which of the following products would you be LEAST likely to use when blowdrying straight or wavy hair for maximum volume? A. Mousse B. Volumizing spray C. Waving lotion D. Lightweight gel

Answer:

According to Le Chatelier's principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. ... If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants.

It carries at least one hydroxyl functional group ( i.e -OH ) bound to a saturated carbon atom.

Therefore the functional group present is -OH functional group.

Answer:

Carboxylic acid

Explanation:

Answer:

Alcl3 and Cl2

Explanation:

the product above will be formed

Answer:

silver (Ag) and aluminum chloride (AlCl₃)

Explanation:

The reaction between aluminum and silver chloride is a single replacement reaction. A single replacement reaction is when one element switches places with another.

Al + 3AgCl ➔︎ 3Ag + AlCl₃

In the reaction, the cations (positively charged ions) switch places. Aluminum (Al) switches places with Silver (Ag). So, the products of the reaction are silver and aluminum chloride.

Hope this helps.

Answer:

J

Explanation:

Answer:

95.7 g CO to the nearest tenth.

Explanation:

2C + O2 ---> 2CO

Using relative atomic masses:

24 g C produces  2*12 + 2*16 g CO.

So 41 g produces  ( (2*12 + 2*16) * 41  ) / 24

= 95.7 g CO,

Answer:

none of these statements is true

according to the question E) None of these statements is true.

The concentration of a chemical substance expresses the amount of a substance present in a mixture. There are many different ways to express concentration. Chemists use the term solute to describe the substance of interest and the term solvent to describe the material in which the solute is dissolved

Quantitative units of concentration include molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.

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Answer:

As the reaction proceeds in the given voltaic cell, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. At the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Explanation:

A voltaic or galvanic cell is an example of an electrochemical cell.

An electrochemical cell is a device that produces an electric current from chemical reactions occuring within it.

Electrochemical cells have two electrodes; the anode and the cathode. The anode is defined as the electrode where oxidation occurs while the cathode is the electrode where reduction occurs.

The voltaic cell uses two different metal electrodes each immersed in an electrolyte solution. The two electrodes are connected to each other by means of a wire which allows the flow of electrons from the anode to the cathode. The electrolytes are connected by means of a salt bridge which is a junction that connects the electrolytic solution in the anode and cathode compartment. The salt bridge usually consists of a strong electrolyte like NaCl, KCl, Na₂SO₄, etc.

The electrolyte in the salt bridge serves two purposes: it completes the circuit by providing a path for electron flow and it maintains electrical neutrality in both solutions by allowing ions to migrate between them.

As the reaction proceeds in the given voltaic cell above, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. Also, at the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Answer:

2.28 M

Explanation:

Step 1: Given data

Percent by mass (%m/m): 20.0 %

Density (ρ): 1.114 g/mL

Step 2: Calculate the percent by volume (%m/v)

We will use the following expression.

[tex]\% m/v = \% m/m \times \rho = 20.0 \% \times 1.114g/mL = 22.3 g \% mL[/tex]

Step 3: Calculate the moles of solute in 100 mL of solution

The molar mass of phosphoric acid is 97.99 g/mol. The moles corresponding to 22.3 g are:

[tex]22.3g \times \frac{1mol}{97.99g} = 0.228mol[/tex]

Step 4: Calculate the molarity of the solution

0.228 moles of solute are in 100 mL (0.100 L) of solution. The molarity of the solution is:

[tex]M = \frac{0.228mol}{0.100L} =2.28 M[/tex]

Answer:

10.11 mL

Explanation:

Given that :

Total volume of decolorizer = 500 mL

A common recipe is equal parts 95% ethanol and acetone.

So;

The volume of 95% ethanol in the decolorizer = 500mL/2 = 250 mL

Let represent V(ml) for the 99% of ethanol needed to make 95% of the 250 mL of ethanol;

Therefore:

V(ml) × 0.99 = 250 × 0.95

V(ml) × 0.99 = 237.5

V(ml)  = 237.5/0.99

V(ml) = 239.89 mL

Hence; the amount of water to be added to 95% of ethanol = ( 250 -  239.89 )mL = 10.11 mL

Answer:

3.74 atmospheres

Explanation:

If the temperature is constant, then the formula is

V*P = V1 * P1

V = 22.6 L

P = 1.67 atm

V1 = 10.0 L

P1 = ??

