Answer:
answer a is correct
Step-by-step explanation:
Answer: A. 5 positive x-tiles and 6 positive unit tiles on the left side; 4 positive x-tiles and 3 negative unit tiles on the right side
Step-by-step explanation: On Edge!!!!!!!!!!!
Imagine a player getting ready for a tournament. He has 4 games to play during the day: 9:00 a.M., 11:00 a.M., 1:00 p.M., and 3:30 p.M. He refuses to wear shorts until temperature rises to at least +5 degrees. Based on a starting temperature of -9 degrees at 6am and an increase in temperature of 2 degrees an hour, when might he be able to change from his pants to shorts? Provide explanations why he can/can't put his shorts on for Game 1, Game 2, Game 3 and Game 4.
Answer:
by game 3(at 1:00 p.m.)
temperature increases to 5 degrees at 1:00 p.m
What is the slope of the line that contains the points (0, -8) and (4, 1)?
4
OA)
9
9
B)
4
C) 4
7
OD)
4
Answer:
9/4
Step-by-step explanation:
Using the slope formula
m = (y2-y1)/(x2-x1)
= (1--8)/( 4-0)
= (1+8)/4
= 9/4
What is the appropriate symbol? 1.42 _____ 1.420 = < >
Answer:
=
Step-by-step explanation:
1.42 is equal to 1.420. The 0 adds no value since it is after the decimal point so 1.420 is just 1.42, which is equal to itself, 1.42.
Answer:
=
Step-by-step explanation:
When you are looking at decimals, specifically on the right side of the decimal point, the amount of 0's after the last given non-0 digit can be disregarded.
1.420 is the same as 1.42
With this given information:
1.42 ____ 1.420
1.42 ____ 1.42
1.42 = 1.42
= would be your sign.
~
Find the slope of the line that passes
through these two points.
Point 1(3,5) Point 2(4,2)
Answer:
Slope = -3
Step-by-step explanation:
(3 , 5) ; (4, 2)
[tex]Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{2-5}{4-3}\\\\=\frac{-3}{1}\\\\=-3[/tex]
If f(x) = 3^x + 10x and g(x) = 2x - 4, find (f + g)(x)
Answer:
3^x + 12x -4
Step-by-step explanation:
f(x) = 3^x + 10x
g(x) = 2x - 4,
(f + g)(x) = 3^x + 10x + 2x - 4
Combine like terms
= 3^x + 12x -4
Answer:
(f + g)(x)= 3^x +12x -4
Step-by-step explanation:
To find (f+g)(x), we must add f(x) and g(x).
(f + g)(x)= f(x) + g(x)
We know that f(x)= 3^x + 10x and g(x)= 2x-4
Therefore, we can substitute these into the equation.
(f + g)(x)= (3^x+10x) + (2x-4)
Combine like terms. Add all the terms with an x.
(f + g)(x)= 3^x + (10x+2x) -4
(f + g)(x)= 3^x +12x -4
(f + g)(x) is 3^x +12x -4
The points (0, –1) and (4, 5) lie on the straight line L.
Find an equation of the line which is parallel to L and passes through the point (–2, 0).
Answer:
y = 3/2x + 3.
Step-by-step explanation:
With these two points, we can find the equation of line L.
y = mx + b
Slope: (5 --1) / (4 - 0) = 5 + 1 / 4 = 6 // 4 = 3/2
Intercept: [stated by the first pair of coordinates] (0, -1)
y = 3/2x - 1
Since the line is parallel to L, the slope is the same as line L.
y = 3/2x + b
The line passes through (-2, 0), so we can substitute the points into the equation and solve for b.
0 = 3/2 * -2 + b
b - 3 = 0
b = 3
So, the equation of the line which is parallel to L and passes through the point (-2, 0), is y = 3/2x + 3.
Hope this helps!
How is the graph of the cosine function different from the graph of the sine function? How is it the same?
Answer:
Similarity:
In Both cosine and sine graphs, a positive and negative number vertically flips the graph and tells whether the graph starts at maximum (positive) or minimum (negative).
Difference:
The difference between the sine and the cosine graph is the point where they start.
The graph of positive cosine starts at the maximum while that of the negative cosine starts at the minimum.
The graph of a positive sine starts at the middle, goes up and then down while that of the negative sine starts at the middle goes down and then up.
