what test is an aptitude test

Answer:

0.5s

Explanation:

if the frequency is 2Hz that means it makes 2 complet cycles in one second. The time period for one cycle would be 0.5s

Answer:

The correct answer is t = 0.92s

Explanation:

Initial velocity v​0 = 3.0 m/s

Displacement Δy = ?

Acceleration a = -9.8m/s2

Final velocity v = -6.0m/s

Time t=? Target unknown

We can use the kinematic formula missing Δy to solve for the target unknown t:

V=v0+at

We can rearrange the equation to solve to t:

V-v0=at

t= v-v0/a

Substituting the known value into the kinematic formula gives:

t= (-6.0m/s)-(3.0m/s)

————————————

-9.8m/s2

= -9m/s

—————-

-9.8m/s2

=0.92s

Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s.  It lands on the ground with a final speed of 6.0 m/s.

How long is the ball in the air?

Answer: 0.92

Answer:

4.5 because just do the math and its 4.5

Answer:

AHAHHAH DEW DEW

Explanation:

Condensation causes dew to form on blades of grass. This is because the water molecules react to the grass when it is heated, and the surroundings became cool. The molecules would bring to calm and turn to liquid.Image result for heart eyes cat emoji

Answer:

B. I looked it up I hope it's right

Explanation:

i hope this helps.

Answer:

its obviously C

Explanation:

i smart like dat

Explanation:

The coefficient of friction = tanθ,

 the angle would be 30∘

Answer:

Tan¯¹ /3=60 degree

Explanation:

you know coefficient is friction is equal to tan 0 equal to square root of 3 is equal to tan of civil 20 skills equal to 60 degree

4.58 m/s

Speed = displacement / time

Answer:

4kg

Explanation:

pressure=50pa

force=200N

Area=?

now,

pressure=force/area

50=200/area

area=200/50

area=4kg

The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².

Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).

Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.

Pressure = Force / area.

Given that force = 200 N

pressure = 50 Pa = 50 N/m²

Therefore, area =  force/pressure

                          = 200 N / 50 Pa

                          = 4 m²

Therefore, the area of the surface is 4 m².

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Answer:

It starts from rest so Vi=0

Vf=10 m/s

t=5 seconds

Explanation:

a=Vf-Vi/t

a=10-0/5

a=10/5

a=2m/s^s

Answer: For the angles below 40, The air time and range are directly proportional meaning that if air time increases, the range increases. Like said earlier, the total traveled distance in the x-direction depends on the initial velocity and time.

Answer:

The answer is C

Explanation:

I ave K12 and i just finished it.

The phrase which is not an example of intracellular communication is :

C) Molecule in a cell changes function of cell.

The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.

The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.

The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.

Thus, the correct answer is C.

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Answer:

It will reduce by 9 times and become 400 N.

This question can be solved using the concepts of Newton's Law of Gravitation, and gravitational force.

The gravitational force between the two objects if the mass of each object is reduced to one-third of its original mass will be "A. 400 N".

According to Newton's Law of Gravitation the gravitational force between two objects is given as follows:

[tex]F = \frac{Gm_1m_2}{r^2}[/tex]---------- eqn (1)

where,

F = Gravitational force between objects = 3600 N

G = Universal gravitational constant

m₁ = mass of the first object

m₂ = mass of the second object

r = distance between the objects

Now, the masses have become one-third of the original value:

[tex]F'=\frac{G(\frac{m_1}{3})(\frac{m_2}{3})}{r^2}\\\\F' = \frac{1}{9}\frac{Gm_1m_2}{r^2}\\\\using\ eqn\ (1):\\\\F' = \frac{F}{9} = \frac{3600\ N}{9}\\\\[/tex]

F' = 400 N

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The attached picture illustrates Newton's Law of Gravitation.

Answer:

A is true ,b is true

Explanation:

Answer:

A hydraulic braking system transmits brake-pedal force to the wheel brakes through pressurized fluid.

Explanation:

T1 = 2×W / squrt (3) +1

T2 = squrt(6) ×W/ squrt (3) +1

Here, T1 is along A.

T2 is along B

W = 250N.

Yo can directly use above formula to find solution.

Answer:

690.8895705521 × 10^8 is the perfect answer of your question.

Explanation:

maaf kalau saya salah pada jawaban anda

Answer:

the magnitude of the dog's total displacement to the nearest tenths = 53.12°

Explanation:

Given that:

a dog walks 8.0m due to the north and 6.0 m due east.

We can determine the magnitude of the dog's total displacement by using the Pythagoras theorem.

Consider the north direction be the opposite and the east direction to be the adjacent, therefore the hypotenuse will be the dog's total displacement.

