When is ur last day of school

Answer:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

Step-by-step explanation:

Given

[tex]y = 4x[/tex]

[tex](x_1,x_2) = (x,x+1)[/tex]

Required

Show that the y values increases by 4 for [tex]x_2 - x_1 = 1[/tex]

We have:

[tex]y = 4x[/tex]

For [tex]x_1 = x[/tex]

[tex]y_1 = 4x_1[/tex]

Substitute [tex]x_1 = x[/tex]

[tex]y_1 = 4x[/tex]

For [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4x_2[/tex]

Substitute [tex]x_2 = x + 1[/tex]

[tex]y_2 = 4(x+1)[/tex]

[tex]y_2 = 4x+4[/tex]

So, we have:

[tex]y_2 = 4x+4[/tex]

[tex]y_1 = 4x[/tex]

Subtract [tex]y_1[/tex] from [tex]y_2[/tex]

[tex]y_2 - y_1 = 4x + 4 - 4x[/tex]

Collect like terms

[tex]y_2 - y_1 = 4x - 4x+ 4[/tex]

[tex]y_2 - y_1 = 4[/tex]

Hence:

[tex]x_2 - x_1 = 1[/tex] gives [tex]y_2 - y_1 = 4[/tex]

i.e. an increment of 4

Answer:

[tex]a =7[/tex]   [tex]b = 2[/tex]  [tex]c = -4[/tex]

Step-by-step explanation:

Given

[tex]\frac{3x}{x + 2} + \frac{4x}{x - 2} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Required

Find a, b and c

[tex]\frac{3x}{x + 2} + \frac{4x}{x - 2} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Take LCM

[tex]\frac{3x(x -2) + 4x(x+2)}{(x + 2)(x - 2)} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Expand

[tex]\frac{3x^2 -6x + 4x^2+8x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Collect like terms

[tex]\frac{3x^2 + 4x^2-6x+8x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

[tex]\frac{7x^2+2x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

By direct comparison:

[tex]ax^2= 7x^2 \to a = 7[/tex]

[tex]bx = 2x \to b = 2[/tex]

[tex]-4 = c \to c = -4[/tex]

Answer:

29 IS THE ANSWER PLEASE MARK AS BRAIN IST

Step-by-step explanation:

Answer:

[tex]r=3\\h=5\\\\8r+h\\= 8(3) + (5)\\= 24 + 5\\= 29[/tex]

Answer:

d= -32

Step-by-step explanation:

Answer:

-5=d/4+3

-5-3=d/4

-8=d/4

-8*4=d

-32=d

Step-by-step explanation:

Answer:

zMNP=180-73

=107 IS THE ANSWER

Answer:

please show answer choices

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

A) is the right answer.

Answer:

A

Step-by-step explanation:

A)  Yes, this is solution

b) No

c) No

d) NO

Answer:

false

Step-by-step explanation:

Given:

The stem-and-leaf plot or a date set.

To find:

The mode of data set.

Solution:

From the given stem-and-leaf plot, we get the numbers of the data set.

64, 67, 70, 70, 71, 75, 76, 78, 78, 80, 82, 82, 88, 91, 93, 94, 97, 98, 100, 100, 100

Mode of a date set is the most frequent value.

In the given data set the most frequent value is 100 with frequency 3.

Therefore, the mode of data set is 100. Hence, option A is correct.

Answer:it is A: 100

Step-by-step explanation:

i got it right

good luck with your test :)

Answer:

The answer is Gerald R. Ford, Jimmy Carter, Ronald Reagan, and lastly George H.W Bush

Step-by-step explanation:

Answer:

ok

Step-by-step explanation:

Answer:

The length is 8.

Step-by-step explanation:

If you know the formula for area is LxW. Use this but reverse it. The area is 24 and the width is 3. Now divide 24/3=8. Simple as that!

