Answer:
Approximately [tex]480\; \rm kPa[/tex], assuming that this gas is an ideal gas.
Explanation:
Let [tex]V(\text{Initial})[/tex] and [tex]P(\text{Initial})[/tex] denote the volume and pressure of this gas before the compression. Let [tex]V(\text{Final})[/tex] and [tex]P(\text{Final})[/tex] denote the volume and pressure of this gas after the compression.By Boyle's Law, the pressure of a sealed ideal gas at constant temperature will be inversely proportional to its volume. Assume that this gas is ideal. By this ideal gas law:
[tex]\displaystyle \frac{P(\text{Final})}{P(\text{Initial})} = \frac{V(\text{Initial})}{V(\text{Final})}[/tex].
Note that in Boyle's Law, [tex]P[/tex] is inversely proportional to [tex]V[/tex]. Therefore, on the two sides of this equation, "final" and "initial" are on different sides of the fraction bar.
For this particular question:
[tex]V(\text{initial}) = 1.0\; \rm m^3[/tex].[tex]P(\text{Initial}) = 120\; \rm kPa[/tex].[tex]V(\text{final}) = 0.25\; \rm m^3[/tex].The pressure after compression, [tex]P(\text{Final})[/tex], needs to be found.Rearrange the equation to obtain:
[tex]\displaystyle P(\text{Final}) = \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})[/tex].
Before doing any calculation, think whether the pressure of this gas will go up or down. Since the gas is compressed, collisions between its particles and the container will become more frequent. Hence, the pressure of this gas should increase.
[tex]\begin{aligned}P(\text{Final}) &= \frac{V(\text{Initial})}{V(\text{Final})} \cdot P(\text{Initial})\\ &= \frac{1.0\; \rm m^{3}}{0.25\; \rm m^{3}} \times 120\; \rm kPa = 480\; \rm kPa\end{aligned}[/tex].
At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming that the electron has an instantaneous velocity of 8.50 ✕ 106 m/s directed to the east.
Answer:
A) F_g = 8.9278 × 10^(-30)
B) F_e = 1.6 × 10^(-17) N upwards
C) F_m = 6.8 × 10^(-17) N downwards
Explanation:
A) Formula for gravitational force is;
F_g = m_e × g
m_e is mass of electron = 9.11 x 10^(-31) kg
F_g = 9.11 x 10^(-31) × 9.8
F_g = 8.9278 × 10^(-30) N downwards
B) Formula for Electric force is;
F_e = qe
q is charge on electron = 1.6 × 10^(-19) C
E is electric field = 100 N/C
F_e = 1.6 × 10^(-19) × 100
F_e = 1.6 × 10^(-17) N upwards
C) Magnetic force is given by the formula;
F_m = qVB
q is charge on electron = 1.6 × 10^(-19) C
V is velocity given as 8.50 × 10^(6) m/s
B is magnetic field = 50.0 μT = 50 × 10^(-6) T
F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)
F_m = 6.8 × 10^(-17) N downwards
1.what are some of the impacts of modern communication in our socio economic life?
2.how is possible to make a call to our relatives residing in other part of country ?explain?
Answer:
The impacts of modern communication in our socio economic life includes;
a) Staying connected
b) Carrying out business transaction
c) Exceeding boundaries
d) Overcoming weakness and disability
e) Reaching out to a wider audience
2. It is possible to make long distant call to our relatives in other part of the country by direct distance dialing (DDD)
Explanation:
The telecommunication service called direct distance dialing allows a caller to make a call to a location outside the area where they are calling without the assistance of an operator. To make a direct dialing call, a subscriber or caller will be required to include extra prefix digits to the original number than for numbers within hers or his particular local area code.
Average acceleration. Please help!
Answer:
8.43 m/s²
Explanation:
Average acceleration is the change in velocity over change in time.
a = Δv/Δt
First, convert km/h to m/s.
45 km/h = 12.5 m/s
500 km/h = 138.9 m/s
Now find the acceleration.
a = (138.9 m/s − 12.5 m/s) / 15.0 s
a = 8.43 m/s²
Does the earths magnetic field change with time?
