A 2[kg] rock and a 4[kg] rock are lifted to a height of 10[m].
How much PE does each rock have?
Answer:
See below
Explanation:
Potential Energy = mgh
for 2 rock = 2 * 9.81 * 10 = 196.2 j
for 4 rock = 4 * 9.81 * 10 = 392.4 j
A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some solar panels on the roof of a building. Which form of energy to collected by the solar panels?
A. Wind
B. sound
C. Magnetic
D. Light
A dropped ball gains speed because
its nature is to become closer to Earth,
its velocity changes.
a gravitational force acts on it
Of inertia
Answer:
3 and 3 and 3
Explanation:
I am sure Hope for brain list
How much time does it take a dropped object to fall 180 m on Earth?
18 s
36 S
10 s
6s
Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:
[tex]s=ut+\frac{1}{2} at^2[/tex]
180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s
A particle moves along the x-axis according to the equation (x=14-7t+t^2+t^3 ), where (x) in meter and (t) in seconds. At (t=7 sec) Find (a) The position of the particle (b) It’s velocity (c) It’s acceleration
Answer:
jjnn ok jjjmkkmmkijnnkko
An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.
Answer:
q = 1.84×10^-8coulombs
Explanation:
Surface area = 4πr²
r is the distance
1.2 = 4(3.14)r²
1.2 = 12.56r²
r² = 1.2/12.56
r² = 0.0956
r = √0.0956
r = 0.309m
Get the charge C
V = kq/r
536 = 9.0×10^9q/0.309
536×0.309 = 9×10^9q
165.73 = 9×10^9q.
q = 165.73/9×10^9
q = 1.84×10^-8coulombs
Integrate your expressions for dEx and dEy from θ=0 to θ=π. The results will be the x-component and y-component of the electric field at P
.
Express your answers separated by a comma in terms of some, all, or none of the variables Q
and a and the constants k and π.
Answer:
hello your question is incomplete below is the missing part
Ex = 0
Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]
Explanation:
Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π
Ex = 0
Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]
What is the acceleration of a car that goes from 0 MS to 60 MS and six seconds
A high-voltage transmission line carries 1,000A at 700,000 V. What is the power carried by the line?
If the resistance in the wire is 1ohm/mile and the line is 110 miles long, what is the power loss due to resistive losses in this wire?
a. 11kW
b. 110kW
c. 11 MW
d. 110 MW
Answer:
d. 110 MW
Explanation:
The computation of the power loss is given below:
= I^2 × R
= 1000^2 × 110
= 110 × 10^6 W
= 110 MW
Here I represent the current through the resistance
ANd, R represent the resistance
So, the correct option is d
pdf
Due date: February 22, 2021
10:00 AM EST
5: Holt SF 05Rev 43 - 10.0 pts possible
A 0.290 kg block on a vertical spring with a
spring constant of 4.65 x 103 N/m is pushed
downward, compressing the spring 0.0500 m.
When released, the block leaves the spring
and travels upward vertically.
The acceleration of gravity is 9.81 m/s.
How high does it rise above the point of
release?
Answer in units of m.
x x
What is the correct description of any change in a position farther to the left of zero?
1- negative displacement
2- negative position
Answer:
negative displacement
Explanation:
cause its written farther that means its doin movement
A storage tank has the shape of an inverted circular cone with height 12 m and base radius of 4 m. It is filled with water to a height of 10 m. Find the work required to empty the tank by pumping all of the water to the top of the tank. (The density of water is 1000 kg/m3. Assume g
Answer:
Work required to empty the tank by pumping all of the water to the top of the tank = 1674700 Kgm/s^2
Explanation:
Volume of Circular cone = V = (1/3)πr2h
where r is the radius in meters
and h is the height in meters
Substituting the given values in above equation, we get -
V = [tex]\frac{1}{3} * 3.14 * 4^2 * 10 = 167.47[/tex] cubic meters.
The force required will be equal to the mass of water in the cone
[tex]= 167.47 * 1000[/tex]
= 167470 Kg
Weight = Mass * g
= 167470 * 10
= 1674700 Kgm/s^2
- .
