Answer:
D $175
Step-by-step explanation:
15 point:Which label on the cone below represents the center of the base?
Answer:its C because the base is the bottom of the figure and C goes to the middle point at the bottom of the figure
Step-by-step explanation:
In parallelogram HJKL if m
Answer:
24
Step-by-step explanation:
if you add all of them together u get 108 divide it by 44 and u get 24
Answer:
70
Step-by-step explanation:
∠J and ∠K are supplementary angles
Supplementary angles have a sum of 180°
Thus, ∠J + ∠K = 180
110 + ∠K = 180
subtract 110 from each side
180 - 110 = 70
110 - 110 cancels out
we're left with ∠K = 70°
What is the quotient of 6.58* 10^6 and 4.7×10^3
expressed in scientific notation?
Answer:
1.4 · 10³
Step-by-step explanation:
6.58 · [tex]10^{6}[/tex] ÷ 4.7 · 10³
6.58 ÷ 4.7 = 1.4
[tex]10^{6}[/tex] - 10³ = 10³
1.4 · 10³
Answer:
3.0926 x 10^10
Step-by-step explanation:
Triangle EFG is dilated by a scale factor of one half centered at (1, 1) to create triangle E'F'G'. Which statement is true about the dilation?
Answer:
A triangle is dilated by scale factor of 1/5
Step-by-step explanation:
A triangle has three sides. All the corresponding angles of triangle must be congruent. When the triangle is dilated it is rotated 90 degrees clockwise about its origin. The shape of the triangle will not change due to rotation of dilation.
DUS is a 30°-60°-90° triangle with short leg SU. If SU = x, determine the
length of the long leg and the length of the hypotenuse.
Answer:
SD = 2x
UD = x[tex]\sqrt{3}[/tex]
Step-by-step explanation:
The hypotenuse of a 30-60-90 triangle is 2 times the length of the shorter leg.
SU is the shorter leg = x
So, SD = 2x
The longer leg of a 30-60-90 triangle is [tex]\sqrt{3}[/tex] times the shorter leg.
So, UD = x[tex]\sqrt{3}[/tex]
Answer:
Below in bold.
Step-by-step explanation:
In a 30-60-90 triangle the sides are in the ratio 1:√3:2 so if the shortest side SU = x then the long leg = √3x and the hypotenuse = 2x.
A circle has a radius of 17 in. Find the length s of the arc intercepted by a central angle of 0.7 radians.
Round your answer to the nearest tenth .
Given:
The radius of the circle is 17 in.
Central angle of intercepted arc is 0.7 radians.
To find:
The length s of the intercepted arc.
Solution:
The formula for the length of intercepted arc is:
[tex]s=r\theta[/tex]
Where, r is the radius of the circle and [tex]\theta [/tex] is the central angle in radians.
Substituting [tex]r=17,\ \theta =0.7[/tex] in the above formula, we get
[tex]s=17\times 0.7[/tex]
[tex]s=11.9[/tex]
Therefore, the length of the intercepted arc is 11.9 inches.
Mr Johns surveyed students in his math classes to determine how many hours they use their cell phones each day. The results are shown in the dot plot below what is the range of his data
Answer:
17
Step-by-step explanation:
Range is the biggest number minus the smallest number. So 20-3=17
Pablo wants to pour 82.69 grams of salt into a container. So far, he has poured 38.4 grams. How much more salt should Pablo pour?
please help =)
helppppp
Answer:
44.29 grams
Step-by-step explanation:
82.69 - 38.4 gives you 44.29.
44.29 + 38.4 gives you 82.69.
The diameter of a circle is 22 meters. What is the circle's area?
Answer:
Step-by-step explanation:
A=3.14 x 22m x 22m
A=69.08m x 22m
A=1519.76m2 (squared po yan)
I’ll mark as brainliest!!!! Plz no links
note: I don’t really like giving people answers. I like them to learn:
To find a(n) area of a triangle, all you need to do is use the triangle shape to make a rectangle and then calculate the area of the rectangle and divide it by the number of triangles you used to make the triangle.
for your triangle I can imagine it needs four triangles to make a rectangle.
unless you want to multiply 1/2x6x11 to get your answer.
hope this helped !
What is the value of expression of x=5
What is the coefficient of 6x-3
Answer:
27
Step-by-step explanation
6x - 3
6(5) - 3 || replace the x with its value
30 - 3 || multiply (also known as simplify)
27 || subtract 3 from 30
What is simplifying? I honestly know what it is, but I forgot the definition.
Is it possible to find two data sets A and B such that A has a greater median and mode,
while B has a greater average and range? If you think the answer is yes, provide an example. If you think the answer is no, explain why not.
Answer:
54
Step-by-step explanation:
You add 5+19 and divide my 2
Which factors of −14 are used to factor x2+5x−14?
Answer:
+ 7 and - 2
Step-by-step explanation:
Given
x² + 5x - 14
Consider the factors of the constant term (- 14) which sum to give the coefficient of the x- term (+ 5)
The factors are + 7 and - 2 , since
7 × - 2 = - 14 and 7 - 2 = + 5 , then
x² + 5x - 14 = (x + 7)(x - 2) ← in factored form
A diagram shows a kite and its frame.
Answer:
indeed it does
Step-by-step explanation:
wheres the diagram exactly?
Which expression is equivalent to 2(3 - x) - 12 + 4x?
2x - 6
3х - 6
3x-7
2x - 7
Answer:
2x - 6
Step-by-step explanation:
2(3 - x) - 12 + 4x =
6 - 2x - 12 + 4x =
-6 + 2x =
2x - 6
(1, -3) and (0,-1)
Equation: y=-2x-1
Slope:-2
Y-intercept:___?
Answer:
-1
Step-by-step explanation:
The coordinates of the vertices of parallelogram MATH are M(-7,5), A(6,5), T(4,-2), and H(-9,-2). What are the coordinate of G, the point of intersection of diagonals MT and ?
Answer:
[tex]G = (-1.5,1.5)[/tex]
Step-by-step explanation:
Given
[tex]M = (-7,5)[/tex]
[tex]A = (6,5)[/tex]
[tex]T = (4,-2)[/tex]
[tex]H = (-9,-2)[/tex]
Required
Determine the coordinate of G
From the complete question, G is at the intersection of MT and AH.
So, G is calculated using midpoint formula
[tex]G = \frac{1}{2}(x_1 + x_2, y_1 + y_2)[/tex]
For MT:
[tex]M = (-7,5)[/tex] [tex]T = (4,-2)[/tex]
[tex]G = \frac{1}{2}(-7 + 4, 5 -2)[/tex]
[tex]G = \frac{1}{2}(-3, 3)[/tex]
Open bracket
[tex]G = (-1.5,1.5)[/tex]
To show that [tex]G = (-1.5,1.5)[/tex]
We have:
[tex]A = (6,5)[/tex] [tex]H = (-9,-2)[/tex]
[tex]G = \frac{1}{2}(x_1 + x_2, y_1 + y_2)[/tex]
[tex]G =\frac{1}{2}(6-9,5-2)[/tex]
[tex]G = \frac{1}{2}(-3, 3)[/tex]
Open bracket
[tex]G = (-1.5,1.5)[/tex]
Hence, the coordinates of G is:
[tex]G = (-1.5,1.5)[/tex]
Find the rectangle that has:
Area 24 square feet
Perimeter = 20 feet
PLEASE HELP ME
Answer:
option E
Step-by-step explanation:
have a great day
Rotate the given triangle
90°clockwise about the origin.
21
2 21
-1 3
?
1
Answer:
Step-by-step explanation:
-1 -1 3
1 -2 -2
The new coordinates of the vertices after a 90° clockwise rotation about the origin are:
[tex]\left[\begin{array}{ccc}-1&1&-3\\1&2&2\\\end{array}\right][/tex]
What occurred when you rotated 90 degrees clockwise?If we rotate a triangle 90° counter clockwise about the origin,
Then if one of its vertices be (x, y), it will be changed to (y, x).
The triangle is given as follows:
[tex]\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\\\end{array}\right][/tex]
To rotate the given triangle 90° clockwise about the origin, we can use the rotation matrix:
[tex]\left[\begin{array}{ccc}cos90^{o}&-sin90^{o}\\sin90^{o}&cos90^{o}\\\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}0&-1\\1&0\\\end{array}\right][/tex]
To apply this rotation matrix to each vertex of the triangle, we multiply it with the coordinate vector of each vertex.
Let's denote the vertices of the triangle as A, B, and C.
A = (-1, -1)
B = (2, -1)
C = (2, 3)
Applying the rotation matrix to each vertex, we have:
[tex]A' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} -1 \ -1 \end{bmatrix} = \begin{bmatrix} 1 \ -1 \end{bmatrix}[/tex]
[tex]B' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 2 \ -1 \end{bmatrix} = \begin{bmatrix} 1 \ 2 \end{bmatrix}[/tex]
[tex]C' = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} \begin{bmatrix} 2 \ 3 \end{bmatrix} = \begin{bmatrix} -3 \ 2 \end{bmatrix}[/tex]
Therefore, the new coordinates of the vertices after a 90° clockwise rotation about the origin are:
A' = (1, -1)
B' = (1, 2)
C' = (-3, 2)
This can be written as follows:
[tex]\left[\begin{array}{ccc}-1&1&-3\\1&2&2\\\end{array}\right][/tex]
Learn more about the rotating triangle here:
https://brainly.com/question/22878771
#SPJ7
Please help me, I haven't learned this yet so I have no idea what to do.
