which two substances are among the four major types of organic compounds made by living things
A.lipids
B.water
C.carbon dioxide
D.Nucleic acids


will give brainliest

Answers

Answer 1
Which two substances are among the four major types or organic compounds made by living things, The answer C,
would be carbon dioxide

Related Questions

A 0.0250L solution of HCl is neutralized by 0.0780L of an unknown Mg(OH)2 solution. Also 0.050L of this Mg(OH)2 solution is neutralized by 0.0300L of a 0.20 M H3(PO3) solution. What is the concentration of the HCl solution

Answers

Answer:

[tex]M_{HCl} = 1.12M[/tex]

Explanation:

Hello!

In this case, for the first reaction we need to focus on, the neutralization of magnesium hydroxide by phosphoric acid, we can write up the following equation:

[tex]3Mg(OH)_2+2H_3PO_4\rightarrow Mg_3(PO_4)_2+6H_2O[/tex]

Whereas the acid and base react in a 3:2 mole ratio; thus, we can write:

[tex]2M_{Mg(OH)_2}V_{Mg(OH)_2}=3M_{H_3PO_4}V_{H_3PO_4}[/tex]

Now, solving for the concentration of the magnesium hydroxide solution we get:

[tex]M_{Mg(OH)_2}=\frac{3M_{H_3PO_4}V_{H_3PO_4}}{2V_{Mg(OH)_2}} \\\\M_{Mg(OH)_2}=\frac{3*0.20M*0.0300L}{2*0.050L}=0.18M[/tex]

Now, for the reaction between hydrochloric acid and magnesium hydroxide we have:

[tex]Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O[/tex]

[tex]2M_{Mg(OH)_2}V_{Mg(OH)_2}=M_{HCl}V_{HCl}[/tex]

Therefore, solving for the concentration of the hydrochloric acid solution we get:

[tex]M_{HCl}=\frac{2M_{Mg(OH)_2}V_{Mg(OH)_2}}{V_{HCl}} \\\\M_{HCl}=\frac{2*0.18M*0.078L}{0.025L}\\\\M_{HCl} = 1.12M[/tex]

Best regards!

A chemist has a block of copper metal (density is 8.96). They drop the metal into a graduated cylinder containing water, and find the volume change is 2.90 mL. What is the mass of the block , in grams?​

Answers

Answer:

26g

Explanation:

Given parameters:

Density  = 8.96g/cm³

Volume of metal = 2.9mL

    Since 1mL  = 1cm³;

          Volume  = 2.9cm³  

Unknown:

Mass of the blocks in grams  = ?

Solution:

Density is the mass  per unit volume of a substance;

   Mass  = density x volume  = 8.96 x 2.9  = 26g

How many moles of phosphoric acid would be needed to produce 15 grams of water?

Answers

Moles of phosphoric acid would be needed : 0.833

Further explanation

Given

15 grams of water

Required

moles of phosphoric acid

Solution

Reaction(decomposition) :

H3PO4 -> H2O + HPO3

mol water (H2O :

= mass : MW

= 15 g : 18 g/mol

= 0.833

From the equation, mol ratio H3PO4 = mol H2O = 1 : 1, so mol H3PO4 = 0.833

Ivy has a mixture salt and sand . She wants to separate the two substances by pouring the mixture into a jar of water . How could ivy speed up the separation of the two substance? Shake the jar , put the jar into the freezer, add a third substance such as soil to the jar , remove some of the water from the jar before adding the mixture

Answers

Answer:

Remove some water from the jar before adding the mixture.

Explanation:

She will speed it up when removing some water it will stay dry and not be sticky to separate the two ingredients

Answer: Remove a bit of water from the jar

Explanation:

4. Which employees should be aware of how to turn off power to a shop in an emergency?

Answers

Answer:

All employees should know how to work the system

1 Define Soft water and Hard water.​

Answers

Answer

software is a set of instruction given to a computer to perform specific function. MS office etc.

the tangible parts of a computer are known as hardware.

Explanation:

software pprforms the function while hardwares are the structural parts of a computer.

