Which of the following is the graph of (x + 1)2 + (y − 6)2 = 36?

Answers

Answer 1

Answer:

Step-by-step explanation:

Slope:  

− 1

y-intercept:  

23

Which Of The Following Is The Graph Of (x + 1)2 + (y 6)2 = 36?
Answer 2
Heyy!:)
So
(X+1)2+(y-6)2=36

To Find x-intercept/zero substitute y=0
So it’s goin to be like this ;
(X+1)x2(0-6)x2=36


Solve the Equation for X
Answer;x=23 :)

Related Questions

Which of the following theorems verifies that WVU= RST

Answers

Answer:

C. HL

Step-by-step explanation:

The Hypotenuse-Leg Theorem is the only viable way to determine congruency between 2 right triangles.

Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent the number of domestic stamps and let y represent the number of foreign stamps. This system of equations models the given information for both stamp types. x – y = 34 x + y = 212

Answers

Step-by-step explanation:

x - y = 34

x + y = 212

2x = 246

x = 123

123 + y = 212

y = 89

(123, 89)

The weight of male babies less than months old in the United States is normally distributed with mean pounds and standard deviation pounds. Answer the following.

Required:
a. What proportion of babies weigh more than 12 pounds?
b. What proportion of babies weigh less than 15 pounds?
c. What proportion of babies weigh between 9 and 13 pounds?
d. Is it unusual for a baby to weigh more than 18.1 pounds?

Answers

Answer:

a. P ( X > 12 ) = 0.5254

b. P ( X < 15 ) = 0.7172

c. P ( 9 < X < 13 ) =  0.3179

d. Not unusual

Step-by-step explanation:

Solution:-

- We will define our random variable X as follows:

       X: The weights of the male babies less than 2 month old in USA ( lb )

- The distribution given for the random variable ( X ) is defined to follow normal distribution.

- The normal distribution is identified by two parameters mean ( u ) and standard deviation ( σ ). The distribution is mathematically stated or expressed as:

                               X ~ Norm ( u , σ^2 )

- The parameters for the normal distribution followed by the random variable ( X ) are given. Hence,

                              X ~Norm ( 12.3 , 4.7^2 )

- We will use standard normal tables to determine the following probabilities:

a) What proportion of babies weigh more than 12 pounds?

- To use the standard normal tables we need to standardized our limiting value of the required probability by finding the corresponding Z-score value.

- The formula used to compute the Z-score value is given below:

                                [tex]Z-score = \frac{x - u}{sigma}[/tex]

- We are requested to compute the probability p ( X > 12 ). the limiting value is 12 pounds. We will use the conversion formula and compute the Z-score:

                               [tex]Z-score = \frac{12 - 12.3}{4.7} \\\\Z-score = -0.06382[/tex]

- The standard normal table gives the probabilities of Z-score values in "less than ". So to determine the required probability we look-up:

                            P ( X > 12 ) = P ( Z > -0.06382 ) = ...

                            P ( Z > -0.06382 ) = 1 - P ( Z < -0.06382 )  

Use standard normal look-up table:

                            P ( X > 12 ) =  1 - 0.4746

                            P ( X > 12 ) = 0.5254  ... Answer

Answer: The proportion of babies that weigh more than 12 pounds is the probability of finding babies weighing more than 12 pounds among the total normally distributed population. The proportion is 0.5254

b) What proportion of babies weigh less than 15 pounds?

- We are requested to compute the probability p ( X < 15 ). the limiting value is 12 pounds. We will use the conversion formula and compute the Z-score:

                             [tex]Z-score = \frac{15-12.3}{4.7} \\\\Z-score = 0.57446[/tex]

- The standard normal table gives the probabilities of Z-score values in "less than ". So to determine the required probability we look-up:

                            P ( X < 15 ) = P ( Z < 0.57446 )

                            P ( X < 15 ) = 0.7172

Answer: The proportion of babies that weigh less than 15 pounds is the probability of finding babies weighing less than 15 pounds among the total normally distributed population. The proportion is 0.7172

c) What proportion of babies weigh between 9 and 13 pounds?

