Why do waves slow down?

Answers

Answer 1

Answer:

because of moon  

Explanation:


Related Questions

When an object levitates, the magnetic force causes the object to repel. Without this magnetic force, ________ would pull the object down. ​

Answers

Answer:

gravity

Explanation:

I don't know what the explanations would be


Which statement describes a characteristic of deposition

Answers

Explanation:

when soil builds up over time in the location

What is the saying that can help you remember the order of the visible spectrum? ROYBVIG ROYGBIV RIBYOVG RYOBIVG​

Answers

Answer:

ROYGBIV

Explanation:

mark me brainliest pls

Answer:

ROYGBIV

Explanation:

What is hypothesis testing

Answers

Hypothesis testing is basically testing the results of a experiment to see weather your results are valid or not.

A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 7.2 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall

Answers

Answer:

480N

Explanation:

Given data

M1= 1.2kg

U1= 8m/s

V1=7.2 m/s

T= 2ms= 0.002

We know that the impulse expression is

P=FT

M(U1-V1)= FT

substitute

1.2(8-7.2)= F*0.002

1.2*0.8=  F*0.002

0.96=  F*0.002

F= 0.96/0.002

F=480N

Hence the force is 480N

A spinning disc with a mass of 2.5kg and a radius of 0.80m is rotating with an angular velocity of 1.5 rad/s. A ball of clay with unknown mass is dropped onto the disk and sticks to the very edge causing the angular velocity of the disk to slow to 1.13 rad/s. What is the mass of the ball of clay

Answers

Answer:

M = 1.90 Kg

Explanation:

Given data: mass = 2.5 Kg

radius R = 0.8 m

angular velocity ω = 1.5 rad/s

Angular momentum L =0.5×Iω^2

Where, I  is the moment of inertia of the spinning disc.

I = 0.5MR^2

I = 0.5×2.5×0.8^2

I = 0.8 Kg/m^2

Then L = 0.5×0.8×1.5^2 = 0.8×2.25 = 0.9 Kg-m^2/sec

Let unknown mass be M

New mass of disc = (2.5+M) Kg, R = 0.8 m

New I = 0.5(2.5+M)(0.8)^2

Since, angular momentum is conserved

Angular momentum before = angular momentum after

0.5×0.5(2.5+M)(0.8)^2×(1.13)^2 = 0.9

Solving for M we get

0.204304(2.5+M)=0.9

M = 1.90 Kg

the mass of an ice block is 500kg and density is 920kg\m^3. calculate the volume of an ice block ​

Answers

0.107

That the answer. Mark me brainlieat plz

The volume of an ice block ​will be 0.543 m³.

What is density?

Density is defined as the mass per unit volume. It is an important parameter to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

The given data in the problem is as ;

v is the volume of ice block =?

ρ is the density = 920kg/m³

m is the mass of ice block = 500kg

The mass and density relation is given as;

mass = density × volume

500 kg =920kg/m³ ×v

v=0.543 m³

Hence, the volume of an ice block ​will be 0.543 m³.

To learn more about the density refer to the link;

https://brainly.com/question/952755

#SPJ2

a car drives 24 meters to the left in three seconds what is the velocity of the car?

Answers

Answer:

8 m/s to the left.

Explanation:

Applying,

V = d/t...................... Equation 1

Where V = Velocity of the car, d = distance, t = time

From the question,

Given: d = 24 meters, t = 3 seconds

Substitute these values into equation 1

V = 24/3

V = 8 m/s to the left.

Hence the velocity of the car is 8 m/s to the left.

A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.25 \times 10^{-16} N2.25×10 −16 N in the +y-direction, and an electron moving at 4.75 km/s in the -z-direction experiences a force of 8.50 \times 10^{-16} \mathrm{N}8.50×10 −16 N in the +y-direction.
(a) What are the magnitude and direction of the magnetic field?
(b) What are the magnitude and direction of the magnetic force on an electron moving in the -y-direction at 3.20 km/s?

Answers

Answer:

a)  B = 0.9375 T  -z, b)      B = 1.54 T

Explication

a) The magnetic force is

         F = q v x B

         f = q v B sin θ

bold indicates vectors

For direction let's use the right hand rule.

