Which scale factor was used to create triangle SRT?

Hope you liked that.

Answer and Step-by-step explanation:

Solution:

Range:

Let f(x) = -x-1

                        Here a=0 and b= -1, x=-b/a

Put the values, we get

       X= - (-1)/0 = infinity

Hence the range of the function f(x) = (-∞, ∞)

Injective:

A function is said to be injective if f(x1) = f(x2), gives x1=x2

Let f(x1) = -x1-1

 f(x2) = -x2-1

 f(x1) = f(x2)

Answer:

h=5

Step-by-step explanation:

Answer: Covert the mixed number to an improper fraction for them to be too simple fractions and multiply them.

Step-by-step explanation:

By multiply fraction  by a mixed fraction you will have to rewrite the mixed number as an improper fraction.

For example ,

1  1/2  is a mixed fraction. If you convert it to improper fraction, you will get 3/2 then you multiply.

Answer:C

Step-by-step explanation:

Answer:

Horizontal compression

Step-by-step explanation:

Just took a test

Answer: horizontal compression

Step-by-step explanation:

Edge

Answer:

272

Step-by-step explanation:

Do you need this?

Answer:

272

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

Using binomial probability:

p = probability of a rural student getting admission = 1/2

q = probability of a rural student not getting admission = 1/2

n = number of students = 100

P(x) = [tex]C(n,x) p^xq^{(n-x)[/tex]

But [tex]p^xq^{n-x}=\frac{1}{2}^x\frac{1}{2}^{n-x}=\frac{1}{2}^{n}[/tex]

P(x > 50) = P(x = 51) + P(x = 52) + P(x = 53) + . . . + P(x = 100)

P(x > 50) = [tex]\frac{1}{2} ^{100}[C(100,51)+C(100,52)+C(100,53)+\ .\ .\ .+C(100,100)]\\[/tex]

[tex]P(x>50)=\frac{1}{2}^{100} (\frac{1}{2}( 2^{100}-C(100,50)))\\\\P(x>50)=(\frac{1}{2}^{100} *\frac{1}{2}*2^{100})- (\frac{1}{2}^{100} *\frac{1}{2}*C(100,50))\\\\P(x>50)=\frac{1}{2}[(2^{-100}*2^{100})-(\frac{1}{2}^{100} *C(100,50))]\\ \\P(x>50)=\frac{1}{2}[1-\frac{1}{2}^{100} *C(100,50)][/tex]

Answer:

3 and 4

Step-by-step explanation:

Look at the factors of 12 and list them out

1 and 12

2 and 6

3 and 4

Find the 2 numbers that are consecutive

3 and 4

Answer:

its B, C and E

Step-by-step explanation:

on edge

Answer:

2a + 3p = 18

Step-by-step explanation:

The total has to equal 18 so then you have $2 and $3. Apples cost $2 so the 2 should have an a for Apples. The peppers cost $3 so the 3 should have a p for peppers. So the equation would be 2a + 3p = 18.

Answer:

Step-by-step explanation:

i think yes

The absolute value of 3.4 = 3.4

The absolute value of something is always positive.

The answer is A

Answer: A. 3.4

Step-by-step explanation:

Concept:

Absolute value is the distance from a number to zero. Distance is always positive, so absolute value of any number is positive. Absolute value is often written as ( |x| ).

Solve:

Answer: 144π or 452.389342117

Step-by-step explanation:

24= circumference

c=dπ

c=24π

24/2=12

12=radius

12^2π=area

144π=area

Answer:

a==3.3  a=-3 1/3  a=-10/3

all of those are different possible answers

Step-by-step explanation:

Answer:

What's the question???

Answer:

Cool can you give me brainliest

Step-by-step explanation:

Answer:

$8

Step-by-step explanation:

In debt at $20 (like an overdraft) = -20

To make a $10 purchase = -10 on the account

Total debt = -20 + (-10)

                 = -30

You deposit $38 (this is what you added to your account.) = +38

Balance of the checking = -30 + (+38)

                                         = $8

I really hope this helps. If I am right, please thank, rate 5 stars, and give brainliest. Thank you.

