Which of the following is not an advantage of e-commerce for consumers?
a. You can choose goods from any vendor in the world.
b. You can shop no matter your location, time of day, or conditions.
c. You have little risk of having your credit card number intercepted.
d. You save time by visiting websites instead of stores.

Answers

Answer 1

Answer:  c. You have little risk of having your credit card number intercepted.

====================================

Explanation:

Choice A is false because it is an advantage to be able to choose goods from any vendor from anywhere in the world. The more competition, the better the outcome for the consumer.

Choice B can also be ruled out since that's also an advantage for the consumer. You don't have to worry about shop closure and that kind of time pressure is non-existent with online shops.

Choice D is also a non-answer because shopping online is faster than shopping in a brick-and-mortar store.

The only thing left is choice C. There is a risk a person's credit card could be intercepted or stolen. This usually would occur if the online shop isn't using a secure method of transmitting the credit card info, or their servers are insecure when they store the data. If strong encryption is applied, then this risk can be significantly reduced if not eliminated entirely.

Answer 2

Answer:

c. You have little risk of having your credit card number intercepted.

Explanation:

Hope this helps


Related Questions

The Basic premise of____is that objects can be tagged, tracked, and monitored through a local network, or across the Internet.
The basic premise of
a. artificial intelligence
b. intelligent workspaces
c. the Internet of Things
d. the digital divide

Answers

Answer:

C.

Explanation:

Internet of things

The Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.

What is IoT?

The term "Internet of things" refers to actual physical items that have sensors, computing power, software, and other innovations and can link to those other systems and gadgets via the Internet or other communication networks and share files with them.

As we know,

Using a local network or the Internet, things may be identified, tracked, and monitored is the fundamental tenet of the Internet of Things.

Thus, the Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.

Learn more about the IoT here:

https://brainly.com/question/25703804

#SPJ2

11. Its collection of toys which could be used in the game via an implanted RFID chip made Activision’s game _______ one of the most important in gaming history.
a) 102 Dalmations
b) Skylanders
c) Lego Star Wars
d) Super Monkey Ball

Answers

Answer:

I think it's B correct me if I'm wrong

Explanation:

Answer:

B

Explanation:

I say it is the right one although in this 2021 there is no other game but it is its 10th anniversary

A major advantage of direct mapped cache is its simplicity and ease of implementation. The main disadvantage of direct mapped cache is: a. it is more expensive than fully associative and set associative mapping. b. it has a greater access time than any other method. c. its performance is degraded if two or more blocks that map to the same location are used alternately. d. it does not allow the cache to store the tag that corresponds to the block currently residing in that cache location.

Answers

brainlest   pl     jk  mmmmmmmmmmmmm

Mohammed needs to ensure that users can execute a query against a table but provide different values to the query each time it is run. Which option will achieve this goal?

parameter queries
dynamic queries
query joins
static queries

Answers

Answer:

the answer is B

Explanation:

Annapurno
Page
Date
corite
a programe to input length and the
breath of the rectangle and cliculate the
anecan perimeter .write a program to input length and breadth of the rectangle and calculate the area and perimeter ​

Answers

Answer:

The program in Python is as follows:

Length = float(input("Length: "))

Width = float(input("Width: "))

Area = Length * Width

print("Area: ",Area)

Explanation:

This gets input for length

Length = float(input("Length: "))

This gets input for width

Width = float(input("Width: "))

This calculates the area

Area = Length * Width

This prints the calculated area

print("Area: ",Area)

Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For example, photograph and tomography have several common substrings of length one (i.e., single letters), and common substrings ph, to, and ograph as well as all the substrings of ograph. The maximum common substring length is 6. Let X = X122 . Im and Y = yıy2 - - • Yn be two character strings. Using dynamic programming, design an algorithm to find the maximum common substring length for X and Y using dynamic programming. Please follow the general steps for designing a dynamic programming solution as in Q1 (other than the actual programming part).

