Which relationship in the triangle must be true? Triangle A B C is shown. Angle A C B is a right angle. The length of side C B is a, the length of side A C is b, and the length of side A B is c. sin(B) = sin(A) sin(B) = cos(90 – B) cos(B) = sin(180 – B) cos(B) = cos(A)

Answer: 342.32

Step-by-step explanation: sin(25) = h/a

Sin(25)= h/27

27*sin(25) = h

b*h = area

Answer:

x = 22

Step-by-step explanation:

Since the the 2 bisectors are equal, that means the chords are also equal. Since bisector splits into 2 equal parts, 11 + 11 equals 22

Answer:

ur pito is to small

Step-by-step explanation:

it to little

Answer:

2. Precise but not accurate

Step-by-step explanation:

In a high precision, low accuracy case study, the measurements are all close to each other (high agreement between the measurements) but not near/or close to the center of the distribution (how close a measurement is to the correct value for that measurement)

Answer: the answer is d sin30degrees equal 5/x because sin is opposite over hyponuese

Answer: f(f(f(x)))=8x-7

Step-by-step explanation:

Since we were given f(x) and f(f(x)), We plug that into f(x) again to get f(f(f(x))).

2(4x-3)-1                          [distribute]

8x-6-1                              [combine like terms]

8x-7

Answer:

Make a point at (3pm, 45), (4.5 pm, 45), (5.5pm, 30), (6.5pm, 15), and (7.5pm, 0). Then connect the dots starting at (0,0) Then you have your graph :)

Step-by-step explanation:

Answer:

y=4x-8

Step-by-step explanation:

First you must use the distributive property and get y-8=4x-16.

Then you have to add 8 on both sides so just y is left on the left side.

This will get you y=4x-8 in slope-intercept form.

Answer:

20

Step-by-step explanation:

The linear function represents the number of units sold y in terms of profit x is y = 27.5x - 1015.

A straight line on the coordinate plane is represented by a linear function.

A linear function always has the same and constant slope.

The formula for a linear function is f(x) = ax + b, where a and b are real values.

As per the given pair of (number of units sold y, profit x)

Linear equation slope and y-intercept

A linear equation or function is given as ;

y = mx + c

Here, c is the y-intercept and m is the slope.

The slope associated with two points (x₁, y₁) and (x₂, y₂) is given by

Slope m  = (y₂ - y₁)/(x₂ - x₁)

Therefore slope of (46,250), (48, 305)

m = (305 - 250)/(48 - 46) = 27.5

Put, m = 27.5 and (46,250)

250 = 27.5(46) + c

c = -1015

y = 27.5x - 1015

Hence "The linear function represents the number of units sold y in terms of profit x is y = 27.5x - 1015".

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Answer:

y = 2x + 3

Step-by-step explanation:

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope-Intercept Form: y = mx + b

Step 1: Find slope m

m = (-1 - 3)/(-2 - 0)

m = -4/-2

m = 2

y = 2x + b

Step 2: Rewrite equation

y = 2x + 3

*You are given y-intercept (0, 3), so simply add it to your equation.

Part A

g(x) = 3x+1

g(-4) = 3(-4)+1 ... every x replaced with -4

g(-4) = -12+1

g(-4) = -11

Plug this into the f(x) function

f(x) = x^2 - 2x

f( g(-4) ) = (g(-4))^2 - 2( g(-4) )

f( g(-4) ) = (-11)^2 - 2(-11)

f( g(-4) ) = 121 + 22

====================================================

Part B

Plug the g(x) function into the f(x) function

f(x) = x^2 - 2x

f( g(x) ) = ( g(x) )^2 - 2( g(x) ) ... replace every x with g(x)

f( g(x) ) = (3x+1)^2 - 2(3x+1)

f( g(x) ) = (9x^2+6x+1) + (-6x-2)

f( g(x) ) = 9x^2+6x+1-6x-2

Note that we can plug x = -4 into this result and we would get

f( g(x) ) = 9x^2-1

f( g(-4) ) = 9(-4)^2-1

f( g(-4) ) = 9(16)-1

f( g(-4) ) = 144-1

f( g(-4) ) = 143 which was the result from part A

====================================================

Part C

Replace g(x) with y. Then swap x and y. Afterward, solve for y to get the inverse.