Answer:

the order of operations tells us how to solve a problem.

first is P for parentheses. this means you solve all the expressions within the parentheses. this ensures a simplified expression before moving on.

second is E for exponents. this means you solve all the expressions with exponents. by doing this before MDAS, you do not raise the wrong values.

third and fourth is M/D for multiplication/division. the / is between these two because these steps are interchangeable. you can multiply or divide first. the results will be the same.

this also applies to the fifth and sixth, which are A/S for addition/subtraction.

Given :

The weight of an object on a particular scale is 125.2 lbs.

The actual weight by at most 0.4 lbs.

To Find :

The range of actual  weights of the object.

Solution :

It is given that uncertainty in weight is 0.4 lbs.

So, minimum weight can be( 125.2 -0.4 ) = 124.8 lbs.

Maximum weight is given by  ( 125.2 + 0.4 ) = 125.6 lbs.

Therefore, the range of actual  weights of the object is between :

124.8  x 125.6 .

Hence, this is the required solution.

Answer:

x = 6, y = 8

Step-by-step explanation:

First, we need to find the scale factor from the smaller polygon to the larger polygon. To do this, we can calculate 18 / 12 which is 1.5. Therefore, we can write the following equations:

x · 1.5 = 9 → x = 6

y · 1.5 = 12 → y = 8

Answer:

7×2=14 (for the long side)5×2=10 (for the short sides) the you add up the two answers 14+10=24

Answer:

2.6

Step-by-step explanation:

First you subtract and get 40 and then you add the 12 which gets 52 and then you divide it by 20 and get your 2.6

Answer:

Step-by-step explanation:

40.6 hope it helps

(6 - 2) - 1 = 4 - 1 = 3

6 - (2 - 1) = 6 - 1 = 5

The associative rule doesn't work for subtraction because you get different results when you move the parentheses.

33 in corresponds with the 11 in side

33 in / 11 in = 3

The scale factor is 3

24 in / 3 = 8 in

x = 8 in

Answer:

Step-by-step explanation:

In similar triangles, corresponding sides will be in same ratio.

[tex]\frac{33}{11}=\frac{24}{x}[/tex]

Cross multiply,

33*x = 24 * 11

[tex]x=\frac{24 *11}{33}\\\\x=\frac{24*1}{3}\\\\x = 8 in[/tex]

Answer: D because it would mess with your feelings

I would put the answer as D.

Answer:

10 pages

Step-by-step explanation:

1 and 1/3 pages multiplies by 7.5 brings us to the answer of ten pages

20 minutes goes into 2 and 1/2 hours 7.5 times

10 pages i did this on edge

2020 hope this helps

your welcome =)

Complete Question

Find a particular solution to [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]  

[tex]y_1 = 1 + t , \ y_2 = e^t[/tex]

Answer:

The solution is    [tex]y_p = -e^{2t} + t + \frac{3t^2}{2} + \frac{t^3}{2}[/tex]

Step-by-step explanation:

  Now the given equation is [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]

             dividing through by  t

       We have  

         [tex]y'' - \frac{1 + t }{t}y' + \frac{1}{t} y = te^t \\\\ let's\ call\ it \ g(t)[/tex]

Now for the given initial value we can generate our Wronskian as follows

        [tex]W(y_1 ,y_2) = | \left y_1} \atop {y_1'}} \right. \left y_2} \atop {y_2'}} \right | = | \left {(1 + t)} \atop {1}} \right. \left e^t} \atop {e^t}} \right | = (1 + t )e^t - e^t = te^t[/tex]

Now applying  method of variation of parameters to obtain the particular solution

So here we assume that

          [tex]y_p = v_1 y_1 + v_2 y_2[/tex]

So

       [tex]v_1 = - \int\limits {\frac{y_2 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{e^t te^t}{te^t} } = - \int\limits { e^t} } = -e^t[/tex]

And

    [tex]v_2 = - \int\limits {\frac{y_1 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{(1 + t) te^t}{te^t} } = - \int\limits (1 + t) = t + \frac{t^2}{2}[/tex]

So

     [tex]y_p = -e^t * e^t + t + \frac{t^2}{2} * 1 + t[/tex]

     [tex]y_p  =  -e^{2t}   +  t +   \frac{3t^2}{2} + \frac{t^3}{2}[/tex]