An aptitude test is a systematic means of testing a job candidate's abilities to perform specific tasks and react to a range of different situations. The tests each have a standardised method of administration and scoring. The results are quantified and compared with all other test takers.
Answer:
Hi There!
Explanation:
An aptitude test is a systematic means of testing a job candidate’s abilities to perform specific tasks and react to a range of different situations. The tests each have a standardised method of administration and scoring, with the results quantified and compared with all other test takers.
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PLEASE HELP ASAP!!!!
T1 = 2×W / squrt (3) +1
T2 = squrt(6) ×W/ squrt (3) +1
Here, T1 is along A.
T2 is along B
W = 250N.
Yo can directly use above formula to find solution.
A biker accelerates from rest to 10 m/s in 5 seconds. What is the biker's
acceleration? Calculate for the missing variable
Your answer
Answer:
It starts from rest so Vi=0
Vf=10 m/s
t=5 seconds
Explanation:
a=Vf-Vi/t
a=10-0/5
a=10/5
a=2m/s^s
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s
It lands on the ground with a final speed of 6.0 m/s
How long is the ball in the air?
Round the answer to two significant digits
Answer:
The correct answer is t = 0.92s
Explanation:
Initial velocity v0 = 3.0 m/s
Displacement Δy = ?
Acceleration a = -9.8m/s2
Final velocity v = -6.0m/s
Time t=? Target unknown
We can use the kinematic formula missing Δy to solve for the target unknown t:
V=v0+at
We can rearrange the equation to solve to t:
V-v0=at
t= v-v0/a
Substituting the known value into the kinematic formula gives:
t= (-6.0m/s)-(3.0m/s)
————————————
-9.8m/s2
= -9m/s
—————-
-9.8m/s2
=0.92s
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s. It lands on the ground with a final speed of 6.0 m/s.
How long is the ball in the air?
Answer: 0.92
A force of 200N is creating a pressure of 50Pa on a surface. Calculate the area of the surface.
Answer:
4kg
Explanation:
pressure=50pa
force=200N
Area=?
now,
pressure=force/area
50=200/area
area=200/50
area=4kg
The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².
What is force?Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).
Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.
Pressure = Force / area.
Given that force = 200 N
pressure = 50 Pa = 50 N/m²
Therefore, area = force/pressure
= 200 N / 50 Pa
= 4 m²
Therefore, the area of the surface is 4 m².
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Explain the process that causes dew to form on blades of grass.
Answer:
AHAHHAH DEW DEW
Explanation:
Condensation causes dew to form on blades of grass. This is because the water molecules react to the grass when it is heated, and the surroundings became cool. The molecules would bring to calm and turn to liquid.Image result for heart eyes cat emoji
If an object is moving and it changes its position by 2 min
every 4 s starting from the origin, then the position vs. time
graph is:
Answer: a straight line with a positive slope
Explanation:
If an object is moving and it changes its position by 2 units every 4 s starting from the origin,
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second.
Learn more about speed from here If an object is moving and it changes its position by 2 units every 4 s starting from the origin,
speed = distance /time
= 2 units / 4 seconds
= 0.5 units/seconds
Thus, the speed of the object would be 0.5 units /seconds
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the question seems incomplete the complete question is If an object is moving and it changes its position by 2 units every 4 s starting from the origin, then the position vs. time graph is
A snail can move app approximately 0.30 inches per minute. How many meters can the snail cover in 15 minutes
Answer:
4.5 because just do the math and its 4.5
The time period of a wave T is the the time taken to produce one complete wave. If the frequency of a wave is 2 Hz, what is it’s time period?
Answer:
0.5s
Explanation:
if the frequency is 2Hz that means it makes 2 complet cycles in one second. The time period for one cycle would be 0.5s
Question number 2 ppllzzzzzzz
Describe the relationship between air time and range.
Answer: For the angles below 40, The air time and range are directly proportional meaning that if air time increases, the range increases. Like said earlier, the total traveled distance in the x-direction depends on the initial velocity and time.
A soccer ball is kicked horizontally. What is its average speed if its displacement is 55.0 m after 12.00 s? What formula was used to solve this problem?
4.58 m/s
Speed = displacement / time
hey can anyone help me out in dis pls!