Answer:
As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.
ULIULIOL
THIS. AJUSI
A bus is moving with a velocity of 72 km/hr. On seeing the red signal of traffic
at 27 m ahead on the road, the driver applied brakes and the bus stopped at a
distance of 25 m. Calculate the time taken by the car to come at rest. (Ans: 2.5 s)
with
of 60 km/hr. On seeing a child at 11m ahead on
A
a
Answer:
The time taken by the car to come at rest is 2.5 seconds
Explanation:
The parameters given are;
Speed of bus = 72 km/hr
Distance at which bus stopped = 25 m
Given that the speed and the distance covered before stopping are j=known, we have;
v² = u² - 2·a·s
Where:
v = Final velocity = 0
a = Deceleration of the bus
s = Distance covered while decelerating = 23 m
u = Initial velocity = 72 km/hr = 20 m/s
Which gives;
0² = (20 m/s)² - 2×a×25 m
20² = 2×a×25 m
a = 20²/(2×25) = 8 m/s²
The time, t, it takes for the car to come at rest is given by the relation;
v = u - at
0 = 20 - 8×t
t = 20/8 = 2.5 s.
On which body would a 10 kg lamp have the most gravitational potential energy when lifted to height of 2 m? A) Earth B) Mars C) Neptune D) Uranus
Answer: C.) Neptune
Explanation:
The Gravitational Potential Energy (GPE) of a body is calculated using the formula :
GPE = mgh
Where m = mass of the body
g = acceleration due to gravity
h = distance above a surface
Mass = 10kg
h = 2m
Using the formula :
GPE of lamp on Earth: g = 9.8
GPE = 10 × 9.8 × 2 = 71.8J
GPE of lamp on Mercury: g = 3.59
GPE = 10 × 3.59 × 2 = 196J
GPE of lamp on Mars: g = 3.7
GPE = 10 × 3.7 × 2 = 74J
GPE of lamp on Neptune: g = 14.07
GPE = 10 × 14.07 × 2 = 281.4J
GPE of lamp on Uranus: g = 9
GPE = 10 × 9 × 2 = 180J
GPE of lamp on Pluto: g = 0.42
GPE = 10 × 0.42 × 2 = 8.4J
Neptune has the highest gravitational potential energy as the value of acceleration due to gravity acting on objects is highest on Neptune.
Answer:
The correct option is;
C) Neptune
Explanation:
The force of gravity is given by the equation;
[tex]F_g = G\dfrac{m_1m_2}{r^2} = m_2 \times g[/tex]
Where:
m₁ = Mass of the planet
m₂ = Mass of the body = 10 kg
r = The distance between the body and the planet = 2 m
g = Gravitational acceleration on the planet
G = Gravitational constant
Given that the potential energy, PE = m × g × h
We have that,
[tex]PE = m_2 \times g \times (r + 2) = G\dfrac{m_1m_2}{r^2} \times (r + 2) \approx G\dfrac{m_1m_2}{r^2} \times r = G\dfrac{m_1m_2}{r}[/tex]
Therefore, the gravitational potential energy is directly proportional to the acceleration of gravity, such that the body will have the most gravitational potential energy in the planet with the highest acceleration due to gravity which is Neptune with acceleration due to gravity of 14.07 m/s².
If you hold a bar magnet in each hand and bring your hands together, will the force be attractive or repulsive if the magnets are held:
a) with the two north poles together?
b) with a north pole and south pole together
Answer:
Part A:
They will repel each other because same poles repel each other.
Part B)
They will attract each other because different poles attract each other..
Please help. Brainliest will be given! 25 points. Show all work.
Explanation:
Given:
v₀ₓ = 15 m/s cos 20° = 14.10 m/s
aₓ = 0 m/s²
v₀ᵧ = 15 m/s sin 20° = 5.13 m/s
aᵧ = -9.8 m/s²
t = 1.5 s
Find: Δx and Δy
Δx = v₀ₓ t + ½ aₓ t²
Δx = (14.10 m/s) (1.5 s) + ½ (0 m/s²) (1.5 s)²
Δx = 21.1 m
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (5.13 m/s) (1.5 s) + ½ (-9.8 m/s²) (1.5 s)²
Δy = -3.33 m
state any two physical properties for believing that aluminium is a metal.