=============

22.6 * 1.67 = 10 * P1

37.742 = 10 * P1

37.742/10 = P1

P1 = 3.742

Note there are 3 sig digs in each given, so the answer should be

P1 = 3.74 atmospheres

Answer:

I'd say elastic

Metallic atomic solids, forming metal objects, can pass electric currents through, need a lot of heat to melt, and since electricity can easily pass through, it's quite tough/impossible to find an insulating point.

Answer:

Vapour pressure of the solution is 223.8mmHg

Explanation:

Based on Raoult's law, vapour pressure of a solution decreases related to the vapour pressure of the pure solvent following the equation:

[tex]P_{solution} = X_{solvent}P_{solvent}^0[/tex]

Where P is vapour pressure and X mole fraction of each related substance.

Vapour pressure of pure water is 233.8mmHg

To find Mole fraction of the solution you need to find moles of glycerin and moles of water, mole fraction of water will be:

[tex]\frac{n_{water}}{n_{water}+n_{glycerin}}[/tex]

Moles of water (Molar mass: 18.02g/mol):

125g × (1mol / 18.02g) = 6.937 moles water

Moles of glycerin (Molar mass: 92.09g/mol):

28.5g × (1mol / 92.09g/mol) = 0.309 moles glycerin

Thus, mole fraction of water, X, is:

[tex]\frac{6.937mol}{6.937mol+0.309mol}[/tex]

= 0.957

Replacing in Raoult's law:

[tex]P_{solution} = 0.957*233.8mmHg[/tex]

P = 223.8mm Hg

Answer:

C) a halohydrin

Explanation:

In organic chemistry, a halohydrin is a compound whereby halogen and hydroxyl functional groups are bonded to adjacent carbon atoms in the molecule. Halohydrins are formed from alkenes such as cyclohexene in this case.

NBS is a very suitable alternative to Br2 in the synthesis of a halohydrin. Recall that the reactive intermediate when bromine reacts with an alkene is the brominium ion which is a three atom ring ion. If excess water is used as the solvent, then the water attacks the brominium ion to yield the product halohaydrin with trans a trans stereochemistry.

Answer:

Drill bits  

Explanation:

Gemstones such as diamonds are used in drill bits because of their hardness.

They are a 10 on the Mohs scale of hardness, which runs from 0 to 10.

Drill bits are produced from gemstones due to their hardness.

Gemstones are the name given to pieces of minerals  that can be cut and polished valuable accessories.

Gemstones such as diamonds are used in drill bits because of their hardness.

Thus, drill bits are produced using gemstones.

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Answer:

The answer is option a. The evaporation of water from the skin

Explanation:

An endothermic reaction is any synthetic reaction that retains heat from its environment. The ingested energy gives the enactment energy to the reaction to happen.

No new bonds formed, no bonds broken in this example. water molecules go from liquid to vapour (gas ), intermolecular bond exist between polar (-OH) molecules and energy is required to break these bonds during the change from liquid to gas. So, it is endothermic .

Remaining three above examples are exothermic. combustion of gas releases energy(exothermic). burninig of the candle exothermic because the energy released from the oxygen into carbon dioxide and water.oxidation of iron also exothermic

Answer:

2.75X10^16

Explanation:

C=FXwavelength

wavelength=C/F

We have that for the Question "Calculate the wavelength in meters of electromagnetic radiation that has a frequency of 1.09 × 10⁸ s⁻¹."

it can be said that  the wavelength in meters of electromagnetic radiation that has a frequency of 1.09 × 10⁸ s⁻¹ is

[tex]\lambda=2.7522m[/tex]

From the question we are told

Calculate the wavelength in meters of electromagnetic radiation that has a frequency of 1.09 × 10⁸ s⁻¹. (c = 3.00 X 10⁸ m/s)

Generally the equation for the Wavelength  is mathematically given as

[tex]\lambda=\frac{c}{f}\\\\Therefore\\\\\lambda=\frac{c}{f}\\\\\lambda=\frac{3*10^8}{1.09*10^8}\\\\[/tex]

[tex]\lambda=2.7522m[/tex]

Therefore

the wavelength in meters of electromagnetic radiation that has a frequency of 1.09 × 10⁸ s⁻¹ is

[tex]\lambda=2.7522m[/tex]

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Answer:

Adding a catalyst increases the speed of the reaction.

