Answer: The number of quarter inches in 23 inches is 4 × 23 = 92
None of the answers given is correct.
Step-by-step explanation:
The ÷ sign means divide.
There are 4 quarter inches in each inch, so you have to multiply 23 × 4
Dividing by 14 makes no sense.
23 ÷ 1/4 = 92 is also an equation that makes sense.
A regular octagon has what type of symmetry?
A.
line symmetry only
B.
point symmetry only
C.
both point and line symmetry
OD.
neither point nor line symmetry
Answer:
C
Step-by-step explanation:
A regular octagon has 8 lines of symmetry.
The point of intersection of the lines of symmetry of a regular octagon is the point of symmetry.
A regular octagon has both point and line symmetry. Thus, option C is the right choice.
What are the different types of symmetry?The different types of symmetry are:
Line symmetry: A shape is symmetric about a line when the two images formed on the two sides of the line are identical.Point symmetry: A shape is symmetric about a point, when the shape is rotated about the point for 180°, gives the same shape.Rotational symmetry: A shape is rotationally symmetric, when the shape on rotation about a point, with an angle of value less than 360°, gives the same shape back.How to solve the given question?In the question, we are asked about the types of symmetry that a regular octagon has.
A regular octagon has 8 lines of symmetry about which the shape divides itself into equal halves.
These are the 4 lines joining each opposite vertex, and the other 4 are the lines passing through the midpoints of opposite sides.
A regular octagon is point symmetric as 180° rotation about the point of intersection of the lines of symmetry gives the same shape back.
Thus, we can say that a regular octagon has both point and line symmetry. Thus, option C is the right choice.
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What is the volume of this container?
Step-by-step explanation:
Concepto 20 pies, 20´ × 8´ × 8´6" 40 pies High Cube, 40´ × 8´ × 9´ 6"
Ancho 2352 mm / 7´9" 2352 mm / 7´9"
Altura 2393 mm / 7´10" 2698 mm / 8´10"
Capacidad 33,2 m³ / 1172 ft³ 76, m³ / 2700 ft³
ESPERO QUE TE AYUDE :D
Find the volume of the cone.
4 cm
3 cm
V = [?] cm3
Round to the nearest tenth.
Answer:
Volume of a cone = 1/3πr²h
h = height
r = radius
r = 3cm h = 4cm
Volume = 1/3π(3)²(4)
= 36 × 1/3π
= 12π
= 36.69cm³
= 37cm³ to the nearest tenth
Hope this helps
Answer:
37.7
_______
NOT 37
Step-by-step explanation:
v = [tex]\frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]r^{2}[/tex] · [tex]h[/tex]
v = [tex]\frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]3^{2}[/tex] · [tex]4 = 12\pi = 37.69911 =[/tex] 37.7
What is the algebraic expression for "the sum of three times a number and seven"? A. 3 x + 7 B. 3 x + 11 x C. 3 + 7 x
Answer:
3x+7
Step-by-step explanation:
Three times a number, let x be the number and 7 so plus 7
The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.
The given phrase is "the sum of three times a number and seven".
Variables and constants are combined to generate algebraic expressions using a variety of techniques. Terms comprise expressions. A term is the sum of several elements. Both numerical and algebraic (literal) factors are acceptable.
Let the unknown number be x.
Three times of a number = 3x
The number 7 is added to the obtained sum.
That is, 3x+7
So, the expression is 3x+7
The algebraic expression for the given phrase is 3x+7. Therefore, the correct answer is option A.
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Is (1,2), (2,3) (3,4), (4,5) a function?
Answer:
yes
Step-by-step explanation:
The domain is the set of x-values: {1, 2, 3, 4}. None of these are repeated, so this relation is a function.
An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individuals, what is the approximate distribution of the number who carry this gene
Answer:
Brianliest!
Step-by-step explanation:
4
1 in 500
500 x 4 = 2000
4 in 2000
IM Systems assembles microcomputers from generic components. It purchases flat screen monitors from a manufacturer in Taiwan; thus, there is a long lead time of 25 days. Daily demand is normally distributed with a mean of 3.5 monitors and a standard deviation of 1.2 monitors. The company maintains a 90% customer service level. How much safety stock of monitors should IM Systems hold
Given Information:
Mean daily demand = 3.5 monitors
standard deviation daily demand = 1.2 monitors
Lead time = 25 days
customer service level = 90%
Required Information:
Safety Stock = ?
Answer:
Safety Stock = 8 monitors
Step-by-step explanation:
The safety stock of monitors that IM Systems should hold is given by
[tex]Safety \:\: Stock = z \times \sigma \times \sqrt{n}[/tex]
Where σ is the standard deviation of daily demand, n is the lead time and z is the z-score corresponding to 90% service level.
From the z-table, the z-score corresponding to 90% is found to be
z = 1.282
So the required safety stock is
[tex]Safety \:\: Stock = z \times \sigma \times \sqrt{n} \\\\Safety \:\: Stock = 1.282 \times 1.2 \times \sqrt{25} \\\\Safety \:\: Stock = 1.282 \times 1.2 \times 5 \\\\Safety \:\: Stock = 7.692\\\\[/tex]
Rounding off to nearest whole number yields
Safety Stock = 8 monitors
Therefore, IM Systems should hold 8 monitors.
Which graph shows a function whose domain and range exclude exactly one value?
Answer:
C (the third graph)
Step-by-step explanation:
This graph's function has a domain and range that both exclude one value, which is 0. The x and y values are never 0 in the function, as it approaches 0 but never meets it.
Answer:
see below
Step-by-step explanation:
This graph has an asymptote at y = 0 and x=0
This excludes these values
The domain excludes x =0
The range excludes y=0
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. Using the data, construct the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level.
Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then
[tex]n = 1537, \pi = \frac{353}{1537} = 0.2297[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507[/tex]
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
A fence 6 feet tall runs parallel to a tall building at a distance of 6 feet from the building. We want to find the the length of the shortest ladder that will reach from the ground over the fence to the wall of the building. Here are some hints for finding a solution: Use the angle that the ladder makes with the ground to define the position of the ladder and draw a picture of the ladder leaning against the wall of the building and just touching the top of the fence. If the ladder makes an angle 0.82 radians with the ground, touches the top of the fence and just reaches the wall, calculate the distance along the ladder from the ground to the top of the fence. equation editorEquation Editor The distance along the ladder from the top of the fence to the wall is equation editorEquation Editor Using these hints write a function L(x) which gives the total length of a ladder which touches the ground at an angle x, touches the top of the fence and just reaches the wall. L(x) = equation editorEquation Editor . Use this function to find the length of the shortest ladder which will clear the fence. The length of the shortest ladder is equation editorEquation Editor feet.
Answer:
12√2 feet ≈ 16.97 feet
Step-by-step explanation:
For the dimensions shown in the attached diagram, the distance "a" along the ladder from the ground to the fence is ...
a = (6 ft)/sin(x) = (6 ft)/sin(0.82) ≈ 8.206 ft
The distance along the ladder from the top of the fence to the wall is ...
b = (6 ft)/cos(x) = (6 ft)/cos(0.82) ≈ 8.795 ft
__
In general, the distance along the ladder from the ground to the wall is ...
L(x) = a +b
L(x) = 6/sin(x) +6/cos(x)
This distance will be shortest for the case where the derivative with respect to x is zero.
L'(x) = 6(-cos(x)/sin(x)² +sin(x)/cos(x)²) = 6(sin(x)³ -cos(x)³)/(sin(x)²cos(x²))
This will be zero when the numerator is zero:
0 = 6(sin(x) -cos(x))(1 -sin(x)cos(x))
The last factor is always positive, so the solution here is ...
sin(x) = cos(x) ⇒ x = π/4
And the length of the shortest ladder is ...
L(π/4) = 6√2 + 6√2
L(π/4) = 12√2 . . . . feet
_____
The ladder length for the "trial" angle of 0.82 radians was ...