[tex]g(x) = 3x+1\\\\y = 3x+1\\\\x = 3y+1\\\\3y+1 = x\\\\3y = x-1\\\\y = \frac{1}{3}(x-1)\\\\y = \frac{1}{3}x-\frac{1}{3}\\\\g^{-1}(x) = \frac{1}{3}x-\frac{1}{3}\\\\[/tex]

Answer:

104.93 in

Step-by-step explanation:

When we draw out a picture of our triangle, we should see that we need to use sin∅ to solve:

sin23° = 41/x

xsin23° = 41

x = 41/sin23°

x = 104.931

Answer:

16

Step-by-step explanation:

X^2 + 8x= 11

Take the coefficient of x

8

Divide by 2

8/2 =4

Square it

4^2 = 16

Add 16 to each side

Answer:

c = 5.5

Step-by-step explanation:

We can find the slope of the line using the given points (5,5) and (-3,1) using rise over run:

-4/-8 = 1/2

Now, we can plug in the slope and a point into the equation y = mx + b to find b:

5 = 1/2(5) + b

5 = 2.5 + b

2.5 = b

Then, we can plug in 6 in the point (6,c) to find c:

y = (1/2)(6) + 2.5

y = 3 + 2.5

y = 5.5

c = 5.5

Answer:

c = 5.5

Step-by-step explanation:

Find the slope with two points

m = (y2-y1)/(x2-x1)

m = (1-5)/(-3-5)

   = -4/-8

   = 1/2

If all the points are on the same line, then they have the same slope

m = (y2-y1)/(x2-x1)

Using the first and third points

1/2 = (c-5)/(6-5)

1/2 =  (c-5)/1

1/2 = c-5

Add 5 to each side

5+1/2 = c

5.5 =c

Answer:

D. Two-sample chi-square

Step-by-step explanation:

A chi-square test is a test used to compare the data that is observed, from the data that is expected.

In a two-sample chi-square test the observed data should be similar to the expected data if the two data samples are from the same distribution.

The hypotheses of the two-sample chi-square test is given as:

H0: The two samples come from a common distribution.

Ha: The two samples do not come from a common distribution

Therefore, in this case, the best statistical test to utilize is the two-sample chi-square test.

Answer: 7/8

Step-by-step explanation:

Let the boy is letter B and the girl is letter G.

So the possible outcomes are as follows below

BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG

SO the number of possible outcomes is 8

The number of outcomes where is at least 1 girl ( triples where is 1 girl, 2 girls or all 3 children are the girls) is 7

So the probability, that family with 3 kids has at least 1 girl is

P(number of girls >=1)=  7/8  

Answer:

b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.

Step-by-step explanation:

A square matrix is said to be invertible if the product of the matrix and its inverse result into an identity matrix.

3  0 -4

2  0  6

-3 0  8

Since the second column elements are all zero, the determinant of the matrix is zero ad this implies that the inverse of the matrix does not exist(i.e it is not invertible )

A square matrix is said to be invertible if it has an inverse.

The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.

The matrix is given as:

[tex]\left[\begin{array}{ccc}3&0&-4\\2&0&6\\-3&0&8\end{array}\right][/tex]

Calculate the determinant

The determinant of the matrix calculate as:

[tex]|A| = 3 \times(0 \times 8- 6 \times 0) - 0(2 \times 8 - 6 \times -3) -4(2 \times 0 - 0 \times -3)[/tex]

[tex]|A| = 3 \times(0) - 0(34) -4(0)[/tex]

[tex]|A| = 0 - 0 -0[/tex]

[tex]|A| = 0[/tex]

When a matrix has its determinant to be 0, then

Hence, the correct option is (b)

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Answer:

He should accept contract 2 because it has a higher present value.