I am giving 30 points for this.
A soup can will have a radius of 4 cm and a
height of 10.5 cm. How much metal is needed
to make the can?
Answer:
It's about 365 cm²Step-by-step explanation:
2×πr² + 2πr×h =
= 2×π×4² + 2π×4×10.5 =
= 32π + 84π =
= 116π ≈
≈ 364.42 cm²
The total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.
What is a cylinder?In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.
We have:
The radius of the soup can r = 4 cm
The height of the soup can h = 10.5 cm
We know the surface area of the cylinder:
[tex]\rm S = 2\pi r(r+h)[/tex]
[tex]\rm S = 2\pi \times 4(4+10.5)[/tex]
S = 364.42 square cm
Thus, the total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.
Learn more about the cylinder here:
brainly.com/question/3216899
#SPJ2
Consider the diagram below with parallel planes D and N.
Which of the following statements about the figure are true? Select all that apply.
FA is a line, line segment, and a ray.
Lines rands are perpendicular,
Ray RO and Ray CA form an angle.
A FA is a line, line segment and a ray
B lines r and s are perpendicular
C Ray RO and Ray CA form an angle
D M and C are Collin war and coplanar
E F, O, and R are coplanar in D
F Ray MC and Ray CA form a 90 degree angle
G using segment addition postulate, FO + OC = FA
Answer:A
Step-by-step explanation:line segment
Arc measure - Hello! Can you please help me and if you can explain the formula that would be awesome!
9514 1404 393
Answer:
88°
Step-by-step explanation:
Angle MQP is called an "inscribed angle." Its vertex (Q) is on the circle, and its sides are chords of the circle. The ends of the sides intercept arc MP. The relationship between an inscribed angle and the intercepted arc is that the measure of the arc is twice the measure of the angle.
arc MP = 2×∠MQP = 2×44°
arc MP = 88°
EASY BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 100pts-
(if you put links or don't answer accordingly im reporting your account)
Answer:D..the diagonals bisect each other. Since bisectors divide the diagonals equally in two parts.
Answer:
C.
Step-by-step explanation:
You deposit $6000 in an account that earns 3% annual interest. Find the balance after 6 years if this interest is
compounded with the given frequency.
7/2 x+1/2x=1/2+9/2x help
Answer:
[tex]x=-1[/tex]
Step-by-step explanation:
[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]
Step 1: Simplify both sides of the equation.
[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]
[tex](\frac{7}{2}x+\frac{1}{2}x)=\frac{9}{2}x+\frac{1}{2}[/tex] (Combine Like Terms)
[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]
[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]
Step 2: Subtract [tex]\frac{9}{2}x[/tex] from both sides.
[tex]4x-\frac{9}{2}x=\frac{9}{2}x+\frac{1}{2}-\frac{9}{2}x[/tex]
[tex]\frac{-1}{2}x=\frac{1}{2}[/tex]
Step 3: Multiply both sides by [tex](\frac{2}{-1})[/tex].
[tex](\frac{2}{-1})*(\frac{-1}{2}x)=(\frac{2}{-1})*(\frac{1}{2})[/tex]
[tex]x=-1[/tex]
Therefore, [tex]x=-1[/tex] will be your final answer.
Sorry this took very long. I had to calculate all of this.
Mancuso wants to draw a sector whose area is 2 times the area of the sector shown
Which method will NOT work?
Answer:
Multiply the radius, r, by 2. Keep the angle measure x.
Step-by-step explanation:
The area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².
What is function?A function is a relation between a dependent and independent variable.
Mathematically, we can write → y = f(x) = ax + b.
Given is that Mancuso wants to draw a sector whose area is 2 times the area of the sector shown.
The area of the sector given is -
A = {x/180} x πr²
For the area to be double, we can write the area of the sector as -
A{new} = 2 × {x/180} × πr²
A{new} = {x/90} × πr²
Therefore, the area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².
To solve more questions on sectors, visit the link-
brainly.com/question/29014197
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Drag each tile to the correct box.
Tickets for all of the described charity raffles cost $2 per ticket. Arrange the raffles in ascending order of their expected values to the player,
The player picks a single letter from A to J
and
a single digit from 0 to 9. If both the letter
and
the digit match the letter and the digit
picked
on that day, the player wins $150.
Answer: 4,2,3,1,5,6
Step-by-step explanation:
Plato
solve each inequality and show work.
1) 4x - 2 > 2x + 8
2) -3x - 6 > 4x - 20
3) 4(x + 1) < 3x - 2
4) 2x + 3 + x < -2x + 1 + 12
5) 2(x - 1) > 4x + 4 - 5x
6) 2 + 4x -7 < 8x + 2 - 2x
Answer: Use the app photo math, you just take a picture and it gives you the answer and shows you the steps:)
1) x> 5
2) x< 2
3) x<-6
4) x< 2
5) x> 2
6) x> - 7/2
Step-by-step explanation:
See the images below for the work:) The images will be in order with the number the first problem will be the answer to the first.