0.8 gram of divalent metal was dissolved in 100 CC of 1.28 N HCl and the solution was diluted to to 200 cc. then 50cc of this solution required 54.6 CC of 0.22N NaOH for the neutralization. find the atomic weight of metal .​

Answers

Answer:

80g/mol is the molar mass of the metal

Explanation:

A divalent metal M reacts with HCl as follows:

M + 2HCl → MCl₂ + H₂

The excess of HCl is titrated with NaOH. Thus, we can solve the moles of HCl that reacts with the metal and the moles of the metal. As the atomic weight is the ratio between the mass and moles of the atom:

Moles NaOH:

0.0546L * (0.22mol / L) = 0.0120 moles NaOH = Moles HCl in excess

For NaOH and HCl solutions, Normality is the same than molarity.

Moles HCl added:

0.100L * (1.28mol / L) = 0.128 moles HCl * (50mL / 200mL) = 0.032 moles

Moles HCl in that react:

0.032 moles - 0.012 moles = 0.020 moles HCl

Moles M:

0.020 moles HCl * (1mol M / 2 mol HCl) = 0.010 moles M

Molar mass M:

0.8g / 0.010mol =

80g/mol is the molar mass of the metal

A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, each containing 100 g of this liquid, would a 85 kg victim need to consume to reach a toxic level of ethylene glycol

Answers

Answer:

0.432 drinks are toxic

Explanation:

The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):

1.11g/mL * (0.1mL / kg) =  0.111g/kg

If the victim weighs 85kg, its letal dose is:

85kg * (0.111g/kg) = 9.435g of ethylene glycol

Using the concentration of ethylene glycol in the liquid:

9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.

The drinks are:

43.2g of liquid * (1 drink / 100 g) =

0.432 drinks are toxic

Uranus has a force of Gravity of 8.87 m/s^2. Sam has a MASS of 85 kg. What is his weight in Uranus? *

Answers

Answer:

Explanation:

Weight = mass x gravity

mass given = 85 kg

gravity = 8.87 m /s²

Weight = 85 x 8.87 = 753.95 N .

Weight on Uranus = 753.95 N .

2. The heat from an acetylene torch is produced by burning acetylene (C2H2) in oxygen.

2C2H2 + 502 --> 4CO2 + 2H20

When 2.40mol C2H2 reacts with 7.40mol O2,

a. Which reactant is the limiting reactant?

b. How many grams of water can be produced by the reaction?

c. How many moles of the excess reactant remains?



I NEED THIS ANSWER QUICKLY IF YOU CAN ONLY DO B THATS FINE THANK YOU

Answers

Answer: a. C₂H₂

              b. 43.2 g

              c. 1.4 moles

Explanation: In a chemical reaction, when a reagent is completely consumed and limits the product formed is called Limiting Reagent. The reactant that is left is the Excess Reactant.

For the burning of acetylene:

[tex]2C_{2}H_{2}+5O_{2} \rightarrow 4CO_{2}+2H_{2}O[/tex]

a. An easy way to determine which reactant is limiting, is to divide the number of moles of each reactant by the coefficient in the balanced reaction. The component that gives the smallest number is the limiting reagent.

The ratio for acetylene is

[tex]\frac{2.4}{2}[/tex] = 1.2

For oxygen:

[tex]\frac{7.4}{5}=[/tex] 1.48

So, the limiting reactant is acetylene.

b. From the balanced reaction, for each 2 moles of acetylene is consumed, 2 moles of water is produced. Then, for 2.4 moles, it will be produced 2.4 moles of water.

Mol is mass in grams divided by molar mass of the component.

[tex]n=\frac{m}{M}[/tex]

Molar mass of water is M = 18 g/mol.