Explanation:

The catalyst increases the reaction rate since what it does is to consume the reagents more easily in order to obtain the products faster.

The catalysts DO NOT ALTER THE QUANTITY OF PRODUCTS OR REAGENTS, that is to say that they do not add grams nor do they intervene in the masses of the chemical compounds of the reaction, they only speed up the procedure.

Answer:

[tex]0.688M[/tex]

Explanation:

Hello,

In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):

[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]

In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):

[tex]0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}[/tex]

Or simply:

[tex]0.688M[/tex]

Regards.

Answer:

Explanation:

Following are a few consequences of fossil fuels

1. It causes air pollution.

2. When they are burned, they produce toxic substances which leads to global warming.

3. Waste products are hazardous to public health and environment.

4. They are non - renewable and unsustainable.

5. Drilling fossil fuels is a dangerous process

Hope this helps

plz mark as brainliest!!!!

Answer:

Explanation:

Baking soda decomposes to produce sodium carbonate .

2NaHCO₃  = Na₂CO₃ + CO₂ + H₂O.

2 x 84 g          106 + 10 x 18  g

Molecular mass of Na₂CO₃ .10H₂O = 286

168 g baking soda  produces 286  g sodium carbonate

1.555g baking soda will produce 286 x 1.555 / 168

= 2.647 g

Percentage yield = actual yield / theoretical yield x 100

= ( .991 /2.647 ) x 100

= 37.43 %.

Answer:

[tex]6.022x10^{23}atoms \ Al[/tex]

Explanation:

Hello,

In this case, given the described concept regarding the Avogadro's number, we can easily notice that 27.0 g of aluminium foil has 6.022x10²³ atoms as shown below based on the mass-mole-particles relationship:

[tex]27.0gAl*\frac{1molAl}{27.0gAl} *\frac{6.022x10^{23}atoms \ Al}{1molAl} \\\\=6.022x10^{23}atoms \ Al[/tex]

Notice this is backed up by the fact that aluminium molar mass if 27.0 g/mol.

Best regards.

Answer: (i) [tex]C_2H_3O_2H[/tex] and (ii) [tex]NaC_2H_3O_2[/tex]

Explanation:

Buffer is a solution which resists changes in pH when small quantities of acid or alkali are added to it.

Acidic buffer is formed by combination of weak acid and salt of weak acid with strong base. Example: [tex]CH_3COOH[/tex] and [tex]CH_3COONa[/tex]

Basic buffer is formed by combination of weak base and salt of weak base with strong acid. Example: [tex]NH_4OH[/tex] and [tex]NH_4Cl[/tex]

Thus pair of substance can be dissolved together (in the right ratio) to prepare a buffer solution is [tex]C_2H_3O_2H[/tex] and [tex]NaC_2H_3O_2[/tex]

Answer:

C. the evolution of building techniques

Hope this helps.

Answer:

a. pH = 5.22

b. Acidic.

c. pH = 5.14

Explanation:

a. It is possible to find the pH of a buffer using Henderson-Hasselbalch equation (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (For acetic acid =  4.74), [A⁻] is molar concentration of conjugate base (Acetate salt) and [HA] concentration of the weak acid (Acetic acid).

Replacing:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

You use the concentration of the acetic acid and sodium acetate because you're adding equal volumes, doing the ratio of the species the same

b. As the solution has a pH lower that 7.0, it is considered as a acidic solution.

c. When you add HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

Where acetate ion reacts with the acid producing acetic acid.

As you have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid. Initial moles of both compounds and moles of HCl added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The moles added of HCl are the same moles you're consuming of acetate ion and producing of acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

Replacing in H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

(a) The pH of the solution is 5.22

(b) The solution is Acidic

(c) The pH of the resultant solution is 5.14

(a) The pH of a buffer can be calculated by using (H-H equation):

pH = pKa + log₁₀ [A⁻] / [HA]

Where pKa is -log Ka (for acetic acid =  4.74),

[A⁻] is the molar concentration of Acetate salt, and

[HA] concentration of the Acetic acid

According to the question:

pH = 4.74 + log₁₀ [0.600M] / [0.200M]

pH = 5.22

(b) The pH of the solution is lower than 7.0, therefore it is an acidic solution.

(c) After adding HCl to the buffer, the reaction is:

CH₃COO⁻ + HCl → CH₃COOH + Cl⁻

We have 0.200L of the buffer, 0.100L are of the acetate ion and 0.100L of the acetic acid.