Answer:
[tex]\sf 1)\:4x - 2 > 2x + 8[/tex]
Add 2 from both sides:
[tex]\sf 4x-2+2>2x+8+2[/tex]
[tex]\sf 4x>2x+10[/tex]
Subtract 2x from both sides:
[tex]\sf 4x-2x>2x+10-2x[/tex]
[tex]\sf 2x>10[/tex]
Divide both sides by 2:
[tex]\sf \cfrac{2x}{2}>\cfrac{10}{2}[/tex]
[tex]\boxed{\sf x>5}[/tex]
_______________________________
[tex]\sf 2)\: -3x - 6 > 4x - 20[/tex]
Add 6 from both sides:
[tex]\sf -3x-6+6>4x-20+6[/tex]
[tex]\sf -3x>4x-14[/tex]
Subtract 4x from both sides:
[tex]\sf -3x-4x>4x-14-4x[/tex]
[tex]\sf -7x>-14[/tex]
Multiply both sides by -1:
[tex]\sf\left(-7x\right)\left(-1\right)<\left(-14\right)\left(-1\right)[/tex]
[tex]\sf 7x<14[/tex]
Divide both sides by 7:
[tex]\sf \cfrac{7x}{7}<\cfrac{14}{7}[/tex]
[tex]\boxed{\sf x<2}[/tex]
_______________________________
[tex]\sf 3)\: 4(x + 1) < 3x - 2[/tex]
Apply distributive property:
[tex]\sf 4x+4<3x-2[/tex]
Subtract 4 from both sides:
[tex]\sf 4x+4-4<3x-2-4[/tex]
[tex]\sf 4x<3x-6[/tex]
Subtract 3x from both sides:
[tex]\sf 4x-3x<3x-6-3x[/tex]
[tex]\boxed{\sf x<-6}[/tex]
_______________________________
[tex]\sf 4)\: 2x + 3 + x < -2x + 1 + 12[/tex]
Combine like terms:
[tex]\sf (2x+x)= 3x[/tex]
[tex]\sf( 1+12)=13[/tex]
[tex]\sf 3x+3<-2x+13[/tex]
Subtract 3 from both sides:
[tex]\sf 3x+3-3<-2x+13-3[/tex]
[tex]\sf 3x<-2x+10[/tex]
Add 2x from both sides:
[tex]\sf 3x+2x<-2x+10+2x[/tex]
[tex]\sf 5x<10[/tex]
Divide both sides by 5:
[tex]\sf \cfrac{5x}{5}<\cfrac{10}{5}[/tex]
[tex]\boxed{\sf x<2}[/tex]
________________________________
[tex]\sf 5)\: 2(x - 1) > 4x + 4 - 5x[/tex]
Combine like terms:
[tex]\sf (4x-5x)=-x[/tex]
[tex]\sf 2\left(x-1\right)>-x+4[/tex]
Apply distributive property:
[tex]\sf 2x-2>-x+4[/tex]
Add 2 from both sides:
[tex]\sf 2x-2+2>-x+4+2[/tex]
[tex]\sf 2x>-x+6[/tex]
Add x from both sides:
[tex]\sf 2x+x>-x+6+x[/tex]
[tex]\sf 3x>6[/tex]
Divide both sides by 3:
[tex]\sf \cfrac{3x}{3}>\cfrac{6}{3}[/tex]
[tex]\boxed{\sf x>2}[/tex]
_______________________________
[tex]\sf 6)\: 2 + 4x -7 < 8x + 2 - 2x[/tex]
Subtract 2 from both sides:
[tex]\sf 2+4x-7-2<8x+2-2x-2[/tex]
[tex]\sf 4x-7<8x-2x[/tex]
Combine like terms:
[tex]\sf (8x-2x)=6x[/tex]
[tex]\sf 4x-7<6x[/tex]
Add 7 from both sides:
[tex]\sf 4x-7+7<6x+7[/tex]
[tex]\sf 4x<6x+7[/tex]
Subtract 6x from both sides:
[tex]\sf 4x-6x<6x+7-6x[/tex]
[tex]\sf -2x<7[/tex]
Multiply both sides by -1:
[tex]\sf \left(-2x\right)\left(-1\right)>7\left(-1\right)[/tex]
[tex]\sf 2x>-7[/tex]
Divide both sides by 2:
[tex]\sf \cfrac{2x}{2}>\cfrac{-7}{2}[/tex]
[tex]\boxed{\sf x>-\frac{7}{2}}[/tex]
_______________________________________