Help pls I’ll give extra points

Answer:

I'm sorry hindi ko po alam eh

35 is the answer

have a wonderful day

Answer:

49/5 mm

Step-by-step explanation:

7/2×14/5

multiply the numerator and denominator

98/10

simplify

49/5 or

9 4/5 mm

Answer:

y = 5 sin (2x) + 4

Step-by-step explanation:

this is sines function,

the amplitude is [9 - (-1)]/2 = 10/2 = 5

the period is 2πx/π = 2x

the x-axis of actual function is at y = 4

so, the function is :

y = 5 sin (2x) + 4

Answer:

200.

Step-by-step explanation:

35% = 0.35 so

0.35x = 70

x = 70 / 0.35

= 200.

Answer:

200

Step-by-step explanation:

Let the number = x

35% of x = 70

35/100 * x = 70                      Multiply by 100

35x = 70 * 100

35x = 7000                           Divide by 35

x = 7000/35

x = 200

9514 1404 393

Answer:

  551.07 yd²

Step-by-step explanation:

For radius r and height h, the total surface area of the cylinder is given by ...

  SA = 2πr(r +h)

Here, the radius is 4.5 yards (half the diameter) and the height is 15 yards. That makes the surface area ...

  SA = 2(3.14)(4.5 yd)(4.5 +15 yd) = 551.07 yd²

Solution :

Avrami relationship

[tex]$1-y=exp(-kt^n)$[/tex]

[tex]$\ln(1-y)=-kt^n$[/tex]

[tex]$-\ln(1-y)=kt^n$[/tex]

[tex]$\ln\left[\ln\left(\frac{1}{1-y}\right)\right]=\ln k + n \ln t$[/tex]

The fraction transformed is 0.2 at 12.6 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.2}\right)\right]=\ln k + n \ln (12.6)$[/tex]

[tex]$-1.5 = \ln k + 2.533 n$[/tex]  .........(i)

The fraction transformed is 0.7 at 25.7 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.7}\right)\right]=\ln k + n \ln (25.7)$[/tex]

[tex]$0.5 = \ln k + 3.24 n$[/tex]   ..............(ii)

Subtract (ii) from (i),

-2 = -0.71 n

n = 2.81

Therefore, from (i),

[tex]$-1.5 = \ln k + 2.533 (2.81)$[/tex]

k = 0.000181

Now if the fraction transformed is 0.92, then

[tex]$kt^n=-\ln (1-y)$[/tex]

[tex]$t=\left[\frac{-\ln (1-y)}{k}\right]^{\frac{1}{n}}$[/tex]

[tex]$t=\left[\frac{-\ln (1-0.92)}{0.000181}\right]^{\frac{1}{2.81}}$[/tex]

t = 29.8528 s

Answer: The test statistic for this hypothesis test =1.597

Step-by-step explanation:

When population standard deviation is unknown, we use t-test statistic:

[tex]t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}[/tex]

[tex]\overline{x}[/tex] = sample mean, [tex]\mu[/tex] = population mean , s= sample standard deviation, n = sample size.

As per given,

[tex]t=\dfrac{10.7-10}{\dfrac{3.1}{\sqrt{50}}}\\\\=1.59669273171\approx1.597[/tex]

Hence, the test statistic for this hypothesis test =1.597

Answer:

Nobody knows its a mistery :'D

Answer:

Because lma/os

Step-by-step explanation:

5 ( x + 20 )

-----------------

1. Simplifly

2. Distribute

3.  5 ( x + 20 )

     5 x + 100

Answer:

s = 32

Step-by-step explanation:

s - 12 = 20

s (- 12 + 12) = 20 + 12

s = 32

Step-by-step explanation:

s-12=20

s=20+12

s=32

Hope it helps.

Answer:

8 hectáreas por día

Step-by-step explanation:

72 hectares en 9 días por eso divides 72 por 9 para encontrar la repusta es 8

¡Espero que esta te ayudar! :)

(y sí, hablo un poco de español porque he aprendido desde el primer grado)

Answer:

A. True

Step-by-step explanation:

Even numbers are divisible by 2 with no remainder. 13/2 = 6.5 so yes.