?
y
(っ◔◡◔)っ ♥ chose the answer with the question marks ♥
Answer:
okay I'm a bit confused but I like the little emoji dudw
Answer:
?
Explanation:
.
A boy of mass 60 kg is sledding down a 70 m slope starting from rest. The slope is angled at 15° below the horizontal. After going 20 m along the slope he passes his friend of mass 50 kg, who jumps on the sled. They now move together to the bottom of the slope. The coefficient of kinetic friction between the sled and the snow is 0.12. Ignoring the mass of the sled, find their speed at the bottom.
You and a friend each hold a lump of wet clay. Each lump has a mass of 30 grams. You each toss your lump of clay into the air, where the lumps collide and stick together. Just before the impact, the velocity of one lump was < 3, 3, -3 > m/s, and the velocity of the other lump was < -4, 0, -4 > m/s. What is the velocity of the stuck-together lump just after the collision
Answer:
[tex]<-0.5, 1.5, -3.5>\ \text{m/s}[/tex]
Explanation:
[tex]u_1[/tex] = Velocity of one lump = [tex]3x+3y-3z[/tex]
[tex]u_2[/tex] = Velocity of the other lump = [tex]-4x+0y-4z[/tex]
m = Mass of each lump = [tex]30\ \text{g}[/tex]
The collision is perfectly inelastic as the lumps stick to each other so we have the relation
[tex]mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=<-0.5, 1.5, -3.5>\ \text{m/s}[/tex]
The velocity of the stuck-together lump just after the collision is [tex]<-0.5, 1.5, -3.5>\ \text{m/s}[/tex].
I have a problem in this questions?
Answer:
8.46E+1
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 39 C
Charge 2 (q₂) = –53 C
Force (F) of attraction = 26×10⁸ N
Electrical constant K) = 9×10⁹ Nm²/C²
Distance apart (r) =?
The distance between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
26×10⁸ = 9×10⁹ × 39 × 53 / r²
26×10⁸ = 1.8603×10¹³ / r²
Cross multiply
26×10⁸ × r² = 1.8603×10¹³
Divide both side by 26×10⁸
r² = 1.8603×10¹³ / 26×10⁸
r² = 7155
Take the square root of both side
r = √7155
r = 84.6 m
r = 8.46E+1 m
Mr. Voytko wants to know how high in meters he can lift an 0.3 kg apple with 7.35 joules?
Answer:
the height above the ground through Mr. Voytko lifted the apple is 2.5 m.
Explanation:
Given;
energy of Mr. Voytko, E = 7.35 J
mass of the apple, m = 0.3 kg
Apply the principle of conservation of energy.
Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.
E = mgh
where;
h is the height above the ground through Mr. Voytko lifted the apple.
g is acceleration due to gravity = 9.8 m/s²
h = E / (mg)
h = 7.35 / (0.3 x 9.8)
h = 2.5 m
Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.
What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 cm from the other) is 293 V?
Answer:
E = 4156.02 Vm⁻¹
Explanation:
The magnitude of the uniform electric field between the plates can be given by the following formula:
[tex]E = \frac{\Delta V}{d}\\[/tex]
where,
E = Electric field strength = ?
ΔV = Potetial Difference = 293 V
d = distance between plates = 7.05 cm = 0.0705 m
Therefore,
[tex]E = \frac{293\ V}{0.0705\ m}\\\\[/tex]
E = 4156.02 Vm⁻¹
toy car A drives with a steady force of 35N and covers 2000 m with fully charged battery. toy car B drives with a steady force of 80 N. how far would it be able to drive using the same fully charged battery as car A.
The distance travelled by toy car B using the same fully charged battery as car A is 875 m
How to determine the energy of car AForce (F) = 35 NDistance of car A (d) = 2000 mEnergy (E) = ?E = fd
E = 35 × 2000
E = 70000 J
How to determine the distance travelled by car BEnergy (E) = 70000 JForce (F) = 80 NDistance of car B =?E = fd
70000 = 80 × Distance of car B
Divide both sides by 80
Distance of car B = 70000 / 80
Distance of car B = 875 m
Learn more about energy:
https://brainly.com/question/10703928
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When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making the crossing. Using the principles of Kinetic Molecular Theory (KMT), explain why it is a good idea to follow this recommendation.
