Answer:
only neon has electron i n it's outer shell.so it reacts normally.other given elements do not have 8 electron in its outer shell.
Answer:
A -neon
Explanation:
apexx
Based on their locations on the periodic table, which two elements would you expect to form positive ions with a +1 charge?
A. Hydrogen, H
B. Chlorine, CI
C. Fluorine, F
D. Lithium, Li
Based on their locations on the periodic table, Hydrogen, H and Lithium, Li these two elements expect to form positive ions. Hence option A and D is correct.
What is Atom ?Atom is smallest entity of a body. Body is made up of atoms. it is basic building block of a body. An atom consist of electrons, protons and neutrons as sub atomic particle. whole mass of the atom is concentrated at the center of the atom which we call it as nucleus, nucleus consist of proton and neutron. Electron revolve around the nucleus at determined(fixed) orbit. Total number of protons in the atom decides the atomic number and the elements in the periodic table.
The electrons which are completely filled orbitals are called as core shell electrons and which are not filled completely are called as valence electron. valence electrons are responsible for physical and chemical properties of the element. Elements which are on same column in periodic table have same number of valence electrons . Hence they have same properties.
Elements on the Left side of the periodic table are called as donor atom cause they donate electrons in the formation of compound and Elements that are on the right side is called as acceptors cause they accepts electrons.
Oxidation state of Hydrogen and lithium is +1 they donate electrons, hence it forms positive ions. whereas oxidation of state Chlorine and Florine is -1, it accepts electrons and it forms negative ions.
Hence option A and D is correct.
To know more about Atom :
https://brainly.com/question/13654549
#SPJ2.
2.(Ramp section) Suppose the height of the ramp is h1= 0.40m, and the foot of the ramp is horizontal, and is h2= 1.5m above the floor. What will be the horizontal distance traveled by the following four objects before they hit the floor? Assume that R= 15mm in each case; assume that the density of steel is 7.8 g/cm3; and assume that the density of aluminum is 2.7 g/cm3.a.A solid steel sphere slidingdown the ramp without friction.b.A solid steel sphere rollingdown the ramp without slipping.c.A spherical steel shell with shell thickness 1.0 mm rollingdown the ramp without slipping.d.A solid aluminum sphere rollingdown the ramp without slipping.
Answer:
a) the distance that the solid steel sphere sliding down the ramp without friction is 1.55 m
b) the distance that a solid steel sphere rolling down the ramp without slipping is 1.31 m
c) the distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping is 1.2 m
d) the distance that a solid aluminum sphere rolling down the ramp without slipping is 1.31 m
Explanation:
Given that;
height of the ramp h1 = 0.40 m
foot of the ramp above the floor h2 = 1.50 m
assuming R = 15 mm = 0.015 m
density of steel = 7.8 g/cm³
density of aluminum = 2.7 g/cm³
a) distance that the solid steel sphere sliding down the ramp without friction;
we know that
distance = speed × time
d = vt --------let this be equ 1
according to the law of conservation of energy
mgh₁ = [tex]\frac{1}{2}[/tex] mv²
v² = 2gh₁
v = √(2gh₁)
from the second equation; s = ut + [tex]\frac{1}{2}[/tex] at²
that is; t = √(2h₂/g)
so we substitute for equations into equation 1
d = √(2gh₁) × √(2h₂/g)
d = √(2gh₁) × √(2h₂/g)
d = 2√( h₁h₂ )
we plug in our values
d = 2√( 0.40 × 1.5 )
d = 1.55 m
Therefore, the distance that the solid steel sphere sliding down the ramp without friction is 1.55 m
b)
distance that a solid steel sphere rolling down the ramp without slipping;
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{5}[/tex]mR²) ω²
v = √( [tex]\frac{10}{7}[/tex]gh₁ )
so we substitute √( [tex]\frac{10}{7}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1;
d = vt
d = √( [tex]\frac{10}{7}[/tex]gh₁ ) × √(2h₂/g)
d = 1.69√( h₁h₂ )
we substitute our values
d = 1.69√( 0.4 × 1.5 )
d = 1.31 m
Therefore, the distance that a solid steel sphere rolling down the ramp without slipping is 1.31 m
c)
distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping;
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{3}[/tex]mR²) ω²
v = √( [tex]\frac{6}{5}[/tex]gh₁ )
so we substitute √( [tex]\frac{6}{5}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1 again
d = vt
d = √( [tex]\frac{6}{5}[/tex]gh₁ ) × √(2h₂/g)
d = 1.549√( h₁h₂ )
d = 1.549√( 0.4 × 1.5 )
d = 1.2 m
Therefore, the distance that a spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping is 1.2 m
d) distance that a solid aluminum sphere rolling down the ramp without slipping.