- We are requested to compute the probability p ( 9 < X < 13 ). the limiting value are 9 and 13 pounds. We will use the conversion formula and compute the Z-score:

                           [tex]Z_1 = \frac{9-12.3}{4.7} = -0.70212\\\\Z_2 = \frac{13-12.3}{4.7} = 0.14893\\[/tex]

- The standard normal table gives the probabilities of Z-score values in "less than ". So to determine the required probability we look-up:

                          P ( 9 < X < 13 ) = P ( -0.70212 < X < 0.14893 )

        P ( -0.70212 < X < 0.14893 ) = P ( X < 0.14893 ) - P ( X < -0.70212 )  

Use standard normal look-up table:

                            P ( 9 < X < 13 ) =  0.5592 - 0.2413

                            P ( 9 < X < 13 ) =  0.3179  ... Answer

Answer: The proportion of babies that weigh less than 13 pounds but greater than 9 pounds is the probability of finding babies weighing less than 13 pounds and more than 9 pounds among the total normally distributed population. The proportion is 0.3179

d)

Is it unusual for a baby to weigh more than 18.1 pounds?

- We are requested to compute the probability p (  X > 18.1 ). the limiting value is 18.1 pounds. We will use the conversion formula and compute the Z-score:

                             [tex]Z-score = \frac{18.1-12.3}{4.7} \\\\Z-score = 1.23404[/tex]

The standard normal table gives the probabilities of Z-score values in "less than ". So to determine the required probability we look-up:

                            P ( X > 18.1 ) = P ( Z > 1.23404 )

                            P ( X > 18.1 ) =  0.1086

Answer: The proportion of babies that weight more than 18.1 pounds are 0.1086 of the total babies population. We can say that the proportion of babies that weigh more than 18.1 pounds are significant because the proportion lies is significant. Not enough statistical evidence to be classified as "unusual".

Complete the steps to solve this linear equation: 2x + 9(x – 1) = 8(2x + 2) – 5 1.Apply the distributive property: 2x + 9x– 9 = 16x + 16 – 5 2.Combine like terms on each side: 11x – 9 = 16x + 11 3.Use the subtraction property of equality to isolate the variable term: –9 = 5x + 11 Use the subtraction property of equality to isolate the constant: –20 = 5x 4. Use the division property of equality to solve: = x

Answers

Answer:

it should be -4=x.

Answer: -4

Step-by-step explanation:

6 out of 9 pairs of your jeans are blue. What percentage of you
jeans are NOT blue?​

Answers

Answer:

33.333333%

Step-by-step explanation:

If 6/9 (66.66666666%) of the jeans are blue it means that 3/9 of the jeans are not blue. 3/9 as a percentage is 33.333333%

Answer:

33.3%

Step-by-step explanation:

6 ÷ 9 = 66.66666667%

100% - 66.66666667% = 33.3% (Or you can put 33.33333333)

Hope this helped! :)

PLEASE HELP MEEEE HURRRY!!! :)

Answers

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

[tex]\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}[/tex]

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

[tex]\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}[/tex]  First, I swapped the first and third rows.

[tex]\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}[/tex]  Leading coefficient of row 2 canceled.  

[tex]\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}[/tex]  The start value of row 3 was canceled.

[tex]\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}[/tex]       Matrix rows 2 and 3 were swapped.

[tex]\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}[/tex]      Leading coefficient in row 3 was canceled.

[tex]\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}[/tex]

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

[tex]\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}[/tex]

The positioning of the zeros indicated that there was no solution!

Hope that helps!

Which best describes thermal energy?​

Answers

Answer:

It's the third Answer: It is the portion of internal energy that can be transferred from one substance to another.

Hope this helps

Answer:

c

Step-by-step explanation:

s defined to be the dollar value of loans defaulted divided by the total dollar value of all loans made. Banking officials claim that the mean bad debt ratio for all Midwestern banks is 3.5%, but that Ohio’s is different. Suppose that a random sample of seven Ohio banks is selected and that the bad debt ratios for these banks are: 7%, 4%, 6%, 3%, 5%, 4%, and 2%. Assuming that bad debt ratios are approximately normal, test at the 0.05 level of significance whether the mean bad debt ratio for Ohio banks is different than the Midwestern average.H0: Mu = 3.5Ha: Mu neq 3.5Hint: data <- c(7, 4, 6, 3, 5, 4, 2) # you can find xbar=mean(data) and s=sd(data) of the sample in R.a) What type of hypothesis test do you need to use? (3 points)b) Determine the test statistic? (3 points)c) Determine the critical value? Stat your conclusion. (5 points)d) Determine the p-value? State your conclusion. (4 points)

Answers

Answer:

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean bad debt ratio for Ohio banks is different than the Midwestern average (3.5%).

Test statistic t = 1.431

Critical values tc = ±2.447

P-value = 0.203

Step-by-step explanation:

This is a hypothesis t-test for the population mean.

The claim is that the mean bad debt ratio for Ohio banks is different than the Midwestern average (3.5%).

Then, the null and alternative hypothesis are:

H_0: \mu=3.5\\\\H_a:\mu\neq 3.5

The significance level is 0.05.

The sample has a size n=7.

We calculate  the sample mean and standard deviation as:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{7}(7+4+6+3+5+4+2)\\\\\\M=\dfrac{31}{7}\\\\\\M=4.43\\\\\\[/tex]

[tex]s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{6}((7-4.43)^2+(4-4.43)^2+(6-4.43)^2+. . . +(2-4.43)^2)}\\\\\\s=\sqrt{\dfrac{17.71}{6}}\\\\\\s=\sqrt{2.95}=1.72\\\\\\[/tex]

The sample mean is M=4.43.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1.72.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1.72}{\sqrt{7}}=0.65[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.43-3.5}{0.65}=\dfrac{0.93}{0.65}=1.431[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=7-1=6[/tex]

This test is a two-tailed test, with 6 degrees of freedom and t=1.431, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=2\cdot P(t>1.431)=0.203[/tex]

As the P-value (0.203) is bigger than the significance level (0.05), the effect is not significant.

If we use the critical value approach, for this level of confidence, the critical values are tc = ±2.447. The test statistic is within the bounds of the critical values and falls within the acceptance region.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean bad debt ratio for Ohio banks is different than the Midwestern average (3.5%).

When testing for current in a cable with sixsix ​color-coded wires, the author used a meter to test threethree wires at a time. How many different tests are required for every possible pairing of threethree ​wires?

Answers

Answer:

20 tests

Step-by-step explanation:

There are six different wires, and for each test the author picks three, this means that each test is a combination of three out of six wires (₆C₃) . The number of total combinations possible is given by:

[tex]_6C_3=\frac{6!}{(6-3)!3!}\\_6C_3=\frac{6*5*4}{3*2*1}\\_6C_3=20[/tex]

20 tests are required to verify every possible pairing of three wires.

The line segment AB with endpoints A (-3, 6) and B (9, 12) is dilated with a scale

factor 2/3 about the origin. Find the endpoints of the dilated line segment.

O A) (2, 4), (6,8)

B) (4, -2), (6,8)

O C) (-2, 4), (6,8)

OD) (-2, 4), (8,6)

Answers

Answer:

C) (-2, 4), (6,8) is the correct answer.

Step-by-step explanation:

Given that line segment AB:

A (-3, 6) and B (9, 12) is dilated with a scale  factor 2/3 about the origin.

First of all, let us calculate the distance AB using the distance formula:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Here,

[tex]x_2=9\\x_1=-3\\y_2=12\\y_1=6[/tex]

Putting all the values and finding AB:

[tex]AB = \sqrt{(9-(-3))^2+(12-6)^2}\\\Rightarrow AB = \sqrt{(12)^2+(6)^2}\\\Rightarrow AB = \sqrt{144+36}\\\Rightarrow AB = \sqrt{180}\\\Rightarrow AB = 6\sqrt{5}\ units[/tex]

It is given that AB is dilated with a scale factor of [tex]\frac{2}{3}[/tex].

[tex]x_2'=\dfrac{2}{3}\times x_2=\dfrac{2}{3}\times9=6\\x_1'=\dfrac{2}{3}\times x_1=\dfrac{2}{3}\times-3=-2\\y_2'=\dfrac{2}{3}\times y_2=\dfrac{2}{3}\times 12=8\\y_1'=\dfrac{2}{3}\times y_1=\dfrac{2}{3}\times 6=4[/tex]

So, the new coordinates are A'(-2,4) and B'(6,8).

Verifying this by calculating the distance A'B':

[tex]A'B' = \sqrt{(6-(-2))^2+(8-4)^2}\\\Rightarrow A'B' = \sqrt{(8)^2+(4)^2}\\\Rightarrow A'B' = \sqrt{64+16}\\\Rightarrow A'B' = \sqrt{80}\\\Rightarrow A'B' = 4\sqrt{5}\ units = \dfrac{2}{3}\times AB[/tex]

So, option C) (-2, 4), (6,8) is the correct answer.

How much interest is earned if $2500 is invested for 25 years at 8% simple
interest?
*
0500
50000
250
O 5000

Answers

Answer: $5,000

Step-by-step explanation: First begin with the interest formula.

Interest = Principal × Rate × Time

In this problem, we're solving for the interest.

The principal is the amount invested or $2,500.

The rate is 8% which we can write as .08.

The time is 25 years.

So we have I = (2,500)(.08)(25).

Now we multiply.

(2,500)(.08) is equal to 200.

Now, multiply 200(25) to get 5,000.

This means that the interest earned is $5,000.

Please answer this correctly

Answers

Answer:

0

Step-by-step explanation:

The probability of picking a even number is 1/3

If u don’t replace it then the probability of picking an even number is 0/3

Multiply and u get 0/9 or 0

Hope this helps

Answer:

0

Step-by-step explanation:

The number 2 is even.

The probability of picking an even number is 1/3.

You don't put the first card back.

1 and 3 are odd.

1/3 × 0 = 0

"There is a group of people. The average height of these people is 67 inches. Is it more likely to pick an individual who is more than 68 inches tall or a sample of four people who average more than 68 inches tall

Answers

Answer:

Step-by-step explanation:

The spread of the height of each person in the group depends on the standard deviation. A low standard deviation means that the heights are closer to the mean than that of a high standard deviation. If an individual is picked, the probability of picking one who is more than 68 inches tall is small as this depends on the number of individuals in this category. The probability of picking a sample of four people who average more than 68 inches tall would be higher since average would be taken. Therefore, it is more likely to pick a sample of four people who average more than 68 inches tall

what is the answer to 4n-2n=4

Answers

Answer: n=2

Step-by-step explanation: 4n-2n=4

4(2)-2(2)=

8-4=4

Answer:

n=2

Step-by-step explanation:

Step by Step Solution:

More Icon

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4*n-2*n-(4)=0  

Step by step solution :

STEP

1

:

Pulling out like terms

1.1     Pull out like factors :

  2n - 4  =   2 • (n - 2)  

Equation at the end of step

1

:

STEP

2

:

Equations which are never true

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

2.2      Solve  :    n-2 = 0  

Add  2  to both sides of the equation :  

                     n = 2

An equilateral triangular plate with sides 6 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s^2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m^3.) rhog^3(3)^1/2 _______ dx = _______ N

Answers

Answer:

26,400 N

Step-by-step explanation:

PLEASE CHECK ATTACHMENT FOR COMPLETE SOLUTION

Pls help me pick the right answer! Please

Answers

I think it is choice 3 (c)

I NEED ANSWER SUPER BAD PLEASE!!!!!!!!!!!What is the greatest integer less than 100 for which the greatest common divisor of that integer and 12 is 4?

Answers

Answer:

92

Step-by-step explanation:

We will list out the numbers which are factors of 12. They include:

1, 2, 3, 4, 6, 12.

We need to get the highest number that has its greatest factor to be 4. It means that 6 and 12 cannot divide it.

To do this, we will write out the multiples of 4. They include:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88,92,96.

We will have to choose the highest number which only 4  can divide and  6 and 12 cannot divide.

Since we are looking for the largest, We can try dividing all the numbers by 4, 6, and 12 starting from 96.

We will quickly see that 4 can divide 92 but 6 and 12 cannot.

This gives us 92 as the answer.

Answer:

92

Step-by-step explanation:

Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.) μ = 24; σ = 4.2 P(x ≥ 30) = ?

