Which is a characteristic of aromatic hydrocarbons?
A. Alternating single and double bonds
B. Bonds between oxygen and carbon atoms
C. Oxygen atoms bonded to hydrogen atoms
D. Two hydrogen atoms bonded together​

Which best compares kinetic energy and temperature?

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A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

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Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

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SERIOUS flooding IN DELHI

Explanation:

Tungsten is the Largest

Having an atomic No of 74

Answer:

8.44 * 10^-3 %

Explanation:

The solubility of CO2 gas in water is 0.15g/100 ml at a CO2 pressure of 760 mmHg.

Determine the percentage of the CO2 that dissolved originally in the solution that remains

Amount remaining ( Sg = kpg )

Sg = solubility of gas = 0.15 / 100 g/ml

pg. = partial pressure of gas = 760 mmHg = 1 atm

therefore ; K = 1.5 * 10^-3 gm^-1 atm^-1

solubility of gas inside container

Sg = 0.675 * 10^-2 g/ml

solubility of gas during/after dissolution ( amount that remains )

sg = 1.5 * 10^-3 * 0.00038

    =  5.7 * 10^-7  g/ml

therefore the percentage remaining

= (5.7 * 10^-7  / 0.675 * 10^-2 ) * 100

= 8.44 * 10^-3 %

The percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is 8.4 × 10⁻³ %

There exists some missing information in the question.

Let us assume that:

Then, by applying Henry's law:

[tex]\mathbf{S_g = k P_g}[/tex]

[tex]\mathbf{k = \dfrac{S_g}{P_g}}[/tex]

[tex]\mathbf{k =\dfrac{1.5 \times 10^{-3} g/mL}{1\ atm}}}[/tex]

k = 1.5 × 10⁻³ g/m* atm

The percentage of CO2 that was originally dissolved in the solution is:

[tex]\mathbf{S_g = k P_g}[/tex]

Then;

[tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 4.5 \ atm}[/tex]

[tex]\mathbf{S_g =0.00675 \ g/mL}[/tex]

The partial pressure in the can when the soft drink is being opened is 0.00038 atm.

The solubility of the gas [tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 0.00038 \ atm}[/tex]

[tex]\mathbf{S_g =5.7 \times 10^7 \ g/mL}[/tex]

Thus, the percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is:

[tex]\mathbf{=\dfrac{5.7\times 10^{-7}}{0.00675} \times 100 \%}[/tex]

[tex]\mathbf{=0.0084 \%}[/tex]

= 8.4 × 10⁻³ %

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Answer:

Mountains are built by tectonic processes that cause portions of the Earth's crust to rise. These processes are fueled by the escape of heat from the interior of the Earth, causing crustal uplift by volcanic activity and by movement along faults that, in turn, is responsible for the formation of mountains.

Explanation:

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

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Answer:

I hope this helps you

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Answer:

They tax the citizens and then provide them with relief efforts

Explanation:

Common disease protocol

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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Answer:

2.24 g

Explanation:

First we use the PV=nRT formula to calculate the number of moles of the gas:

Then we can use the given molar mass to calculate the mass:

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

Answer:

92.9 °C

Explanation:

Step 1: Given data

Step 2: Convert 55.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 55.0 + 273.15 = 328.2 K

Step 3: Calculate the final temperature of the gas

If we assume constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

T₁/V₁ = T₂/V₂

T₂ = T₁ × V₂/V₁

T₂ = 328.2 K × 502 mL/450. mL = 366 K = 92.9 °C

Answer:

it has volume( takes up space).

Explanation:

The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

A physical substance in general, that which occupies space and possesses rest mass, especially as distinct from energy.

Matter is important because it makes up everything around us and matter can not be created or destroyed but instead, they just transformed into a different form.

Any characteristic that can be measured, such as an object's density, colour, mass, volume, length, malleability, melting point, hardness, odour, temperature, and more, are considered properties of matter.

Therefore, The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

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Answer:

CH3NH2

Explanation:

Hydrogen bonding is a bond that occurs between hydrogen and a highly electronegative element. It is a kind of dipole - dipole interaction. Hydrogen bonding only occurs when hydrogen is bonded to a highly electronegative element.

If we look at the options stated, it is only in CH3NH2  that hydrogen is bonded to a very electronegative element (nitrogen). Hence, CH3NH2  exhibits hydrogen bonding as its strongest intermolecular force among other intermolecular forces.

Answer:

CH3NH2

Explanation:

To form hydrogen bondings between the molecules, the compound needs a highly electronegative atom (usually N, O, or F) bonded with a hydrogen atom;

Answer:

5.3 grams

Explanation:

The maximum amount of magnesium oxide that can be produced during the reaction is 5.3 grams.

From the given reaction:

Mg + O2 → MgO

we see that if 1 mole of Mg reacts to 1 mole of oxygen, it produces 1 mole of MgO.