Answer:
amongst the properties that makes aluminium a metal is that it is malleable and ductile...and it has high melting and boiling points
I hope that helps
Explanation:
properties of metals include
1. high melting and boiling points
2 high densities
3 malleability and ductility
If three vectors added together, forms a triangle, the resultant will be equal to twice the vector zero doubled the magnitude none of the above
Answer:
the resultant vector will be a null vector or with 0 magnitude
Explanation:
A 5000 kg mass rocket “breaks the engine” when it is 100 m high and climbing at a speed of 75 m / s. Calculate:
1) The maximum height it will reach
2) The speed with which it will hit the ground after the fall.
Answer:
1:281.25m
2:75m/s
Explanation:
using the equation
[tex]v^{2} = u^{2} + 2gs[/tex]
at maximum height v is zero so using that you can make s the subject of the formula
[tex]h \: max = u^{2} \div \: 2g[/tex]
so substitute the velocity 75 and the constant g-10m/s^2
as for the returning velocity we say displacement is zero since you go and come back the same distance
so
[tex]v = { + or - }u[/tex]
u is the initial speed in this case it's positive since going in the direction of gravity
Which is a negative effect of deforestation on the environment? A. habitat restoration B. desertification C. soil production D. urbanization
Answer:Deforestation refers to the decrease in forest areas across the world that are lost for other uses such as agricultural croplands, urbanization, or mining activities. Greatly accelerated by human activities since 1960, deforestation has been negatively affecting natural ecosystems, biodiversity, and the climate. The UN’s Food and Agriculture Organization estimates the annual rate of deforestation to be around 1.3 million km2 per decade.
Explanation:
The negative effect of deforestation on the environment is desertification. The correct option is B.
What is desertification?Desertification is the process by which fertile land becomes desert, typically as a result of drought, deforestation, and inappropriate agriculture or land use practices. It occurs when land that was once able to support vegetation and life becomes increasingly dry, barren, and unable to sustain crops, livestock, or human populations. This can be due to natural causes such as prolonged droughts, but it is often exacerbated by human activities such as deforestation, overgrazing, and soil degradation. Desertification can have devastating effects on the environment, leading to soil erosion, loss of biodiversity, and reduced productivity of the land. It can also cause social and economic problems, such as displacement of people, food shortages, and conflicts over resources.
Here in the question,
Deforestation is the clearing of trees and other vegetation from an area, leading to the loss of habitat and biodiversity, and disruption of water cycles. It can also cause soil erosion, which can result in the depletion of soil nutrients, reduced productivity, and eventually lead to desertification. Additionally, deforestation contributes to climate change by releasing carbon dioxide into the atmosphere, which can cause global warming and other environmental problems. Habitat restoration, soil production, and urbanization are not negative effects of deforestation but can be impacted by it.
Therefore, The correct answer is B i. e Desertification.
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PLZ HELP Sound is a form of wave. List at least three reasons to support the idea that sound is a wave
Answer:
Sound is a form of wave . Wave is defined as a periodic disturbance in medium.
Reasons:
1. It follows all properties of light at a boudary.
2. Noise cancelling headphones.
3. It carry energy from one place to another.
Explanation:
I hope this will help you guy.
Sound wave is a mechanical type of wave because it requires a material medium for its propagation.
The following are three reasons sound is classified as a wave.
Reflection: sound waves are reflected like other waves when they strike a plane surface. This effect results to a phenomenon called Echo. Echo is the sound heard after the reflection of sound waves from a plane surface.Interference: sound wave like other form of wave exhibits interference. Interference of sound occurs when two waves of same frequency emitted by two close sources are superposed.Refraction: sound wave like other forms of wave also exhibits changes in velocity, frequency and wavelength when it moves from one medium to another.To learn more about sound waves, please visit: https://brainly.com/question/15805783
write a story that ends with poor no friend
Answer:
Writing of a story that ends with the character becoming poor with no friends.
