What is the pH of a 0.8 M solution of HCI?

Answer:

a)

For Methylcyclohexane  N₁ = 2770

For Methylcyclohexene N₂ = 2827

For Toluene N₃ = 2557

b) the standard deviation for the average in (a) is 143.31

c)

For Methylcyclohexane; H₁ = 0.01444 cm

For Methylcyclohexene; H₂ = 0.01415 cm

For Toluene; H₃ = 0.01564 cm

Explanation:

Given the data in the question;

Gas-liquid chromatography on a 40-cm packed column:

Compound                   tR, min                           W, min

Air                                   1.9                                    —

Methylcyclohexane      10.0                               0.76

Methylcyclohexene      10.9                               0.82

Toluene                        13.4                                1.06

a)

an average number of plates from the data;

To get the Number of plates N, we use the following expression;

N = 16( tR / W )², we use it for Methylcyclohexane, Methylcyclohexene and Toluene

-

For Methylcyclohexane  N₁ = 16( 10 / 0.76 )² = 16( 173.13 ) = 2770.08 ≈ 2770

-

For Methylcyclohexene N₂ = 16( 10.9 / 0.82 )² = 16( 176.7 ) = 2827.2 ≈ 2827

-

For Toluene N₃ = 16( 13.4 / 1.06 )² = 16( 159.8078 ) = 2556.9 ≈ 2557

b) standard deviation for the average in (a).

First we get the mean;

Mean N" = ( N₁ + N₂ + N₃ ) / 3 = ( 2770 + 2827 + 2557 ) / 3 = 8154 / 3 = 2718

Next we determine the deviation

d₁² = (N₁ - N")² = (2770 - 2718)² = (52)² = 2704

d₂² = (N₂ - N")² = (2827 - 2718)² = (109)² = 11881

d₃² = (N₃ - N")² = (2557 - 2718)² = (-161)² = 25,921

∴ ∑d²[tex]_i[/tex] = 40506

Standard Deviation S = √( ∑d²[tex]_i[/tex]  / ( n-1 ) )

Standard Deviation S = √( 40506 / ( 3-1 )

Standard Deviation S = √( 40506 / 2 )

Standard Deviation S = √( 20253 )

Standard Deviation S = 143.31

Therefore, the standard deviation for the average in (a) is 143.31

c)

an average plate height for the column

Given that; Gas-liquid chromatography on a 40-cm packed column, L = 40 cm

-

For Methylcyclohexane; H₁ = L/N₁ = 40 / 2770 = 0.01444 cm

-

For Methylcyclohexene; H₂ = L/N₂ = 40 / 2827  = 0.01415 cm

-

For Toluene; H₃ = L/N₃ = 40 / 2557 = 0.01564 cm

Answer:

20 moles of Iron are needed

Explanation:

In 1 mole of Iron (III) oxide, Fe₂O₃, there are 2 moles of Iron, Fe. The equation that we can write is:

2 moles Fe = 1 mole Fe₂O₃

To find the moles of iron that are needed to produce 10 moles of Fe₂O₃ we must use this equation as follows:

10 moles of Fe₂O₃ * (2 moles Fe / 1mole Fe₂O₃) =

Answer:

Explanation:

Givens

P1 = 3.14 atm

T1 = 26 + 273 = 299

P2 = 3.96

T2 = ?

Equation

P1 / T1 = P2 / T2

Solution

3.14 / 299 = 3.96 / x                   Cross multiply

3.14 x = 299 * 3.96                     Divide by 3.14

x = 299*3.96 / 3.14

x = 1184.04/3.14

x = 377.08 oK                             Take off 273 to get the degrees Centigrade.

x = 104.08 oC

Part B

If you want the temperature to increase, the relationship is a direct  one. That means as the temperature goes up, the pressure will as well. So for a bicycle, it makes sense that the volume remains constant. That makes the formula above without volume because the volume would cancel out on both sides of the equation.

So as the pressure increases, the particles making up the air begin to respond by the molecules moving faster. Temperature really is the a measurement of how fast molecules are moving. So the momentum is increasing. When the particles hit something, it is with a much greater force and that increases the apparent pressure.