Step-by-step explanation:

we need to find the present value of each contract:

Contract 1 = $3,000,000/1.1 + $3,000,000/1.1² + $3,000,000/1.1³ + $3,000,000/1.1⁴  = $2,727,273 + $2,479,339 + $2,253,944 + $2,049,040 = $9,509,596

Contract 2 $2,000,000/1.1 + $3,000,000/1.1² $4,000,000/1.1³ + $5,000,000 /1.1⁴  = $1,818,182 + $2,479,339 + $3,005,259 + $3,415,067 = $10,717,847

Contract 3 $7,000,000/1.1 + $1,000,000/1.1² + $1,000,000/1.1³ + $1,000,000/1.1⁴  = $6,363,636 + $826,446 + $751,315 + $683,013 = $8,624,410

Answer:

$36,241.20

Step-by-step explanation:

Compounded Interest Rate Formula: A = P(1 + r/n)^nt

Since we are given P, r, n, and t, simply plug it into the formula:

A = 35000(1 + 0.035/4)⁴⁽¹⁾

A = 35000(1 + 0.00875)⁴

A = 35000(1.00875)⁴

A = 35000(1.03546)

A = 36241.2

Answer:

945 ways

Step-by-step explanation:

Total

Required Selection

2  Appetizers out of 7 can be selected in [tex]^7C_2[/tex] ways

8 main courses out of 9 can be selected in [tex]^9C_8[/tex] ways

4 desserts out of 5 can be selected in [tex]^5C_4[/tex] ways

Therefore, the number of ways this can be done

[tex]=^7C_2 \times ^9C_8 \times ^5C_4[/tex]

=945 ways

Answer:

84%

Step-by-step explanation:

The probability that the selected player is a football player, P(F)=19%

The probability that the selected player is a basketball player, P(B)=79%

The probability that the selected player play both football and basketball,

[tex]P(B \cap F)=14\%[/tex]

We want to determine the probability that a randomly chosen athlete is either a football player or a basketball player, [tex]P(B \cup F)[/tex]

In probability theory

[tex]P(B \cup F)=P(B)+P(F)-P(B \cap F)\\=79\%+19\%-14\%\\=84\%[/tex]

The probability that a randomly chosen athlete is either a football player or a basketball player is 84%.

We multiply the numerators together to get x*2x = 2x^2 as the numerator for the answer.

The denominators pair up and multiply to get (x-5)(x+4) = x^2+4x-5x-20 = x^2-x-20. You can use the distributive property, FOIL, or the box method to expand out (x-5)(x+4)

So that's how we end up with (2x^2) all over (x^2-x-20) as the answer.

Answer:

aaaaha pues

Step-by-step explanation:

Answer:

what happened

Step-by-step explanation:

Answer:

1). SUBTRACTION property of equality

2). MULTIPLICATION property of equality

Step-by-step explanation:

Step 2:

When we subtract the same number from both the sides of an equation it represents the subtraction property of equality.

[tex]\frac{x}{4}+5-(5)=23-(5)[/tex]

Here 5 has been subtracted from both the sides.

Therefore, SUBTRACTION property of equality was applied.

Step 4:

If the same number is multiplied to both the sides of an equation, multiplication property of equality is applied.

[tex]4\times \frac{x}{4}=4\times (18)[/tex]

Here 4 has been multiplied to both the sides.

Therefore, MULTIPLICATION property of equality was applied.

Answer:

  see attached

Step-by-step explanation:

The limit as x gets large is the ratio of the highest-degree terms. In most cases, the limit can be found by evaluating that ratio. Where an absolute value is involved, the absolute value of the highest-degree term is used.

If the ratio gives x to a positive power, the limit does not exist. If the ratio gives x to a negative power, the limit is zero.

The arrangement of functions according to the given condition

[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]

[tex]h(x)=\frac{x^{3} -x^{2} +4}{1-3x^{2} }[/tex]

[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]

[tex]i(x)=\frac{x-1}{|1-4x| }[/tex]

[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]

[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]

[tex]f(x)=\frac{x^{2} -1000}{x-5}[/tex]

[tex]j(x)=\frac{x^{2}-1 }{|7x-1|}[/tex]

A limit is the value that  a function approaches as the input approaches some value.

