When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glass (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare. Part A If the glass has a refractive index of 1.58 and you use TiO2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 480 nm

Answers

Answer 1

Answer:

  t = 9.16 10⁻⁸ m

Explanation:

In this exercise we fear a case of interference by reflection,

We have two aspects

* when the light ray passes from the air to the TiO2 that has a higher refraction start, the reflected ray has a phase change of 180º

* when the beam is inside the material its wavelength changes

            λₙ = λ₀ / n

with these two done the equation for destructive interference remains

           2t = m  λₙ

           2nt = m λ₀

They ask us for the thickness t of the film for m = 1

           t = m λ₀ / 2n

let's calculate

          t = [tex]\frac{1 \ 480 1 10^9 }{2 \ 2.62}[/tex]

          t = 9.16 10⁻⁸ m


Related Questions

problema de coeficiente de rozamiento

Answers

If you take the positive horizontal direction to be to the right (the same direction as F₂), then by Newton's second law, the block has

• a net horizontal force of

F = F₁ cos(-50°) + F₂ - f = m a

• a net vertical force of

F = F₁ sin(-50°) + n - m g = 0

where

f = µ n = magnitude of friction

• µ = coefficient of kinetic friction

• n = magnitude of the normal force

• m = 20 kg

• a = acceleration of the block

Solve for n :

n = m g + F₁ sin(50°)

n = (20 kg) (9.80 m/s²) + (50 N) sin(50°)

n ≈ 234.302 N

If the block accelerates uniformly from rest with acceleration a, then this acceleration is equal to its average, given by

a = ∆v / ∆t = (9 m/s - 0) / (3 s) = 3 m/s²

Solve for f :

f = F₁ cos(50°) + F₂ - m a

f = (50 N) cos(50°) + 80 N - (20 kg) (3 m/s²)

f ≈ 52.1394 N

Solve for µ :

µ = f / n

µ ≈ (52.1394 N) / (234.302 N)

µ ≈ 0.22253 ≈ 0.22

NEED HELP PLZ!!! ASAP

Which of the following happens during a solar eclipse?

The moon appears red.
The moon casts a shadow on Earth.
Earth, the moon, and the sun form a triangle.
Earth comes between the sun and the moon.

Ok so I'm Confused, that last answer- Shouldnt that say the moon comes between the sun and the earth? This is what it says on my test instead..

Answers

U r correct mate it's the right answer.

Hope it helps u

Plz mark me brainlest

What is the electric field at a distance of 3 cm from 4 mC
of negative charge?
ucharee

Answers

Answer:

The magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.

Explanation:

Given;

magnitude of the charge, q = 4 mC = 4 x 10⁻³ C

distance of the charge, r = 3 cm = 0.03 m

The magnitude of the electric field is calculated as follows;

[tex]E = \frac{F}{q} = \frac{Kq}{r^2} \\\\[/tex]

where;

K is Coulomb's constant, = 9 x 10⁹ Nm²/C²

[tex]E = \frac{Kq}{r^2}\\\\E = \frac{(9\times 10^9)(4 \times 10^{-3})}{0.03^2} \\\\E = 4 \times 10^{10} \ N/C[/tex]

Therefore, the magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.

A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
completed the race in 120 seconds, and the black horse completed the race in 150
seconds. Which choice correctly describes the speed of the horses?
A- Only the red horse ran at a constant speed
B- The red horse's average speed was greater than the black horse's average speed.
C- The black horse's average speed was greater than the red horse's average speed.
D- Only the black horse ran at a constant speed.

Answers

Answer

your format is incorrect!!

Explanation:

there is no such thing as a red horse. there are chestnuts, bays and red roans, just no reds. usually though, blacks are faster scientifically than red roans.

If a team of workers comes to a consensus, what probably happened in the meeting?
A. They compromised with each other to reach an agreement.
B. They disagreed and were unable to come to a decision.
OC. They were forced by their manager to follow a new policy.
O D. They all turned in their letters of resignation.