So, generally if x moles Mg is taken then it will combine with X moles of O2 to produce x moles of MgO.

Now the number of moles in 3.2 grams of Mg = given mass/ molar mass

x = 3.2/24.2

x = 0.132 moles

So it will react with 0.132 moles of oxygen and produce 0.132 moles of MgO, the rest of the oxygen will be left unused.

So, the maximum amount of MgO produces is 0.132 moles, converting to grams

0.132 moles of MgO = 0.132× molar mass of MgO

= 0.132 × 40.3g

0.132 moles of MgO = 5.3 grams of MgO is produced.

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Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

percentage yield =(actual yield/theoretical yield) ×100/1

chlorine is the limiting reagent hence would be the major determinant of the product

71[Cl2]=2×58.5[NaCl]

200[Cl2]=x[NaCl]

x=(200×58.5×2)/(71)

x=329.58g(theoretical yield of NaCl)

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

The answer is that the percentage yield is 72.8 % .

Chemical reactions in the real world do not always go exactly as planned on paper.

In the course of an experiment, many things will contribute to the formation of less product than would be predicted.

Besides spills and other experimental errors, there are often losses due to an incomplete reaction, undesirable side reactions, etc.

Chemists need a measurement that indicates how successful a reaction has been. This measurement is called the percent yield.

Percentage yield =(actual yield/theoretical yield) ×100 %

Chlorine is the limiting reagent hence would be the major determinant of the product

Molecular weight of Cl₂ is 71

Molecular weight of NaCl is 58.5

For 1 mole of Cl₂ 2 moles of NaCl is produced

so it is given that Cl₂ is 200 grams

= 200/71

=2.82 moles.

=5.63 moles of NaCl

=5.63* 58.5 grams

=329.58 g of Nacl

So , 329.58g is theoretical yield of NaCl

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

Therefore the percentage yield = 72.8%

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Answer:

3584.21 J/kg.K

Explanation:

Applying

Q = cm(t₂-t₁)........... equation 1

Where Q = Quantity of heat absorb, c = specific heat capacity of the metal, m = mass of the metal, t₁ = intial temperature, t₂ = Final temperature.

make c the subject of the equation

c = Q/(m(t₂-t₁)........... Equation 2

From the question,

Given: Q = 1362 J, m = 15.2 g = 0.0152 kg, t₁ = 17°C, t₂ = 42°C

Substitute these values into equation 2

c = 1362/0.0152(42-17)

c = 1362/0.38

c = 3584.21 J/kg.K

Answer:

[tex]V=2.9L[/tex]

Explanation:

Hello there!

In this case, by considering the given information in this problem, it is possible  for us to infer that this problem is solved by using the ideal gas equation:

[tex]PV=nRT[/tex]

Next, since we are given the moles, pressure and temperature, we proceed as follows:

[tex]V=\frac{nRT}{P}[/tex]

Then, we plug in the given data to obtain:

[tex]V=\frac{0.108mol*0.08206\frac{atm*L}{mol*K}*315K}{0.96atm}\\\\V=2.9L[/tex]

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Sulfuric Acid, H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms.

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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Answer:

1683.6J

Explanation:

Given:

n= no. Of mol= 2.70 mol

T= Temperature= 30.0 K

Q= n Cv × ∆T .........eqn(1)

Where CV= molar heat capacity=5/2R for diatomic particle ,such as H2

CV= molar heat capacity=3/2R for diatomic, such as H

R= gas constant= 8.314 J/mol.K

Q= heat energy

For a diatomic molecules

Q= n Cv × T

But

Cv= molar heat capacity=5/2R = 5/2(8.314)=20.785

CV= 20.785

. ∆T= Temperature= 30.0 K

Then substitute the values into the eqn(1)

Q= 2.70 × 5/2(8.314) × 30

Q= 2.70 × 20.785 × 30

=1683.6J

Answer:

The temperature of the sample increase by 48 Kelvin

Explanation:

The sample is identical.

Hence the heat at constant pressure is equal to the heat at the constant Volume

Q1 = Q2

Q 1 = heat at constant pressure

Q2 = heat at the constant Volume

Substituting the given values, we get -

[tex]\frac{3}{2} nRT_1 = \frac{5}{2} nRT_2\\3 * 80 = 5 * T_2\\T_2 = 48[/tex]

The temperature of the sample increase by 48 Kelvin

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Then we divide the number of moles by the number of liters to calculate the molarity:

Answer:

a. Does not obey Conservation of Mass law

Explanation:

An example of an unbalanced chemical equation is:

As you can see, there are two Na atoms on the right side of the equation, while only one on the left side, causing the masses on both sides of the equation to not be equal. In other words, not fulfilling the Conservation of Mass law.

Compare with the correctly balanced equation:

Now both sides of the equation possess the same number of atoms for each element.

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

[tex]P \propto \frac{1}{V}[/tex]

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

Answer:

Temperature and number of moles

Explanation: