What is wrong with a MOV BL, CX instruction?

Answers

Answer 1

Answer:

The MOV bl , cx instruction is wrong because the contents of cx are to big for bl .

I think this is the answer.

Related Questions

What protects your computer so that it doesn’t get a computer virus?

Internet Browser

Antivirus Software

Keyboard Protector

My Teacher

Answers

Answer:

Antivirus Software

Explanation:

I believe Antivirus Software.

Sorry if I am wrong.

Answer:

Antivirus Software

Explanation:

Antivirus scans the incoming files or code that has been passed through your network traffic. Companies who build these softwares maintain a database of viruses that are already known. That database teaches the antivirus to remove, flag or quarantine any viruses in your computer.

What are the characteristic features of TFTP?

Answers

Answer:

TFTP Server is used for simple file transfer

Explanation:

Example

boot-loading remote devices

explain 5 important of using a word processor

Answers

Answer:

Spelling

Word processors contain an electronic spell checker. The student writer has immediate feedback about misspelled words. Student must discern which of the computer-generated spellings is correct for the context. Teachers no longer have to red-ink spelling errors. They can focus on the few exceptions the spellchecker does not catch.

Security

Teachers and students gain a sense of security about losing assignments. When the student saves her work, she avoids the possibility of the assignment being lost or misplaced. If an assignment is ever misplaced, a replacement can be easily printed.

Legibility

Teachers benefit by receiving a readable copy that is easy to grade. Students with poor handwriting can increase their scores with better looking papers. Students should be instructed to turn in copies of work in a readable font.

Publishing

Work done on a word processor can easily published on a bulletin board. Teachers can create electronic anthologies of their students' writings. Each student can receive an electronic copy of published works with no printing costs.

Mobility

Work done on a word processor and saved on the Internet is highly portable and accessible from any computer with Internet access. Dogs do not eat papers in cyberspace. "I forgot it at home" is irrelevant. Just log onto the nearest computer and your work appears on the screen.

Explanation:

Answer:

1. they are faster creation of document.

2.document can be stored for future use.

3. quality document are created.

4. it has access to higher variation.

5. tiredness Is greatly reduced.

In this lab, you complete a C++ program that uses an array to store data for the village of Marengo.
The program is described in Chapter 8, Exercise 5, in Programming Logic and Design. The program should allow the user to enter each household size and determine the mean and median household size in Marengo. The program should output the mean and median household size in Marengo. The file provided for this lab contains the necessary variable declarations and input statements. You need to write the code that sorts the household sizes in ascending order using a bubble sort and then prints the mean and median household size in Marengo. Comments in the code tell you where to write your statements.
Instructions
Make sure that the file HouseholdSize.cpp is selected and open.
Write the bubble sort.
Output the mean and median household size in Marengo.
Execute the program by clicking the Run button and the bottom of the screen.
Enter the following input, and ensure the output is correct. Household sizes: 4, 1, 2, 4, 3, 3, 2, 2, 2, 4, 5, 6 followed by 999 to exit the program.
Here is my code so far. I need help finishing it (printing the mean & median, etc). Thanks so much:
// HouseholdSize.cpp - This program uses a bubble sort to arrange up to 300 household sizes in
// descending order and then prints the mean and median household size.
// Input: Interactive.
// Output: Mean and median household size.
#include
#include
using namespace std;
int main()
{
// Declare variables.
const int SIZE = 300; // Number of household sizes
int householdSizes[SIZE]; // Array used to store 300 household sizes
int x;
int limit = SIZE;
int householdSize = 0;
int pairsToCompare;
bool switchOccurred;
int temp;
double sum = 0;
double mean = 0;
double median = 0;
// Input household size
cout << "Enter household size or 999 to quit: ";
cin >> householdSize;
// This is the work done in the fillArray() function
x = 0;
while(x < limit && householdSize != 999)
{
// Place value in array.
householdSizes[x] = householdSize;
// Calculate total of household sizes
sum+= householdSizes[x];
x++; // Get ready for next input item.
cout << "Enter household size or 999 to quit: ";
cin >> householdSize;
} // End of input loop.
limit = x;
// Find the mean
// This is the work done in the sortArray() function
pairsToCompare = limit - 1;
switchOccured = true;
while(switchOccured == true)
{
x = 0;
switchOccured == false;
while (x < pairsToCompare)
{
if(householdSizes[x]) > householdSizes[x+1])
{
//perform switch
}
x++;
}
pairsToCompare--;
}
// This is the work done in the displayArray() function
//Print the mean
// Find the median
median = (limit-1) / 2;
if (limit % 2 ==0)
{
cout << "Median is: " << (householdSizes[(int)median] + householdSizes[(int)median + 1]) / 2.0 << endl;
}
else {
// Print the median household size
}
// Print the median
return 0;
} // End of main function

Answers

Answer:

For the mean, do the following:

mean = sum/limit;

cout<<"Mean: "<<mean;

For the median do the following:

for(int i = 0; i<limit; i++) {

for(int j = i+1; j<limit; j++){

if(householdSizes[j] < householdSizes[i]){

temp = householdSizes[i];

householdSizes[i] = householdSizes[j];

householdSizes[j] = temp; } } }

median= (householdSizes[(limit-1)/2]+householdSizes[1+(limit-1)/2])/2.0;

if((limit - 1)%2==0){

median = householdSizes[limit/2];

}

cout<<endl<<"Median: "<<median;

Explanation:

The bubble sort algorithm in your program is not well implemented;

So, I replaced the one in your program with another.

Also, some variable declarations were removed (as they were no longer needed) --- See attachment for complete program

Calculate mean

mean = sum/limit;

Print mean

cout<<"Mean: "<<mean;

Iterate through each element

for(int i = 0; i<limit; i++) {

Iterate through every other elements forward

for(int j = i+1; j<limit; j++){

Compare both elements

if(householdSizes[j] < householdSizes[i]){

Reposition the elements if not properly sorted

temp = householdSizes[i];

householdSizes[i] = householdSizes[j];

householdSizes[j] = temp; } } }

Calculate the median for even elements

median= (householdSizes[(limit-1)/2]+householdSizes[1+(limit-1)/2])/2.0;

Calculate the median for odd elements

if((limit - 1)%2==0){

median = householdSizes[limit/2];

}

Print median

cout<<endl<<"Median: "<<median;

The term ________ refers to the use of a single unifying device that handles media, Internet, entertainment, and phone needs. Group of answer choices

Answers

The term [tex]\sf\purple{digital \:convergence}[/tex] refers to the use of a single unifying device that handles media, internet, entertainment, and phone needs.

[tex]\large\mathfrak{{\pmb{\underline{\red{Happy\:learning }}{\orange{.}}}}}[/tex]

Which of the following class definition defines a legal abstract class Group of answer choices public class Rectangle abstract { public abstract double findArea ( ); } public abstract class Rectangle { public abstract double findArea ( ); } public class Rectangle { public abstract double findArea ( ); } public class abstract Rectangle { public abstract double findArea ( ); }

Answers

Question

Which of the following class definition defines a legal abstract class Group of answer choices

(a)

public class Rectangle abstract {