Answers

Answer:

A

Explanation:

A consensus is when you come to an agreement

If unlike magnetic poles attract, how does a magnet attract an un-magnetized piece of metal such as a piece of iron?
A
It does this via a process called magnetic induction which temporarily makes a magnet of the metal.

B
It can only do this if the piece of metal already is a magnet internally.

C
What actually happens is that the un-magnetized metal attracts the magnet rather than the other way around.

D
Only powerful electro-magnets, such as are found in wrecking yards, can attract unmagnetized metals.

Answers

Answer:

A

Explanation:

The lets say the magnet is is facing the north and a piece of iron is near it. The iron will become magnetized since the protons will be repelled leaving only the electrons creating a magnetic field. Or in other words a temporary magnet is made, this is only as long a the actual magnet is close enough to the iron.

A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it
starts from rest?
a. -0.5 m/s2
b. 0.5 m/s?
c. 2 m/s?
d. 22.5 m/s2

Answers

[tex]acceleration = \frac{velocity}{time} = \frac{7.5}{15} = 0.5ms^-^2[/tex]

So the answer is option b.

When we experience positive "g forces", it is as if we have become...

Answers

Answer:

heavier

Explanation:

In a chemical reaction, substances react in a specific ratio. Chemical reactions are used to make many products, including food. For a company that carries out a chemical reaction to make a product, why would it be important to know the ratio of substances?

Answers

Answer: “Chemical equations need to be balanced in order to satisfy the law of conservation of matter, which states that in a closed system matter is neither created nor destroyed. There are some things called mole ratios, which are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.”

You need to make sure you have an equal balance so that you don’t make a mistake and mess up the reaction. If anything goes minutely wrong, it may alter the substance. Knowing the ratios of substances can help to make the product as expected.

It is important to know the ratio of substances because:

Mole ratios are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.The mole ratios are determined using the coefficients of the substances in the balanced chemical equation. Mole ratios are used as a means of comparison of substances in a balanced chemical equation in order to determine amounts.

Example: 2H₂ + O₂ → 2 H₂O

Learn more:

brainly.com/question/14197404

A large truck of mass 4M is traveling at a speed of V when it collides with a small car of mass M that is at rest. The truck and car stick together after the collision. When the truck and car stuck together after the collision, the speed of the center of mass of the truck-car system is Vf. If the truck and car have an elastic collision, the speed of the center of mass of the truck-car system is Vf2. Which of the following expressions for Vf2 must be true?

a. 4/5 V
b. 1/5 V
c. V
d. 5/4 V
e. 5V

Answers

Answer: (a)

Explanation:

Given

Mass of large truck is 4M with velocity V

Mass of small car is M which is at rest

After the collision car and truck stick together

Conserving momentum

[tex]\Rightarrow 4MV+M(0)=5M\times V_f\\\\\Rightarrow V_f=\dfrac{4}{5}V[/tex]

For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.

So, for elastic collision velocity [tex]V_f_2=\frac{4}{5}V[/tex]

As a result of collision when there is no loss in the kinetic energy of the object then the collision is said to be elastic and the kinetic energy and the momentum of the objects are conserved.

The momentum is written as:

[tex]\rm m_{1}v_{1}+m_{2}v_{2} = m_{1}v_{1}'+m_{2}v_{2}'[/tex]

Where, mass = m and velocity = v

The following option is true:

Option a.  [tex]\dfrac{4}{5} \rm V[/tex]

The momentum can be estimated by:

Given,

Mass of large truck = 4M

Mass of small car = M

The velocity of truck = V

After the collision the conserving momentum will be:

[tex]\begin{aligned}\rm 4MV + M(0) &= 5\rm M \times V_{f}\\\\\rm V_{\rm f} &= \dfrac{4\rm MV}{5\rm M}\\\\\rm V_{f} &= \dfrac{4}{5V}\end{aligned}[/tex]

There will be no acceleration as the momentum is conserved and the center of mass is the same.

Therefore, elastic collision will have a momentum of  [tex]\dfrac{4}{5} \rm V[/tex].

