Answer:
A, D and E
Step-by-step explanation:
If you convert them all to decimals, they will be:
A= 0.75
B= 0.45
C= 0.3333...
D= 0.62
E= 0.59
F=0.315
1/2= 0.5
So any number larger than 0.5 is correct, and this will be (answer above).
Please answer this....
Answer:
c) [tex]2\frac{23}{30}[/tex] d)[tex]1\frac{23}{24}[/tex]
7) a. [tex]6\frac{3}{11}[/tex] kg b. [tex]6 \frac{2}{3}[/tex] cm c. 20 cm
d. [tex]9\frac{9}{10}[/tex] kg e. 10 g f. [tex]23 \frac{1}{4}[/tex] kg
Step-by-step explanation:
c) [tex]8\frac{2}{3}[/tex] - [tex]5\frac{9}{10}[/tex]
First we will change to improper fraction and then solve
[tex]\frac{26}{3} - \frac{59}{10}[/tex]
= [tex]\frac{260 - 177}{30}[/tex]
= [tex]\frac{83}{30}[/tex]
we will now change to mixed number
= [tex]2\frac{23}{30}[/tex]
d) [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]
we will first change it to improper fraction and then solve
= [tex]\frac{65}{8} - \frac{37}{6}[/tex]
= [tex]\frac{390 - 296}{48}[/tex]
= [tex]\frac{94}{48}[/tex]
we can reduce the fraction
=[tex]\frac{47}{24}[/tex]
we will change it mixed number
=[tex]1\frac{23}{24}[/tex]
7)
a. [tex]\frac{3}{11}[/tex] of 23
= [tex]\frac{3}{11}[/tex] × 23
= [tex]\frac{69}{11}[/tex]
=[tex]6\frac{3}{11}[/tex] kg
b. [tex]\frac{2}{3}[/tex] of 10 cm
= [tex]\frac{2}{3}[/tex] × 10 cm
= [tex]\frac{20}{3}[/tex] cm
=[tex]6 \frac{2}{3}[/tex] cm
c. [tex]\frac{5}{6}[/tex] of 24cm
= [tex]\frac{5}{6}[/tex] × 24 cm
6 will divide 24
=5 × 4 cm
= 20 cm
d. [tex]\frac{3}{10}[/tex] of 33 kg
= [tex]\frac{3}{10}[/tex] × 33 kg
=[tex]\frac{99}{10}[/tex] kg
=[tex]9\frac{9}{10}[/tex] kg
e. [tex]\frac{2}{7}[/tex] of 35 g
= [tex]\frac{2}{7}[/tex] × 35 g
7 will go into 35
=2×5 g
=10 g
f. [tex]\frac{3}{4}[/tex] of 31 kg
= [tex]\frac{3}{4}[/tex] × 31 kg
=[tex]\frac{93}{4}[/tex] kg
=[tex]23 \frac{1}{4}[/tex] kg
Which of the following is the correct factored form of the given equation? 6x^2 -13x - 8 = 0
Answer:
the 2nd
Step-by-step explanation:
Find the total surface area of this cylinder. Give your answer to one decimal place PLEASE HELP THANK YOUUUU
Answer:
Step-by-step explanation:
surface area of cylinder=2 πr²+2πrh
=2πr(r+h)
=2π×12(12+18)
=24π×30
=720π
≈2261.9 cm²
What number : Decreased by 95% is 81 ?
Answer:
1620
Step-by-step explanation:
If a number decreased by 95% is 81, then
5% is 81.
So, the number = 100/5 x 81= 20 x 81 = 1620
Hope this helps
Answer:
the answer is 1620
Step-by-step explanation:
What is the 5th equivalent fraction to 1/11 ?
Answer: 5/55
Step-by-step explanation:
1/11 x 5 = 5/55
So, the fifth equivalent fraction to 1/11 is 5/55.