Answers

Answer:

Explanation:

The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.

import java.util.*;

class Test

{

   public static void main(String[] args)

   {

       String X = "photograph";

       String Y = "tomography";

       System.out.println(X + '\n' + Y);

       System.out.println("Longest common substring length: " + longestSub(X, Y));

   }

   static int longestSub(String X, String Y)

   {

       char[] word1 = X.toCharArray();

       char[] word2 = Y.toCharArray();

       

       int length1 = X.length();

       int length2 = Y.length();

       int substringArray[][] = new int[length1 + 1][length2 + 1];

       int longestSubstringLength = 0;

       

       for (int i = 0; i <= length1; i++)

       {

           for (int j = 0; j <= length2; j++)

           {

               if (i == 0 || j == 0)

                   substringArray[i][j] = 0;

               else if (word1[i - 1] == word2[j - 1])

               {

                   substringArray[i][j]

                           = substringArray[i - 1][j - 1] + 1;

                   longestSubstringLength = Integer.max(longestSubstringLength,

                           substringArray[i][j]);

               }

               else

                   substringArray[i][j] = 0;

           }

       }

       return longestSubstringLength;

   }

}

Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static method named search. search takes a SearchList as its first parameter and a Comparable as its second. If either parameter is null, or if the SearchList is empty, you should throw an IllegalArgumentException. SearchList is a provided class. It provides a get(int) method that returns the Comparable at that index, and a size method that returns the size of the SearchList. Those are the only two methods you should need! search returns a boolean indicating whether the passed value is located in the sorted SearchList. To search the sorted SearchList efficiently, implement the following algorithm: Examine the value in the middle of the current array (index (start + end) / 2) If the midpoint value is the value that we are looking for, return true If the value that we are looking for is greater than the midpoint value, adjust the current array to start at the midpoint if the value that we are looking for is less than the midpoint value, adjust the current array to end at the midpoint Continue until you find the value, or until the start reaches the end, at which point you can give up and return false This is a fun problem! Good luck! Keep in mind that every time you call SearchList.get that counts as one access, so you'll need to reduce unnecessary accesses to pass the test suite.

Answers

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}

The following table describes the required fields for two classes and typical values stored in those fields.

You are required to create a base class Printer and its child class PrinterCumScanner. Each of these classes should have user defined constructor and overridden Display() method so that the following test driver can work properly.

Answers

Answer:

hope this helps,if it did pls mark my ans as brainliest

Explanation:

using System;

class Printer{ string companyName; int pagesOutput;

double price;

public Printer(string companyName,int pagesOutput,double price){

this.companyName=companyName; this.pagesOutput=pagesOutput; this.price=price;

}

public virtual void Display(){ Console.WriteLine("companyName: "+companyName+" pagesOutput: "+pagesOutput+" price: "+price);

}

}

class PrinterCumScanner:Printer{ int imageDpi;

public PrinterCumScanner(string companyName,int pagesOutput,double price,int imageDpi):base(companyName,pagesOutput,price){ this.imageDpi=imageDpi; }

public override void Display(){ base.Display(); Console.WriteLine("imageDpi: "+imageDpi);

}

}

public class Program { static void Main(string[] args) { const int NUM_PRINTERS=3;

Printer []stock=new Printer[NUM_PRINTERS];

stock[0]=new Printer("HP",40,89.50);

stock[1]=new PrinterCumScanner("HP",40,215.0,320); stock[2]=new PrinterCumScanner("Cannon",30,175.0,240);

foreach(Printer aPrinter in stock){ aPrinter.Display();

}

}

}

Write a function process_spec that takes a dictionary (cmap), a list (spec) and a Boolean variable (Button A) as arguments and returns False: if the spec has a color that is not defined in the cmap or if Button A was pressed to stop the animation Otherwise return True

Answers

Answer:

Explanation:

The following code is written in Python. The function takes in the three arguments and first goes through an if statement to check if Button A was pressed, if it was it returns False otherwise passes. Then it creates a for loop to cycle through the list spec and checks to see if each value is in the dictionary cmap. If any value is not in the dictionary then it returns False, otherwise, it returns True for the entire function.

def process_spec(cmap, spec, buttonA):

   if buttonA == True:

       return False

   

   for color in spec:

       if color not in cmap:

           return False

   return True

10.The front end side in cloud computing is​

Answers

Answer:

The front end is the side the computer user, or client, sees. The back end is the "cloud" section of the system.

The front end includes the client's computer (or computer network) and the application required to access the cloud computing system.

Explanation:

can i have brainliest please

Sergio needs to tell his team about some negative feedback from a client. The team has been
working hard on this project, so the feedback may upset them. Which of the following explains
the best way for Sergio to communicate this information?

A) Hold an in person meeting so that he can gauge the team's body language to assess their
reaction

B) Send a memorandum so everyone will have the feedback in writing

C) Hold a video conference so everyone can see and hear about the client's concern without the group witnessing each other's reactions

D) Send an email so everyone will have time to think about the feedback before the next team meeting

Answers

Answer:

A

Explanation:

I feel that if everyone is with eachother, there may be a better hope to improve the next time

CHALLENGE ACTIVITY
1.6.1: Type casting: Computing average owls per zoo.
Assign avg_owls with the average owls per zoo. Print avg_owls as an integer.

Sample output for inputs: 1 2 4
Average owls per zoo: 2

-------------------------------------------------------------------
Someone please explain what I am doing wrong?

Answers

Answer:

avg_owls=0.0

num_owls_zooA = int(input())

num_owls_zooB = int(input())

num_owls_zooC = int(input())

num_zoos = 3

avg_owls = (num_owls_zooA + num_owls_zooB + num_owls_zooC) / num_zoos

print('Average owls per zoo:', int(avg_owls))

Explanation:

There is a problem while you are trying the calculate the average owls per zoo.

As you may know, in order to calculate the average, you need to get the total number of owls in all the zoos, then divide it to the number of zoos. That is why you need to sum num_owls_zooA + num_owls_zooB + num_owls_zooC and divide the result by num_zoos

Be aware that the average is printed as integer value. That is why you need to cast the avg_owls to an int as int(avg_owls)

6. Which of the following games will most likely appeal to a casual player?
a) Wii Sport
b) Contra
c) Farmville
d) Both A and C

Answers

Answer:

A

Explanation:

Wii sports is a good game for a casual player. :)

The variable strFirst's scope is _____.

Answers

pretty sure it’s d, hope this helps

Answer:

- the usernameMaker function

Explanation:

When you look at the code, you can see it's located alongside the usernameMaker. It it only utilized then, therefore being it's scope. For reassurance, it's also correct on Edge.

I hope this helped!

Good luck <3

Taran is concerned with the security of his macros in a database. Which security option could he use to provide protection?

digital signatures
hide database objects
start-up options
secure VBA code

Answers

Answer:security VBA code

Explanation:

Which tab can be used to change the theme and background style of a presentation?
O Design
O Home
O Insert
O View

Answers

Answer:

Design

Explanation:

seems the most correct one..

I would say design as well.

I need help
I am thinking about coming out to my mom because we are going to the store today and I will be in the car, I dont know if I should or not

Answers

Answer:

do it! you will have to one day so why not now? hopefully she will understand and say nice things as well and be like mom ive

been thinking a lot and i really want to tell you something. Explanation:

Answer:most likely she is your parent that you live with so she might already know but has not said anything it also depends her personality but if your ready and know or think she would not hate you forever go for it

Explanation:

What does getfenv() do?

Answers

Answer: getfenv() is a type of function. Particually a envirotment function. for a lua coding.

Explanation: What this does it goes thourgh  line of code in a particular order.