Five thousand tickets are sold atâ $1 each for a charity raffle. tickets are to be drawn at random and monetary prizes awarded asâ follows: 1 prize of â$500â, 3 prizes of â$300â, 5 prizes of â$30â, and 20 prizes ofâ $5. what is the expected value of this raffle if you buy 1â ticket?
Answer:
-$0.67
Step-by-step explanation:
If you buy one ticket, the possible outcomes are:
100% chance of spending $1 (buying the ticket)
1 in 5,000 chance of winning $500
3 in 5,000 chance of winning $300
5 in 5,000 chance of winning $30
20 in 5,000 chance of winning $5.
The expected value of the raffle is determined by:
[tex]E(X)=-1+\frac{1}{5,000}*500+\frac{3}{5,000}*300+\frac{5}{5,000}*30+\frac{20}{5,000}*5\\E(X)=-\$0.67[/tex]
The expected value of this raffle if you buy 1 ticket is -$0.67.
A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 lower than in the first. The tax in the first city was 3%, and the tax in the second city was 7.5% . The total hotel tax paid for the two cities was $487.50. How much was the hotel charge in each city before tax? First city: Second city:
Answer:
Step-by-step explanation:
Lets assume that x (First city) and x-500 (Second City)
[tex]x.\frac{3}{100} +(x-500)\frac{7.5}{100} =487.5\\\\\frac{3x+7.5x-3750}{100}=487.5\\ 10.5x=48750+3750\\10.5x=52500\\x=5000 (first city)\\5000-500(second city)\\[/tex]
You can ask me ıf you don't understand
I need help with this question please help
A $3,000 bond has coupons at a rate 12% paid semi-annually and matures on December 1st, 2025 at $3,200. Find the practical clean and dirty book values of this bond on October 15th, 2020 to yield 6% convertible semi-annually.
Answer:
Clean price is $3,977.22
Dirty price = $4110.99
Step-by-step explanation:
We proceed as follows;
Semiannual coupon payments = $3000* 12%/2 = 6% * 3,000 = 6/100 * 3,000 = $180
Coupons are paid on 1st June and 1st December every year(semi-annually means twice a year, every 6 months)
No. of payments remaining = 11 (1 payment in 2020 on 1st December,2020 and 2 in each of the following 5 years)
Semiannual Yield = 6%/2 =3%
The clean price of the bond is given by
P = 180/1.03+ 180/1.03^2+.....+180/1.03^11+ 3200/1.03^11
=180/0.03*(1-1/1.03^11)+3200/1.03^11
=$3977.22
Dirty price = clean price +accrued interest
Accrued Interest = Interest from 1st June , 2020 to 1st December,2020
= no of days from 1st June to 15th October/no of days from 1st June to 1st December * $180
= 136/183*$180
=$133.77
So, Dirty price = $3977.22+$133.22 = $4110.99
The nth term of a sequence is n(n - 1).
What are the first four terms?
What is the 50th term?
Is 59 a term in the sequence?
Which term is 182?
The ______ th term
Answer:
T1=0
T2=2
T3=6
T4=12
T50=2450
59 is not a term in the sequence
Step-by-step explanation:
Tn=n(n-1)
182=n2 - n
0=n2 - n - 182
0=n2-14n+13n-182
0=n(n-14)+13(n-14)
0=(n-14) (n+13)
Since n cannot be negative n is not equal to -13
Therefore,
n=14
Five submarines sink on the same day, and all five go down at the same spot where a sixth had previously sunk. How might they all lie at rest so that each submarine touches the other five? To simplify, arrange six wooden matches so that each match touches every other match. No bending or breaking allowed.
Answer:
picture is attached
Step-by-step explanation:
there are many options but this is one
3x = 2x + 18 : slove the equation
Answer:
3x= 2x+18
3x-2×=2×-2×+18
×=18
Answer:
18
Step-by-step explanation:
3x = 2x + 18
3x - 2x = 18
x = 18
solve (-t-5)/3= (t-3)/5
Answer & Step-by-step explanation:
[tex]\frac{-t-5}{3}=\frac{t-3}{5}[/tex]
Cross multiply.
[tex]-5t-25=3t-9[/tex]
Subtract -3 on both sides.
[tex]-8t-25=-9[/tex]
Add 25 on both sides.
[tex]-8t=16[/tex]
Divide -8 on both sides.