The 5th equivalent fraction should be [tex]5\div 55[/tex]
Calculation of the equivalent fraction:Since the fraction is [tex]1\div 11[/tex]
So here the 5th equivalent should be
[tex]= 1\div 11 \times 5\div 5[/tex]
= [tex]5\div 55[/tex]
Here 5 represent the numerator and 55 represent the denominator.
Therefore, we can concluded that The 5th equivalent fraction should be [tex]5\div 55[/tex]
Learn more about fraction here: https://brainly.com/question/1786648
There is a bag filled with 5 blue, 6 red and 2 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting 2 blues?
Answer:
Step-by-step explanation:
Total marbles = 5 + 6 + 2 = 13
P( getting blue ball from first draw) = 5/13
The marble is not replaced. So, Now total marbles will be 12 & number blue marbles will be 4
P( getting blue ball from second draw) = 4/12 = 1/3
P(getting two blues) = [tex]\frac{5}{13}*\frac{1}{3}\\[/tex]
= 5/39
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
questions.
Online Content: Site 1
Suggest changing to "On the graph of an exponential function representing growth, what happens to the slope of the graph as x
increases?"
Answer:
The slope also increases
Step-by-step explanation:
The slope of a function is the ratio of change in y to change in x. For an exponential function f(x) = e^x, the slope of the function is equal to the function, i.e slope = e^x.
For a function represented by [tex]y=2^x[/tex], this is an exponential function representing growth, the slope of [tex]y=2^x[/tex] is also [tex]2^x[/tex], therefore as the value of x increases, the value of the slope also increases.
At x = 1, slope = 2^1 = 2, At x = 4, slope = 2^4 = 16.
Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1, 0) and (1, 2), line b has a negative slope and goes through (negative 2, 2) and (negative 1, negative 1), line c has a negative slope and goes through (0, 3) and (1, 0), and line d is horizontal at y = 1. By inspection, which system would have no solution? line a and line b line a and line c line b and line c line b and line d
Answer:
C) line b and line c
Step-by-step explanation:
On edge
A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The system of equations that do not have any solution is line b and line c. Hence, the correct option is C.
What is the equation of a line?A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is the y-intercept.
The equation of line a passing through (-1,0) and (1,2) are,
m = (0-2)/(-1-1) = -2/-2 = 1
y= x + c
0 = -1 + c
c = 1
Equation of line 1, y=x+1
The equation of line b passing through (-2,2) and (-1,-1) are,
m = (2+1)/(-2+1) = 3/-1 = -3
y= -3x + c
-1 = -3(-1) + c
c = -4
Equation of line 1, y=-3x-4
The equation of line c passing through (0,3) and (1,0) are,
m = (3-0)/(0-1) = 3/-1 = -3
y= -3x + c
3 = -3(0) + c
c = 3
Equation of line 1, y=-3x+3
Also, the equation of line d is y=1
The solution of two-equation is the point at which the two equations are not intersecting. Therefore, the system of equations that do not have any solution is line b and line c.
Hence, the correct option is C.
Learn more about Equation of Line:
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WILL GIVE BRAINLEST ANSWER IF DONE IN 24 HRS Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 40° and 170°, respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer. (pls show work)
Answer:
114.96 pounds at angle 81.76°
Step-by-step explanation:
Let i be the component along x-axis and j be the component along y-axis.
First force that is given is 150 acting at angle 40; [tex]F1 = 150cos170i + 150sin40j = 114.91i +96.42j[/tex]
The second force 100 is acting at angle 170;
[tex]F2 = 100cos170i + 100sin170j = -98.48i + 17.36j[/tex]
We now have the resultant force, which is: [tex]114.91i + 96.42j + (-98.48i + 17.36j) = 16.43i + 113.78j[/tex]
Magnitude of resultant:
[tex]\sqrt{16.43^{2} + 113.78^{2} }[/tex] = 114.96 pounds
Angle it makes with horizontal; inverse tangent of [tex]\frac{(113.78)}{(16.43)}[/tex] = 81.76 degrees
Hope this helps; Brainliest appreciated!