we know that;
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] [tex]I_{}[/tex]ω²
mgh₁ = [tex]\frac{1}{2}[/tex] mv² + [tex]\frac{1}{2}[/tex] ([tex]\frac{2}{5}[/tex]mR²) ω²
v = √( [tex]\frac{10}{7}[/tex]gh₁ )
so we substitute √( [tex]\frac{10}{7}[/tex]gh₁ ) for v and t = √(2h₂/g) in equation 1;
d = vt
d = √( [tex]\frac{10}{7}[/tex]gh₁ ) × √(2h₂/g)
d = 1.69√( h₁h₂ )
we substitute our values
d = 1.69√( 0.4 × 1.5 )
d = 1.31 m
Therefore, the distance that a solid aluminum sphere rolling down the ramp without slipping is 1.31 m
We have that for the Question it can be said that
[tex]A solid steel sphere sliding down the ramp without friction = 1.55m[/tex][tex]A solid steel sphere rolling down the ramp without slipping = 1.309m[/tex]A spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping =[tex]1.2m[/tex]A solid aluminum sphere rolling down the ramp without slipping = [tex]1.309m[/tex]From the question we are told
Suppose the height of the ramp is h1= 0.40m, and the foot of the ramp is horizontal, and is h2= 1.5m above the floor. What will be the horizontal distance traveled by the following four objects before they hit the floor? Assume that R= 15mm in each case; assume that the density of steel is 7.8 g/cm3; and assume that the density of aluminum is 2.7 g/cm3.
Generally the equation for sliding without friction is mathematically given as
[tex]V = \sqrt{4Hh}[/tex]
the equation for sliding without slipping is mathematically given as
[tex]X = \sqrt{\frac{4Hh}{1+I/mR^2}}[/tex]
A) A solid steel sphere sliding down the ramp without friction.[tex]V = \sqrt{4*1.5*0.4}\\\\= 1.55m[/tex]
B) .A solid steel sphere rollingdown the ramp without slipping.[tex]I = 2/5 mR^2\\\\X = \sqrt{\frac{4*1.5*0.4}{1+2/5}}\\\\= 1.309m[/tex]
C) A spherical steel shell with shell thickness 1.0 mm rolling down the ramp without slipping.
[tex]I = 2/3 mR^2\\\\X = \sqrt{\frac{4*1.5*0.4}{1+2/3}}\\\\= 1.2m[/tex]
D) A solid aluminum sphere rolling down the ramp without slipping.
[tex]X = \sqrt{\frac{4*1.5*0.4}{1+2/5}}\\\\= 1.309m[/tex]
For more information on this visit
https://brainly.com/question/23379286
can someone please answer this for me ❤️
Answer:
I don't understand the question
Explanation:
sorry I cant help because I am just a first former
If 32g of kerosene of densities of 0.80gcm-3 are mixed with 8g of water, what is the densities of the resulting
mixtures? Take the densities of water to be 1.0g/cm3.
(3mks)
Answer:
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Explanation:
The density of a mixture can be calculated from the individual densities. The average density of the mixture of 32 g kerosene and 8 g of water is 0.9 g/cm³.
What is density?Density of a substance is the measure of its mass per unit volume. Thus, mathematically it is the ratio of mass to the volume of the substance. Density depends on the mass, volume, temperature,bond type and pressure.
The ratio of density of a substance to the density of water is called specific gravity. If the specific gravity is greater than 1 then the object will sink on water and if it is less than 1 then it will float on water.
If two liquids of densities ρ₁ and ρ₂ then after mixing their densities will be:
[tex]\rho =\frac{ \rho_{1} + \rho_{2} }{2}[/tex]
Hence the density of mixture of water (1 g/cm³) and kerosene (0.8 g/cm³) is :
= (0.8 + 1) /2
=0.9 g/cm³.