According to the ideal gas law, pressure will rise as a gas's temperature rises. There is a limit to how much the tire can expand before the rubber gives in to the pressure build-up.
What the principles of Kinetic Molecular Theory?For every 10 degrees that the temperature drops, the inflation pressure in tires typically decreases by 1 to 2 psi. Moreover, as the tire pressure heats up during the first 15 to 20 minutes of driving, it will increase by one psi every five minutes.
The ideal gas law states that pressure will increase as a gas's temperature increases. Before the rubber gives in to the pressure build up, the tire can only expand so far.
Therefore, The pressure in your tires will increase due to the increased particle movement in hot air, which will cause the centre of the tread to bow out and wear out first. Increasing the demand for new tires.
Learn more about Molecular Theory here:
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A ball is thrown straight up into the air. Which of the following best describes the energy present at various stages?
There is more energy at the top of the ball's path than there is at the bottom.
The total amount of energy varies, with more energy at the bottom and less at the top of the path.
At the very top, most of the energy is potential and just before it hits the ground, most of the energy is kinetic.
At the very top, most of the energy is kinetic and just before it hits the ground, most of the energy is potential.
Answer:
Uhh 2 one
Explanation
The torque required to turn the crank on an ice cream maker is 4.50 Nm. How much work does it take to turn the crank through 300 full turns?
A) 4240 J
B) 8480 J
C) 2120 J
D) 1350 J
E) 2700 J
Answer:
B) 8480 J
Explanation:
From the question,
The work required to turn the Crank in on turn is
W = 2πT................ Equation 1
Where W = work, T = torque.
Given: T = 4.50 Nm, π = 3.14
Substitute into equation 1
W = 4.5(2)(3.14)
W = 28.26 J per turn.
For 300 full tern,
W = 28.26×300
W = 8476 J
Hence,
W≈ 8480 J.
The right answer is B) 8480 J
Two forces are exerted on an object in the vertical direction: a 20 N force downward and a 10 N force upward. The mass of the object is 25 kg. (1) What are some possibilities about the motion of this object? (2) Represent the motion of the object with a force diagram and a motion diagram.
Answer:
They are equal.
Explanation:
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.
Static Friction
Now let’s examine the static case. Remain on the “Force graphs” tab at the top of the window. Make sure the box labeled “Ffriction” is checked at the left of the screen, this will allow us to measure to force of friction experienced by an object as it slides down the ramp.
Draw a free body diagram for an object sitting on the incline at rest, assuming the incline is at the maximum angle BEFORE the object starts to move. Be sure to include friction and stipulate whether it is kinetic or static.
2. Using a giant screw, a crew does 650 J of work to drill a hole into a rock.
The screw does 65 J of work. What is the efficiency of the screw? Show your
work. Hellpppp
Answer:
42,250
Explanation:
It goes inside=
Displacemt
It does work=
Work done
To find efficiency of jule we do=
Dicplacement × Work done
650 × 65
42,250
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man is walking due east at the rate of of 4kmph and the rain is falling 30° east of vertical with a velocity of 6kmph the velocity of rain relative to the man will be?
Answer:
No answer
Explanation:
no explanation
.................,,,,,,,,,,,
Answer:
B
Explanation:
Motion is movement, the teacher's movement is motion
Jeni walks 100 meters east and then 50 meters north. How big is Jeni's displacement from the starting point?
a. 100 meters
b. 150 meters
c. 50 meters
d. About 112 meters
Answer:
d. About 112 meters.
Explanation:
From the question, John's displacement forms a right angle triangle as below.
Using Pythagoras theorem,
a² = b²+c²....................... Equation 1
Where a = John's displacement from the starting point, b = 100 m, c = 50 m
Substitite these values into equation 1
a² = 100²+50²
a² = 10000+2500
a² = 12500
a = √12500
a = 111.8 meters.
a = about 112 meters.
The right answer is d. About 112 meters.
The lever shown above can be used to move the
bowling ball off the shelf. Pushing down at what
point on the lever would require you to apply the
least amount of force to move the ball?
A. 1
B. 2
C. 3
D. 4
Answer:
C your answer would be C
Explanation:
It should be right