What is the slope of a line perpendicular to the line whose equation is
x - 5y = -10. Fully reduce your answer
Answer:
The slope or incline is -5
Step-by-step explanation:
rewrite to get the form
y = ...
x - 5y = -10
- 5y = -10 -x
divide left and right if the = sign by -5 gives:
(-5/-5)y = (-1/-5)x + (-10/-5)
y = 1/5x +2
So the incline is 1/5
a perpendicular line has an incline of -1 *5/1 = -5
The slope or incline is -5
What is the solution to……………………ASAP
Answer:
first option
Step-by-step explanation:
Using the rules of logarithms
log x - log y = log ([tex]\frac{x}{y}[/tex] )
log[tex]x^{n}[/tex] ⇔ n log x
ln e = 1
Given
4 + 5[tex]e^{x+2}[/tex] = 11 ( subtract 4 from both sides )
5[tex]e^{x+2}[/tex] = 7 ( divide both sides by 5 )
[tex]e^{x+2}[/tex] = [tex]\frac{7}{5}[/tex] ( take ln of both sides )
ln [tex]e^{x+2}[/tex] = ln ([tex]\frac{7}{5}[/tex] )
(x + 2) lne = ln ([tex]\frac{7}{5}[/tex] )
x + 2 = ln ([tex]\frac{7}{5}[/tex] ) ( subtract 2 from both sides )
x = ln([tex]\frac{7}{5}[/tex] ) - 2
Employee B got a one time $90 bonus. He got
paid $330 this week. He worked 24 hours this
week. How much did he make per hour this
week before his bonus?
Answer:
$10 an hour
Step-by-step explanation:
Subtract the bonus to get the pay.
330-90=240
Divide 240 by 24 hours to get his rate of pay.
240/24=10
He gets $10 an hour.
Answer:
Step-by-step explanation:
Subtract 90 dollars from 330. 330-90=240.
The man earned 240 dollars that wee and worked 24 hours.
240/24=10
Line A has an x-intercept of -4 and a y-intercept of 8. What is its slope?
Answer:
Step-by-step explanation:
We can use the intercept form of the equation of a line, then solve for y.
Intercept form
x/(x-intercept) +y/(y-intercept) = 1
x/-4 +y/8 = 1
__
Solving for y, we have ...
-2x +y = 8 . . . . multiply by 8
y = 2x +8 . . . . add 2x
The coefficient of x is 2, so the slope is 2.
__
The graph shows you the rise is 8 for a run of 4, so ...
slope = rise/run = 8/4
slope = 2
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0
(x − 6)2 + (y − 4)2 = 56
x2 + y2 + 6x − 8y − 10 = 0
(x − 2)2 + (y + 6)2 = 60
3x2 + 3y2 + 12x + 18y − 15 = 0
(x + 2)2 + (y + 3)2 = 18
5x2 + 5y2 − 10x + 20y − 30 = 0
(x + 1)2 + (y − 6)2 = 46
2x2 + 2y2 − 24x − 16y − 8 = 0
x2 + y2 + 2x − 12y − 9 = 0
Answer:
1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]
2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]
3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex], the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex], the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex], the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
6) For[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]
Step-by-step explanation:
This can be done using the completing the square method.