So, suppose hypotenuse is represented by a

the opposite represented by b, and the adjacent represented by c

Then;

a² = b² + c²

a² = 8²  +  6²

a² = 64 + 46

a² = 100

a =[tex]\sqrt{100[/tex]

a = 10.0 m

However, the magnitude of the dog's total displacement is calculated by taking the tangent of the system.

tan θ = opposite / adjacent

tan θ = b/c

tan θ = 8/6

tan θ = 4/3

tan θ = 1.333

θ = tan⁻¹ (1.333)

θ = 53.12

the magnitude of the dog's total displacement to the nearest tenths = 53.12°

Answer:49594.5

Explanation:

Answer:

The answer is

Explanation:

The velocity of w given body given the distance and time taken can be found by using the formula

[tex]velocity = \frac{distance}{time} \\ [/tex]

From the question

distance = 5 m

time = 20 s

The velocity of the ball is

[tex]velocity = \frac{5}{20} = \frac{1}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Formula: v = d/t

v = velocity

d = distance

t = time

We are given the distance (5 meters) and the time (20 seconds). Solve with these given values.

v = 5/20

v = 1/4 m/s

Best of Luck!

Answer: a straight line with a positive slope

Explanation:

If an object is moving and it changes its position by 2 units every 4 s starting from the origin,

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second.

Learn more about speed from here If an object is moving and it changes its position by 2 units every 4 s starting from the origin,

speed = distance /time

          = 2 units / 4 seconds

          = 0.5 units/seconds

Thus, the speed of the object would be 0.5 units /seconds

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the question seems incomplete the complete question is If an object is moving and it changes its position by 2 units every 4 s starting from the origin, then the position vs. time graph is

Answer:

To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.

Answer:

You can use the following things

Explanation:

Rubber ball - A rubber ball can decrease pressure if you throw it against the wall and catch it.

Rubber squeezy toy - If you squeeze this in your hands also you can decrease pressure.

Hope this helps....

Have a nice day!!!!

Answer:

Explanation:

Initial velocity u = V₀ in upward direction so it will be negative

u = - V₀

Displacement s = H . It is downwards so it will be positive

Acceleration = g ( positive as it is also downwards )

Using the formula

v² = u² + 2 g s

v² = (- V₀ )² + 2 g H

= V₀² + 2 g H .

v = √ ( V₀² + 2 g H )

Answer: A. Overweight and obesity

Explanation:

Overweight and obesity are labeled for ranges of weight that are greater than what is generally considered healthy for a given height. Hence, option A is correct.

Overweight and obesity are calculated by Body Mass Index (BMI). BMI is a person's weight in kilograms divided by the square of height in meters. The healthy adult human BMI ranges from 18.5 to 25.

If BMI is less than 18.5, it falls within the underweight range. If the BMI ranges from 25.0 to 29.9, it falls within the overweight range. If the BMI is greater than 30, it comes under the obesity range. A high BMI indicates high fatness.

Obesity and overweight are determined as an abnormal growth or excessive fat accumulation in the healthy range. It is caused by an energy imbalance between calories consumed and calories expended.

Obesity and Being overweight can cause certain diseases and health issues. It increases the risk of high blood pressure, heart disease, diabetes, and stroke.

It is important to maintain a healthy range BMI. Obesity and overweight are reduced by making the choice of healthier foods and regular physical activities like yoga and exercise.

Hence, The correct option is A) Overweight and Obesity.

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Answer:

velocity

Explanation:

I think i dont really know

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is [tex]\mu_s = 0.60[/tex]

The value for static friction is [tex]\mu_k = 0.70[/tex]

Explanation:

From the question we are told that

The mass of the clock is [tex]m = 95 \ kg[/tex]

The first horizontal force is [tex]F _s = 560 \ N[/tex]

    The second horizontal force is    [tex]F _k  =  650  \  N[/tex]

Generally the static frictional force is equal to the first  horizontal force

So

     [tex]F _s  =  m  *  g  *  \mu_s[/tex]

=>   [tex]560  =  95  *  9.8  *  \mu_s[/tex]

=>    [tex]\mu_s =  0.60[/tex]

Generally the kinetic frictional force is equal to the second horizontal force

So

      [tex]F _k  =  m  *  g  *  \mu_k[/tex]

      [tex]650 =  95  *  9.8  *  \mu_k[/tex]

     [tex]\mu_k =  0.70[/tex]

Answer:

acceleration is 1.6 m/s^2

Explanation:

This is a question involving Kinematics so we can use one of the kinematic equations.

Given info: Vi= 2.6 m/s. Vf= 15.4 m/s. T= 8s

We need to solve for acceleration

The best equation to use is (Vf = Vi + at) as it contains all the info we need to solve for acceleration.

Now substitute the values given into the equation.

Vf = Vi + at >> 15.4 = 2.6 + a8

Now solve for a by rearranging the equation.

15.4 -2.6= 8a >> 12.8=8a >> 12.8/8= 8a/8 >> 1.6 =a

NOTES:

Acceleration is the rate of increase of velocity

Vf is final velocity or velocity after acceleration/de-accaeleration occurs

Vi is intial velocity or velocity before acceleration or de-accaeleration occurs

Time is time it took for a certain motion to occur.

Answer:

I think it is acute angle.

Explanation:

Because it is an angle between 0° and 90°. Hope this answer wil help you.