Explanation:
There was a young girl who believed that all things revolve around her. She had the money, the power, the family, and the beauty to ensure she was the center of attention. She would always be the main focus, everywhere she goes.
But there came a time when she had a major misfortune. Her family had come upon unfortunate times. They are going to lose their money and may even be jailed for embezzlement. It was true that she had no idea what her parents had done but she was also so familiar with the 'princess' lifestyle that she did not know how to downgrade her lifestyle. And so, when this misfortune happened, she was unsure how to react. She also assumed that her friends will be there for her. Little did she know everyone was just after her wealth and influence and had nothing to do with genuine friendship.
In a few months, their family position moved from top to bottom, which everyone found hard to accept. She had to maintain her status while at the same time try to live up with that without losing her circle. But as rumors spread fast and she wasn't able to spend the way she would normally send, she eventually experienced a dwindled friend circle. And in about a year, she had lost all of her friends, couldn't even convince someone to stay with her faithfully and worse of all, she was also poor, the very status she had degradingly taunted other people with.
Find average speed in
time interval t = 2 tot = 10s
Distance (m)
10+
8-
2
+ Time (s)
10
Answer: 3.75 m/s
Explanation:
Average speed is distance covered per time taken.
If the time interval is from t = 2 to t = 10s
Then, the time taken will be
t = 10 - 2 = 8s
Given that the distance covered are 10 + 8 - 2 + 10
Since distance is a scalar quantity, we will only consider the magnitude and not the direction.
Total distance = 10 + 8 + 2 + 10 = 30m
Average speed = total distance/time
Substitute total distance and time into the formula
Average speed = 30/8
Average speed = 3.75 m/s
a 35g ball is lifted up from 1.0m to 3.0m. How much work is done?
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Work And Energy.
So we here use the formula as,
W= Mgh
so after solving we get as,
W = 0.686 Joules
a 2500kg car is travelling at a constant speed of 14 m/s along an icy, but straight and level road. the driver of the car, seeing an approaching traffic light turn red., slams on the brakes. Wheels locked and ttired skidding, the car slide to a halt in a distance of 25m. What is the coefficient of friction
Answer:
0.40
Explanation:
Given that :
the mass of the caer = 250 kg
initial speed = 14 m/s
final speed = 0 m/s
distance s = 25 m
Using the equation of motion
[tex]v^2 = u^2 + 2as[/tex]
making a the subject of the formula ; we have:
[tex]v^2-u^2 = 2as[/tex]
[tex]a= \dfrac{v^2-u^2 }{2 \ s}[/tex]
[tex]a= \dfrac{(0)^2-(14)^2 }{2 \ (25)}[/tex]
[tex]a= \dfrac{0-196 }{50}[/tex]
[tex]a= \dfrac{-196 }{50}[/tex]
a = -3.92 m/s²
However; the relation for the coefficient of the kinetic static friction can be expressed as:
[tex]f= \mu_k *mg= ma[/tex]
[tex]f= \mu_k *g= a[/tex]
[tex]f= \mu_k = \dfrac{a}{g}[/tex]
[tex]f= \mu_k = \dfrac{3.92}{9.8}[/tex]
[tex]f= \mu_k = 0.40[/tex]
the coefficient of friction between a hard rubber and normal street pavement is 0.8 What is the steepest incline on which a car can be safely parked
Answer:
38.7°
Explanation:
Draw a free body diagram of the car. There are three forces:
Weight force mg pulling down,
Normal force N pushing up perpendicular to the incline,
and friction force Nμ pushing parallel up the incline.