Answers

Answer:

Step-by-step explanation:

x is a random variable. Since we are assuming that x has a normal distribution, then we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 24

σ = 4.2

The indicated probability to be determined is P(x ≥ 30)

P(x ≥ 30) = 1 - P(x < 30)

For P(x < 30),

z = (30 - 24)/4.2 = 1.43

Looking at the normal distribution table, the probability corresponding to the z score is 0.9236

Therefore,

P(x ≥ 30) = 1 - 0.9236 = 0.0764

circumference of 6cm ? help plz <3 heyyy b a e (bet you won't reply :)

Answers

Answer:

If r = 6 cm, the the circumference is c = 2π(6) = 12π cm

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

THNXX :)

Progress
Question ID: 470099

One student can paint a wall in 12 minutes. Another student can paint the same wall in 24 minutes. Working together, how long will it
take for them to paint the wall?

Answers

Answer:

8 min

Step-by-step explanation:

Try this:

    1 wall                           1                   288

------------------------ =  ---------------  =  --------------- min  =  8 min

1 wall        1 wall         24 + 12                 36

(---------) + (---------)      ------------

12 min      24 min           288

Please answer this correctly

Answers

it would be possible because if it's 6 it's even if it 4 it's even if it's 2 it's even so you okay so it is certain and possible babes

Name the triangle with the following characteristics. sides: 5 cm, 6 cm, 7 cm; Angles: 75° and 60°. yeah

Answers

Answer:

Step-by-step explanation:

this triangle is regular one

we can't apply the pytahgorian theorem 5²+6²≠7² the angles have different sizes 75≠60≠45the sides have different lengths 5≠6≠7

Answer:

obtuse scalene triangle

Does anyone know how to solve this? I don't know how to type it out so Im gonna attach a pic

Answers

Answer:

tan =-1

Step-by-step explanation:

tan(θ)=sen(θ)/cos(θ)

so

[tex]tan(angle)=\frac{\frac{-\sqrt{2} }{2} }{\frac{\sqrt{2} }{2} } }\\\\tan(angle)=-1[/tex]

Answer:

Sin (theta)=[tex] - \frac{ \sqrt{2} }{2} [/tex]

Tan ( theta)= [tex] - 1[/tex]

Step-by-step explanation:

[tex]cos \: \: theta \: = \frac{ \sqrt{2} }{2} = \frac{1}{ \sqrt{2} } = cos \: \frac{\pi}{4 } [/tex]

[tex]cos \: (2\pi \: - \frac{\pi}{4} ) \: \: ( \frac{3\pi}{2} < theta < 2\pi)[/tex]

[tex] = cos \: \frac{7\pi}{4} [/tex]

Theta = 7π / 4

[tex]sin \: theta = sin \: \frac{7\pi}{4} [/tex]

[tex] = sin \: (2\pi \: - \frac{\pi}{4} )[/tex]

[tex] - sin \: \frac{\pi}{4} [/tex]

[tex] = \frac{ - 1}{ \sqrt{2} } [/tex]

[tex] = - \frac{ \sqrt{2} }{2} [/tex]

Finding tan theta:

[tex]tan \: theta = tan \: \frac{7\pi}{4} [/tex]

[tex] =tan \: (2\pi - \frac{\pi}{4} )[/tex]

[tex] = - tan \: \frac{\pi}{4} [/tex]

[tex] = - 1[/tex]

Hope this helps...

Good luck on your assignment...

A loan of $25,475 is taken out at 4.6% interest, compounded annually. If no payments are
made, after about how many years will the amount due reach $37,500? Round to the
nearest year.
Please helpppp

Answers

Answer:

It will take 9 years

Step-by-step explanation:

use formula A=P(1+ r/n)^nt

37,500= 25,475(1+.046/1)^1*x

37,500/25,475=1.046^x

1.47203= 1.046^x

try out different numbers for x and use whole number since it asks for the nearest year

1.046^8 = 1.43302 and 1.046^9 = 1.4989

so we know its inbetween

8 and 9 to figure out one is the closest whole number try raising it to the power of 8.5 and if it passes 1.47203 then its 9, if it doesnt then its 8

1.046^8.5 = 1.46561

1.46561< 1.47203

since 1.046561 is lower than 1.47203 its safe to assume that the year is between 8.5-8.99 thus we can round up to 9

a classical music concert is to constist of 3 cello pieces, 3 choral works, and 3 pieces for piano. In how many ways can the program be arranged if a piano piece must come first

Answers

Answer:

120,960 ways

Step-by-step explanation:

Assuming that each piece is unique, then the order of each piece matters.