According to the given question

[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]

⇒[tex]\lim_{nx\to \infty} \frac{5x^{2} -1}{x^{2} +1}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x^{2} }{x^{2} } \frac{5-\frac{1}{x^{2} } }{1+\frac{1}{x^{2} } }[/tex]

= 5           ([tex]\frac{1}{x^{2} } = 0[/tex] ,as x tends to infinity  [tex]\frac{1}{x^{2} }[/tex] tends to 0)

[tex]i(x)=\frac{x-1}{|1-4x|}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x-1}{|1-4x|}[/tex] =  [tex]\lim_{x \to \infty} \frac{x}{x} \frac{1-\frac{1}{x} }{|\frac{-1}{4}+\frac{1}{x} | }[/tex]  =[tex]\frac{1}{\frac{1}{4} }[/tex] =[tex]\frac{1}{4}[/tex]

As x tends to infinity 1/x tends to 0, and |[tex]\frac{-1}{4}[/tex]| gives 1/4

[tex]f(x)= \frac{x^{2} -1000}{x--5}[/tex]

⇒[tex]\lim_{x \to \infty} \frac{x^{2} -1000}{x-5}[/tex]= [tex]\lim_{x \to \infty} \frac{x^{2} }{x} \frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex]= [tex]\lim_{x \to \infty} x\frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex] ⇒ limit doesn't exist.

[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]

⇒[tex]\lim_{x\to \infty} \frac{4x^{2} -6}{1-4x^{2} }[/tex]=[tex]\lim_{x\to \infty} \frac{x^{2} }{x^{2} } \frac{4-\frac{6}{x^{2} } }{\frac{1}{x^{2} } -4}[/tex]  [tex]= \lim_{n \to \infty} \frac{4}{-4}[/tex] = -1

As x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0.

[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]

⇒[tex]\lim_{x\to \infty} \frac{|4x-1|}{x-4}[/tex] = [tex]\lim_{x \to \infty} \frac{|x|}{x} \frac{4-\frac{1}{x} }{1 -\frac{4}{x} } }[/tex] = 4

as x tends to infinity 1/x tends to 0

and |x|=x ⇒[tex]\frac{|x|}{x}=1[/tex]

[tex]h(x)=\frac{x^{3}-x^{2} +4 }{1-3x^{3} }[/tex][tex]\lim_{x \to \infty} \frac{x^{3} -x^{2} +4}{1-3x^{3} }[/tex][tex]= \lim_{x \to \infty} \frac{x^{3} }{x^{3} } \frac{1-\frac{1}{x}+\frac{4}{x^{3} } }{\frac{1}{x^{3} -3} }[/tex]  = [tex]\frac{1}{-3}[/tex] =[tex]-\frac{1}{3}[/tex]

[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]

[tex]\lim_{x \to \infty} \frac{5x+1000}{x^{2} }[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{5+\frac{1000}{x} }{x}[/tex] =0

As x tends to infinity 1/x tends to 0

[tex]j(x)= \frac{x^{2}-1 }{|7x-1|}[/tex]

[tex]\lim_{x \to \infty} \frac{x^{2}-1 }{|7x-1|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{|x|}\frac{x-\frac{1}{x} }{|7-\frac{1}{x}| }[/tex]  = [tex]\lim_{x \to \infty} 7x[/tex] = limit doesn't exist.

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Answer:

false

Step-by-step explanation:

hello

this is false

FOREX means Foreign Exchange

it refers to the foreign exchange market

hope this helps

Answer:

true, forex trading is a profitable than staking cryptocurrency. forex trading is the best thing I will refer someone I love because learning never stops and no on is above blowing accounts when beginning Forex

Answer:

The second question

Step-by-step explanation:

The orca starts at -25 meters. She goes up 25 meters.

up 25 = +25

-25+25=0

Answer:

Option 2

Step-by-step explanation:

The orca swims at the elevation of -25 meters. The orca swims up 25 meters higher than before.

-25 + 25 = 0

Answer:

53 in.

Step-by-step explanation:

to find the area u do 8 times 6 and 1/2 2(5)

triangle = 1/2bh

rectangle = bh

hope this helps

Answer: £20.