The initial amount of compounds added are:

CH₃COO⁻: 0.100L ₓ (0.600mol / L) = 0.0600 moles

CH₃COOH: 0.100L ₓ (0.200mol / L) = 0.0200 moles

HCl: 3.0mL = 3x10⁻³L ₓ (0.034mol / L) =  0.00010 moles HCl

The HCl reacts with the same amount of acetate ion and produces acetic acid. Thus, moles after the reaction are:

CH₃COO⁻: 0.0600 moles - 0.0001 moles = 0.0509 moles

CH₃COOH: 0.0200 moles + 0.0001 moles = 0.0201 moles

From the H-H equation:

pH = 4.74 + log₁₀ [0.0509moles] / [0.0201moles]

pH = 5.14

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Answer:

lithium is akali metal

Answer:

lithium is an alkali metal as it lies in group 1st in modern perodic table.

Answer:

Predicting the polarity of a bond is the correct answer to this question.

Explanation:

Polar-covalent bonded substances have atoms that are distributed unequally among the central atom. The polarity of this bond is essentially determined by the bound atoms uniformly electronegativities.

To evaluate the polarity using numerical means of a covalent bond, if the result is between 0.4 and 1.7, then the bond is usually polar covalent.

Answer:

5 degrees Celsius.

Explanation:

Temperature measures the average kinetic energy of  particles of the substances. Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

Temperature is used to measure degree or intensity of heat of a particular substance. Temperature is measured by an instrument called thermometer.

Temperature can be measured in degree celsius °c, Kelvin k or in Fahrenheit. Temperature is a physical quantity. Heat always flow from higher temperature source to lower temperature source.

We can convert these units of temperature into one another. The relationship between degree Celsius and  Fahrenheit can be expressed as:

°C={5(°F-32)}÷9

Substituting given values in above equation

°C= {5(41-32)}÷9

°C= 5°C

Therefore a temperature of 41 Fahrenheit is the same as 5 degree Celsius

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Answer:

THE MOLARITY OF THE SOLUTION IS 0.1039 MOL/DM3

Explanation:

Molarity is the number of moles of solute in a given solution,

Molarity in mol / dm3 = Molarity in g/dm3 / Molar mass

Mass = 15.2 g

Volume of solution = 2.5 l

Molar mass  of NaCl = (23 + 35.5) = 58.5 g/mol

First, we calculate the molarity in g/dm3

Molarity in g/dm3 = mass /volume

= 15.2 g * 1 L  / 2.5 L

=6.08 g /dm3

Hence, we will introduce the values and solve for molarity in mol/dm3

Molarity = 6.08 g/dm3/ 58.5 g/mol

Molarity = 0.1039 mol/dm3

The molarity of the solution is 0.1039 mol/dm3

Answer:

A.  1.88 mol H₂

B.  182 g Al₂(SO₄)₃

C.  54.8%

Explanation:

2 Al  +  3 H₂SO₄  ⇒  Al₂(SO₄)₃  +  3 H₂

A.  Convert grams of Al to moles.  The molar mass is 26.98 g/mol.

(33.8 g)/(26.98 g/mol) = 1.253 mol Al

Use stoichiometry to convert moles of Al to moles of H₂.  Looking at the equation, you can see that for every 2 mol of Al consumed, 3 moles of H₂ is produced.  Use this relationship.

(1.253 mol Al) × (3 mol H₂)/(2 mol Al) = 1.879 mol H₂

You will produce 1.88 mol of H₂ gas.

B.  Again, use stoichiometry.  For every 3 moles of H₂SO₄ consumed, 1 mole of Al₂(SO₄)₃ is produced.

(1.60 mol H₂SO₄) × (1 mol Al₂(SO₄)₃/3 mol H₂SO₄) = 0.533 mol Al₂(SO₄)₃

Convert moles of Al₂(SO₄)₃ to grams.  The molar mass is 342.15 g/mol.

(0.533 mol) × (342.15 g/mol) = 182.48 g Al₂(SO₄)₃

You will produce 182 g of Al₂(SO₄)₃.

C.  Calculate percent yield by dividing the actual yield by the theoretical yield.  Multiply by 100%.

(100.0/182.48) × 100% = 54.8%

The percent yield is 54.8%.

Answer:

Conductors allow a flow of current or a charge of flow

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