Thus the density of the resulting mixture be 0.9 g/cm³
To find more on density, refer here:
https://brainly.com/question/15164682
#SPJ2
What is the difference between inertia and momentum?
Which of these colors of light has the
most energy?
red
yellow
orange
Answer:
I think it is yellow but i'm not 100%.
Explanation:
Explain how magnets have an attractive force and repulsive force
I need help on how to start my essay on the 3 laws of motion
Answer:
for the first paragraph introduce the definition. for the second paragraph write about the first law, for the third paragraph write about the 2nd for the fourth paragraph write about the 3rd law. for the last paragraph do a brief summary of what you wrote and a conclusion about the laws.
i hope this helps a bit
Answer:
You can start off with the first law of motion (newtons first law), talk about what it is or what it does, give examples.
A 30-g bullet is fired with a horizontal velocity of 450 m/s andbecomes embedded in block B, which has a mass of 3 kg. After theimpact, block B slides on 30-kg carrier C until it impacts the endof the carrier. Knowing the impact between B and C is perfectlyplastic and the coefficient of kinetic friction between B and C is 0.2,determine (a) the velocity of the bullet and B after the first impact,(b) the final velocity of the carrier.
Answer:
a) [tex]v_{fb+B}=4.46\: m/s[/tex]
b) [tex]v_{fc}=1.21\: m/s[/tex]
Explanation:
a) Let's use the conservation of linear momentum.
[tex]m_{b}v_{iv}=m_{B}v_{f}+m_{b}v_{f}[/tex]
Where:
m(b) is mass of bullet (0.03 kg)v(ib) is the initial velocity of the bullet (450 m/s)m(B) is the mass of the block (3 kg)v(f) is the final velocity of the bullet and the block[tex]m_{b}v_{iv}=m_{B}v_{f}+m_{b}v_{f}[/tex]
[tex]v_{f}=\frac{m_{b}v_{iv}}{m_{B}+m_{b}}[/tex]
[tex]v_{f}=\frac{0.03*450}{0.03+3}[/tex]
[tex]v_{fb+B}=4.46\: m/s[/tex]
b) As we have an external force between B and C we can not use the conservation of linear momentum here. We need to use the work definition.
The work here is due to the friction force.
[tex]W=\Delta K[/tex]
[tex]W=K_{f}-K_{i}[/tex]
[tex]-\mu m_{B}g=0.5(m_{b}+m_{B}+m_{C})v_{f}^{2}-0.5(m_{b}+m_{B})v_{i}^{2}[/tex]
[tex]-\mu m_{B}g=0.5(m_{b}+m_{B}+m_{C})v_{f}^{2}-0.5(m_{b}+m_{B})v_{i}^{2}[/tex]
[tex]-0.2*3*9.81=0.5(0.03+3+30)v_{f}^{2}-0.5(0.03+3)4.46^{2}[/tex]
[tex]v_{f}^{2}=\frac{-0.2*3*9.81+0.5(0.03+3)4.46^{2}}{0.5(0.03+3+30)}[/tex]
[tex]v_{fC}=1.21\: m/s[/tex]
I hope it helps you!
I need huge help understanding this type of questions :( Please and thank you
The coefficient of static and kinetic frictions between a 15.2-kg box and a desk are 0.55 and 0.36, respectively. What is the net force on the box when a 120.9 N horizontal force is applied to the box while moving?
Answer:
67.28 N
Explanation:
Given that,
The mass of an box, m = 15.2 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.55 and 0.36, respectively.
The force of static friction,
[tex]F_s=\mu_smg\\\\F_s=0.55\times 15.2\times 9.8\\\\F_s=81.92\ N[/tex]
The force of kinetic friction,
[tex]F_k=\mu_kmg\\\\F_k=0.36\times 15.2\times 9.8\\\\F_k=53.62\ N[/tex]
Net force acting on the object is :
F = 120.9 -53.62
= 67.28 N
Hence, this is the required solution.
A bicycle camper rides from her starting point to her first campsite one day, then continues to a second campsite the next day. If her average speed for the two days equals the average of her speeds each day, what must be true about her journey?