Sum of forces in the perpendicular direction:
∑F = ma
N − mg cos θ = 0
N = mg cos θ
Sum of forces in the parallel direction:
∑F = ma
Nμ − mg sin θ = 0
Nμ = mg sin θ
μ = (mg sin θ) / N
μ = (mg sin θ) / (mg cos θ)
μ = tan θ
Given μ = 0.8:
θ = tan⁻¹(0.8)
θ = 38.7°
two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at 4 metre apart
Answer: 0.5N
Explanation:
Gravitational force is calculated using the formula :
F = Gm1m2/r^2
Where G is the gravitational constant (6.67 × 10^-11)
At a distance 'r' of 2metres apart:
Mass of objects are m1 and m2
Gravitational force 'F1' = 2N
Inputting values into the formula :
2 = Gm1m2 / 2^2 - - - - - (1)
At a distance 'r' of 4meters apart:
Mass of objects are m1 and m2
Gravitational force 'F2' = y
Inputting values
F2 = Gm1m2 / 4^2 - - - - - (2)
Dividing equations 1 and 2
2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2
2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)
2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)
2/F2 = 16 / 4
Cross multiply
2 × 4 = 16 × F2
8 = 16F2
F2 = 8/16
F2 = 0.5N
What is the net force acting on the buggy. ?The net force is pointing to the ?
Answer: 390, right
explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.
the net force acting on the buggy is 390 and The net force is pointing to the is right
The following information should be considered:
The net force should be the sum of all of these forces that acted an object.This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equivalent to the mass of the object and multiplied by the acceleration of the objectLearn more: https://brainly.com/question/17961582?referrer=searchResults
I NEED HELP PLEASE, THANKS! :)
Three 15.0-W resistors are connected in parallel across a 30.0-V battery. Please show all work.
a) Find the current through each branch of the circuit.
b) Find the equivalent resistance of the circuit.
c) Find the current through the battery.
Answer:
Take a look at the attachment below.
Explanation:
Current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.
What is Current?An electric current is defined as a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space, which is described as the flow of electric charge through a surface or in a control volume.
Current is expressed as:
I=V/R
Where, I is the current
V is the voltage
R is the resistance
For above given information,
Since all resistors have the same resistance, it would be fine to find only 1 branch as the current would be the same for all branches.
[tex]I=V/R_1[/tex]
I= 30/15= 2 A
Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.
[tex]1/R= 1/R_1+ 1/R_2+ 1/R_3[/tex]
1/R= 1/15+ 1/15 + 1/15
1/R=3/15
R = 15/3= 5 ohms
I = V/R
Where I is current, V is voltage and R is the equivalent resistance
=> I = 30/5
=> I = 6 A
Thus, current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.
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A flat polished area is turned through 15 degrees. If the angle of incidence is 20 degrees, what is the angle between the incident ray and the reflected ray of the turned surface?
Answer:
50°Explanation:
Angle of rotation of the flat polished surface [tex]\theta[/tex] = 15°
angle of incidence i = 20°
Since the polished surface is turned at an angle of 15°, the angle of reflection
r = 2[tex]\theta[/tex] (Note that the angle of rotation only have effect of the angle of reflection)
r = 2*15 = 30°
The angle between the reflected ray and the incident ray will be equal to the sum of the angle of incidence and the angle of reflection i.e i+r
The angle between the reflected ray and the incident ray = 20°+ 30° = 50°
We weigh less in water than in air. Why?
the weight of a body will be zero during free fall. Why?
Answer:
The apparent weight of a freely falling body is zero. When a body falls freely, it is falling with an acceleration =g. Thus the entire gravitational force acting on it is utilized in accelerating it and hence its weight is not felt.
answer the following question
Answer:
A) OA, AB, BC
B) 25m/s^2
C) see explanation
D) 25
E) Rest
Explanation:
From the Velocity time graph shown:
The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.
Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.
-ve slope = BC
B) Acceleration of body in path OA.
Acceleration = change in Velocity / time
Acceleration = (150 - 0) / 6
Acceleration = 150/6 = 25m/s^2
C) Path AB is Parallel to the because it marks the period of constant velocity (that is Velocity does not increase or decrease during the time interval).
D) Length of BC
BC corresponds to the distance moved, that velocity / time
Velocity = 150 ; time = 6
Therefore Distance (BC) = 150/6 = 25
E.) Velocity =0 ; Hence body is at rest
You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that
the flagpole makes 20 complete vibrations in 10 seconds. You read somewhere that this
flagpole vibrates at a speed of 25 m/s when the wind is blowing. Find the wavelength of these
vibrations
Answer:
Wavelength =50 m
Explanation:
Given:
n=20
t=10sec
V=25m/s
Wavelength =?
