which of the following amino acids may be considered hydrophobic at physiological ph?
a. isoleucine
b. Arginine
c. Aspartic acid
d. Threonine​

Answer:

until the next harvest, and seed must be held for the next season's ... successful grain storage is the moisture content of the crop. ... or both. If ambient temperatures are low, then air alone may cool the ... allow some of the drying to take place naturally while the crop ... employed to cool grain that has been placed in storage.

Answer:

meeting ones legal responsibility

Answer:

7.15g/cm³

Explanation:

To solve this question we must know that a body-centered cubic unit cell contains 2 atoms.

The volume of the unit cell is:

289pm = (289x10⁻¹²m)³ =

2.414x10⁻²⁹m³ * (1cm³ / 1x10⁻⁶m³) = 2.414x10⁻²³cm³

And the mass is -Molar mass Chromium = 51.9961g/mol:

2atoms * (1mol / 6.022x10²³atoms) * (51.9961g / mol) =

1.727x10⁻²²g

The density is:

1.727x10⁻²²g / 2.414x10⁻²³cm³ =

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

Answer:

Explain

The Akautski is now assembled

The final temperature of the system can be calculated using calorimetric equation. The heat gained by water is equal to the heat lost by iron. Hence, the final temperature is 28 °C.

Calorimetry is an analytical tool used to determine the heat energy absorbed or released by a system. The calorimetric equation connecting the heat energy q with mass m, specific heat capacity c and temperature difference ΔT is given as:

q = m c ΔT

Here, the heat lost by iron = heat gained by water

m of iron = 255.15 g

initial temperature = 816 °C

c = 0.461 J/°C g.

Mass of water = 4000 g

c = 4.18 J/°C g

initial temperature = 23 °C

Let T be the final temperature of the system.

then,

0.461 J/°C g × 255.15 g × (816 - T) = 4.18J/°C g × 4000 g × (T - 23)

117.62 J(816 - T) = 16720 (T - 23)

T = 28°C.

Therefore, the final temperature of the system will be  28°C.

Find more on calorimetry:

https://brainly.com/question/11477213

#SPJ7

Answer:

The answer is:

[tex]PART \ A: CH_4\\\\PART \ B: CH_30H\\\\PART \ C: H_2CO[/tex]

Explanation:

Parts A:

The vapor pressure is higher in [tex]CH_4[/tex] because it is non-polar, while [tex]CH_3Cl[/tex] is polar. [tex]CH_4[/tex] has a lower molar weight as well.

Part B:

Although hydrogen bonding is found in both commodities, the vapor pressure is higher because of the smaller molar mass of [tex]CH_30H[/tex].

Part C:

[tex]H_2CO[/tex] does not show hydrogen due to the increased vapor pressure

[tex]CH_3OH[/tex] bonding.

Answer:

203 grams

Explanation:

The no. of moles of (6.3 x 10²⁴ molecules--Avagadros number) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.

The no. of grams of NH₃ present = no. of moles x molar mass = (11.96 mol)(17.0 g/mol) = 203.3 g ≅ 203.0 g.

The answer is the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is 203 grams.

A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

6.02214076 × 10²³  molecules constitutes 1 mole of NH₃

7.20 x 10²⁴ molecules constitutes of

[tex]\rm\dfrac{7.20 \times 10^{24}}{6.02\times 10^{23}}\\[/tex]

=11.19 moles

1 mole of NH₃ = 17 gm

11.19 mole will be = 17 * 11.19

= 203 grams

Therefore the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is  203 grams.

To know more about molecule

https://brainly.com/question/19922822

#SPJ2

Answer:

Explanation:

Given Information :

Mass = 4.0kg

Acceleration  due to gravity = 10 m/s

Weight= ?

[tex]Weight = \frac{mass}{acceleration\: due \:to \:gravity} \\\\W= \frac{4.0}{10} \\\\W= \frac{2}{5} \\\\W=0.4[/tex]

Answer:

Q = -535 J.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:

[tex]Q=mC(T_F-T_i)[/tex]

Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:

[tex]Q=28.3g*0.450\frac{J}{g\°C} (24.0\°C-66.0\°C)\\\\Q=-535J[/tex]

Regards

Answer:

B.Anything that takes up space and has mass

Answer:

What about it? I don't get the question

Answer:

Q = 797.5 cal

Explanation:

Given that,

Mass of iron, m = 50 g

The temperature rises from 55°C to 200°C.

