Answer:
the right answer is d i took the unit test on edge
Explanation:
The Enlightenment is also known as the Age of Humanism. Rationalism. Reason. Secularism.
Answer:
The Enlightenment is also known as the Age of Reason.
Explanation:
This is because considered a time that man used his reason to discover the world.
Answer:
Reason
Explanation:
Morgan opens a savings account that earns simple interest at the rate of 4.5\%4.5%4, point, 5, percent annually. If she initially deposits \$50$50dollar sign, 50 in the account, what is the minimum number of years it will take for her savings to be at least \$68$68dollar sign, 68, assuming she makes no other deposits or withdrawals?
Answer:
8
Explanation:
If (4^a^-2)(4^3) = 64^2 , what is the value of a? a. 0 b. 4 c. 5 d. 7 e. 8
Answer:
[tex]\boxed{a=4}[/tex]
Explanation:
Part 1. Finding product of [tex](4a^2)(4^3)[/tex]
Step 1. [tex]4^3=64[/tex]
Step 2. [tex](4a^2) * (64) = (64 * 4)(a^2)[/tex]
Step 3. [tex](64 * 4)(a^2) = 256a^2[/tex]
[tex]\boxed{(4a^{2})(4^3) = 256a^{2}}[/tex]
Part 2. Simplifying the equation & solving for a
Step 1. [tex]\sqrt{256a^{2}} = \sqrt{64^{2}}[/tex] ⇒ [tex]16a = 64[/tex]
Step 2. [tex]\frac{16a}{16} = \frac{64}{16}[/tex] (divide both sides by coefficient of variable)
[tex]\boxed{a = 4}[/tex]
Half the difference of 18 and a number n is equal to the sum of n and three. what is the value of n?
Answer:
n=12
Explanation:
First you have to write out the equation for the problem.
(18+n)/2=n+3
To get rid of the fraction, multiply both sides by 2.
18+n=2n+6
Now subtract n and subtract 6 from both sides and you will have your answer.
12=n
Answer:
n=4
Explanation:
(18-n)/2=n+3
2*((18-n)/2)=(n+3)*2
18-n=2n+6
+n +n
18 = 3n+6
-6 -6
12 =3n
÷3 ÷3
4=n
n=4
which of the following is equivalent to (3^x+1)(3^x-1)^2/9^x for all x? a. 3^2x-1 b. 3^x c. 3^x-1 d. 3^x-2 e. 3^3-x
Answer:
[tex]3^{x-1}[/tex]
Explanation:
Given
[tex]\frac{(3^{x+1})(3^{x-1})^2}{9^x}[/tex]
Required
Find its equivalent
[tex]\frac{(3^{x+1})(3^{x-1})^2}{9^x}[/tex]
Expand the numerator
[tex]\frac{(3^{x+1})(3^{x-1})(3^{x-1})}{9^x}[/tex]
Apply law of indices: [tex]a^m * a^n = a^{m+n}[/tex]
This gives
[tex]\frac{3^{x+1+x-1+x-1}}{9^x}[/tex]
Collect like terms
[tex]\frac{3^{x+x+x+1-1-1}}{9^x}[/tex]
[tex]\frac{3^{3x-1}}{9^x}[/tex]
Express [tex]9^x[/tex] as a factor of 3
[tex]\frac{3^{3x-1}}{3^2^x}[/tex]
Apply law of indices: [tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This gives
[tex]3^{3x-1-2x}[/tex]
[tex]3^{3x-2x-1}[/tex]
[tex]3^{x-1}[/tex]
Hence,
[tex]\frac{(3^{x+1})(3^{x-1})^2}{9^x}[/tex] is equivalent to [tex]3^{x-1}[/tex]
Who is 11 on this app
What are some tests for assessing each of the health-related components of fitness
Answer:
The fitness gram and pacer test
Explanation:
when using reducing balance method
straight line
sum digit method
Answer:
straight line method:
depreciation=cost - residual value
number of years
1. D=8000-200 = 7800 = 1560
5. 5
2. D=1600-5000 = 11000 = 2750
4. 4
3.D= 7500-0 = 7500 = 2500
3. 3
4.D 14300-2800 = 11500 = 2300
5. 5
I am not really good at the rest of them but I hope this works