Answer:

H0 : μ1 - μ2 = 0

H0 : μ1 - μ2 > 0

Test statistic = 3.96

Critical value = 1.67

Reject H0

We can conclude that there is significant evidence to support the claim that geese do travel more Than pelicans

Step-by-step explanation:

M= xbar1 = 191 ; M = xbar2 = 190 miles

n1 = 61 n2 = 61

s = 1.429 ; s2 = 1.355

Hypothesis :

H0 : μ1 - μ2 = 0

H0 : μ1 - μ2 > 0

Test statistic :

(x1 - x2) ÷ √[(s1²/n1) + (s2²/n2)]

(191 - 190) ÷ √[(1.429²/61) + (1.355²/61)]

1 ÷ √[(0.0334760) + (0.0300987)]

1 ÷ √0.0635747

1 ÷ 0.2521402

= 3.966

Degree of freedom :

df = n - 1

df = 61 - 1 = 60

Critical value :

Tcritical at 0.05%, df = 60

Tcritical = 1.67

Decision region:

Reject H0 if Tstatistic > Tcritical

Since ;

3.96 > 1.67 ; We reject H0

We can conclude that there is significant evidence to support the claim that geese do travel more Than pelicans

9514 1404 393

Answer:

  3

Step-by-step explanation:

For x > 0, the function f(x) is ...

  f(x) = 3x -4 . . . . . . . . for x > 0

Translating this down 1 unit makes it ...

  g(x) = f(x) -1 = 3x -5

The rate of change for any interval such that x > 0 in the whole interval is the coefficient of x: 3.

The rate of change on the interval is 3.

__

If you like, you can find the rate of change from ...

  m = (g(5) -g(2))/(5 -2) = (10 -1)/3 = 9/3 = 3

The rate of change is 3.

Answer: shehshywhwyw

Step-by-step explanation:

(a)  [tex]\frac{26}{51}[/tex]

(b)  [tex]\frac{26}{51}[/tex]

(i) Probability is the likelihood of whether or not an event will occur. It is given by the ratio of the number of favourable outcomes to the number of expected outcomes. i.e

P = number of favourable outcomes / total number of possible outcomes

For drawing a first card which is black,

number of favourable outcomes = 26 (since there are a total of 26 black cards in a deck of card)

total number of possible outcomes = 52 (since the total number of cards in a deck of card is 52)

∴ Probability of drawing the first black card = 26 / 52 = 1 / 13

Since the second card is not a black card, it is a red card.

number of favourable outcomes = 26 (since there are a total of 26 red cards in a deck of card)

total number of possible outcomes = 51 (since a black card has been previously picked from the deck)

∴ Probability of drawing a second black card = 26 / 51

The probability that the second is not a black card is 26 / 51

(ii) The conditional probability of a given event B is the probability that the event will occur knowing that a previous event A has already occurred,

It is given by;

P(B|A) = P(A and B) ÷ P(A)

In this case;

event B is drawing a second card which is not black

event A is drawing a first card which is black

This implies that;

P(A and B) = [tex]\frac{1}{13}[/tex] x [tex]\frac{26}{51}[/tex]

P(A) = [tex]\frac{1}{13}[/tex]

Substitute these values in the equation for conditional probability as follows;

P(B|A) = [tex]\frac{1}{13}[/tex] x [tex]\frac{26}{51}[/tex] ÷ [tex]\frac{1}{13}[/tex]

P(B|A) = [tex]\frac{1}{13}[/tex] x [tex]\frac{26}{51}[/tex] x [tex]\frac{13}{1}[/tex]

P(B|A) = [tex]\frac{26}{51}[/tex]

Therefore the conditional probability is  [tex]\frac{26}{51}[/tex]

Rotating the figure about the y-axis results in the creation of a cylindrical figure of radius 2 units and 6 units tall.

Answer:

The probability that the month starts with the letter J or the letter M is 41.66%.

Step-by-step explanation:

Given that a month of the year is chosen at random, to determine what is the probability that the month starts with the letter J or the letter M, the following calculation must be performed:

January - March - May - June - July = 5 months

(5/12) x 100 = X

0.4166 x 100 = X

41.66 = X

Therefore, the probability that the month starts with the letter J or the letter M is 41.66%.