Formula: A/W=L or A/L= W use this if you need more help! Hope it helps (:(:

Answer:

1057.89 feet

Step-by-step explanation:

Trig time! Start with a diagram and listing out your trig functions, either mentally or on paper. SOH CAH TOA

The best trig function for this problem is likely tan:

tan84.6 = height / 100

100 * tan 84.6 = height

height = 1057.89 feet

Answer: 18x -15 -y =0

Step-by-step explanation:

because linear equations in two variables are always in the format of ax+by+c=0

where a,b and c are constant terms

in this case a = 18; ax= 18x

b= -1 , by= -y

c= 15

Answer:

90x + 75 = 90x + 12, they don't intersect

Step-by-step explanation:

18x + 15 - y = 0

5y = 90x + 12

1. We will be using substitution, to do so, bring y to the other side in the first eqaution.

18x + 15 - y = 0

18x + 15 = y

2. Now plug in 18x+15 into the second equation

5(18x + 15) = 90x + 12

3. Distribute and solve for x

90x + 75 = 90x + 12

Because the slopes are the same (90x) this means that the system does not have an intersect.

Answer:

Your answer is 9 farms breed cattle.

Step-by-step explanation:

(3/4)*12 = 9

      or

.75*12 = 9

Answer:

9

Step-by-step explanation:

Three quarter means ¾

¾ of 12

3 × 3

9

Answer: A, C, D

Step-by-step explanation:

A is correct because Audrey reads 40 pages a day, and David reads 20. When you divide 40 by 20, you get 2. This means that 2 times 20 would be 40, and anything multiplied by 2 is "twice".

40 ÷ 20 = 2

2 × 20 = 40

B is not correct because after 6 days, Audrey reads 240 pages, and David reads only 120. We can figure this out by multiplying the pages read by 6.

Audrey: 40 × 6 = 240

David: 20 × 6 = 120

C is correct because when you subtract 20 from 40, you get 20. Since Audrey reads 40 pages a day and David reads 20, you can use this equation: 40-20 to figure the answer out. Audrey reads 20 more pages every day.

[tex]40-20=20[/tex]

D is correct because after 2 days, Audrey will have read 80 pages, and David will have read 40 pages. When you subtract 40 from 80, you get 40 pages.

40 × 2 = 80

20 × 2 = 40

80 - 40 = 40

E is not correct because, after 3 days, Audrey will have read 120 pages, and David will have read 60 pages. One-third of 120 is 40, not 60. Three times 60 would be 180, not 120. So, This answer is incorrect.

Answer: [tex]m=\frac{-30}{79},\ y=5.40[/tex]

Step-by-step explanation:

Given

Points are [tex]\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)[/tex]

Convert mixed numeral to fraction

[tex]\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)[/tex]

Slope of the line is

[tex]\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}[/tex]

Equation of line

[tex]\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40[/tex]

Answer:

perimeter of tile =2(l+b)

hope it helps

stay safe healthy and happy.

Answer:

55 in²

Step-by-step explanation:

Base x Height

Answer:

240% of 150 is 360

Step-by-step explanation:

240% of [tex]x[/tex] = 360

[tex]\frac{240}{100}[/tex] x [tex]x[/tex] = 360

2.4 [tex]x[/tex] = 360

[tex]x[/tex] = [tex]\frac{360}{2.4}[/tex]

[tex]x[/tex] = 150

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ([tex]S_{5}[/tex]) = 250

or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]

or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]

or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

Answer:

80

Step-by-step explanation:

20+80+x=180

100+x=180

x=180-100

x=80

plz mark as brainliest

Answer:

i think its b but im not 100 percent sure...

Step-by-step explanation:

Answer:

Step-by-step explanation:

The answer is d

Lets note the change between each of the numbers in the sequence:

-2 --> 6 ---> 14

Next, make an equation between each of these numbers with x being the change between them

-2+ x = 6, 6 + x = 14 .

Now, solve each of these equations:

-2+ x = 6 --> -2+ x = 6 Add 2 on both sides to cancel out the -2 --> x = 8

6+ x = 14 --> -2+ x = 6 Minus 6 on both sides to cancel out the 6 --> x = 8

From this, the common difference will be 8.

Hope that helps.

Answer:

50 square feet.

Step-by-step explanation:

Let x represent the width of the fence and y represent the length of the fence.

