Answer: Technology advancement includes the creation of printhead arrays and multiple carriage systems that cover a larger area of cloth in a single pass of the substrate.
Explanation:
a. With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 45m?
b. How long will it be in the air?
Answer:
A. 29.7 m/s
B. 6.06 s
Explanation:
From the question given above, the following data were obtained:
Maximum height (h) = 45 m
A. Determination of the initial velocity (u)
Maximum height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Initial velocity (u) =.?
v² = u² – 2gh (since the ball is going against gravity)
0² = u² – (2 × 9.8 × 45)
0 = u² – 882
Collect like terms
0 + 882 = u²
882 = u²
Take the square root of both side
u = √882
u = 29.7 m/s
Therefore, the ball must be thrown with a speed of 29.7 m/s.
B. Determination of the time spent by the ball in the air.
We'll begin by calculating the time take to reach the maximum height. This can be obtained as follow:
Maximum height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) to reach the maximum height =?
h = ½gt²
45 = ½ × 9. 8 × t²
45 = 4.9 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the time spent by the ball in the air. This can be obtained as follow:
Time (t) to reach the maximum height = 3.03 s
Time (T) spent by the ball in the air =?
T = 2t
T = 2 × 3.03
T = 6.06 s
Therefore, the ball spent 6.06 s in the air.
Two identical conducting spheres each have a charge of 2 C. They have a radius of 0.1 m and are separated by 0.5 meters. If you were to increase the radius of these spheres to 0.2 meters, the electrostatic force between them would
Answer:
The electrostatic force will remain the same
Explanation:
From the question we are told that
The charge on the each conducting sphere is [tex]q = 2 \ C[/tex]
The radius each sphere is [tex]r_1 = r_2 = r = 0. 1\ m[/tex]
Generally electrostatic force between the sphere is mathematically represented as
[tex]F = \frac{k * q_1 q_2 }{d^2}[/tex]
Here k is the coulomb constant ,
d is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere
Now from the question we are told that the radius of the spheres is doubled (i.e from 0.10 m to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position
and given there is no change in the distance between the spheres , the electrostatic force will remain the same
If a 25 kg lawnmower produces 347 w and does 9514 J of work, for
how much time did the lawnmower run?
Steps 1 and 2)
The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.
The goal is to solve for the unknown time t.
-----------------------
Step 3)
Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P
-----------------------
Step 4)
t = W/P
t = 9514/347
t = 27.4178674351586
t = 27.4 seconds
-----------------------
Step 5)
The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.
-----------------------
Note: we don't use the mass at all
HELP ASAP !!!!!!!!!!!!!!
Answer:
big bang theory
Explanation:
Edwin Hubble is credited for the initial development of the Big Bang theory, an idea which helps to explain the formation of the universe over 15 billion years ago.
Two balls collide in a head-on elastic collision and rebound in opposite directions. One ball has velocity 1.2 m/s before the collision, and −2.3 m/s after. The other ball has a mass of 1.1 kg and a velocity of −4.2 m/s before the collision. (a) What is the mass of the first ball? (b) What is the velocity of the second ball after the collision?
Answer:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
Explanation:
Mark me as brainliest and follow me
What must happen to an atom of magnesium in order to become a magnesium ion Mg+2?
It must lose two neutrons and become a different isotope.
It must gain two neutrons and become a different isotope.
It must lose two electrons and become an ion.
It must gain two electrons and become an ion.
Answer:
Answer is: c. It must lose two electrons and become an ion.
Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).
Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.
Explanation:
Answer:
the third option
Explanation:
The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point located 0.40 L from the end
Answer:
The value is [tex]I = 0.0932 ML ^2[/tex]
Explanation:
From the question we are told that
The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]
The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]
Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is [tex]0.4 M[/tex]
Generally the length of the rod from the its beginning to the axis of rotation consider is
[tex]k = 1 - 0.4 L = 0.6L[/tex]
Generally the mass of the portion of the rod from the its beginning to the axis of rotation consider is
[tex]m = 1- 0.4 M = 0.6 M[/tex]
Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is
[tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
[tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]
Generally the rotational inertia about the axis of rotation consider for the second portion of the rod is
[tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is
[tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
=> [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]
=> [tex]I = 0.0932 ML ^2[/tex]
One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?