We need to find the heat needed to raise the temperature. The heat raised is given by :

[tex]Q=mc\Delta T[/tex]

Put all the values,

[tex]Q=50\times 0.11\times (200-55)\\\\Q=797.5\ cal[/tex]

So, 797.5 calories of heat is needed.

Answer:

P = 487 Torr

mN₂ = 0.347 g

mO₂ = 0.174 g

mHe = 0.0333 g

Explanation:

Step 1: Calculate the total pressure of the mixture

The total pressure of the mixture (P) is equal to the sum of the partial pressures of the gases.

P = pN₂ + pO₂ + pHe

P = 231 Torr + 101 Torr + 155 Torr = 487 Torr

Step 2: Calculate the moles of each gas

We have 3 gases in a 1.00 L container at 25.0 °C (298.2 K). We can calculate the number of moles using the ideal gas equation: P × V = n × R × T.

nN₂ = pN₂ × V / R × T

nN₂ = 231 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.0124 mol

nO₂ = pO₂ × V / R × T

nO₂ = 101 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00543 mol

nHe = pHe × V / R × T

nHe = 155 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00833 mol

Step 3: Calculate the mass of each gas

The molar mass of N₂ is 28.01 g/mol.

mN₂ = 0.0124 mol × 28.01 g/mol = 0.347 g

The molar mass of O₂ is 32.00 g/mol.

mO₂ = 0.00543 mol × 32.00 g/mol = 0.174 g

The molar mass of He is 4.00 g/mol.

mHe = 0.00833 mol × 4.00 g/mol = 0.0333 g

Answer:

50 g Sucrose

Explanation:

Step 1: Given data

Step 2: Calculate the mass of sucrose needed to prepare the solution

The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:

2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: [tex]V_{1}[/tex] = 571 mL,       [tex]T_{1} = 26^{o}C[/tex]

(a) [tex]T_{2} = 5^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL[/tex]

(b) [tex]T_{2} = 95^{o}F[/tex]

Convert degree Fahrenheit into degree Cesius as follows.

[tex](1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL[/tex]

(c) [tex]T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL[/tex]

Mass of Calcium Carbonate = 500 grams

The required reaction would be:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

Number of moles of CaCO₃:

Number of moles = given mass / molar mass

Number of moles = 500 / 100              [molar mass of CaCO₃ = 100g/mol]

Number of moles = 5 moles

Using the power of stoichiometry!!!

CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

from the balanced reaction listed above, we can see that one mole of CaCl₂ and one mole of Na₂CO₃ produces one mole of CaCO₃

Moles of CaCl₂ = Moles of Na₂CO₃ = Moles of CaCO₃

we just solved for the number of moles of CaCO₃, which gives us

Moles of CaCl₂ = Moles of Na₂CO₃ = 5 moles

Hence, 5 moles of CaCl₂ and Na₂CO₃ each is required

Unnillium (101)

Unnilbium (102)

Unniltrium (103)

Unnilquadium (104)

Unnilpentium (105)

Unnilhexium (106)

Unnilseptium (107)

Unniloctium (108)

Unnilennium (109)

Ununnillium (110)

Answer:

A budget is an estimation of revenue and expenses over a specified future period of time and is usually compiled and re-evaluated on a periodic basis. Budgets can be made for a person, a group of people, a business, a government, or just about anything else that makes and spends money.

Answer:

ecosystem i think

Answer:

c. composed of only one type of atom or molecule.

Explanation:

Pure substances are the substances that could be made up of only one type of particles and also it contains fixed structure. They would be further categorized as the elements & compounds. It is an elements that only consist of only one type of atom or molecule

Therefore as per the given situation, the option c is the answer

Answer: correct answer is C

Explanation:

Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

Aluminium and Nitrogen!

Answer:

A

Explanation:

Hydrogen isn't an alkali metal

Answer:

hydrogen

Explanation:

hydrogen is a gas not a metal

Answer:

mass of sucrose = 17.115 grams

Explanation:

Given that:

mass = 2000 grams

molar mass of sucrose = 342.3 g/mol

2.5% of the sucrose soltion.

Let assume we are given 1 M of the sucrose solution;

2.5% of 1 M = 0.025 M

∴

Molarity = ( mass/molar  mass )(1000/V)

mass = (0.025 * 342.3 * 2000)/(1000)

mass of sucrose = 17.115 grams

Answer:I believe it is c.

Explanation:

Answer:

C., or "geothermal energy."