Answer:
A is true ,b is true
Explanation:
A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in motion, in horizontal force of 650N
Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is [tex]\mu_s = 0.60[/tex]
The value for static friction is [tex]\mu_k = 0.70[/tex]
Explanation:
From the question we are told that
The mass of the clock is [tex]m = 95 \ kg[/tex]
The first horizontal force is [tex]F _s = 560 \ N[/tex]
The second horizontal force is [tex]F _k = 650 \ N[/tex]
Generally the static frictional force is equal to the first horizontal force
So
[tex]F _s = m * g * \mu_s[/tex]
=> [tex]560 = 95 * 9.8 * \mu_s[/tex]
=> [tex]\mu_s = 0.60[/tex]
Generally the kinetic frictional force is equal to the second horizontal force
So
[tex]F _k = m * g * \mu_k[/tex]
[tex]650 = 95 * 9.8 * \mu_k[/tex]
[tex]\mu_k = 0.70[/tex]
_________________ are labels for ranges of weight that are greater than what is generally considered healthy for a given height.
A. Overweight and obesity
B. Overweight and morbidity
C. Obesity and diabetes
D. Obesity and heft
Answer: A. Overweight and obesity
Explanation:
Overweight and obesity are labeled for ranges of weight that are greater than what is generally considered healthy for a given height. Hence, option A is correct.
What are Overweight and obesity?Overweight and obesity are calculated by Body Mass Index (BMI). BMI is a person's weight in kilograms divided by the square of height in meters. The healthy adult human BMI ranges from 18.5 to 25.
If BMI is less than 18.5, it falls within the underweight range. If the BMI ranges from 25.0 to 29.9, it falls within the overweight range. If the BMI is greater than 30, it comes under the obesity range. A high BMI indicates high fatness.
Obesity and overweight are determined as an abnormal growth or excessive fat accumulation in the healthy range. It is caused by an energy imbalance between calories consumed and calories expended.
Obesity and Being overweight can cause certain diseases and health issues. It increases the risk of high blood pressure, heart disease, diabetes, and stroke.
It is important to maintain a healthy range BMI. Obesity and overweight are reduced by making the choice of healthier foods and regular physical activities like yoga and exercise.
Hence, The correct option is A) Overweight and Obesity.
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The gravitational force between two objects is 3600 N. What will be the gravitational force between the objects if the mass of each object is reduced to one third of its original mass
A. 400 N
B. 1200 N
C. 10,800 N
D. 32,400
Answer:
It will reduce by 9 times and become 400 N.
This question can be solved using the concepts of Newton's Law of Gravitation, and gravitational force.
The gravitational force between the two objects if the mass of each object is reduced to one-third of its original mass will be "A. 400 N".
According to Newton's Law of Gravitation the gravitational force between two objects is given as follows:
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]---------- eqn (1)
where,
F = Gravitational force between objects = 3600 N
G = Universal gravitational constant
m₁ = mass of the first object
m₂ = mass of the second object
r = distance between the objects
Now, the masses have become one-third of the original value:
[tex]F'=\frac{G(\frac{m_1}{3})(\frac{m_2}{3})}{r^2}\\\\F' = \frac{1}{9}\frac{Gm_1m_2}{r^2}\\\\using\ eqn\ (1):\\\\F' = \frac{F}{9} = \frac{3600\ N}{9}\\\\[/tex]
F' = 400 N
Learn more about Newton's Law of Gravitation here:
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The attached picture illustrates Newton's Law of Gravitation.
Find the velocity of a ball traveling 5 meters for 20 seconds.
Formula:
Substitute:
Solution:
Answer:
The answer is
0.25 m/sExplanation:
The velocity of w given body given the distance and time taken can be found by using the formula
[tex]velocity = \frac{distance}{time} \\ [/tex]
From the question
distance = 5 m
time = 20 s
The velocity of the ball is
[tex]velocity = \frac{5}{20} = \frac{1}{4} \\ [/tex]
We have the final answer as
0.25 m/sHope this helps you
Formula: v = d/t
v = velocity
d = distance
t = time
We are given the distance (5 meters) and the time (20 seconds). Solve with these given values.
v = 5/20
v = 1/4 m/s
Best of Luck!
In general, which factor is NOT critical when beginning an exercise program? A. using appropriate protective equipment during exercise B. finding friends who like to exercise the same way you do C. seeing your doctor for a physical assessment prior to beginning exercise D. choosing clothing that is designed to match your exercise program Please select the best answer from the choices provided.
O A
О В
O C
PLEASE HELP!!!
Answer:
B. I looked it up I hope it's right
Explanation:
i hope this helps.
Answer:
its obviously C
Explanation:
i smart like dat
A bicycle is going 2.6 m/s when it speeds up to 15.4 m/s in 8 seconds. What is the acceleration?
Answer:
acceleration is 1.6 m/s^2
Explanation:
This is a question involving Kinematics so we can use one of the kinematic equations.