One side of the length is already covered by the house. This leaves 2x and y. This must sum to 20. Hence:

[tex]2x+y=20[/tex]

The area of the enclosure will be given by:

[tex]A=xy[/tex]

From the first equation, we can subtract 2x from both sides:

[tex]y=20-2x[/tex]

Substitute:

[tex]A=x(20-2x)[/tex]

This is now a quadratic. Recall that the maximum value of a quadratic always occurs at its vertex. So, find the vertex of the equation. Distribute:

[tex]A=20x-2x^2[/tex]

In this case, a = -2, b = 20, and c = 0.

Hence, the vertex is:

[tex]\displaystyle x=-\frac{b}{2a}=-\frac{(20)}{2(-2)}=5[/tex]

Substitute this value back into the equation and evaluate:

[tex]A(5)=20(5)-2(5)^2=50\text{ ft}^2[/tex]

The maximum area is 50 square feet.

This occurs when the dimensions are 5 feet by 10 feet.

Answer:

x int. (-1,0) and (-2,0).   y-int,(0,10)

Step-by-step explanation:

y-int. it's 10 because the y-int is always the c value.

x-int.

x=-b±√b²-4ac/2a

x=-15±√15²-4(5)(10)/2(5)

x=-15±√225-200/10

x=-15±√25/10

x= -15+5/10.      x=-15-5/10

x=-10/10.           x=-20/10

x=-1.                  x=-2

Answer:

10 11 12 13 14 15 16 17 18 19

10 10 11 12 13 14 15 16 17 18 19  

Step-by-step explanation:

Answer:

(a) Name: Multinomial distribution

Parameters: [tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]

(c) Name: Binomial distribution

Parameters: [tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

[tex](d)\ E(x) = 1[/tex]   [tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y) = 17[/tex]

Step-by-step explanation:

Given

[tex]p_1 = 5\%[/tex]

[tex]p_2 = 85\%[/tex]

[tex]p_3 = 10\%[/tex]

[tex]n = 20[/tex]

[tex]X \to[/tex] High Slabs

[tex]Y \to[/tex] Medium Slabs

[tex]Z \to[/tex] Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

[tex]X \to[/tex] Number of voids considered as high slabs

[tex]Y \to[/tex] Number of voids considered as medium slabs

[tex]Z \to[/tex] Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

[tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

And the mass function is:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

[tex]n = 20[/tex]

The number of voids (x, y and z) cannot be negative and they must be integers; So:

[tex]x + y + z = n[/tex]

[tex]x + y + z = 20[/tex]

Hence, the range is:

[tex]\{(x,y,z)| x + y + z=20\}[/tex]

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

[tex]E(x) = p_1* n[/tex]

[tex]E(x) = 5\% * 20[/tex]

[tex]E(x) = 1[/tex]

[tex]Var(x) = E(x) * (1 - p_1)[/tex]

[tex]Var(x) = 1 * (1 - 5\%)[/tex]

[tex]Var(x) = 1 * 0.95[/tex]

[tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]

In (b), we have: [tex]x + y + z = 20[/tex]

However, the given values of x in this question implies that:

[tex]x + y + z = 1 + 17 + 3[/tex]

[tex]x + y + z = 21[/tex]

Hence:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]

This question implies that:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]

Because

[tex]0, 1 \le 1[/tex] --- for x

In (e), we have:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

In (a), we have:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

So:

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]

Expand

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]

Using a calculator, we have:

[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1)[/tex]

This implies that:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

In (c), we established that X is a binomial distribution with the following parameters:

[tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

Such that:

[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]

So:

[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]

[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]

[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]

[tex]P(X=0) = 0.3585[/tex]

[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]

[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]

[tex]P(X=1) = 0.3774[/tex]

So:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]

[tex]P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y)[/tex]

Y has the following parameters

[tex]p_2 = 85\%[/tex]  and    [tex]n = 20[/tex]

[tex]E(Y) = p_2 * n[/tex]

[tex]E(Y) = 85\% * 20[/tex]

[tex]E(Y) = 17[/tex]