To learn more about momentum and elastic collision follow the link:

https://brainly.com/question/8169285

Bob uses a wheelbarrow to move soil from his garden to a new flowerbed. He exerts an average force of 185 N while pushing the wheelbarrow, and he does 6.1 kJ of work while moving each load of soil. How far is he moving the soil?


A. 0.026 m

B. 0.039 m

C. 26 m

B. 39 m

Answers

Answer:

A. reduce the amount of soil by one-half and apply the same amount of force

Explanation:

what makes molecules move. A. covection. B. Radiation. C. Thermal or heat. D. conduction.​

Answers

Radiation or Conduction?

Answer:

the answer is C

Explanation:

A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.


The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s

Answers

Answer:

PE=0.92414J and KE=0.28175J

Explanation:

Gravitational potential energy=mass*gravity*height

PE=mgh

Data,

M=0.046kg

H=2.05m

g=9.8m/s^2

PE=0.046kg * 9.8m/s^2 * 2.05m

PE =0.92414J

KE=1/2mv^2

M=0.046kg

V=3.5m/s

KE=[(0.046kg)*(3.5m/s)^2]\2

KE=0.28175J

How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​

Answers

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

[tex] G.P.E = mgh[/tex]

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a distant screen that has been set up behind the slit. The first dark fringe in the diffraction pattern is 4.0 cm from the center point of the pattern. If you replace the orange laser with an unknown laser and observe that the second dark fringe of the diffraction pattern appear at 4.0 cm from the center point, what is the wavelength of the unknown laser

Answers

Answer:

 λ = 3 10⁻⁷ m,   UV laser

Explanation:

The diffraction phenomenon is described by the expression

         a sin θ = m λ

let's use trigonometry

         tan θ = y / L

as in this phenomenon the angles are small

        tan θ = [tex]\frac{sin \ \theta}{cos \ \theta}[/tex] = sin θ

        sin θ = y / L

we substitute

      a y / L = m  λ

let's apply this equation to the initial data

       a  0.04 / L = 1 600 10⁻⁹

       a / L = 1.5 10⁻⁵

now they tell us that we change the laser and we have y = 0.04 m for m = 2

      a 0.04 / L = 2  λ

       a / L = 50  λ

we solve the two expression is

         1.5 10⁻⁵ = 50  λ

          λ = 1.5 10⁻⁵ / 50

          λ = 3 10⁻⁷ m

    UV laser

What is the derivation for Newtons Law of universal gravitation?​

Answers

Answer:

In symbols, the magnitude of the attractive force F is equal to G (the gravitational constant, a number the size of which depends on the system of units used and which is a universal constant) multiplied by the product of the masses (m1 and m2) and divided by the square

A torsional pendulum has a centroidal mass moment of inertia of 0.40 kg·m2 and when given an initial twist and released is found to have a frequency of oscillation of 200 rpm. Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm, determine the damping constant for the oil. The damping constant for the oil is

Answers

0.00246914 come to the damping of the constant for the oil

Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm,0.00246914 come to the damping of the constant for the oil

what is frequency ?

The frequency can be defined as the  number of oscillation per unit time which is used for defining the cyclic process like rotation, oscillation, wave etc.

The SI unit of the frequency is denoted as  Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.

The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The  “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.

If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.

For more details regarding frequency, visit

brainly.com/question/14400059

#SPJ2

A pair of slits, separated by 0.150 mm, are illuminated by light with a wavelength of 643 nm. An interference pattern is observed on a screen at 140 cm from the slits. Consider a point seen on the screen that is located 1.80 cm to the right of the central bright fringe. Will the point be a minimum (destructive) point, a maximum (constructive) point or somewhere in between

Answers

Answer:

Explanation:

slit separation d = .15 mm

screen distance D = 1.4 m

wavelength of light used λ= 643 x 10⁻⁹ m

position of n th bright fringe x

x = n x λ D / d

1.8 x 10⁻² = n x 643 x 10⁻⁹ x 1.4 / .15 x 10⁻³

1.8 x 10⁻² = n x 6 x 10⁻³

n = 3

So 3 rd bright fringe will be formed at a point 1.8 cm from the central bright fringe .