Step-by-step explanation:

Let the old price = £x

Percent increase. = 10%

Increment. = 10% of £x

= 10x/100

Now new price = £22

To determine the old price we have

x + 10x/100. = 22

We now multiply everything by 100 to make it a linear expression

100x + 10x = 2200

110x = 2200, therefore

x. = 2200/110

= £20

Therefore, the price before the increase. = £20.

Answer:

1) Option B is correct.

Expected frequency of satisfied customers from the Berwick sample = 75

2) Option D is correct.

Expected frequency of satisfied customers from the Milton sample = 90

3) Option A is correct.

Expected frequency of satisfied customers from the Leesburg sample = 60

4) Option B is correct.

The chi-square test statistic for these samples = 2.44

5) Option B is correct.

The degrees of freedom for the chi-square critical value = 2

6) Option C is correct.

The chi-square critical value using alpha = 0.05 is 5.991

7) Option D is correct.

The conclusion for this chi-square test would be that because the test statistic is less than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.

Step-by-step explanation:

Berwick Milton Leesburg

Number Satisfied 80 85 60

Unsatisfied 20 35 20

Sample Size 100 120 80

Since this is a chi test that aims to check if there are differences in the proportion of expected number of customers for each location, we state the null and alternative hypothesis first.

The null hypothesis usually counters the claim we hope to test and would be that there is no difference between the proportion of expected frequency of satisfied customers at the three locations.

The alternative hypothesis confirms the claim we want to test and is that there is a significant difference between the proportion of expected frequency of satisfied customers at the three locations.

So, the total proportion of satisfied customers is used to calculate the expected number of satisfied customers for each of the three locations.

80+85+60= 225

Total number of customers = 100 + 120 + 80 = 300

Proportion of satisfied customers = (225/300) = 0.75

1) Expected frequency of satisfied customers from the Berwick sample = np = 100 × 0.75 = 75

2) Expected frequency of satisfied customers from the Milton sample = np = 120 × 0.75 = 90

3) Expected frequency of satisfied customers from the Leesburg sample = np = 80 × 0.75 = 60

4) Berwick Milton Leesburg

Number Satisfied 80 85 60

Unsatisfied 20 35 20

Sample Size 100 120 80

Proportion for unsatisfied ccustomers = 0.25

So, expected number of unsatisfied customers for the three branches are 25, 30 and 20 respectively.

Chi square test statistic is a sum of the square of deviations from the each expected value divided by the expected value.

χ² = [(X₁ - ε₁)²/ε₁] + [(X₂ - ε₂)²/ε₂] + [(X₃ - ε₃)²/ε₃] + [(X₄ - ε₄)²/ε₄] + [(X₅ - ε₅)²/ε₅] + [(X₆ - ε₆)²/ε₆]

X₁ = 80, ε₁ = 75

X₂ = 85, ε₂ = 90

X₃ = 60, ε₃ = 60

X₄ = 20, ε₄ = 25

X₅ = 35, ε₅ = 30

X₆ = 20, ε₆ = 20

χ² = [(80 - 75)²/75] + [(85 - 90)²/90] + [(60 - 60)²/60] + [(20 - 25)²/25] + [(35 - 30)²/30] + [(20 - 20)²/20]

χ² = 0.3333 + 0.2778 + 0 + 1 + 0.8333 + 0 = 2.4444 = 2.44

5) The degree of freedom for a chi-square test is

(number of rows - 1) × (number of columns - 1)

= (2 - 1) × (3 - 1) = 1 × 2 = 2

6) Using the Chi-square critical value calculator for a degree of freedom of 2 and a significance level of 0.05, the chi-square critical value is 5.991.

7) Interpretation of results.

If the Chi-square test statistic is less than the critical value, we fail to reject the null hypothesis.

If the Chi-square test statistic is unusually large and is greater than the critical value, we reject the null hypothesis.

For this question,

Chi-square test statistic = 2.44

Critical value = 5.991

2.44 < 5.991

test statistic < critical value

The test statistic is Less than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.

Hope this Helps!!!