8.206 +8.795 = 17.001 . . . ft
The actual shortest ladder is ...
12√2 = 16.971 . . . feet
for a sample size of 115 and a population parameter of 0.1,what is the standard deviation of the normal curve that can be used to approximate the binomial probability histogram. Round your answer to three decimal places
A.0.028
B.0.054
C.0.043
D.0.035
Answer:
A) 0.028
Step-by-step explanation:
Given:
Sample size, n = 115
Population parameter, p = 0.1
The X-Bin(n=155, p=0.1)
Required:
Find the standard deviation of the normal curve that can be used to approximate the binomial probability histogram.
To find the standard deviation, use the formula below:
[tex]\sigma = \sqrt{\frac{p(1-p)}{n}}[/tex]
Substitute figures in the equation:
[tex]\sigma = \sqrt{\frac{0.1(1 - 0.1)}{115}}[/tex]
[tex]\sigma = \sqrt{\frac{0.1 * 0.9}{115}}[/tex]
[tex]\sigma = \sqrt{\frac{0.09}{115}}[/tex]
[tex] \sigma = \sqrt{7.826*10^-^4}[/tex]
[tex] \sigma = 0.028 [/tex]
The Standard deviation of the normal curve that can be used to approximate the binomial probability histogram is 0.028
If the radius of a circle is 31.2 cm, what is the approximate area if you use 3.14 for pi and the area is rounded to the nearest tenth?
Answer:
3056.6 cm^2
Step-by-step explanation:
A = (pi)r^2 = 3.14 * 31.2 cm * 31.2 cm = 3056.6 cm^2
Answer: 3056.60 sq. cm.
Step-by-step explanation:
Area of a circle = π x r^2
= 3.14 x 31.2^2
= 3056.60
HELPPP PLEASE THANKS
Answer:
ur dumb kid
Step-by-step explanation
learn it your self
What is the midpoint of the line segment with endpoints (1,-6) and (-3,4)?
O A. (-1,-1)
O B. (-2,-2)
O C. (-1,-2)
OD. (-2,-1)
please help
Answer:
(-1,-1)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2
(1+-3)/2 = -2/2 = -1
To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2
(-6+4)/2 = -2/2 = -1
(-1,-1)
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. StartAbsoluteValue Start 3 By 3 Matrix 1st Row 1st Column 3 2nd Column 0 3rd Column 3 2nd Row 1st Column 2 2nd Column 3 3rd Column 3 3rd Row 1st Column 0 2nd Column 4 3rd Column negative 2 EndMatrix EndAbsoluteValue
Answer:
Step-by-step explanation:
It is given that
[tex]\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}[/tex]
By cofactor expansion across the first row, we get
[tex]\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}[/tex]
[tex]\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right][/tex]
[tex]\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right][/tex]
[tex]\Delta=-54+0+24[/tex]
[tex]\Delta=-30[/tex]
Therefore, the value of determinant is -30.
By cofactor expansion across the second column, we get
[tex]\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}[/tex]
[tex]\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right][/tex]
[tex]\Delta=0\left[(-1)(-4)\right]+3\left[(-6)\right]+4\left[(-1)3\right][/tex]
[tex]\Delta=-18-12[/tex]
[tex]\Delta=-30[/tex]
Therefore, the value of determinant is -30.
If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options.
m∠ABC = 125° and AB ≅ DB
ΔACD is isosceles with base AD
ΔABD is isosceles with base AD
CD = 52 cm
AB = 29 cm
Answer:
Option (1)
Step-by-step explanation:
In the figure attached,
BC is the angle bisector of angle ACD.
To prove ΔABC and ΔDBC congruent by SAS property we require two sides and the angle between these sides to be congruent.
Since BC ≅ BC [Reflexive property]
∠ABC ≅ ∠CBD ≅ 125°
And sides AB ≅ BD
Both the triangles will be congruent.
Therefore, additional information required to prove ΔABC ≅ ΔDBC have been given in option (1).
Therefore, Option (1) will be the answer.
The additional information that could be used to prove ΔABC ≅ ΔDBC
using SAS are;
m∠ABC = 125° and [tex]\overline{AB}[/tex] ≅ [tex]\overline{DB}[/tex] ΔACD is isosceles, with base [tex]\overline{AD}[/tex][tex]\overline{CD}[/tex] = 52 cmReasons:
The given information are;
[tex]\overline{CB}[/tex] bisects ∠ACD
The given information from the diagram are;
[tex]\overline{AC}[/tex] = 52 cm
[tex]\overline{BD}[/tex] = 29 cm
∠CBD = 125°
Solution;
First selected option; m∠ABC = 125° and [tex]\overline{AB}[/tex] ≅ [tex]\overline{DB}[/tex]
m∠ABC = 125° and [tex]\overline{AB}[/tex] ≅ [tex]\overline{DB}[/tex][tex]\overline{CB}[/tex] ≅ [tex]\overline{CB}[/tex] (reflexive property)
ΔABC ≅ ΔDBC (SAS rule of congruency)
Second selected option; ΔACD is isosceles, with base [tex]\overline{AD}[/tex]
∠ACB ≅ ∠DCB (definition of angle bisector)
ΔACD is isosceles, with base [tex]\overline{AD}[/tex] (Additional information)[tex]\overline{CD}[/tex] ≅ [tex]\overline{AC}[/tex] (definition of isosceles triangle)
[tex]\overline{CB}[/tex] ≅ [tex]\overline{CB}[/tex] (reflexive property)
ΔABC ≅ ΔDBC (SAS rule of congruency)
Third selected option; [tex]\overline{CD}[/tex] = 52 cm
∠ACB ≅ ∠DCB (definition of angle bisector)
[tex]\overline{CD}[/tex] = 52 cm = [tex]\overline{AC}[/tex] (given) (additional information)[tex]\overline{CD}[/tex] ≅ [tex]\overline{AC}[/tex] (definition of congruency)
[tex]\overline{CB}[/tex] ≅ [tex]\overline{CB}[/tex] (reflexive property)
ΔABC ≅ ΔDBC (SAS rule of congruency)
The Side-Angle-Side, SAS, rule of congruency states that two triangles are
congruent if two sides and an included angle of one triangle are
congruent to the corresponding two sides and included angle on the other
triangle.
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What is the general form of the equation of the line shown? 2 x - y + 3 = 0 2 x - y - 3 = 0 x - 2 y - 3 = 0
Answer:
2x - y - 3 = 0
Step-by-step explanation:
Find slope-intercept form first: y = mx + b
Step 1: Pick out 2 points
In this case, I picked out (2, 1) and (0, -3) from the graph
Step 2: Using slope formula y2 - y1/x2 - x1 to find slope
-3 - 1/0 - 2
m = 2
Step 3: Place slope formula results into point-slope form
y = 2x + b
Step 4: Plug in a point to find b
-3 = 2(0) + b
b = -3
Step 5: Write slope-intercept form
y = 2x - 3
Step 6: Move all variables and constants to one side
0 = 2x - 3 - y
Step 7: Rearrange
2x - y - 3 = 0 is your answer
A line passes through the points (–1, 10) and (3, 2). Which shows the graph of this line?
Answer:
Hope this helps!!
Answer:
the correct answer is ...... A
Step-by-step explanation:
Hope this helps
According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year, and approximately 3% of all births in the United States result in birth defects each year. Consider two babies being born independently of one another. 1. The probability that both babies have birth defects is;______ a. 0.0009. b. 0.0400.c. 0.0606. d. 0.2000. 2. The probability that neither baby catches the flu in a given year is:_____ a. 0.024. b. 0.040. c. 0.230 d. 0.640. 3. Event A occurs with probability 0.1. Event B occurs with probability 0.6. If A and B are independent, then:______ a. P(A and B) = 0.06. b. P(A or B) = 0.70. c. P(A and B) = 0.70. d. P(A or B) = 0.06. 4. Event A occurs with probability 0.2. Event B occurs with probability 0.9. Event A and B:______ are disjoint cannot be independent. cannot be disjoint. are reciprocating. The center for Disease Control and Prevention reports that the rate of Chlamydia infections among American women ages 20 to 24 is 2791.5 per 100,000. Take a random sample of three American women in this age group. 5. The probability that all of them have a Chlamydia infection is:_____ a. nearly 0. b. 0.028. c. 0.084. d. 0.837 6. The probability that none of them have a Chlamydia infection is:_______ a. 0.084. b. 0.919. c. 0.972. d. nearly 1.