A spring of negligible mass and force constant k = 430 N/m is hung vertically, and a 0.270 kg pan is suspended from its lower end. A butcher drops a 2.1 kg steak onto the pan from a height of 0.40 m. The steak makes a totally inelastic collision with the pan and sets the system into vertical SHM. What are:

a. the speed of the pan and steak immediately after the collision
b. the amplitude of the subsequent motion
c. the period of that motion

Answers

it’s b because a spring of negligible mass then if u multiply

How many significant figures are in the number 54,100?

Answers

Answer:

3

Explanation:

The answer must be 3

A truck with a mass of 1520 kg and moving with a speed of 16.0 m/s rear-ends a 663 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. vcar

Answers

Answer:

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

Explanation:

By law of conservation of momentum  

momentum before collision = momentum after collision

[tex]m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2[/tex]

Since, collision is elastic

[tex]16 = v_2-v_1///v_2 = v_1+16 ....(b)[/tex]

solving the above two equations we get

v_1 = 6.28 m/s and v_2 = 22.28 m/s

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

1. A 2,000-turn solenoid is 65 cm long and has cross-sectional area 30 cm2. What rate of change of current will produce a 600 Volts emf in this solenoid.

Answers

Answer:

[tex]\frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]

Explanation:

First, we will calculate the inductance of the solenoid by using the following formula:

[tex]L = \frac{\mu_o AN^2}{l}[/tex]

where,

L = self-inductance of solenoid = ?

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

A = Cross-sectional area = 30 cm² = 3 x 10⁻³ m²

N  = No. of turns = 2000

l = length = 65 cm = 0.65 m

Therefore,

[tex]L = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(3\ x\ 10^{-3}\ m^2)(2000)^2}{0.65\ m}\\\\L = 0.0232\ H[/tex]

Now, we will use Faraday's law to calculate the rate of change of current:

[tex]emf = L\frac{dI}{dt}\\\\ \frac{dI}{dt} =\frac{emf}{L} \\\\ \frac{dI}{dt} =\frac{600\ V}{0.0232\ H}\\\\ \frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]

a 60 kg pupil runs for 600m in 1 minute uniformly calculate kinetic energy​

Answers

velocity = traveled distance ÷ time of the traveled distance is seconds

velocity = 600 ÷ 60

velocity = 10 m/s

_________________________________

Kinetic Energy = 1/2 × mass × ( velocity )^2

KE = 1/2 × 60 × ( 10 )^2

KE = 30 × 100

KE = 3000 j

A 4.50-kg centrifuge takes 200 s to spin up from rest to its final angular speed with constant angular acceleration. A point P located 10.0 cm from the axis of rotation of the centrifuge moves with a speed of 150 m/s when the centrifuge is at full(final) speed. a) [4 points] What was its final angular speed

Answers

Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

A 10kg block is Pulled along a horizontal
Surfact by a fores of son at an ansie
of 37° with the horizontal If the
coefficient of sliding friction 6/n the
block ound the surface is 0.2
(8-10 mis? Sin 37=016 and cos 37.2008)
of what frictional for acting on the block
b what is the acceleration of the block?​

Answers

Answer:

Explanation:

I hate these kinds of problems,  luckily I can't understand how much the kinetic friction is for this ,  the words are all mixed around.  and don't read well.  Maybe this went through a translator program?   My suggestion draw the free body diagram.   so you can see where the forces are, and how they are acting.   getting the free body diagram right.. usually makes these problems pretty straight forward.   just do the steps and you get the answer.

Answer:

I cant understand the question well but i will tell u how to solve it

first apply f = ma eqaulation vertically...then u will get an r = mg which means normal upward force = weight of the object (to find weight multiply mass by 9.81)

[tex]f = ma \\ r - mg = 0 \\ r = mg[/tex]

after that use friction eqaution which is

[tex]f = \mu \times r [/tex]

(mu) is the coefficient of friction and (r) is the vertical normal force then by substituting value you can get an answer for the friction

the use

[tex]f = ma \\ f \cos(37) - fr = ma[/tex]

by using the above eqaution you can get an answer for acceleration...

hope you can understand...

Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a particular direction—like miles per hour going north, kilometers per minute west or meters per second up. Velocity tells us both the speed and direction we are traveling. Acceleration is a change in velocity. It's measured by subtracting the object's starting velocity from the final velocity, divided by the time this change in velocity took. We usually think of acceleration as speeding up, but it can also mean slowing down. We call this negative acceleration or deceleration. If a car was driving 45 miles per hour northeast, and is now driving 30 miles per hour north, A the car’s velocity decelerated. B the car’s velocity accelerated. C the car’s velocity remained unchanged. D the car’s acceleration is 30 miles per hour.

Answers

Answer:

Option A. The car’s velocity decelerated

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 45 mph Northeast

Final velocity (v) = 30 mph North

Now, if we take the difference between the car's final velocity and it's Initial velocity, we shall obtained:

Difference in velocity = v – u

Difference in velocity = 30 – 45

Difference in velocity = –15 mph

Since the difference between the final velocity and the initial velocity of the car is negative, it implies that the car's velocity decelerated.

Thus, option A gives the correct answer to the question

its un1) It is unofficial, but a strong rumor that the world will end in two years' time due to the arrival of a huge comet and its subsequent impact with Earth. You have two years to live, to get the most out of life. How would you react? What would you do? Discuss.​

Answers

Answer:

I'll try my utmost best to get the most out of life...I'd do the things have always wanted to do

Sometimes it might get to me knowing fully well that in two years time the world will end but i will shake it off because the time i spend thinking about it...It will be enough to make some memories.

Hope this help anyways

Volcanic process refers to the eruptive and noneruptive activities that occur on a volcano. Volcanic activities usually
results if one of the following happens: A). Deep within the core of the Earth, it is so hot that some rocks melt and
become a thick and sticky substance called (16)_
Magma B) This substance gets hotter and hotter and pressure
builds deep in the (17)
of the volcano. C) Eventually, magma will push up toward the surface of the
Earth through the volcano's crater and escape through vents in the earth. D) When magma erupts from the volcano, it is
called (18)
During an eruption, volcanic asin and ouiet rock pa licies called (19)
alsu escape
violently into the air and can cause major damage to the volcano's surrounding environment. E) (20)
that erupts from the volcano will fall back down onto the Earth like powdery snow that can cover and suffocate
anlants and animals and also contaminate streams and rivers.

Answers

I need help too anyone know

The Hall effect is to be used to find the sign of charge carriers in a semiconductor sample. The probe is placed between the poles of a magnet so that magnetic field is pointed up. A current is passed through a rectangular sample placed horizontally. As current is passed through the sample in the east direction, the north side of the sample is found to be at a higher potential than the south side. Make a sketch of the situation, then decide if the number density of charge carriers is positively or negatively charged.

Answers

Answer:

the sign of these carriers is POSITIVE

Explanation:

In the effect, he found the charge carriers that were subjected to two forces, one electric and the other magnetic.

        F = F_e + F_m = q E + q v x B

bold indicates vectors

The electric field goes to the east, therefore the current also has this direction, the vector product of the velocity of the charge carriers towards the east and the magnetic field upwards, using the right hand rule a magnetic force is created towards the north if the carriers are positive.

In the exercise they indicate that the north side has a higher potential than the south side, therefore there must be an accumulation of carriers on this side that create an electric field (Hall) that is put to the magnetic force until reaching equilibrium when the total force is zero.

Therefore the sign of these carriers is POSITIVE

A Ring, a solid Cylinder and a solid sphere all having the same mass and the Same radius are held at the top of an inclined plane if the objects are roll without slipping and the (see the picture)between each object and the plane is 0.3 if they are released from an incloed plane at the same time which wal bee reach the bottom first?​

Answers

Answer:

Since they all have the same mass and radius they all experience the same amount of torque.

Torque = moment of inertia * angular acceleration

The one with the smallest moment of inertia will experience the greatest angular acceleration and thus reach the bottom first.

I = M r^2     ring

I = 1/2 M r^2  cylinder

I = 2/5 M r^2   sphere

The sphere will reach the bottom first.

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