Then, mass of water produced:

m = n.M

m = 2.4(18)

m = 43.2 g

With 2.4 moles of acetylene, it will be produced 43.2 grams of water.

c. For each 2 moles of acetylene consumed, 5 moles of oxygen is also consumed. So, for 2.4 moles:

2 moles = 5 moles

2.4 moles = n

[tex]n=\frac{2.4*5}{2}[/tex]

n = 6 moles

For 2.4 moles of acetylene, it is consumed 6 moles of oxygen. Then, the excess is

7.4 - 6 = 1.4

The excess reactant remaining is 1.4 moles of oxygen.

What determines the change of an ion formed by an atom

Answers

Answer:

Ions are formed when the number of protons in an atom does not equal the number of electrons. If more protons are present, the ion is positive and is known as a cation; if more electrons are present, the ion is negative and referred to as an anion. Ions are highly reactive species.

Explanation:

Answer:

An atom becomes charged when the number of protons does not equal the number of electrons. For example, if an element has six protons but only five electrons, the net charge of the element is +1. Conversely, if an element has six protons but seven electrons, then the net charge of the element is -1.

Explanation:

Which nitrogen bases always pairs with thymine?​

Answers

Answer:

The four different bases pair together in a way known as complementary pairing. Adenine always pairs with thymine, and cytosine always pairs with guanine.

Explanation:

identified the nucleus that is found in an item that has a stable valance electron configuration

Answers

Answer:

Nucleus 3 i believe

What is aspartame? EXPLAIN

Answers

Answer:

it's an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages. it's a methyl ester of the aspartic acid/phenylalanine dipeptide with the trade names NutraSweet, Equal, and Canderel

Explanation:

Answer:

Aspartame is some type of very sweet substance that is used as an artificial sweetener, and chiefly in low-calorie products. It is a derivative of aspartic acid and phenylalanine.

Explanation:

g Aqueous hydrobromic acid will react with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . Suppose 57.4 g of hydrobromic acid is mixed with 41. g of sodium hydroxide. Calculate the minimum mass of hydrobromic acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answers

Answer:

Zero

Explanation:

The complete reaction for this is as follows -

HBr + NaOH = NaBr + H2O

1 mole of NaOH reacts with 1 mole of HBr

m(HBr) = 57.4g and M(HBr) = 80.9g/mol

m(NaOH) = 16g and M(NaOH) = 40g/mol

Number of moles = m/M

Substituting the given values we get -

n(HBr) = 57.4 g/80.9 g/mol = 0.709

n(NaOH) = 16 g/40 g/mol = 0.4

n(H2O) = n(NaOH) = 0.40 mol

According to balanced equation

40 gram of NaOH reacts with 81 grams of HBr

41 gram of NaOH will react with 81/40 * 41 = 83.025 gram of HBr

We have only 57.4 g of HBr only hence, 0 HBr will be left.

LaKeisha is measuring the density of a solid piece of metal using the graduated cylinder method. She initially measures a volume of water in the cylinder to be 3.28 mL. After placing the metal into the graduated cylinder, the new volume was 8.72 mL. The mass of the metal was 42.26 g on a top loading balance.

Required:
What is the density of the metal calculated to the correct number of significant figures?

Answers

Answer: 7.77 g/ml

Explanation:

Volume of cylinder with only water = 3.28 mL

Volume of cylinder with water and metal = 8.72 mL

Volume of metal = (Volume of cylinder with water and metal ) -(Volume of cylinder with only water)

=8.72-3.28

=5.44 ml

Mass of metal = 42.26 g

Formula of Density =  [tex]\dfrac{\text{Mass}}{\text{Volume}}[/tex]

i.e. the density of the metal = [tex]\dfrac{42.26}{5.44}\approx7.77\text{ g/ml}[/tex]

Hence, the density of metal = 7.77 g/ml

helppp nowwww please!!!!

Answers

Answer:

The sun will appear to rise and set more slowly

have a nice day! (^o^)

The diagram below represents the organizational levels of living things.
organisms
organ systems
?
tissues
cells
Which of the following examples represents the missing organizational level?
A blood
B heart
C plasma
D vein

Answers

Answer: its vein

Explanation:

Answer: It’s blood

Explanation:

I did the quiz

Explain the differences between an ideal gas and a real gas.