Answer:
is there any more to this question
Explanation:
Classify the following situations into contact and non-contact forces.
(a) Applying brakes in a vehicle
(b) a coconut falling from a coconut tree
(c ) the planets revolving around the sun
(d) a ball is rolling on ground.
Answer:
(a) Applying brakes in a vehicle - Contact force
(b) a coconut falling from a coconut tree - Contact force
(c ) the planets revolving around the sun - Non-Contact force
(d) a ball is rolling on ground - Contact force
Explanation:
Contact forces are defined as the forces that apply between two objects which are in physical contacts with each other while non-contact forces forces that act between two objects that are not in physical contact with each other.
Given are some of the examples of contact and non-contact forces. So example of contact forces are applying brakes in a vehicle, a coconut falling from a coconut tree and a ball is rolling on ground.
Example of non-contact force is the planets revolving around the sun.
A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is emitting a constant tone of frequency fs Five points are labeled in the drawing to indicate positions along the arc as the child swings. At which position(s) will the child hear the lowest frequency for the sound from the whistle?
Answer:
Explanation:
We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .
f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .
f will be lowest when v₀ is highest .
velocity of observer is highest when he is at the equilibrium position or at middle point .
So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .
.) What will be the unit of time in that system in
which unit of length is m, unit of mass is kg and
unit of force is kg wt?
(a) [1/V(9.8) second (b) (9.8)2 second
(c) V(9.8) second
(d) 9.8 second
Answer:
yes it is a great question. Thank you .
What is the subject Physic about
Explanation:
Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.
Answer:
if you are very excited to know why ball doesn't go up
A 180kg motorcycle has an acceleration of 20.5m/s^2. what was the net force applied to the motorcycle?
Answer:
3690 Newton
Explanation:
By using the F=ma formula we can find the Force if we know the mass and acceleration, so:
F= 180kg*20.5m/s^2
F=3690 kg*m/s^2 or 3690N
Calculate the momentum of a 6 kg ball thrown at 20 m/s by a 3 newton
force. *
Answer:
momentum = mass × velocity = 6× 20 =120 kg.ms-1
Explanation:
not sure if this is right
Olive and her friend Wellington are playing down by Captain Don's docks when they find an old chain. The old chain has only three links. By measuring with an old fish scale which is a permanent feature of the dock area, they determine that the total mass of the chain is 3.12 kg (the scale reads in newtons, but Olive knows how to calculate the mass of the chain from its weight). While playing with the scale and the chain (the chain is hanging vertically from the end of the scale, and Olive is holding on to the top of the scale with both hands, either moving the entire system upwards or downwards), Olive notices that if she is accelerating the chain either upwards or downwards, the scale no longer accurately reads the weight of the chain. When the Scale Reading is Larger than the Weight of the Chain At one point in their experiments with the chain and the scale, Wellington observes that the scale reads 47.00 N . Part A When the scale reads 47.00 N , what is the tension in the chain at the point where the lowest two links connect
Answer:
T₁ = 15.66 N
Explanation:
From the given information:
Using the free body system in the chain.
T - mg = ma
47 - 3.12 × 9.8 = 3.12a
47 - 30.576 = 3.12a
16.424 = 3.12a
a = 16.424/3.12
a = 5.26 m/s²
Now, by the free body diagram of the lowest link; the tension (T₁ ) in the chain is:
T₁ - (3.12/3) × 9.8 = (3.12/3) × 5.26
T₁ - 1.04 × 9.8 = 1.04 × 5.26
T₁ - 10.192 = 5.4704
T₁ = 5.4704 + 10.192
T₁ = 15.6624
T₁ = 15.66 N
can a body have an east velocity while expressing westward acceleration
Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.
Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.
Hope this helped!
5. Atoms may emit light energy when
O A electrons move to a lower energy level
OB protons move to a lower energy level
C electrons move to a higher energy level
OD protons move to a higher energy level
A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat three people. The lift is operating at a steady speed of 10 km/h. Neglecting friction and air drag and assuming that the average mass of each loaded chair is 250 kg, determine the power required to operate this ski lift. Also estimate the power required to accelerate this ski lift in 5 s to its operating speed when it is first turned on.