This means. getfenv is used to get the current environment of a function. It returns a table of all the things that function has access to. You can also set the environment of a function to another environment.

Forgot to include examples of where this could be used. Although not very common uses, there are some. In the past Script Builders used getfenv to get the environment of a script, and setfenv to set the environment of a created script’s environment to a fake environment, so they couldn’t affect the real one. They could also inject custom global functions.

Not entirely sure if this uses getfenv or setfenv, but the use in Crazyman32’s AeroGameFramework is making the environment of each module have access to other modules without having to require them, and having access to remotes without having to directly reference them.

Answer: ummm, who knows

Explanation:

Write an algorithm (pseudo-code) that takes an unsorted list of n integers and outputs a sorted list of all duplicate integers. There must be no duplicates in the output list, also the output list should be a sorted list. The algorithm must run in O(n) time. Show your analysis of the running time. Note: Assume that inputs are integer values from 0 to 255. (Hint: use the concept that being used in the separate chaining)

Answers

Answer:

brainliest if it did help you

Explanation:

Given array : A[0...n-1]Now, create a count array Cnt[0...n-1]then, initialize Cnt to zero

for(i=0...n-1)

Cnt[i]=0 ---------O(n) time

Linearly traverse the list and increment the count of respected number in count array.

for(i=0...n-1)

Cnt[A[i]]++; ---------O(n) time

Check in the count array if duplicates exist.

for(i=0...n-1){

if(C[i]>1)

output (i); -----------O(n) time

}

analysis of the above algorithm:

Algorithm takes = O(1 + n + n + n)

                           = O(n)          

//java code

public class SortIntegers {

  public static void sort(int[] arr) {

    int min = arr[0];

    int max = arr[0];

    for (int i = 0; i < arr.length; ++i) {

      if (arr[i] > max) {

        max = arr[i];

      }

      if (arr[i] < min) {

        min = arr[i];

      }

    }

    int counts[] = new int[max - min + 1];

    for (int i = 0; i < arr.length; ++i) {

      counts[arr[i] - min]++;

    }

    for (int i = 0; i < counts.length; ++i) {

      if (counts[i] > 1) {

        System.out.print((i + min) + " ");

      }

    }

    

    System.out.println();

  }

  public static void main(String[] args) {

    sort(new int[] { 5, 4, 10, 2, 4, 10, 5, 3, 1 });

  }

}

Need help with 9.2 Lesson Practice edhesive asap please

Answers

Answer:

Can you add an attachment please

In this exercise we have to use the computer language knowledge in python, so the code is described as:

This code can be found in the attached image.

So the code can be described more simply below, as:

height = []

height.append([16,17,14])

height.append([17,18,17])

height.append([15,17,14])

print(height)

See more about python at brainly.com/question/26104476

14. Video game legend Shigeru Miyamoto designed all EXCEPT which of the following games?
a) Donkey Kong
b) Mario Bros
c) The Legend of Zelda
d) Pac-Man

Answers

D pac man hope im right

Identify the following terms being described. Write your answers on the space provided.

1. Worldwide Web
______________________
2.E-mail
________________________
3.Powerline networking
_______________________
5.Cable
_______________________

Answers

Answer:

Find answers below.

Explanation:

1. Worldwide Web: In computing, WWW simply means World Wide Web. The world wide web was invented by Sir Tim Berners-Lee in 1990 while working with the European Council for Nuclear Research (CERN); Web 2.0 evolved in 1999. Basically, WWW refers to a collection of web pages that are located on a huge network of interconnected computers (the Internet). Also, users from all over the world can access the world wide web by using an internet connection and a web browser such as Chrome, Firefox, Safari, Opera, etc.

In a nutshell, the World Wide Web is an information system that is generally made up of users and resources (documents) that are connected via hypertext links.

2.E-mail: An e-mail is an acronym for electronic mail and it is a software application or program designed to let users send and receive texts and multimedia messages over the internet.