If the charge is positive

the flea in the direction of velocity, toward + x

the fingers extended in the direction of B

the palm the direction of the force + and

therefore the magnetic field goes in the direction of -z

           F = q v B

           2.25 10-16 = 1.6 10-19  1.50 103 B

           B = 2.25 10-16 / 2.4 10-16

           B = 0.9375 T  -z

b) now an electron

thumb speed direction, -z

opposite side of palm force + y

therefore the direction of the magnetic field is + x

            B = F / qv

            B = 8.5 10-16 / 1.16 10-19 4.75 103

             B = 1.54 T

wHICH WAVES MOVE BY REPLACING ONE PARTICLE WITH ANOTHER?
A. LIGHT WAVES
B. SOUND WAVES
C. ELECTROSTATIC WAVES
D. ELECTROMAGNETIC WAVES

AGAIN IF ANYONE I KNOW SEES THIS IGNORE BC IM FINNA JUMP OFF A CLIFF

Answers

Answer:

I think it's B. Sound Waves

your answer is B. Sound waves. sorry if im wrong

define electric field intensity​

Answers

Answer:

Electric field intensity is a Vector Field. Electric field intensity (E, N/C or V/m) is a vector field that quantifies the force experienced by a charged particle due to the influence of charge not associated with that particle

Explanation:

A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon weigh 150n with what force must the child pull on the handle if the handle is parallel to the incline?​

Answers

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

[tex]F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\[/tex]

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

[tex]F = (150\ N)Sin\ 20^o[/tex]

F = 51.3°

Select the correct answer.
A car moves with an average speed of 45 miles/hour. How long does the car take to travel 90 miles?
OA.
2 minutes
OB.
2 hours
O c.
45 minutes
OD.
45 hours
O E.
90 minutes
Reset
Next

Answers

Answer:

B. 2 hours

Explanation:

45 miles an hour times 2 is 90 miles in 2 hours

Answer:

B. 2 Hours

Explanation:

If your going at a constant speed of 45 miles per hour then, it will take two hours because 45x2 is 90. and if you divided 90 and 45, you will get 2.

80 POINTSSS
The picture above represents what kind of circuit?




open series circuit


open parallel circuit


closed series circuit


closed parallel circuit

Answers

Answer:

closed parallel circuit

A guy wire 1000 feet long is attached to the top of a tower. When pulled taut it makes a 42˚ angle with the ground. How tall is the tower? How far away from the base of the tower does the wire hit the ground?

Answers

Answer:

669.1 ft and 743.1 ft

Explanation:

Given data

Lenght of wire= = 1000ft

Angle =  42˚

Applying SOH CAH TOA

1. How tall is the tower?

SOH

sine ∅= opp/hyp

sin 42= opp/1000

0.6691= Opp/1000

0.6691*1000= Opp

Opp=669.1 ft

Applying SOH CAH TOA

2.How far away from the base of the tower does the wire hit the ground?

CAH

cos ∅= adj/hyp

cos 42= adj/1000

0.7431*1000=adj

adj=743.1 ft

que estudia la estática?

Answers

La estática es la rama de la mecánica que se ocupa del análisis de cargas que actúan sobre sistemas físicos que no experimentan una aceleración, sino que se encuentran en equilibrio estático con su entorno.

A driver fills an 18.9L steel gasoline can with gasoline at 15.0°C right up to the top. He forgets to replace the cap and leaves the can in the back of his truck. The temperature climbs to 30.0°C by 1pm. How much gasoline spills out of the can​

Answers

Answer:

ΔV = 0.98 L

Explanation:

First, we will calculate the increased volume using Charles' Law:

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

where,

V₁ =initial volume = 18.9 L

V₂ = final volume = ?

T₁ = initial temperature = 15°C + 273 = 288 k

T₂ = final temperature = 30°C + 273 = 303 k

Therefore,

[tex]\frac{18.9\ L}{288\ k} = \frac{V_2}{303\ k}[/tex]

V₂ = 19.88 L

Now, we calculate the change in volume:

ΔV = V₂ - V₁ =  19.88L - 18.9 L

ΔV = 0.98 L

This is the volume of gasoline that will spill out.

A 3 Volt battery is connected in series to three resistors: 4,6, and 2. Find the total current.

Answers

Answer:

using ohm's law I=3/12

I=250ma.

You are studying a population of flowering plants for several years. When you present your research findings you make the statement that, "Increased allocation of resources to reproduction relative to growth diminished future fecundity." Which of the following graph descriptions could accurately present your data?
a) With seeds in the current year on the y-axis and seeds in the previous year on the x-axis, you would see a line that increased from left to right
b) With survivorship on the y-axis and number of seeds produced on the x-axis, you would see a line that decreased left to right.
c) With leaf area on the y-axis and number of seeds produced on the x-axis, you would see a line that increased left to right
d) With survivorship on the y-axis and number of seeds produced on the x-axis, you would see a line that increased left to right.
e) With seeds in the current year on the y-axis and seeds in the previous year on the x-axis, you would see a line that decreased from left to right

Answers

Answer:

Option A

Explanation:

The graph for this problem must depict the following ""Increased allocation of resources to reproduction relative to growth diminished future fecundity."