Answers

Answer:

Ideal Gas

The ideal gas is extremely small and the mass is almost zero and no volume Ideal gas is also considered as a point mass.

Real Gas

The molecules of real gas occupy space though they are small particles and also have volume.

anation:

The differences between an ideal gas and a real gas are that the ideal gas follows the gas laws perfectly under all conditions. Whereas a real gas deviates from ideal gas behaviors.

The ideal gas law, also known as the general gas equation, is a fundamental principle in thermodynamics and relates the pressure, volume, temperature, and number of moles of an ideal gas.

An ideal gas is a theoretical gas that follows the gas laws perfectly under all conditions of temperature and pressure. It is assumed to have no volume, no intermolecular forces, and elastic collisions between its particles. An ideal gas also obeys the ideal gas law.

On the other hand, a real gas is a gas that does not follow the gas laws perfectly under all conditions of temperature and pressure. Real gases have volume and intermolecular forces that affect their behavior. These forces cause deviations from ideal gas behavior, especially at high pressures and low temperatures.

In summary, while an ideal gas is a theoretical gas that follows the gas laws perfectly under all conditions, a real gas is a gas that deviates from ideal gas behavior due to its volume, intermolecular forces, and non-elastic collisions between its particles.

Learn more about ideal gas law here:

https://brainly.com/question/33342075

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When H2(g) reacts with F2(g) to form HF(g) , 542 kJ of energy are evolved for each mole of H2(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term (including the units) in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.

Answers

Answer:

[tex]H_2+F_2\rightarrow 2HF+542 kJ[/tex]

Explanation:

Hello!

In this case, since exothermic reactions evolve or release energy when undergone, we infer that the energy is part of the products as it is a result of the reaction; thus, for the described reaction we should set it up as follows:

[tex]H_2+F_2\rightarrow 2HF+542 kJ[/tex]

However, if the reaction absorbs energy, the energy associated to the reaction is put at the reactants side, keeping in mind that it would be an endothermic reaction.

Best regards!

6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperature (23°C) and 3.00 atm pressure? b) How many grams of oxygen are needed? (Hint: Since moles have been asked, which equation has the moles listed in the equation. Use that to solve this problem. Also don’t forget to use the equation 1 mole = Formula weight or Molecular weight to calculate the grams of O2).

Answers

Answer:

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

Volume of the chamber (V): 200. LRoom temperature (T): 23 °CPressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

Which of the following statements does not describe the structure of an atom?

A) The electron cloud is a small and compacted space around the nucleus.
B) Inside the nucleus of an atom are protons and neutrons.
C) Protons are positively charged sub-atomic particles.
D) Electrons are negatively charged sub-atomic particles.

Answers

Which of the following statements does not describe the structure of an atom?

A) The electron cloud is a small and compacted space around the nucleus.

what is the formula for H-H

Answers

Answer:

H-H equation is written as follows:

pH=pK + log

{HCO3-}(base)

{H2CO3}(acid)

a A student decreases the temperature of a 484 cm ^ 3 balloon from 570 K to 285 Assuming constant pressure, what should the new volume of the balloon be? Round your answer to one decimal place.

Answers

Answer:

242 cm³.

Explanation:

The following data were obtained from the question:

Initial volume (V₁) = 484 cm³

Initial temperature (T₁) = 570 K

Final temperature (T₂) = 285 K

Pressure = constant

Final volume (V₂) =?

The new volume (i.e final volume) of the balloon can be obtained by using the Charles' law equation as illustrated below:

V₁/T₁ = V₂/T₂

484 / 570 = V₂ / 285

Cross

484 × 285 = 570 × V₂

137940 = 570 × V₂

Divide both side by 570

V₂ = 137940 / 570

V₂ = 242 cm³

Therefore, the new volume of the balloon is 242 cm³

The number of atoms in 10. grams of calcium is equal to 6.0 x 1023 multiplied by which number?

Answers

Answer:

1.51×10²³ atoms.

Explanation:

From the question given above, the following data were obtained:

Mass of Calcium (Ca = 10 g

Number of atom of Calcium (Ca) =?