[tex]t=-2[/tex]
Please answer this question fast in 2 minutes
Answer:
<5solution,
<3+<4=180°( linear pair)----> equation (i)
<4+<5=180°( linear pair)------>equation (ii)
From equation (i) and (ii)
<3+<4=<4+<5
<3=<5 (vertically opposite angles)
hope this helps...
Good luck on your assignment
Plzzz helpppp urgenly❤️
Answer:
[tex]\mathrm{D.} \: (\frac{5}{4} )^{\frac{7}{2}[/tex]
Step-by-step explanation:
[tex]\sqrt{(\frac{5}{4})^7 }[/tex]
Apply rule : [tex]\sqrt{a} =a^{\frac{1}{2} }[/tex]
[tex]((\frac{5}{4})^7 )^{\frac{1}{2} }[/tex]
Apply rule : [tex](a^b)^c=a^{bc}[/tex]
[tex](\frac{5}{4} )^{7 \times \frac{1}{2} }[/tex]
[tex](\frac{5}{4} )^{\frac{7}{2}[/tex]
NEED HELP ASAP!!! thanks!!!
Answer:
6.1 square units
Step-by-step explanation:
Since the triangle was translated from one position to another position, the dimensions of the triangle have not changed. The pre-image and image are congruent.
area = base * height/2
The two sides forming a right angle can be used as the base and the height in the area formula.
BC = base = 2
AB = A'B' = height = 6.1
area = 2 * 6.1/2
area = 6.1 square units
The probability that Paul wins a raffle is given by the expression n/n + 6 . What is the expression, in the form of a combined single fraction, for the probability that Paul does not win.
Answer:
The probability that he doesn’t win is 6/(n + 6)
Step-by-step explanation:
Mathematically, the probability that an event occur is 1 minus the probability that the event doe not occur.
Thus, what we are saying here is that the sum of the probabilities that Paul wins the raffle draw and he doesn’t win the raffle draw is 1
This can be mathematically expressed as;
probability that he doesn’t win = 1 - probability that he wins
Thus we have;
1- n/(n+ 6)
= [(n+ 6) -(n)]/(n+6) = 6/n+ 6
The probability that my bus is late on any day is 0.2. The probability that it rains tomorrow is 0.4. If the weather and the bus are independent, what is the probability that it rains AND my bus is late?
Answer:
0.08
Step-by-step explanation:
The probability that the bus is late on any day is 0.2
The probability that it rains tomorrow is 0.4
The probability that it will rain tomorrow and the bus is late is the product of both individuals probabilities.
Therefore:
P(late & rains) = 0.2 * 0.4 = 0.08
Answer:
The probability that it rains and the bus is late is 1/7
Step-by-step explanation:
Practically, we can apply the Bayes’ theorem to solve this.
Mathematically, we use the Bayes’ problem as follows;
P( rain| late) = P(rain ^ late)/P(late) = P( late|rain) • P(rain)/[P(late|rain)P(rain) + P(not late|no rain)P(no rain)]
Where P(no rain) = 1-P(rain) = 1-0.4 = 0.6
P(on time) = 1-P(late) = 1-0.2 = 0.8
Kindly recall that P of raining = 0.4 and the probability that the bus is late is 0.2
Substituting these values into the Bayes’ equation above, we have;
P( rain| late) = (0.2)(0.4)/(0.2)(0.4) + (0.8)(0.6)
= 0.08/(0.08 + 0.48) = 0.08/0.56 = 1/7
NEED ANSWER IN 2 MINUTES!
Answer: 11
Step-by-step explanation:
The stem is the 10s place and leaf is the ones
Work out angle x Triangles are not drawn to scale
Answer:
1) x = 71°, 2) x = 27°, 3) x= 32°
Step-by-step explanation:
1) Rectangle ABCD.
∠D = 90°
From ΔABE.
∠EAB +∠ABE + ∠BEA = 180°
45 + 90 +∠BEA = 180
∠BEA = 45
∠BEA + ∠AED +∠DEC = 180 °, because ∠BEC is a straight angle
45 + x + 64 = 180
x = 71°
2) Δ XYZ is equilateral, all angles = 60°.
∠YZX = 60°.
∠YZW = 180°, because it is a straight angle.
∠YZX + ∠XZW= 180
60 + ∠XZW= 180
∠XZW = 120.