It is considered to be one of the most widely used communication channel or medium is an e-mail (electronic mail).

3. Powerline networking: this is a wired networking technology that typically involves the use of existing electrical cables in a building to connect and transmit data on network devices through powerline network adapters.

4. Cable: this include network cables such as CAT-5, CAT-6 and fiber optic cables used for connecting and transmitting signals between two or more network devices.

In the code snippet below, pick which instructions will have pipeline bubbles between them due to hazards.

a. lw $t5, 0($t0)
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
d. sw $t3, 12($t0)
e. lw $t2, 8($t0)
f. add $t1, $t5, $t2
g. sw $t1, 16($t0)

Answers

Answer:

b. lw $t4, 4($t0)

c. add $t3, $t5, $t4

Explanation:

Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.

(main.c File)
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt”
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used – times.
b was used – times.
c was used – times…. …and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array]
Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]

Answers

Answer:

C code

Explanation:

#include <stdio.h>

void histrogram(int counters[])

{

   int i,j;

   int count;

   for(i=0;i<26;i++)

   {

       count=counters[i];

       printf("%c ",i+97);

       for(j=0;j<count;j++)

       {

           printf("="); //= is used

       }

       printf("\n");

      

   }

      

}

int main()

{

   FILE* fp;

   int i;

   int arr[26];

   char c;

   int val;

   // Open the file

fp = fopen("story.txt", "r");

  

if (fp == NULL) {

printf("Could not open file ");

return 0;

}

else

{

   for(i=0;i<26;i++)

   arr[i]=0;

  

   for (c = getc(fp); c != EOF; c = getc(fp))

   {

       if(c>='a' && c<='z')

       {

           val = c-97;

           //printf("%d ",val);

           arr[val]++;

          

           }

       }

       histrogram(arr);

      

  

      

  

   }

}

Suppose the program counter is currently equal to 1700 and instr represents the instruction memory. What will be the access of the next instruction if:

instr[PC] = add $t0, $t1, $t2

Answers

Answer:

C

Explanation:

omputer chip

sorry btw

Write a script called fact.sh that is located in your workspace directory to calculate the factorial of a number n; where n is a non-negative integer between 1 and 20 that is passed as a parameter from the command line (e.g. ./fact.sh 5). The result should be echoed to the screen as a single integer (e.g. 120).
NOTE: Do not include any other output, just output the single integer result.
Submit your code to the auto-grader by pressing Check-It!
NOTE: You can submit as many times as you want up until the due date.

Answers

Answer:

hope this helps

Explanation:

what is the output of this line of code?
print("hello"+"goodbye")
-"hello"+"goodbye"
-hello + goodbye
-hello goodbye
-hellogoodbye

Answers

The first one
“hello” + “goodbye”

Answer:

“hello” + “goodbye”

Explanation:

Outlines help you visualize the slides and the points you will include on each slide.
False
True

Answers

I don’t know I think true

Answer:

True

Explanation:

because it was correct

Selection Sort List the resulting array after each iteration of the outer loop of the selection sort algorithm. Indicate the number of character-to-character comparisons made for each iteration (line 07 of the Selection Sort algorithm at the end of the assignment). Sort the following array of characters (sort into alphabetical order): CQS A XBT Selection Sort 01 public static void selectionSort (int[] a) { 02 03 int n = a.length; for (int i = 0 ; i 0; j--) { if ( a[j-1] > a[j] ) { exchange(a, j-1, j); } else break; 10 } 12 private static void exchange (int[] a, int i, int j) { 13 // exchange the value at index i with the value at index j int temp = a[i]; a[i] = a[j]; a[j] = temp; 17 }

Answers

Solution :

Initial array = [tex]$\text{C,Q,S,A,X,B,T}$[/tex]

[tex]$n= 7$[/tex](length of the array)