Solution:
Wavelength = frequency ×velocity ---> eq 1
Time period=time/no of vibrations
T=10/20=0.5sec
Frequency =1/Time period(T)
f=1/0.5=2
Put the value of frequency in eq 1
Wavelength =2×25
Wavelength =50m...
Hope you understand!
Have a nice day!
any ss2 here (11th Grade)
Answer:
a) 50°b) 40°Explanation:
Check the complete diagram n the attachment below
a) The angle of incidence on a plane surface is the angle between the incidence ray and the normal ray acting on a plane surface. The normal ray is the ray perpendicular to the surface while the incidence ray is the ray striking a plane surface.
According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.
Given angle of glance on M₂ to be 40°, r₂ = 90-40 = 50°
According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)
Also ∠OO₂O₁ = ∠OO₁O₂ = 40° (angle of glance on M₁){alternate angle}
The angle of incidence on M₁ = 90° - 40° = 50°
b) The angle of incidence to the surface of M₁(∠PO₁A)will be the angle of glance on M₁ which is equivalent to 40°
A neutral atom has the same number of protons as it does neutrons.
A. True
O B. False
SUBMIT
Answer:
The answer is False
Hope this helps you
It is false that a neutral atom has the same number of protons as it does neutrons. The correct option is B.
The claim that "A neutral atom has the same number of protons as it does neutrons" is untrue. Protons and electrons in a neutral atom are equal in number, but neutron counts can change.
Electrons have a negative charge, whereas protons have a positive charge. A neutral atom has a net charge of zero because the protons' positive charge is balanced by the electrons' negative charge.
Neutrons don't have an electric charge, though. Within a single element, the amount of neutrons can change, giving rise to many isotopes.
Isotopes contain the same amount of protons, but their atomic masses vary depending on how many neutrons they have.
Thus, the correct option is B. False.
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PLZ HELP What is necessary condition for production of waves?
Answer:
The length of the rope must be an integral multiple of the wavelength of the wave.
Explanation:
Answer:
The condition necessary for formation or a standing wave is that the length of the rope (or the length over which the wave is distributed) must be an integral multiple of the wavelength of the wave. Therefore, l=nλ where n is a positive integer.
Please HELP!!! I will give brainliest to whoever gives honest help!!! A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the radius of the circular orbit. Determine the speed of the satellite. Determine the period of the orbit.
Given that,
Mass of satellite = 500 kg
Gravitational force = 3000 N
We need to calculate the radius of the circular orbit
Using formula of gravitational force
[tex]F_{g}=\dfrac{GMm}{(R+h)^2}[/tex]
Where, G = gravitational constant
R = radius of earth
h = radius of the circular orbit
M = mass of earth
m = mass of satellite
Put the value into the formula
[tex]3000=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}}{(6.4\times10^{6})^2+h^2}[/tex]
[tex]h^2=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}[/tex]
[tex]h=\sqrt{\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}}[/tex]
[tex]h=5073460.35\ m[/tex]
[tex]h=5.1\times10^{6}\ m[/tex]
(II). We need to calculate the speed of the satellite
Using formula of velocity
[tex]v=\sqrt{\dfrac{GM}{r}}[/tex]
Put the value into the formula
[tex]v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{5.1\times10^{6}}}[/tex]
[tex]v=8858.36\ m/s[/tex]
[tex]v=8.8\times10^{3}\ m/s[/tex]
[tex]v=8.8\ km/s[/tex]
(III). We need to calculate the period of the orbit
Using formula of time period
[tex]T=2\pi\sqrt{\dfrac{r^3}{GM}}[/tex]
Put the value into the formula
[tex]T=2\pi\sqrt{\dfrac{(5.1\times10^{6})^3}{6.67\times10^{-11}\times6\times10^{24}}}[/tex]
[tex]T=3617.40\ sec[/tex]
[tex]T=1.00\ hr[/tex]
Hence, (I). The radius of the circular orbit is [tex]5.1\times10^{6}\ m[/tex]
(II). The speed of the satellite is 8.8 km/s.
(III). The period of the orbit is 1.00 hr.