From ΔXZW
∠ZXW + ∠XWZ + WZX = 180
x + 33 + 120 = 180
x = 27°
3) In ΔPQR,
PQ = PR, so ∠PQR = ∠PRQ = 69°
∠PRQ + ∠PRS = 180, because ∠QRS = 180° as straight angle.
∠PRQ + ∠PRS = 180
69 + ∠PRS = 180
∠PRS = 111°.
From ΔPRS
∠PRS + ∠RSP + ∠SPR = 180
111 + 37 + ∠SPR = 180
111 + 37 + x= 180
x = 32
Suppose you invest $2250 in a D that earns 3% APR and is compounded monthly. The Cd matures in 2 years. How much will this CD be worth at maturity?
Answer:
$2388.95
Step-by-step explanation:
Principal, P= $2250Annual Interest Rate, r= 3% =0.03Time, n= 2 yearsSince it is compounded monthly, Period, k= 12 MonthsThe worth of a compound deposit after a period of n years is calculated using the formula:
[tex]A(n)=P(1+\frac{r}{k})^{nk}[/tex]
[tex]A(2)=2250(1+\frac{0.03}{12})^{12 \times 2}\\\\=2250(1+0.0025)^{24}\\=2250(1.0025)^{24}\\=\$2388.95[/tex]
At maturity, the deposit will be worth $2388.95.
What is the measure of Angle c? 3 lines intersect to form 5 angles. Clockwise, from top left, the angles are b, 90 degrees, c, 124 degrees, a.
Answer:
c
Step-by-step explanation:
Answer:the answer is 90
Step-by-step explanation:
A flare is fired from 4 feet above the ground at a speed of 64 feet per second. The flare will fall to the ground after it burns out.
Answer:
68 feet.Step-by-step explanation:
At maximum height, the velocity of the flare will be zero.
If the flare height above the ground is modeled by the equation
h = -16t²+64t+4
Velocity = dh/dt = 0
-32t + 64 = 0
-32t = -64
t = -64/-32
t = 2secs
This shows that the flare reaches its maximum height after 2secs.
To get the maximum height of the flare, we will substitute t = 2s into the equation h = -16t²+64t+4
h = -16(2)² + 64(2)+4
h = -64+128+4
h = 64+4
h = 68 feet
The maximum height of the flare is 64 feet.
-145 < -14_> -143
a. 4
b. 1
C. 6
d. 9
Answer:
b
Step-by-step explanation:
-141 is larger than -143 and -145
please answer this question!!!! In the graphic above, ΔRQS ≅ ΔTUS by: SSS. AAA. SSA. None of these choices are correct.
Answer:
ssa
Step-by-step explanation:
Answer: SSA
SSA typically applies when there are two triangles
Find the length of AB
Hey there! :)
Answer:
arc AB = 2.5π in (in terms of pi) or ≈7.85 in. (pi = 3.14)
Step-by-step explanation:
Begin by finding the circumference of the circle. Use the formula:
C = 2rπ
C = 2(9)π
C = 18π.
Since ∠AQB equals 50°, set up a ratio to find the length of arc AB:
[tex]\frac{50}{360} = \frac{x}{18\pi }[/tex]
Cross multiply:
50 · 18π = 360x
900π = 360x
Divide both sides by 360:
x = 2.5π in, or ≈7.85 in.
If two lines meet at a right angle they are said to be _________ to each other.
Answer: perpendicular
Answer:
perpendicular
Step-by-step explanation:
If two lines meet at a right angle they are said to be perpendicular to each other.
Two lines are perpendicular when they intersect at a right angle.
Can someone help fast please
Answer:
[tex] \frac{3a}{a-2} [/tex]
Step-by-step explanation:
[tex] \frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14} [/tex]
Factorise [tex] 2a^2 - 11a + 14} [/tex]
[tex]\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}[/tex]
[tex] 2a - 7 [/tex] cancels 2a - 7
[tex] \frac{1}{a}*\frac{3a^2}{(1))(a - 2)} [/tex]
[tex] \frac{1(3a^2)}{a(a-2)} [/tex]
[tex] \frac{a(3a)}{a(a-2)} [/tex]
"a" cancels "a"
[tex] \frac{3a}{a-2} [/tex]
Thus,
[tex] \frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14} [/tex] = [tex] \frac{3a}{a-2} [/tex]