Answer:

5/12

Step-by-step explanation:

Months that start with the letter M are March and May

Months that start with J are January, June, July

So, in total the months that start with J and M are 5 in number.

Total number of months = 12

Therefore the probability = 5/12 or 0.416 (bar on 6)

Hope u understood

Please mark as brainliest

Thank You

Answer:

50 yard South, 40 yard east 60 yard northwest

Answer:

the airspeed of the plane = 660 miles/hr

the speed of the wind = 60 miles/hr

Step-by-step explanation:

The values are missing in the given information in the question.

To able to solve this question, we will make some assumptions.

Let's assume that:

The airplane heading into the wind travels 1800 miles in 3 hours.

While returning via the same distance, it travels 2 hours 30 minutes.

We are to determine the plane's airspeed as well as the wind speed.

First, let us say that the speed of the plane is p and the wind speed is q

during the time the plane is traveling for 1800 miles in 3 hrs.

Then, we can say

3p -3q = 1800 ----- (1)

However, in  2hours 30 minutes, we have 2.5 hours

So, when the plane is returning, we have the following equation:

2.5p + 2.5q = 1800 ---- (2)

So, to find p and q, we can use the elimination method.

Simply by multiplying equation (1) with 5 and equation (2) with 6

 (5)3p    -  (5)3q     = (5) 1800

 (6)2.5p  + (6)2.5q = (6) 1800            

  15p -  15q  = 9000

+

 15p + 15q   = 10800      

 30p -  0     = 19800      

30p = 19800

p = 19800/30

p = 660

Since p = 660, then from equation (1) we can obtain the value of q:

So; Using equation (1):

3p -3q = 1800

3(660) - 3q = 1800

1980 - 3q = 1800

-3q = 1800 - 1980

-3q = -180

q = 180/3

q = 60

Therefore, the airspeed of the plane = 660 miles/hr

the speed of the wind = 60 miles/hr

Answer:

Rounded to the nearest hundredth, 234.506 becomes 234.51.

Answer:

[tex]D = (-4,-9)[/tex]

Step-by-step explanation:

Given

[tex]C =(2,7)[/tex]

 [tex]M=(-1,-1)[/tex]

Required

The coordinates of D

Represent D with:

[tex]D = (x_2,y_2)[/tex]

Using midpoint formula, we have:

[tex]M(x,y) = \frac{1}{2}(x_1 + x_2, y_1 + y_2)[/tex]

So, we have:

[tex](-1,-1) = \frac{1}{2}(2 + x_2, 7 + y_2)[/tex]

Multiply both sides by 2

[tex](-2,-2) = (2 + x_2, 7 + y_2)[/tex]

Compare both sides

[tex]2 + x_2 = -2[/tex]

[tex]7 + y_2 =-2[/tex]

In [tex]2 + x_2 = -2[/tex], we have:

[tex]x_2 =-2-2[/tex]

[tex]x_2 =-4[/tex]

In [tex]7 + y_2 =-2[/tex], we have:

[tex]y_2 = -2 - 7[/tex]

[tex]y_2 = -9[/tex]

So, the coordinates of D is:

[tex]D = (x_2,y_2)[/tex]

[tex]D = (-4,-9)[/tex]

Answer:

(d)  [tex]\displaystyle 12x^3 - 15x^2 + 2[/tex]

General Formulas and Concepts:

Algebra I

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]:                                                                [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = 3x^4 - 5x^3 + 2x - 1[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

( d ) 12x³ - 15x² + 2

Step-by-step explanation:

y = 3x⁴ - 5x³ + 2x - 1

[tex] \small \sf \: y = 4\times 3x^{4-1}+3\left(-5\right)x^{3-1}+2x^{1-1} [/tex]

[tex] \small \sf \: y = 12x^{4-1}+3\left(-5\right)x^{3-1}+2x^{1-1} [/tex]

[tex] \small \sf \: y = 12x^{3}-15x^{3-1}+2x^{1-1} [/tex]

y = 12x³ - 15x² + 2⁰

y = 12x³ - 15x² + 2 × 1

y = 12x³ - 15x² + 2

Hence, option ( d ) is the correct answer.