Answer:
Explanation:
Each chair having mass of 250 kg , separated by 20 m
Total no of chair = 1000 / 20 = 50
Total mass of all chair = 50 x 250 = 12500 kg
Force required to move the chair = mg sinФ where Ф is inclination of lift .
SinФ = 200 / 1000 = .2
Ф = 11.536⁰
Force required to move the chair = mg sin11.53
= 12500 x 9.8 x sin11.53
F = 24485.42 N
velocity of lift = 10 x 1000 / (60 x 60 ) m /s
v = 2.78 m /s
Power required = F v where v is velocity of movement of lift
= 24485.42 x 2.78 W
= 68069.46 W.
What scientific observation did Edwin Hubble use to determine distances between galaxies?
Answer: the expanding universe
Explanation:
Hope that helps!
There are around one billion light years across galaxies on ordinary. The observable cosmos has around 100 billion galaxies.
What is scientific observation?In research, observation is vital. Scientists gather and record data through observation, which allows them to create and subsequently test concepts and hypotheses. Scientists can observe in many different ways, including using their own senses or instruments like telescopes, thermometers, satellites, or stethoscopes.
In addition, Hubble proved a basic fact now known as Hubble's Law: galaxies distant from us are retreating faster than those closer to us. The Big Bang Theory's central tenet is the notion of an expanding cosmos. The first understanding of the beginnings of our cosmos came from Hubble's observations.
There are around one billion light years between galaxies on normal. The observable cosmos has around 100 billion galaxies.
More about the scientific observation link is given below.
https://brainly.com/question/921327
#SPJ6
A chair is pushed with a force of -210 N to the left. If the acceleration of the chair is 35 m/s. What is the mass of the chair?
Answer:
big brr never go wromng
Explanation:
Is inertia a force (will give brainleist for first answer)
Answer:
Yes.
Explanation:
Answer:
I do believe it is. (more characters for character limit)
Karl measures the current through a resistor. What else will he need to measure in order to work out its resistance?
Answer:
The voltage (V)
Explanation:
Ohms, in his law, has explained the relationship between current, resistance and voltage.
Ohm's law, which states that the voltage passing through a resistor is directly proportional to both the current and the resistance of the resistor, has the following equation:
V = IR
Where;
V = voltage (volts)
I = current (Amperes)
R = resistance (ohms)
According to this question, Karl measures the current, I, through a resistor. In order to calculate his resistance, R, he will need to measure the voltage, V.
Someone please help me answer these questions
1. What is the walking
Aquarium to the Key West Cemetery?
A
2. What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
3. If you were walking 4 miles per hour how long would it take you
to get from the Aquarium to the Cemetery? (Speed= D/T)
4. If you were to take off in a helicopter from Ft. Zachary State
Historic Site and fly directly to the US Naval Air Station at a constant
speed of 20 miles per hour how long would it take?
Answer:
house away far from
Explanation:
I dont know tbh
How far can you get away from your little
brother with the squirt gun filled with
paint if you can travel at 3 m/s and you
have 15s before he sees you?
Know
Find
Equation
Solve
spray him in the eyes and you have until he washes it put
0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Answer:
the mouse
Explanation:
the mouse has a momentum of 33 m kg/s
while the elephant has a momentum of 27 m kg/s
i found this out using p=mv
As the mass of object increased it is density increased
Answer:
True.
Explanation:
The density of an object is given by its mass divided by its volume. It can be given as follows :
[tex]d=\dfrac{m}{V}[/tex]
It can be seen that the density of an object is directly proportional to its mass. It means if the mass of an object increase, its density will also increase. Hence, the given statement is true.
g Consider a (12.5 A) cm long metal bar moving horizontally across a vertical magnetic field at a speed of (2.40 B) m/s. The magnetic field strength is 2.45 T. If the ends of the bar are connected to a (1.20 C) ohm resistor, find the power dissipated in the resistor while the bar is moving. Calculate the answer in watts (W) and rounded to three significant figures.
Answer:
Explanation:
emf due to movement of a rod of length L in a perpendicular to magnetic field B with velocity v is given as
emf = BLv
Putting in the given values ,
E = 2.45 x 12.5 x 10⁻² x 2.4
= .735 V
This emf produces current in resistance . Power consumed by resistance
V² / R where R is resistance , V is emf induced .
Power = .735² / 1.2
= .45 W .