There are 9 pieces in total, there are 3 options for the first piece (3 piano pieces), and the remaining 8 pieces can be permuted. The number of possible arrangements is:

[tex]n=3*\frac{8!}{(8-8)!}\\ n=3*8*7*6*5*4*3*2*1\\n=120,960\ ways[/tex]

The program can be arranged in 120,960 ways.

Find the equation for the parabola that has its vertex at the origin and has directrix at x=1/48

Answers

Answer:

The equation for a parabola with vertex at the origin and a directrix at x = 1/48 is [tex]x= \frac{1}{12}\cdot y^{2}[/tex].

Step-by-step explanation:

As directrix is a vertical line, the parabola must "horizontal" and increasing in the -x direction. Then, the standard equation for such geometric construction centered at (h, k) is:

[tex]x - h = 4\cdot p \cdot (y-k)^{2}[/tex]

Where:

[tex]h[/tex], [tex]k[/tex] - Horizontal and vertical components of the location of vertex with respect to origin, dimensionless.

[tex]p[/tex] - Least distance of directrix with respect to vertex, dimensionless.

Since vertex is located at the origin and horizontal coordinate of the directrix, least distance of directrix is positive. That is:

[tex]p = x_{D} - x_{V}[/tex]

[tex]p = \frac{1}{48}-0[/tex]

[tex]p = \frac{1}{48}[/tex]

Now, the equation for a parabola with vertex at the origin and a directrix at x = 1/48 is [tex]x= \frac{1}{12}\cdot y^{2}[/tex].

Couple more! Running out of time lol!

Answers

Answer:

A translation; (x,y) --> (x-4,y-5)

Step-by-step explanation:

This is because the figures are congruent and in the same orientation but just in different locations on the coordinate plane.

A(0,3) --> A'(-4,-2)

So, the rule is (x,y) --> (x-4,y-5)

Given the GCF or LCM, what else do you know about each pair of numbers?
a) Two numbers have a GCF of 2.
b) Two numbers have an LCM of 2.
c) Two numbers have a GCF of 3.
d) Two numbers have an LCM of 10.

Answers

Answer:

LCM is half of given product.GCF is half of given product. LCM is one-third of given product.GCF is one-tenth of given product.

Step-by-step explanation:

We know that'

GCF × LCM = Product of given number

1. Two numbers have a GCF of 2

= 2 × LCM = Product of given number

LCM = Product of given number / 2

LCM is half of given product.

2. Two numbers have an LCM of 2

= GCF × 2 = Product of given number

GCF = Product of given number / 2

GCF is half of given product.

3. Two numbers have a GCF of 3

= 3 × LCM = Product of given number

LCM = Product of given number / 3

LCM is one-third of given product.

4. Two numbers have an LCM of 10

= GCF × 10 = Product of given number

GCF = Product of given number / 10

GCF is one-tenth of given product.

"a. How many study subjects were cases? b. How many study subjects were controls? c. What was the ratio of controls to cases?"

Answers

Answer:

The description is provided following.

Step-by-step explanation:

The given question is incomplete. The complete question will be:

                                     Brain tumors                      No Brain tumors

Cell Phones                          63                                          185

No Cell Phones                    96                                          292                  

The further explanation is given below.

a...

Subjects with these symptoms/diseases are recognized as "cases." Consequently, the majority of the instances would be as follows:

⇒  [tex]63+96[/tex]

⇒  [tex]159[/tex]  

b...

Subjects who might not have the disorder or infection are classified as "controls." Therefore, the amount of controls is as follows:

⇒  [tex]185+292[/tex]

⇒  [tex]477[/tex]

c...

The proportion of control and monitoring of instances:

⇒  [tex]\frac{478}{159}[/tex]

⇒  [tex]3.006[/tex]

I NEED HELP PLEASE, THANKS! :)

Answers

Answer: C

Step-by-step explanation:

We can automatically eliminate D because since both matrices are 2x2, the product exists.

[tex]\left[\begin{array}{ccc}1&5\\-3&4\end{array}\right] \left[\begin{array}{ccc}2&6\\6&-1\end{array}\right] =\left[\begin{array}{ccc}1*2+5*6&1*6+5*(-1)\\(-3)*2+4*6&(-3)*6+4*(-1)\end{array}\right]=\left[\begin{array}{ccc}32&1\\18&-22\end{array}\right][/tex]

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