[tex]$\text{1st}$[/tex] Iteration:

i = 1

  j = 1

  [tex]$\text{a[j-1]}$[/tex] = C

  a[j] = Q

  since [tex]$\text{a[j-1]}$[/tex] < a[j] , break from inner loop

 

Number of comparisons in 1st Iteration = 1

After 1st Iteration:

Array : C,Q,S,A,X,B,T

2nd Iteration:

i = 2

  j = 2

  a[j-1] = Q

  a[j] = S

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 2nd Iteration = 1

After 2nd Iteration:

Array : C,Q,S,A,X,B,T

3rd Iteration:

i = 3

  j = 3

  a[j-1] = S

  a[j] = A

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : C,Q,A,S,X,B,T

 

  j = 2

  a[j-1] = Q

  a[j] = A

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : C,A,Q,S,X,B,T

 

  j = 1

  a[j-1] = C

  a[j] = A

  since a[j-1] > a[j], exchange a[0] with a[1]

  Array : A,C,Q,S,X,B,T

 

  j = 0, break from inner loop

Number of comparisons in 3rd Iteration = 3

After 3rd Iteration:

Array : A,C,Q,S,X,B,T

4th Iteration:

i = 4

  j = 4

  a[j-1] = S

  a[j] = X

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 4th Iteration = 1

After 4th Iteration:

Array : A,C,Q,S,X,B,T

5th Iteration:

i = 5

  j = 5

  a[j-1] = X

  a[j] = B

  since a[j-1] > a[j], exchange a[4] with a[5]

  Array : A,C,Q,S,B,X,T

 

  j = 4

  a[j-1] = S

  a[j] = B

  since a[j-1] > a[j], exchange a[3] with a[4]

  Array : A,C,Q,B,S,X,T

 

  j = 3

  a[j-1] = Q

  a[j] = B

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : A,C,B,Q,S,X,T

 

  j = 2

  a[j-1] = C

  a[j] = B

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : A,B,C,Q,S,X,T

 

  j = 1

  a[j-1] = A

  a[j] = B

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 5th Iteration = 5

After 5th Iteration:

Array : A,B,C,Q,S,X,T

6th Iteration:

i = 6

  j = 6

  a[j-1] = X

  a[j] = T

  since a[j-1] > a[j], exchange a[5] with a[6]

  Array : A,B,C,Q,S,T,X

 

  j = 5

  a[j-1] = S

  a[j] = T

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 6th Iteration = 2

After 6th Iteration:

Array : A,B,C,Q,S,T,X

Sorted Array : A B C Q S T X  

Explain the five generations of computer

Answers

Answer:

1 First Generation

The period of first generation: 1946-1959. Vacuum tube based.

2 Second Generation

The period of second generation: 1959-1965. Transistor based.

3 Third Generation

The period of third generation: 1965-1971. Integrated Circuit based.

4 Fourth Generation

The period of fourth generation: 1971-1980. VLSI microprocessor based.

5 Fifth Generation

The period of fifth generation: 1980-onwards. ULSI microprocessor based.

The phrase "generation" refers to a shift in the technology that a computer is/was using. The term "generation" was initially used to describe different hardware advancements. These days, a computer system's generation involves both hardware and software.

Who invented the 5th generation of computers?

The Japan Ministry of International Trade and Industry (MITI) launched the Fifth Generation Computer Systems (FGCS) initiative in 1982 with the goal of developing computers that use massively parallel computing and logic programming.

The generation of computers is determined by when significant technological advancements, such as the use of vacuum tubes, transistors, and microprocessors, take place inside the computer. There will be five computer generations between now and 2020, with the first one starting around 1940.

Earlier models of computers (1940-1956)Computers of the Second Generation (1956-1963)Computers of the Third Generation (1964-1971)Computers of the fourth generation (1971-Present)Computers of the fifth generation

Learn more about generations of computers here:

https://brainly.com/question/9354047

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