Hence, the survivor ship must be on the Y axis and the resources on the X axis.

Here the resources include the number of seeds produced.

hence, the higher is the number of seeds (resource), the lower is the survivorship (future fecundity)

Hence, option A is correct

What is the momentum of a 12 kg ball
travelling at 35 m/s?

Answers

Answer:

The answer is 420kgm/s

Explanation:

momentum = mass×velocity

= 12kg×35m/s

=420kgm/s

Answer:

ligma

Explanation:

Please help ASAP with questions

Answers

What do you need what question

a football player starts from rest and speeds up to a final velocity of 12 m/s. the speeding up takes a total of 6 seconds. what is the football players acceleration

Answers

Answer:

2 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 6 s

Acceleration (a) =?

The acceleration of the player can be obtained as follow:

v = u + at

12 = 0 + (a × 6)

12 = 6a

Divide both side by 6

a = 12 / 6

a = 2 m/s²

Thus, the acceleration of the player is 2 m/s²

What is Hooke's law? what is meant by elastic limit?
please answer me​

Answers

Answer:

Explanation:

The law is about how object will be deformed when certain amount force is  applied. Elastic limit is a point where object will not return its previous shape after being deformed

A certain CD has a playing time of 74.0 minutes. When the music starts, the CD is rotating at an angular speed of 480 revolutions per minute (rpm). At the end of the music, the CD is rotating at 210 rpm. Find the magnitude of the average angular acceleration of the CD. Express your answer in rad/s2.

Answers

Answer: [tex]0.00636\ rad/s^2[/tex]

Explanation:

Given

CD has a playing time of [tex]t=74\ min\ or\ 74\times 60\ s[/tex]

Initial angular speed of CD is [tex]480\ rpm[/tex]

Final angular speed of DC is [tex]210\ rpm[/tex]

Angular speed, when rpm is given

[tex]\omega =\dfrac{2\pi N}{60}[/tex]

[tex]\omega_i=\dfrac{2\pi \times 480}{60}\\\\\Rightarrow \omega_i=16\pi \ rad/s[/tex]

Final speed

[tex]\Rightarrow \omega_f=\dfrac{2\pi \times 210}{60}\\\\\Rightarrow \omega_f=7\pi \ rad/s[/tex]

Using equation of angular motion

[tex]\Rightarrow \omega_f=\omega_i+\alpha t[/tex]

Insert the values

[tex]\Rightarrow 7\pi =16\pi +\alpha \times 74\times 60\\\Rightarrow -9\pi =\alpha \cdot (4440)\\\\\Rightarrow \alpha=-\dfrac{9\pi}{4440}\\\\\Rightarrow \alpha=-0.00636\ rad/s^2[/tex]

Magnitude of angular acceleration is [tex]0.00636\ rad/s^2[/tex]

anybody from India ?​

Answers

Answer:

No,why you say that

Explanation:

nah from the usa here

Suppose that an electron and a positron collide head-on. Both have kinetic energy of 1.20 MeV and rest energy of 0.511 MeV. They produce two photons, which by conservation of momentum must have equal energy and move in opposite directions. What is the energy Ephoton of one of these photons

Answers

Answer:

E = 1.711 MeV

Explanation:

From the law of the conservation of energy:

[tex]K.E_{e}+K.E_p + E_{e}+E_{p} = 2 E[/tex]

where,

[tex]K.E_e=K.Ep=[/tex] the kinetic energy of positron and electron = 1.2 MeV

[tex]E_e=E_p =[/tex] Rest energy of the electron and the positron = 0.511 MeV

E = Energy of Photon = ?

Therefore,

[tex]1.2\ MeV + 1.2\ MeV + 0.511\ MeV + 0.511\ MeV = 2E\\\\E = \frac{3.422\ MeV}{2}\\\\[/tex]

E = 1.711 MeV


10 A particle in circular motion performs 30 oscillations in 6
seconds. Its angular velocity is?

Answers

Explanation:

Let omega = angular velocity (in rad/s). Then

omega = (# of oscillations)/(6 s)

= (30 osc)/(6 s) = 5 osc/s

We need to convert this to rad/s:

omega = (5 osc/s)(2π rad/osc)

= 10π rad/s

= 31.4 rad/s

Isobaric process is one carried out at constant (A) Speed (B) Volume
(D) Temperature (E) Acceleration.

