weight of the toboggan will act directly downwards.

Therefore, the weight of the toboggan, W = mg

W = 87 * 9.8

W = 852.6 N

Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.

A gas is held at atmospheric pressure, approximately 100kPa, and room temperature, 298K,
in a container closed with a piston. The piston is initially in a fixed position so the container has a volume of 2.0dm3.
The gas is heated to a temperature of 100∘C
What is the pressure in the container?

Answers

Answer:

125 KPa

Explanation:

Data obtained from the question include:

Initial pressure (P1) = 100 KPa

Initial temperature (T1) = 298 K

Final temperature (T2) = 100°C = 100°C + 273 = 373 K

Final pressure (P2) =..?

Since the volume of the container is fixed, the final pressure in the container can be obtained as follow:

P1/T1 = P2/T2

100/298 = P2/373

Cross multiply

298 x P2 = 100 x 373

Divide both side by 298

P2 = (100 x 373) / 298

P2 = 125.2 ≈ 125 KPa

Therefore, the final pressure in the container is approximately 125 KPa.

A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.

What is the magnitude of force that the ground exerted on the egg?

0.66 N

9.2 N

13 N

180 N

Answer is 9.2 N

Answers

Answer: Magnitude of the force exerted on the egg by the ground is 9.2N

Explanation:

Given the following :

Mass of egg (m) = 150g = 0.15kg

Height(h) from which egg is dropped = 3m

velocity of egg before hitting the ground (u) = 4.4m/s

Final velocity of egg (V) = 0

Time taken (t) = 0.072s

Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:

Momentum = mass × velocity

From Newton's second law:

Force = mass × change in Velocity with time ;

That is

F = m * ΔV / t

Inputting our values

F = 0.15 * (4.4 - 0) / 0.072

F = 0.15 × (4.4 / 0.072)

F = 0.15 × 61.11

F = 9.16N

F = 9.2N

Answer:

9.2 N

Explanation:

Just took practice quiz

What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?

Answers

The astronaut would go the opposite direction due to Newton’s third law of -10N, -10N, -9N, -9N

Let me know if this helped you, please rank this was the brainlist answer if possible, thanks!

An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?

Answers

Answer:

6.72 m/s

Explanation:

recall that the equations of motion may be expressed as

v² = u² + 2as

where,

v = final velocity,

u = initial velocity = 0 m/s because it is stationary before it starts falling

a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)

s = distance traveled = 2.3m

in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.

v² = u² + 2as

v² = 0² + 2(9.81)(2.3)

v² = 45.126

v = √45.126

v = 6.72 m/s

shes right it is 6.71 m/s

What is the formula for calculating the efficiency of a heat engine? Answers:

Answers

Efficiency of heat engine is determined by the ratio of difference in temperature of cold from hot reservoir to the temperature of hot reservoir over temperature of hot reservoir.

A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that its tires will not leave the track? Round to one decimal place and include units. Image:

Answers

Answer:

see explanations below

Explanation:

At the point when the car leaves the track, the reaction on the road is zero, meaning that the centrifugal force equals the gravitation force, namely

mv^2/r = mg

Solve for v in SI units

v^2 = gr = 9.81 m/s^2 * 14.2 m = 139.302 m^2/s^2

v = sqrt(139.302) = 11.8 m/s

Answer: at 11.8 m/s (26.4 mph) car will leave the track.

A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?

Answers

Answer:

0.109  m/s

Explanation:

The calculation of the volume flow rate of the water is shown below:-

Av = Velocity ([tex]\pi[/tex])(Radius)^2

= 0.87([tex]\pi[/tex])(0.2)^2

= 0.135258 m^3 / sec

= 0.109371429 m/s

or

= 0.109

So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come

a force of 50 n acts on abody of mass 5 kg .calculate the acceleration produced​

Answers

Answer:

a = 10 m/s²

Explanation:

Given:

Force = F = 50 N

Mass = m = 5 kg

Required:

Acceleration = a = ?

Formula:

F = ma

Solution:

Rearranging the formula for a

=> a = F/m

=> a = 50/5

=> a = 10 m/s²

what are laws of newton

Answers

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

Explanation:

Answer:

Newton's Law of Motion

1- Every object persists in its state of rest or uniform motion -­ in a straight line unless it is compelled to change that state by forces impressed on it.

2- Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration.

3- For every action, there is an equal and opposite reaction.

how does gravitational pull affect planets with the same mass but different distance from the sun?

Answers

Answer:

it just pulls them at the same time

Explanation:

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