What is the oxidation number of bromine in the BrO3- ion?
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Answer:

sorry i dont know

Explanation:

Answer:

Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.

Explanation:

Anabolic steroid is a drug that plays the role of testosterone.

Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.

Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.

Answer:

B

Explanation:

All elements on both sides of the equation have the same amount of moles

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

Answer:

oceanic formation is the right answer.

Explanation:

this os becoz they slide a past each other and do not rub against each other

Answer:

Common names of ethers simply give the names of the two alkyl groups bonded to oxygen and add the word ether. The current practice is to list the alkyl groups in alphabetical order (t-butyl methyl ether), but older names often list the alkyl groups in increasing order of size (methyl t-butyl ether).

Explanation:

Hope it is helpful.......

Answer:

Isopropyl has the specific orientation of being attached to a central carbon atom with two CH3 molecules attached (so in IUPAC naming it can become dimethylethyl), whereas propyl is three carbons all attached in a line branching off the main carbon chain, so it's two CH2 molecules and one CH3 molecule.

Explanation:

n-propane are longer chain hydrocarbon whereas isopropane is branched hydrocarbon. Isopropyl radical is more stable than n-propyl radical.

Radicals are reaction intermediates containing one unpaired electron. They are highly reactive species . The stability of radicals depends on the structure and reaction condition.

n -propyl radical is  CH₃-CH₂-CH₂·

Isopropyl radical  is written as CH₃-CH·-CH₃

The isopropyl group contains a branch in the second carbon and its makes the central carbon with secondary structure.

The stability of tertiary radicals is greater than secondary which is greater than primary. Therefore, isopropyl radical is more stable than n -propyl radical.

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Cuz D is cyclo-thingy molecule and its a sugar

(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)

Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.

Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]

The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.

Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.

Therefore, option D. galactose is the monosaccharide.

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Answer:

Explanation:

All of above except carbon dioxide

The compound that is held together by ionic bonds are CaCl₂,  NaCl, sodium bromide, and FeBr₃. The correct options are A, C, D, and F.

Ionic bonds are electrovalent bonds. These bonds are formed when two or more atoms lose electrons or gain electrons to form an ion. Ions are opposite charges that attract each other. Ionic bonds are formed in both metals and non-metals.

CaCl₂, calcium chloride, is formed between metals and non-metals. Some more examples are NaOH – Sodium Hydroxide, NaHCO₃—Sodium Hydrogen Carbonate, etc.

An example is NaCl, is sodium has 11 atomic numbers. Chloride has 6 electrons in its outermost shell. They will share electrons with each other to make the noble gas configuration.

Thus, the correct options are A. CaCl₂, C. NaCl, D, sodium bromide, and F. FeBr₃.

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Answer:

Explanation:

Newtons 1st law:

If you slide a hockey puck on ice, eventually it will stop, because of friction on the ice. It might also stop if a hockey player places their stick in front of it.

Newton's 2nd law:

If the mass of an object is 20 kg and it's acceleration is 5 m/s, the force acting upon it is (m*a or 20*5) 100 N.

Another example that proves that force is dependent upon mass is that if you were to move a car and a truck (that were both previously stationary) at the same speed, the car would take less force/effort to move than the truck.

Newton's 3rd law:

If a book on a table, the table is exerting a force on it that is equal and opposite to the force of gravity.

If two soccer balls of the same mass collide, one moving and one stationary, then they would both apply an equal and opposite force onto each other, causing the moving ball to stop and the previously stationary ball to move at the speed of  the previously moving ball.

Answer:

It is going to be binary

Explanation:

Answer:uhhhhh should I be concerned

Explanation:

Answer:

hmmm o_O Maybe you... shouldnt

Answer:

D. Keq: [SO3][NO] /[SO2]NO2]

Explanation:

Hello!

In this case, according to the process to set up equilibrium expressions for chemical reactions at equilibrium, we realize we need to write up the concentration of products on top and that of reactants on bottom; thus, for there chemical reaction herein specified, we obtain:

[tex]Keq=\frac{[SO_3][NO]}{[SO_2][NO_2]}[/tex]

Thereby, the answer is D. Keq: [SO3][NO] /[SO2]NO2].

Best regards!

Answer:

D

Explanation:

Answer:Because When you're cleaning your glassware, you use water to rinse it off. If the burette is not completely dry by the time you use it, the remaining traces of water on the inside will make your titrant more dilute and thereby change its concentration.Before a burette is used, it needs to be cleaned. During the cleaning process, usually, water is introduced into the burette. Be the water clean or not, if the burette is then used without rinsing it with the solution that it is going to be filled with, the result of that analytical exercise will not be precise and accurate. The reason is that water residue in the burette would dillute the solution when it's filled in the burette which would make it impossible to determine the exact concentration of the solution moved by the burette. By rinsing and re-rinsing the burette several times with the solution it is going to be filled with, residue water from the cleaning process would be successfully removed from the burette as are other leftover substances from the cleaning process.

hope this helps have a nice night ❤️❤️❤️

Explanation:

Answer:

(a). (I). 0.816; 0.816

(ii). 0.917.

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Explanation:

So, without mincing words let's get straight into the solution to the question above.

(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;

P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).

P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).

The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.

The value of b = (1.2 + 1.2)/ 1.2 = 0.5.

Thus, putting the values into the equation (1) and (2) above gives;

NB: n = 3.

P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.

P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.

Using the (ii) carother's theory to Determine the critical extent of reaction gelation.

We have the following values for glycerol: k = 0.4, n = 3.

For ethylene glycol; k = 0.6, n = 2.

Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Answer:

A.