Answer:
The diameter is [tex]d = 8.18*10^{-19} \ m[/tex]
Explanation:
From the question we are told that
The value of one atomic mass unit is [tex]u = 1.66 *10^{-27} \ kg[/tex]
The density of the proton is [tex]\rho = 5.8 *10^{27} \ kg/m^3[/tex]
Generally the volume of the proton (sphere)is mathematically represented as
[tex]V = \frac{4}{3} * \pi * r^3[/tex]
Generally this volume can also be evaluated as
[tex]V = \frac{u}{\rho}[/tex]
=> [tex]V = \frac{1.66 *10^{-27}}{5.8*10^{27}}[/tex]
=> [tex]V = 2.862 *10^{-55} \ m^3[/tex]
So
[tex]2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3[/tex]
=> [tex]r^3 = 6.832 *10^{-56}[/tex]
=> [tex]r = 4.088 *10^{-19} \ m[/tex]
Now the diameter is mathematically represented as
[tex]d = 2 * r[/tex]
=> [tex]d = 2 * 4.088 *10^{-19}[/tex]
=> [tex]d = 8.18*10^{-19} \ m[/tex]
Our school needs to offer healthier options in the lunchroom. Elever High School has recently updated its cafeteria menu to include whole wheat pasta and breads, a fresh salad bar, and other healthy menu items. Students there claim that they have more energy and focus throughout their school day. Let's encourage healthier menus in our lunchroom!
What type of evidence does the writer of this passage use to support her claim?
statistics
statistics
an expert's opinion
an expert's opinion
examples
examples
the writer's opinion
Answer:
b
Explanation:
What kind of food would you expect a turtle with a hard, sharp beak and short neck to eat?
A golf ball is hit at an angle of 45° above the horizontal. What is the acceleration of the golf ball at the highest point in its trajectory? [Neglect friction.] a = m/s2
Answer:
32* acceleration
Explanation:
why? because if the ball is at a 35* angle then it will accelerate 32*
The acceleration of the golf at the maximum height is equivalent to acceleration due to gravity = 9.8 m/s².
The given parameters;
angle of projection of the ball, Ф = 45°
Acceleration is defined as the change in velocity per change in time of motion.
[tex]a = \frac{\Delta v}{\Delta t} = \frac{v_f }{t}[/tex]
where;
[tex]v_f[/tex] is the final velocity of the golf
At maximum height the final velocity of a projectile is zero (0)
The acceleration for upward motion becomes;
[tex]a = \frac{0 }{t} + g= g[/tex]
Thus, the acceleration of the golf at the maximum height is equivalent to acceleration due to gravity.
Learn more here: https://brainly.com/question/14508598
3) the maximum angular displacement of a pendulum in simple harmonie motion is theta,max then the
kinetic energy is equal to the potential energy when the angular displacement is given by
Answer:
B is correct
Explanation:
Maximum Kinetic energy= Work done.
Now, Work done=mgh=mg(L−Lcosθ)=mgL(1−cosθ)
Option B is thus correct.
You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
30°
110
34°
120
38°
128
42°
133
46°
127
50°
119
54°
109
At which angle will the performer travel the shortest distance?
A. 44°
B. 54
Ο Ο Ο Ο
C. 32
D. 50°
Answer:
128
Explanation:
Answer:
54 degrees
Explanation:
A scale reads 184 N when a piece of copper is hanging from it. What does it read (in N) when it is lowered so that the copper is submerged in water?
Answer:
163 N
Explanation:
The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.
0.8884 × 184 N ≈ 163 N
The submerged weight is about 163 N.