Answer:

a. 2.5 g

b. 0.025

c. i. 10 times ii 25 g of KI

Explanation:

a. A 2.5% (by mass) solution concentration signifies that there is ______ of solute in every 100 g

Since % by mass = mass of solute, m/mass of solvent,M × 100 %

2.5 % = m/M × 100%

since M = 100 g,

2.5 % = m/100 × 100 %

m/100 = 2.5/100

m = 2.5 g

b. Therefore, when 2.5% is expressed as a ratio of solute mass over solution mass, that mass ratio would be ________

The mass ratio = mass of solute/mass of solvent

= m/M

= 2.5 g/100 g

= 0.025

c  A solution mass of 1 kg is _______ times greater than 100 g, thus one kilogram (1 kg) of a 2.5% KI solution would contain ____________of

i. A solution mass of 1 kg is _______ times greater than 100 g

Since 1 kg = 1000 g, 1 kg/100 g = 1000 g/100 g = 10

So,1 kg is 10 times greater than 100 g.

ii. Thus one kilogram (1 kg) of a 2.5% KI solution would contain ____________of KI

So, if M = 1 kg = 1000 g, we find m

Since % by mass = mass of solute, m/mass of solvent,M × 100 %

2.5 % = m/M × 100%

since M = 1000 g,

2.5 % = m/1000 × 100 %

m/1000 = 2.5/100

m = 2.5/100 × 1000 g

m = 2.5 × 10 g

m = 25 g

Answer:

mass of sucrose = 17.115 grams

Explanation:

Given that:

mass = 2000 grams

molar mass of sucrose = 342.3 g/mol

2.5% of the sucrose soltion.

Let assume we are given 1 M of the sucrose solution;

2.5% of 1 M = 0.025 M

∴

Molarity = ( mass/molar  mass )(1000/V)

mass = (0.025 * 342.3 * 2000)/(1000)

mass of sucrose = 17.115 grams

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

To learn more about the chemical equation, follow the link:

https://brainly.com/question/28792948

#SPJ6

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

Answer:

(C) It is favorable and is driven by ΔH° only.

Explanation:

Let's consider the following balanced equation.

2 Na₂O₂ + S + 2 H₂O → 4 NaOH + SO₂

To determine whether it will be favorable or not at 298 K, we need to calculate the standard Gibbs free energy (ΔG°).

We can calculate ΔG° using the following expression.

ΔG° = ΔH° - T.ΔS°

As we can see from the expression above, the favorability will be driven if ΔH° < 0 and if ΔS° < 0. Since ΔH° = -610 kJ/mol and ΔS° = -73 J/K.mol, the favorability will be driven by ΔH°. Now, let's calculate the overall favorability.

ΔG° = ΔH° - T.ΔS°

ΔG° = -610 kJ/mol - 298 K.(-0.073 kJ/K.mol) = -588 kJ/mol

The reaction is favorable and is driven by ΔH° only.

Aluminium and Nitrogen!

Answer: B

Explanation:

According to Charle's law, at constant pressure the volume of a fixed mass of a ga is directly proportional to its absolute temperature.

At constant pressure, V∝T.

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

Answer:

i think is claim 1

Explanation:

moon jellies eat zooplankton and the zooplankton population increased

Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.

Explanation:

Answer:

I would need to see the diagram in order to answer properly

Answer:

the molar mass for Fe and Cl

Answer:

oil based paint

Explanation:

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar /  kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

Answer:

200.0lg

Explanation:

please give a brainliest

Answer: When exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

Explanation:

A degree of randomness in the molecules of a substance is called entropy.

When exhaust from car engines spreads throughout our atmosphere then it means the molecules are moving at a faster speed due to which they spread into the atmosphere rapidly.

This means that the entropy of exhaust is increasing.

Thus, we can conclude that when exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

An increase in entropy

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: [tex]V_{1}[/tex] = 571 mL,       [tex]T_{1} = 26^{o}C[/tex]

(a) [tex]T_{2} = 5^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL[/tex]

(b) [tex]T_{2} = 95^{o}F[/tex]

Convert degree Fahrenheit into degree Cesius as follows.

[tex](1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL[/tex]

(c) [tex]T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C[/tex]

The new volume is calculated as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL[/tex]

Answer:

90.26%

Explanation:

From the question given above, the following data were obtained:

Theoretical yield of AlCl₃ = 1551 g

Actual yield of AlCl₃ = 1400 g

Percentage yield =?

The percentage yield of the reaction can be obtained as follow:

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 1400 / 1551 × 100

Percentage yield = 140000 / 1551

Percentage yield = 90.26%

Thus, the percentage yield of the reaction is 90.26%

Wilma- tt

Wilbur- TT

c) 100% chance

d) 100% chance

it has been a while since I've done this so it could be wrong but im pretty sure its correct

Wilbur's family claims it is pure so they have TT

and his wife simply has big eyes so its tt

so the chances of their children having either eye shape is 100%

I'm sorry- im not too good at explaining it ><

Answer:

True.

Explanation:

Hello!

In this case, according to the ideal gas equation:

[tex]PV=nRT[/tex]

It turns out possible for us to obtain the Boyle's law, as a directly proportional relationship between pressure and volume, considering that both moles and temperature remain constant; in such a way, we write the following:

[tex]PV=k[/tex]

Therefore, for an initial (1) and final state (2) we are able to write:

[tex]P_2V_2=P_1V_1[/tex]

Regards!

Answer:

Ethylbenzoyl chloride | C9H9ClO

Answer:

What about it? I don't get the question