Explanation:

because a theory is like a prediction and a prediction is like a hypothesis.

According to stoichiometry and mole concept,1×10¹⁰ molecules reacted with excess hydrogen to make 2 x 10¹⁰ molecules of ammonia.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.It is important while balancing chemical equations.

In the given example, as 1 molecule of nitrogen produces 2 molecules of ammonia

∴2 x 10¹⁰ molecules of ammonia will be produced when 2 x 10¹⁰×1/2=1×10¹⁰ molecules .

Thus, 1×10¹⁰ molecules reacted with excess hydrogen to make 2 x 10¹⁰ molecules of ammonia.

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Answer:

[tex]\lambda=10^{12}\ m[/tex]

Explanation:

Given that,

The frequency of the light, [tex]f=3\times 10^{-4}\ Hz[/tex]

We need to find the wavelength of the light.

The relation between frequency, wavelength and the speed of light is given by :

[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3\times 10^{-4}}\\\\\lambda=10^{12}\ m[/tex]

So, the wavelength of the light is [tex]10^{12}\ m[/tex].

The wavelength of light will be "[tex]10^{12} \ m[/tex]"

Given:

By using the relation,

→ [tex]\lambda = \frac{c}{f}[/tex]

By putting the values, we get

→    [tex]= \frac{3\times 10^8}{3\times 10^{-4}}[/tex]

→    [tex]= 10^{12} \ m[/tex]

Thus the above response is right.

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Answer:

6.591

explanation

mass of weight is 1.092 , and mass of weight boat and sample = 7.683

mass of the solid sample= (mass of weight boat and sample) - (weight of the boat) = (1.092-7683) = 6.591 g

hence, the mass of the solid sample is 6.591 g

Answer:

A, B and D

Explanation:

Gas particles move randmly at high speed, colliding with each other

Answer:

3.31 g/cm³

Explanation:

1000cm³ = 1L

4.87mL = 4.87 × 10^-3 × 1000 = 4.87 cm³

density = mass/volume = 16.12/4.87 = 3.31 g/cm³

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

Answer:

1 mol C₃H₈

Explanation:

Step 1: Write the balanced equation for the combustion of C₃H₈

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.

Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced

We will use the established molar ratio.

3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈

Answer:an element in a chemical equation is called a subscript.

Explanation:

it represents the the number of atoms of that element present in the compound. hope this helps have a great day yall

The number at the bottom right of an element in a chemical equation is called a subscript.

Subscripts represent the number of atoms of that particular element in a molecule or formula unit. They indicate the ratio of atoms or ions present in a compound. Subscripts are written in a smaller font size and appear slightly below the element's symbol.

For example:

In the chemical compound water [tex](H_2O)[/tex],the subscript '2' indicates that there are two atoms of hydrogen (H) bonded to one atom of oxygen (O). The subscript specifies the ratio of elements in the compound, indicating that there are two hydrogen atoms for every one oxygen atom in water.

Therefore, the term subscript refers to the number on the right of an element in a chemical equation.

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Answer:

4.4 g

Explanation:

Step 1: Write the balanced equation

Cu + 4 HNO₃ ⇒ Cu(NO₃)₂ + 2 NO₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 3.2 L of NO₂ at STP

At standard temperature and pressure, 1 mole of NO₂ occupies 22.4 L.

3.2 L × 1 mol/22.4 L = 0.14 mol

Step 3: Calculate the moles of Cu needed to produce 0.14 moles of NO₂

The molar ratio of Cu to NO₂ is 1:2. The moles of Cu needed are 1/2 × 0.14 mol = 0.070 mol.

Step 4: Calculate the mass corresponding to 0.070 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.070 mol × 63.55 g/mol = 4.4 g

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate [tex]X_{V}[/tex] = moles of vinyl acetate / total  moles

[tex]X_{V}[/tex] = (0.1498 mol / 3.255 mol) × 100

[tex]X_{V}[/tex]  = 4.6%

mole percent of Ethylene [tex]X_{E}[/tex] = moles of Ethylene / total  moles

[tex]X_{E}[/tex]  = (3.1052 mol / 3.255 mol) × 100

[tex]X_{E}[/tex]  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑[tex]X_{i}[/tex][tex]M_{i}[/tex]

where [tex]X_{i}[/tex] is the fraction ratio and [tex]M_{i}[/tex] is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( [tex]X_{V}[/tex][tex]M_{V}[/tex]) + ( [tex]X_{E}[/tex][tex]M_{E}[/tex])

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

[tex]DP_{n}[/tex] = [tex]\frac{M_{n} }{M}[/tex]

where [tex]M_{n}[/tex] is the number average molecular weight ( 39,870 g/mol )

so we substitute

[tex]DP_{n}[/tex] = 39,870 g/mol / 30.72 g/mol

[tex]DP_{n}[/tex]  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

Answer:

it is false

Explanation:

it goes in different ways not in order

Answer:

Molar mass of O is = 16

Molar mass of O2 = 32

Answer:

methane on the other hand is made of one carbon atom and 4 hydrogen atoms. like water, the bonds are covalent.

Liquid methane and Liquid water are both covalent compounds, thus, they both have covalent bonds in common.

Methane is a covalent compound which exists as a gas at room temperature.

Methane is composed of four hydrogen atoms and a carbon atom linked together by covalent bonds.

Water is a covalent compound which exists as a liquid at room temperature.

Water is composed of two atoms of hydrogen and one atom of oxygen linked together by covalent bonds.

Since both liquid water and liquid methane are covalent compounds, they both have covalent bonds in common.

Therefore, liquid methane and liquid water have covalent bonds in common.

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