The standard equation of a circle is given by [tex](x - a)^2 + (y-b)^2 = r^2[/tex]
1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex]
[tex]x^2 - 4x + y^2 + 12y = 20\\x^2 - 4x + 2^2 + y^2 + 12y + 6^2 = 20 + 4 + 36\\(x-2)^2 + (y+6)^2 = 60\\[/tex]
Therefore, for [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]
2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex]
[tex]x^2 + 6x + y^2 - 8y = 10\\x^2 + 6x + 3^2 + y^2 - 8y + 4^2 = 10 + 9 + 16\\(x + 3)^2 + (y- 4)^2 = 35\\[/tex]
Therefore, for [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]
3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex]
Divide through by 3
[tex]x^2 + y^2 + 4x + 6y = 5[/tex]
[tex]x^2 + y^2 + 4x + 6y = 5\\x^2 + 4x + 2^2 + y^2 + 6y + 3^2 = 5 + 4 + 9\\(x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
Therefore, for [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex], the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]
4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex]
Divide through by 5
[tex]x^2 + y^2 - 2x + 4y = 6[/tex]
[tex]x^2 + y^2 -2x + 4y = 6\\x^2 - 2x + 1^2 + y^2 + 4y + 2^2 = 6 + 1 + 4\\(x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
Therefore, for [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex], the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]
5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex]
Divide through by 2
[tex]x^2 + y^2 - 12x - 8y = 4[/tex]
[tex]x^2 + y^2 - 12x - 8y = 4\\x^2 - 12x + 6^2 + y^2 - 8y + 4^2 = 4 + 36 + 16\\(x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
Therefore, for [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex], the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]
6) For [tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex]
[tex]x^2 + 2x + y^2 - 12y = 9\\x^2 + 2x + 1^2 + y^2 - 12y + 6^2 = 9 + 1 + 36\\(x+1)^2 + (y-6)^2 = 46\\[/tex]
Therefore, for[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]
For Plato / Edmentum
Just to the test and got it right ✅
If there are 60 students in a classroom, given that 15 are boys. find percentage of girls in the classroom.
Answer:
75 %
Step-by-step explanation:
Total = 60
Boys = 15
Girls = 60-15
=> 45 girls
Percentage of Girls:
=> [tex]\frac{45}{60} * 100[/tex]
=> [tex]\frac{450}{6}[/tex]
=> 75 %
Answer:
75%
Step-by-step explanation:
There are 60 students in the classroom.
15 are boys.
Find the number of girls:
(total no. of students) - (no. of boys) = (no. of girls)
60 - 15
= 45
There are 45 girls in the classroom.
Find the percentage of girls in the classroom:
(no. of girls)/(total no. of students) × 100
45/60 × 100
9/12 × 100
900/12 = 75
The percentage of girls in the classroom is 75%.
EXCELLENT VOTE!! (only if u give the CORRECT answer)
Answer:
Option C
Step-by-step explanation:
Answer:
B.
You need to subtract 1 term because you don't include the starting 5
4^10 - 1 = 4^9
You multiply 5 by 4 each time for 9 times so it is 5 x 4^9
Hope this helps
Step-by-step explanation:
Can someone please help me I really need help please help me
Answer:
1080
Step-by-step explanation:
does anyone know the answer!!
Answer:
95
Step-by-step explanation:
n is 360-121-144 since all the sums of the exterior angles add up to 360 and so 360-121-144=95 so our answer is 95
13,600 – 500x = 16,000 - 800x
Answer:
x=8
Step-by-step explanation:
13,600 – 500x = 16,000 - 800x
Add 800x to each side
13,600 – 500x+800x = 16,000 - 800x+800x
13600 +300x = 16000
Subtract 13600 from each side
13600 -13600+300x = 16000-13600
300x =2400
Divide each side by 300
300x/3 00 = 2400/300
x = 8
Answer
x = 8
Step-by-step explanation:
y= 13,600 -500x = 16000-800x
13,600-500x = 16000-800x
+800 +800
13,600 +300x = 16,000
-13,600 -13,600
_300x___ = _24,00___
300 300
x = 8
how many millimeters are in a meter
Answer:
There are 1000 millimeters in a meter.
Step-by-step explanation:
I really hope this helps in any way.
Answer:
1,000
Step-by-step explanation:
The word millimeter has the prefix of 'milli-'.
'Milli-' means a thousand.
Applying the prefix meaning to the word, a millimeter would be a thousandth of a meter.
There are 1,000 millimeters in a meter.
Brainilest Appreciated.