Answer:
(1) a. 0.0009
(2) d. 0.640
(3)
a. P(A and B) = 0.06. b. P(A or B) = 0.70.(4)Not disjoint
(5) a. nearly 0.
(6)b. 0.919
Step-by-Step Explanation:
(1)Probability of a baby being born with a birth defect =3%=0.03
The probability that both babies have birth defects=0.03 X 0.03= 0.0009.
(2)The probability of contracting the influenza virus each year = 20%=0.2
Therefore, the probability of not contracting the influenza virus =1-0.2=0.8
The probability that neither baby catches the flu in a given year:
=0.8 X 0.8
=0.64
(3)
P(A)=0.1
P(B)=0.6
P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7
P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06
(4)
P(A)=0.2
P(B)=0.9
Event A and B cannot be disjoint.
(5)
The probability of an American woman aged 20 to 24 having Chlamydia infection [tex]=\dfrac{2791.5}{100000}[/tex]
The probability that three randomly selected women in this age group have the infection
[tex]=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0[/tex]
(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection [tex]=1-\dfrac{2791.5}{100000}[/tex]
The probability that three randomly selected women in this age group do not have the infection
[tex]=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919[/tex]
A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has eight identical components, each with a probability of 0.45 of failing in less than 1,000 hours. The sub system will operate if any four of the eight components are operating. Assume that the components operate independently. (Round your answers to four decimal places.)
Required:
Find the probability that the subsystem operates longer than 1000 hours.
Answer:
0.7396 = 73.96% probability that the subsystem operates longer than 1000 hours.
Step-by-step explanation:
For each component, there are only two possible outcomes. Either they fail in less than 1000 hours, or they do not. The components operate independently. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Eight components:
This means that [tex]n = 8[/tex]
Probability of 0.45 of failing in less than 1,000 hours.
So 1 - 0.45 = 0.55 probability of working for longer than 1000 hours, which means that [tex]p = 0.55[/tex]
Find the probability that the subsystem operates longer than 1000 hours.
We need at least four of the components operating. So
[tex]P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{8,4}.(0.55)^{4}.(0.45)^{4} = 0.2627[/tex]
[tex]P(X = 5) = C_{8,5}.(0.55)^{5}.(0.45)^{3} = 0.2568[/tex]
[tex]P(X = 6) = C_{8,6}.(0.55)^{6}.(0.45)^{2} = 0.1569[/tex]
[tex]P(X = 7) = C_{8,7}.(0.55)^{7}.(0.45)^{1} = 0.0548[/tex]
[tex]P(X = 8) = C_{8,8}.(0.55)^{8}.(0.45)^{0} = 0.0084[/tex]
[tex]P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2627 + 0.2568 + 0.1569 + 0.0548 + 0.0084 = 0.7396[/tex]
0.7396 = 73.96% probability that the subsystem operates longer than 1000 hours.
What is the relative change from 6546 to 4392
Answer:
The relative change from 6546 and 4392 is 49.04
Step-by-step explanation:
What is AB? Geometry help please
Answer:
AB = 37 units.
Step-by-step explanation:
Solve for AB using the Pythagorean theorem:
c² = a² + b² (c being AB in this instance)
Plug in the values of the legs of the triangle:
c² = 12² + 35²
c² = 144 + 1225
c² = 1369
c = √1369
c = 37
Therefore, AB = 37.
a) find the value of 2x+y wehn x =4 and y =3 b) find the value of a^2 + b when a = -2 and b = 5
Answer:
a. 11b. 9Solution,
a. Given,
X=4
y=3
Now,
[tex]2x + y \\ = 2 \times 4 + 3 \\ = 8 + 3 \\ = 11[/tex]
b. Given,
a=-2
b=5
Now,
[tex] {a}^{2} + b \\ = {( - 2)}^{2} + 5 \\ = 4 + 5 \\ = 9[/tex]
hope this helps...