During a race, a runner runs with an average velocity of 4.26 m/s toward city hall. What is the runner’s displacement after 167s?
Answer:
d = 711.42 m
Explanation:
Given that,
The average velocity of a runner, v = 4.26 m/s
Time, t = 167 s
We need to find the runner's displacement.
The average velocity of an object is equal to the displacement per unit time. It can be given by :
[tex]v=\dfrac{d}{t}\\\\d=vt\\\\d=4.26\ m/s\times 167\ s\\\\d=711.42\ m[/tex]
So, the runner's displacement is 711.42 m.
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11. Table salt, NaCl, is a classic binary ionic compound. (4 points)
a. What is the oxidation number of Na? Of Cl?
ave...
Answer:
+1
-1
Explanation:
The oxidation number of Na in NaCl is +1 and that of Cl is -1.
For simple ions, the oxidation number is the charge they carry.When NaCl is oxidized we have;
NaCl → Na⁺ + Cl⁻
In this process, Na will lose an electron to become Na⁺ and thus isoelectronic with Ne, Cl will gain the electrons to become Cl⁻ and thus isoelectronic with Argon.
Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
A. What will be the speed of the shuttle at the end of 8.50 minutes?
B. How far will the shuttle have traveled during this time?
Answer:
A. speed = 7.14 Km/s
B. distance = 1820.7 Km
Explanation:
Given that: a = 14.0 m/[tex]s^{2}[/tex], t = 8.50 minutes.
But,
t = 8.50 = 8.50 x 60
= 510 seconds
A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
u = 0
So that,
v = 14 x 510
= 7140 m/s
The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.
B. the distance traveled can be determined by applying second equation of motion.
s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.
u = 0
s = [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
= [tex]\frac{1}{2}[/tex] x 14 x [tex](510)^{2}[/tex]
= 7 x 260100
= 1820700 m
The distance that the shuttle has traveled during the given time is 1820.7 Km.
Please help me with this question guys.
Answer:
The average speed is 22.2 km/h
Explanation:
Average Speed
Given an object travels a total distance d and took a total time t, then the average speed is:
[tex]\displaystyle \bar v=\frac{d}{t}[/tex]
The mailman first drives d1=7 km at v1=15 km/h. The time taken to drive is:
[tex]\displaystyle t1=\frac{d1}{v1}=\frac{7}{15}=0.467\ h[/tex]
Then he drives d2=7 km at v2=43 km/h taking a time of:
[tex]\displaystyle t2=\frac{d2}{v2}=\frac{7}{43}=0.163\ h[/tex]
The total time is
t=0.467 h + 0.163 h = 0.63 h
The total distance is
d = 7 km + 7 km = 14 km
The average speed is:
[tex]\displaystyle \bar v=\frac{14}{0.63}=22.2\ km/h[/tex]
The average speed is 22.2 km/h
A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, initially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Answer:
1kgExplanation:
According to law of conservation of momentum
m1u1+ m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are their initial velocities
v is their common velocity
Given
m1 = 3kg
m2 = M
u1 = 8m/s
u2 = 0m/s (object at rest)
v = 6.0m/s
Substitute and get M
3(8) + M(0) = (3+M)6
24 = 18+6M
24-18 = 6M
6 = 6M
M = 1kg
Hence the mass M is 1kg
What is the largest planet in our galaxy
Bru challenge with the physics.
Answer:
WHATATATATTAT
Explanation:
he triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2.00 103 N with an effective perpendicular lever arm of 2.80 cm, producing an angular acceleration of the forearm of 145 rad/s2. What is the moment of inertia of the boxer's forearm
Answer:
Moment of inertia = 0.3862kg-m²
Explanation:
2.00x10³
2.80cm
145 rad
r = r⊥ x F
F is an applied force
r⊥ is the distance between the applied force and axis
Force exerted = 2.00x10³
r⊥ = 2.8cm = 0.028m
Alpha = 145rad/s²
r = 0.028m x 2.00x10³
r = 56.0N-m
To get the moment of inertia
56.0N-m² = (145rad/s²) x I
The I would be:
I = (56.0N-m²)/(145rad/s²)
I = 56/145
= 0.3862Kg-m²
This is the moment of inertia.