The number of atoms present in 10 g of Ca be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This implies that 1 mole Ca contains 6.02×10²³ atoms.

1 mole of Ca = 40 g.

Now, if 40 g of Ca contains 6.02×10²³ atoms.

Therefore, 10 g of Ca will contain = (10 × 6.02×10²³) / 40 = 1.51×10²³ atoms.

Thus, 10 g of calcium contains 1.51×10²³ atoms.

ASAP I WILL GIVE BRAINLIEST The diagram shows a lever. What is the mechanical advantage of the lever? O 2 03 3 m 6 m mi 0 9​

Answers

Answer:

A) 2

Explanation:

Answer:

2, i got it right thanks to the other user :) <3

Explanation:

(will give brainliest!! please help me! thank you!)

a) The rows on the periodic table are called periods. How many energy levels are in the atoms of each element in period 2 (lithium-neon)

b) What is the group number of the halogens?

c) What do the elements in each group have in common?


please please help me, i will give brainliest

Answers

Answer:

A two energy levels K and L

B halogen are present in group 17

C in same group elements have same valence electrons

Explanation:

2.Your culture media recipe says you need to add 2.625g of Sodium Bicarbonate per liter of media. You realize you only have a 7.5% solution of Sodium Bicarbonate you can use. What volume of that solution can you add, while making your media, to have the necessary mass of NaHCO3

Answers

Answer:

35mL of the 7.5% solution are required to meake the media

Explanation:

To prepare the culture media there are required 2.625g of sodium bicarbonate. We have a 7.5% solution of sodium bicarbonate (That is, 7.5g of sodium bicarbonate in 100mL of solution). Thus, to obtain 2.625g we need:

2.625g Sodium bicarbonate * (100mL / 7.5g) =

35mL of the 7.5% solution are required to meake the media

Riboflavin is one of the B vitamins It is also known as B6 and is made up of carbon, hydrogen, nitrogen and oxygen atoms. When 10.0 g of vitamin B6 is burned in oxygen, 19.88 g of CO2 and 4.79 g of H2O are obtained. Another experiment shows that vitamin B6 is made up of 14.89% of N. What is the simplest formula for vitamin B6

Answers

Answer:

C₁₇H₂₀N₄O₆

Explanation:

First, we need to determine the percentage of the atoms in the molecule. Then, assuming a basis of 100 we must convert the mass of each atom to moles. Simplest formula is the simplest ratio of atoms presents in the molecule:

%C:

19.88g CO2 * (12.01g/mol C / 44.01g/mol CO2) = 5.425g C

5.425g C / 10.0g * 100 = 54.25% C

%H:

4.79g H2O * (2*1.01g/mol / 18.015g/mol) = 0.537g H

0.537g H / 10.0g * 100 = 5.37%

%N:

14.89%

%O:

100 - 14.89% - 54.25% - 5.37% = 25.49%

Moles of each atom in a basis of 100g:

C: 54.25g * (1mol / 12.01g) = 4.517moles

H: 5.37g * (1mol / 1.01g) = 5.317 moles

N: 14.89g * (1mol / 14.01g) = 1.063 moles

O: 25.49g * (1mol / 16g) = 1.593 moles

Dividing each amount of moles in the lower number of moles (moles N):

C = 4.517mol / 1.063mol = 4.25

H = 5.317mol / 1.063mol = 5

N = 1.063mol / 1.063mol = 1

O = 1.593mol / 1.063mol = 1.5

This ratio multiplied 4 times to obtain whole-numbers:

C = 4.25*4 = 17

H = 5*4 = 20

N = 1*4 = 4

O = 1.5*4 = 6

The simplest formula for vitamin B6 is:

C₁₇H₂₀N₄O₆

Joaquin tells his science class that galaxies consist of gas, dust, and many planets. What is the most important component of galaxios Joaquin is missing in his description?
astero de
comets
constellations
Stars

Answers

Answer:

the answer is asteroids!

Explanation:

Answer:

astroid

Explanation:

becaus

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