Good luck on your assignment..
A data set is shown in the table. The line of best fit modeling the data is y = 2.69x – 7.95.
Answer:
It’s 0.12
Step-by-step explanation:
Took test
Frazier's total monthly expenses are $1,425. His fixed expenses amount to $750. How much are his variable expenses?
Answer:
675 = variable expenses
Step-by-step explanation:
Take the total expenses and subtract the fixed expenses to find the variable expenses
1425-750 = variable expenses
675 = variable expenses
In a sample of 22 people, the average cost of a cup of coffee is $2.70. Assume the population standard deviation is $0.93. What is the 90% confidence interval for the cost of a cup of coffee
Answer:
$2.70+/-$0.33
= ( $2.37, $3.03)
Therefore, the 90% confidence interval (a,b) = ( $2.37, $3.03)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $2.70
Standard deviation r = $0.93
Number of samples n = 22
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
$2.70+/-1.645($0.93/√22)
$2.70+/-1.645($0.198276666210)
$2.70+/-$0.326165115916
$2.70+/-$0.33
= ( $2.37, $3.03)
Therefore, the 90% confidence interval (a,b) = ( $2.37, $3.03)
How many units of insulin are in 0.75 ML a regular U – 100 insulin
Answer:
0.75 ML of insulin contains 75 units of insulin
Step-by-step explanation:
U - 100 insulin hold 100 units of insulin per ml
This means that:
1 ML = 100 units
∴ 0.75 ML = 100 × 0.75 = 75 units
Therefore 0.75 ML of insulin contains 75 units of insulin
Can someone help me with this please
Answer:
21
Step-by-step explanation:
so this is the way i learned it
compare side to side so CA is 12 and LM is 9 so its 4/3
CB is 8 LN is 6 so its 4/3
so AB is 8 so MN would have to be 4/3 which would made MN 6 so MNL would be 21
Answer:
21
Step-by-step explanation:
ΔLMN ≅ ΔABC with a scale factor of 0.75
If Line AB is similar to Line MN, then Line MN is 6.
Perimeter of ΔLMN
9+6+6=
15+6=
21
A jar contains 5 red marbles and 8 white marbles . Event A = drawing a white marble on the first draw Event B = drav drawing a red marble on the second draw If two marbles are drawn from the jar , one after the other without replacement , what is P(AandB) expressed in simplest form?
a: 3/13
b: 10/39
c: 5/12
d: 8/13
Answer:
(B) [tex]\dfrac{10}{39}[/tex]
Step-by-step explanation:
Number of red marbles = 5
Number of white marbles = 8
Total =8+5=13
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
P(A)=8/13
P(B)=5/12
Therefore:
P(A and B)
[tex]=\dfrac{8}{13} \times \dfrac{5}{12}\\\\=\dfrac{10}{39}[/tex]
Answer:
Your answer is B
Step-by-step explanation:
HURRY TIMEDD!!!!!
What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the number of real solutions the equation has? The discriminant is −4, so the equation has 2 real solutions. The discriminant is −4, so the equation has no real solutions. The discriminant is 35, so the equation has 2 real solutions. The discriminant is 35, so the equation has no real solutions.
Answer:
Second option is the correct choice.
Step-by-step explanation:
"The discriminant is −4, so the equation has no real solutions."
[tex]x^2-4x+5=0\\\\a=1,\:b=-4,\:c=5:\\\\b^2-4ac=\left(-4\right)^2-4\cdot \:1\cdot \:5=-4[/tex]
Best Regards!
Answer: B
The discriminant is −4, so the equation has no real solutions.
Step-by-step explanation:
Just took quiz EDG2021
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