A winter recreational rental company is fencing in a new storage area. They have two options. They can set it up at the back corner of the property and fence it in on four sides. Or, they can attach it to the back of their building and fence it in on three sides. The rental company has decided that the storage area needs to be 100 m2 if it is in the back corner or 98 m2 if it is attached to the back of the building. Determine the optimal design for each situation.
Answer:
Rectangular area attached to the back of the building
two sides of legth 7 m and one side of 14 m
Step-by-step explanation:
We need to compare quantity of fencing material to be used in both cases
1.Option
A = 100 m² dimensions of storage area "x" and "y"
x*y = 100 y = 100/x
The perimeter of the storage area is
p = 2*x + 2*y ⇒ p = 2*x + 2*100/x
p(x) = 2*x + 200/x
Taking drivatives on both sides of the equation
p´(x) = 2 - 200/x²
p´(x) = 0 ⇒ 2 - 200/x² = 0
2*x² - 200 = 0 x² = 100
x = 10 m
and y = 100/10
y = 10 m
Required fencing material in first option
2*10 + 2*10 = 40 m
2.-Option
Following the same procedure
A = 98 m² y = A/x y = 98/x
p = 2*x + y p(x) = 2*x + 98/x
p´(x) = 2 - 98/x² p ´(x) = 0
2 - 98/x² = 0
2*x² = 98 x² = 49
x = 7 m and y = 98/ 7 y = 14 m
Total quantity of fencing material
p = 2* 7 + 14 p = 28
Therefore option 2 is more convinient from economic point of view
Optimal design rectangular storage area with two sides of 7 m and one side of 14 m
A car is traveling at x feet per second. The driver sees a red light ahead, and
after 1,5 seconds reaction time, the driver applies the brake. After the brake is
applied, the car takes seconds to stop, during which time the average speed
24
of the car is feet per second. If the car travels 165 feet from the time the
driver saw the red light to the time it comes to a complete stop, which of the
following equations can be used to find the value of x?
A) x2 + 48x - 3,960 = 0
B) x2 + 48x - 7,920 = 0
C) x2 + 72x - 3,960 = 0
D) x2 + 72x - 7,920 = 0
Answer:
The correct option is;
D) x² + 72·x - 7920 = 0
Step-by-step explanation:
The time it takes the car to stop = x/24 seconds
the average speed during stopping = x/2 feet per second
Given that the car was initially travelling at x feet per second and it takes the car 165 feet to stop after the driver takes 1.5 seconds at the initial speed x before the break is applied, we have;
Total distance traveled = (x/24)×(x/2) + x×1.5 = 165
= x²/48 + 1.5·x = 165
Multiply through by 48, we have;
x² + 72·x = 7920
Which gives the equation as follows;
x² + 72·x - 7920 = 0.
Please answer it in two minutes
Answer:
2,700 degrees.
Step-by-step explanation:
17 gon is a heptadecagon.
The formula for the sum of interior angles is [tex](n-2)*180[/tex] degrees.
[tex](17-2)*180=\\15*180=\\2700[/tex]
Avalanche conditions: Winter avalanches occur for many reasons, one being the slope of the mountain. Avalanches seem to occur most often for slopes between 35° and 60° (snow gradually slides off steeper slopes). The slopes at a local ski resort have an average rise of 2000 ft for each horizontal run of 2559 ft. Is this resort prone to avalanches? Find the angle θ and respond. 2000 ft 2559 ft
Answer:
Yes, since angle θ = 38° and is between 35° and 60°, this slope is prone to avalanches.
Step-by-step explanation:
Avalanche conditions: Winter avalanches occur for many reasons, one being the slope of the mountain. Avalanches seem to occur most often for slopes between (snow gradually slides off steeper slopes). The slopes at a local ski resort have an average rise of 2000 ft for each horizontal run of 2559 ft. Is this resort prone to avalanches? Find the angle θ and respond. 2000 ft 2559 ft
Draw a right triangle. Start with a horizontal side and label the horizontal side 2559 ft. Then at one endpoint of that side, draw a vertical side going up from the horizontal side. Label it 2000 ft. Connect the upper point of the vertical side to the other endpoint of the triangle. The acute angle at the bottom is θ.