Thank you!
An elevator is pulled up by a cable with a force of 65,000 N. The upward acceleration of the elevator is 1.8 m/s/s. What is the mass of the elevator?
a. 1.8 kg.
b. 1700 kg.
c. 54880 kg.
d. 5600 kg.
e. 36111 kg.
Answer:
36111 kg
Explanation:
Given
Force = 65000N
Acceleration = 1.8m/s²
Required
Determine the mass of the elevator
This question will be answered using the following Force formula.
Force = Mass * Acceleration
Substitute values for Force and Acceleration
65000N = Mass * 1.8m/s²
Make Mass the subject
Mass = 65000N/1.8m/s²
Mass = 36111.11 kg
From the list of given options, option E answers the question.
Which state of matter does this model represent?
Image of particles tightly packed
Solid
Liquid
Gas
Plasma
Answer:
gas
Explanation:
it is gas because the particles are floating up none of the above would be floating up.
Answer:
Solid
Explanation:
A: Solid- Solids have the particles tightly packed. They have a definite shape and volume
B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume
C: Gas- Gas has particles freely all around. Indefinite shape and volume
D: Plasma- Plasma is different and should be explained with an example; think of lighting....
Since the image shows tightly packed particles, it is clear the answer is a solid.
answer pls urgent pls
Answer:
record vibrations of earthquake
Answer:
[tex]\huge\boxed{\sf Option \ 2}[/tex]
Explanation:
Seismograph is an instrument with is used to record vibrations of earthquake.
Seismographs are basically used to detect seismic waves by which scientists can detect the earth's interior and also can find the depths of earthquakes and their intensity.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807What is the main function of an earthworm organ
Answer:
brain
Explanation:
brain and blood
Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
A man driving a car at 35 mph hits his brakes suddenly to avoid hitting a dog.
Everything in the front seat of his car slides forward and into the floorboard. Which of
Newton's laws does this illustrate?
Answer:
Inertia; Newton's First Law
Explanation:
When you hit you're breaks, the force you feel that pulls you forward is due to inertia.
Newton's first law says that "every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force." The question is a perfect example of this.
It is due to the inertia of motion of the objects that they fall on the floor bed. This is also called Newton's first law of motion.
What is the name of Newton's first law of motion?Newton's first law of motion is known as the law of inertia.
Given is a man who is driving a car at 35 mph hits his brakes suddenly in order to avoid hitting a dog. During the incident, everything in the front seat of his car slides forward and into the floorboard.
The property of body by virtue of which it resist any change in its state of rest or uniform motion is called inertia of body. When the car was moving at 35 mph, every object on front seat was also moving with the same speed. However, when the brakes were applied, they were applied on the car and not on the objects in the front seat. Hence, they keep moving forward and stop only when they strike and fall down. This is called inertia of motion. This is Newton's first law of motion.
Therefore, it is due to the inertia of motion of the objects that they fall on the floor bed. This is also called Newton's first law of motion.
To learn more about Newton's laws of motion, visit the link below-
https://brainly.com/question/974124
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What magnification would be obtained if an eyepiece with a focal length of 0.38 m was placed on telescope?
Answer:
This question is incomplete
Explanation:
This question is incomplete because the telescope's focal length was not provided. The formula to be used here is
Magnification = telescope's focal length/eyepiece's focal length
The eyepiece's focal length was provided in the question as 0.38 m.
NOTE: Magnification can be described as the power of an instrument (in this case telescope) to enlarge an object. It has no unit and thus the two focal lengths mentioned in the formula above must be in the same unit (preferably meters since one of them is in meters already).
uses of atmospheric pressure