Answers

Answer:

Isobaric process is one carried out at constant Pressure.

Explanation:

An isobaric process is a process that takes place under constant pressure. The first law of thermodynamics can be written as follows for the Isobaric Process:

ΔQ = ΔU + PΔV

where,

ΔQ =  Heat Transfer

ΔU = Change in Internal Energy of the System

P = Constant Pressure

ΔV = Chang in Volume of the System

In an isobaric process, heat supplied to the system is utilized to increase its internal energy and to do work.

Hence, all the options given are incorrect. The correct option is:

Isobaric process is one carried out at constant Pressure.

A teacher sets up the following demonstration in which he places a clear glass rod with an index of refraction of 1.47 into a beaker containing an unknown liquid. When he does this, the submerged portion of the glass rod seems to disappear. The teacher gives the students the following list of possible liquids in which this glass rod has been submerged.

Material Index of Refraction
Salt Water 1.37
Glycerin 1.47
Silicon Oil 1.52

Required:
Which material is most likely to represent the liquid in the beaker and why?

Answers

Answer:

salt water

total internal reflection

Explanation:

Let's analyze this experiment, for the rod to disappear it must have happened that the light coming from it does not reach us that we are seeing from the air n = 1, therefore the light from the rod must be reflected, for this to happen we use the refractive ratio

           n₁  sin θ₁  = n₂ sin θ₂  

where n₁ is the refractive index of the rod, the greatest angle that could exist in the liquid is 90º, therefore sin 90 = 1

            n₁ sin θ₁  = n₂

           sin θ₁ = n₂ /n₁

the only way this expression is correct is that

             n₂ <n₁

that is

             n₂ < 1.47

When reviewing the given materials, the only one that meets this condition is salt water by the total internal reflection

define rectilinear propagation of light​

Answers

Answer:

Electromagnetic waves to travel in a straight line. Light only deviates from a straight line when the medium it is travelling through changes density. This is called refraction. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout. Wikipe

Other Questions
Please tell me what you think about my story and any feedback on it!!!We Didnt Know Until it Was Too Late!That night everything changed. It was the morning of October 30, 1995 in the small town of Falls Haven where we all grew up. Sasha, Amanda, Josh, and I decided we wanted to throw a Halloween party since tomorrow was Halloween and our parents were out of town. Before the party, we got all the supplies we needed and got the house ready.A few hours later, It was finally time for the party and every teen from the town showed up in their costumes. Sasha and Amanda wore a matching little red riding hood outfit with a pair of black flats. The two of them matching wasnt surprising to anyone because they were twins and they did everything together whether it be small or big they did it and they were the craziest, down-to-earth people I know. Now Josh on the other hand was the opposite out of all of us, he was the popular kid, captain of the football team, the perfect guy you thought you would only see on T.V. He ended up coming to the party in just his red and black football jersey. I ended up wearing my yellow and black plaid outfit from my favorite movie Clueless.~Later on that night~Hey Josh, have you seen Sasha anywhere? I havent seen her anywhere I asked Josh.No I havent, but I can help you look for her he said.So thats what we did, we looked everywhere, in the sparkly clean bathroom, in the old creaking tree house we used to go up when we were little, and every single cabinet and room in the house. It wasnt until we went to the backyard we found her and what we saw will haunt us forever. What we saw was Sasha's body lying face down in the pool. Josh and I pulled her out of the pool and tried to get her conscious but everything we did nothing worked and so I checked her pulse and it was silent.I think shes dead, what are we going to do? I said frantically.We need to call the police and tell them, he said.No,no,no, no we cant tell the police, if my mom were to find out I was having a party then I would be dead. I said to him.Are you seriously only worried about your mom when our friend is literally dead he said.Of course not, but we cant tell the police because we will all be arrested if they were to show up since we were illegally drinking and smoking. We need to get rid of her body I said to him.But where? He asked.I think I know a place. 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To determine the margin of error for this statistic, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.78. The minimum sample proportion from the simulation is 0.62, and the maximum sample proportion from the simulation is 0.80. The margin of error of the population proportion is found using half the range. What is the interval estimate of the true population proportion?1. (0.74, 0.82)2. (0.64, 0.92)3. (0.72, 0.84)4. (0.69, 0.87) when do materials or objects change?