[tex] \tan \theta = \dfrac{opp}{adj} [/tex]
[tex] \tan \theta = \dfrac{2000}{2559} [/tex]
[tex] \theta = \tan^{-1} 0.7816 [/tex]
[tex] \theta = 38^\circ [/tex]
Since the angle is between 35° and 60°, this slope is prone to avalanches.
Solve x^2 + 6x - 5 = 0 by completing the square.
Answer:
(x + 3)² = 14
Step-by-step explanation:
x² + 6x - 5 = 0
Add 5 and 9 on both sides.
x² + 6x + 9 = 14
Factor left side.
(x + 3)² = 14
Take the square root on both sides.
(x + 3) = ±√14
Subtract 3 on both sides.
x = -3 ±√14
Write equation Derek will get a bonus if he sells at least 50 sets of knives in a month use k to represent the number of knives he can sell to receive his bonus
Answer: k ≥ 50
Step-by-step explanation:
From the question, we are informed that Derek will get a bonus if he sells at least 50 sets of knives in a month. We are further told to us k to represent the number of knives he can sell to receive his bonus.
Since we are told that Derek will get a bonus if he sells at least 50 sets of knives in a month, this means that k will be greater than or equal to 50. Therefore,
k ≥ 50
x is partly constant and partly varies with y. When y=3, x = 7 and when y = 6, x = 9. Find x when y = 4
Answer:
x=23/3
Step-by-step explanation:
x=c+ay
7=c+3a | *(-1)
9=c+6a
-7=-c-3a
9=c+6a
------------
9-7=c-c+6a-3a
2=3a
a=2/3
7=c+3*2/3
7=c+2
-2 -2
5=c
so x=5+2/3*y
when y=4 then x=5+2/3*4=5+8/3
x=15/3+8/3
x=23/3
Pls ppl answer dis question PLS PLS PLS No scaming pls
4√3 x^2+5x-2√3
Answer:
\the zeroes are (2√3)/ 3, (√3)/4,
or -1.15, 0.43 to the nearest hundredth.
Step-by-step explanation:
I am assuming you want to find the zeroes of this function:
4√3 x^2+5x-2√3 = 0
Using the quadratic formula:
x = [ -5 +/- √((5)^2 - 4 * 4√3 * -2√3) ] / (2 * 4√3 )
= ( - 5 +/- √(25 - (-32*3)) / 8√3
= (-5 +/- √ 121) / 8√3
= (-5 - 11) / 8√3 or (-5 + 11) / 8√3
= -16/8√3 or 6/8√3
= -16√3/ 24 or 6√3 / 24
= -2√3/ 3 or √3/4.
Line segment C X is an altitude in triangle ABC. Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn from point C to point X on side A B to form a right angle. Which statements are true? Select two options. ΔABC Is-congruent-to ΔBXC ΔAXC ~ ΔCXB ΔBCX Is-congruent-to ΔACX ΔACB ~ ΔAXC ΔCXA Is-congruent-to ΔCBA
Answer:
ΔAXC ~ ΔCXB
ΔACB ~ ΔAXC
Step-by-step explanation:
B and D are correct
Congruent triangles have equal corresponding sides.
The true statements are: ΔAXC ~ ΔCXB ; and ΔACB ~ ΔAXC
From the figure (see attachment), we have the following highlights
Triangles AXC and CXB are similar by SASTriangles ACB and AXC are also similar by SASThis means that we have the following similarities statements:
ΔAXC ~ ΔCXB ; and ΔACB ~ ΔAXC
Hence, the true options are: (b) and (d)
Read more about congruent triangles at:
https://brainly.com/question/3807969
( brainliest to the correct answer) worth 13 points
Can someone solve this for me I need to finish this assignment today (:
Thank youuuuu
Answer:
8.66 billion?
explanation: 7.1+1.1% X 20=8.662