Given info: Vi= 2.6 m/s. Vf= 15.4 m/s. T= 8s
We need to solve for acceleration
The best equation to use is (Vf = Vi + at) as it contains all the info we need to solve for acceleration.
Now substitute the values given into the equation.
Vf = Vi + at >> 15.4 = 2.6 + a8
Now solve for a by rearranging the equation.
15.4 -2.6= 8a >> 12.8=8a >> 12.8/8= 8a/8 >> 1.6 =a
NOTES:
Acceleration is the rate of increase of velocity
Vf is final velocity or velocity after acceleration/de-accaeleration occurs
Vi is intial velocity or velocity before acceleration or de-accaeleration occurs
Time is time it took for a certain motion to occur.
An object is projected with initial speed v0 from the edge of the roof of a building that has height H. The initial velocity of the object makes an angle α0 with the horizontal. Neglect air resistance. If α0 is 90∘, so that the object is thrown straight up (but misses the roof on the way down), what is the speed v of the object just before it strikes the ground?
Answer:
Explanation:
Initial velocity u = V₀ in upward direction so it will be negative
u = - V₀
Displacement s = H . It is downwards so it will be positive
Acceleration = g ( positive as it is also downwards )
Using the formula
v² = u² + 2 g s
v² = (- V₀ )² + 2 g H
= V₀² + 2 g H .
v = √ ( V₀² + 2 g H )
4.46 x 1010 /6.52x 10-8 =
Answer:
690.8895705521 × 10^8 is the perfect answer of your question.
What other angle would give the same range at 19 degrees?
Answer:
I think it is acute angle.
Explanation:
Because it is an angle between 0° and 90°. Hope this answer wil help you.
if the coefficient of friction is root 3 the angle of friction is
Explanation:
The coefficient of friction = tanθ,
the angle would be 30∘
Answer:
Tan¯¹ /3=60 degree
Explanation:
you know coefficient is friction is equal to tan 0 equal to square root of 3 is equal to tan of civil 20 skills equal to 60 degree
Which phrase is not an example of intracellular communication?
A. molecular movement within a cell
B. reaction to pheromones
C.molecule in a cell changes function of cell
D. control of cell division
Answer:
The answer is C
Explanation:
I ave K12 and i just finished it.
The phrase which is not an example of intracellular communication is :
C) Molecule in a cell changes function of cell.
"Intracellular communication"The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.
The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.
The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.
Thus, the correct answer is C.
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A dog walks 8.0 meters due north and then 6.0 meters due east. Determine the magnitude of the dog's total displacement to the nearest tenths
Answer:
the magnitude of the dog's total displacement to the nearest tenths = 53.12°
Explanation:
Given that:
a dog walks 8.0m due to the north and 6.0 m due east.
We can determine the magnitude of the dog's total displacement by using the Pythagoras theorem.
Consider the north direction be the opposite and the east direction to be the adjacent, therefore the hypotenuse will be the dog's total displacement.
So, suppose hypotenuse is represented by a
the opposite represented by b, and the adjacent represented by c
Then;
a² = b² + c²
a² = 8² + 6²
a² = 64 + 46
a² = 100
a =[tex]\sqrt{100[/tex]
a = 10.0 m
However, the magnitude of the dog's total displacement is calculated by taking the tangent of the system.
tan θ = opposite / adjacent
tan θ = b/c
tan θ = 8/6
tan θ = 4/3
tan θ = 1.333
θ = tan⁻¹ (1.333)
θ = 53.12
the magnitude of the dog's total displacement to the nearest tenths = 53.12°
is the distance traveled during a specific unit of
Answer:
velocity
Explanation:
I think i dont really know
Explain the haudralic break system
Answer:
A hydraulic braking system transmits brake-pedal force to the wheel brakes through pressurized fluid.
Explanation:
An object example to decrease pressure.
Answer:
To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.
Answer:
You can use the following things
Explanation:
Rubber ball - A rubber ball can decrease pressure if you throw it against the wall and catch it.
Rubber squeezy toy - If you squeeze this in your hands also you can decrease pressure.
Hope this helps....
Have a nice day!!!!
TEST
16. What is the average velocity of Mulan as
she covers 20 min 3.5 s to meet her
matchmaker?
0.175 m/s
10 m/s
70 m/s
5.71 m/s
CLEAR ALL
How does the “Sum of Forces” help you?
pls helppppppppppppppp
Explanation:
maaf kalau saya salah pada jawaban anda
Solve.
(3.0 × 107)x (1.5 × 103)
Answer:49594.5
Explanation: