The frequency of the second overtone if the fundamental frequency is 308 Hz is equal to 1540 Hz.
What is overtone?An overtone can be described as any resonant frequency above the fundamental frequency of a sound. Overtones can be defined as all pitches higher than the lowest pitch within an individual sound. While the fundamental can be described as usually heard most prominently, overtones are present in any pitch except a true sine wave.
The lowest normal frequency is called the fundamental frequency, while the higher frequencies are known as overtones.
Given, the fundamental frequency, f₀ = 30 8 Hz
The relationship between the fundamental frequency and the second overtone is given by
f₂ = 5 f₀
f₂ = 5 × 308 = 1540 Hz
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match each vocabulary word with the correct definition. 1 . weight measure of how quickly velocity is changing 2 . acceleration speed in a given direction 3 . velocity force that resists moving one object against another 4 . friction measure of the pull of gravity on an object 5 . magnitude tendency of an object to resist a change in motion 6 . inertia size
The different words used to match the given definitions are acceleration, velocity, friction, weight, inertia, magnitude.
1. Acceleration is a measure of how quickly the velocity is changing
2. Velocity is speed in a given direction
3. Friction is the force that resists the movement of one object against another
4. On an object weight is the measure of pull of gravity
5. Inertia is the tendency of an object to resist change in motion
6. Magnitude is the size.
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when a wave strikes a new medium, three things can happen: reflection, transmission, and absorption. consider a wave propagates in air and is transmitted through a piece of paper. does increasing the frequency increase the amplitude of a sound wave transmitted through the piece of paper
A wave propagates in the air and is transmitted through a piece of paper. If the frequency increased, the amplitude of the sound wave transmitted through the paper is: not increased (decreased).
Why does the increase in frequency not increase the amplitude of sound waves?Frequency is the number of complete waves that passed by a medium per second. Meanwhile, the amplitude is the maximum distance the medium’s particle moves from its resting position when a sound wave passes. The correlation between frequency and amplitude is inversely proportional. That means, when the frequency increases, the sound wave’s amplitude will go down. Hence, the correct answer is: not increased (decreased).
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A container with volume 1.61 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas is low enough for the gas to obey the ideal-gas law to a high degree of accuracy. of the root-mean-square speed of the gas molecules is 192 m/s, what is the pressure of the gas? Express your answer in pascals.
The pressure of the gas is 0.018 atm if the gas obeys the ideal gas law.
What is the reason for this?
We know that;
√ 3RT/M
For N2;
vrms = 192 m/s
R = 8.314 J/K.mol
T = ?
M = 28 g/mol or 0.028 Kg/mol
So;
T = vrms² M/ 3R
T = 192² * 0.028 / 3* 8.314
T = 41.3K
From PV = nRT
n = 0.246 g/28 g/mol = 0.0087 moles
P = nRT/V
P = 0.0087 moles × 0.082 atmLK-1mol-1 × 41.3K/1.61 L
P = 0.018 atm
Therefore, the pressure of gas is 0.018 atm.
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The operating voltage of a power line is increased from 300 kV to 600 kV. If the amount of power delivered to customers over the power line remains constant, how does the power loss in the power line at 300 kV compare to the power loss at 600 kV? Explain.
As the voltage is increased, the power losses would decrease.
What is the power loss?We now that the term power loss has to do with the loss that occurs as a result of the heating effect of current. The transmission of power at high voltage tends to reduce the power losses that accompanies the transmission of power at a lower voltage and a high current.
As such, when we have the operating voltage of a power line is increased from 300 kV to 600 kV we can see that the voltage has doubled and this would mean that the transmission is now at a much higher voltage which would reduce the power losses even further.
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a principle of design in which the visual weight of the forms achieves equilibrium despite being distributed unevenly throughout the picture plane is called:
Answer- Asymmetrical equilibrium Due to unequal visual weight on either side of the composition, the equilibrium is asymmetrical. There could be a dominant element on one side of the composition, which is balanced by one or more weaker focal points on the other.
Explanation: What design principle brings up equilibrium?
Balance. Visual equilibrium and our feeling of balance are related concepts in the field of balancing. Visual stability is the result of a composition's reconciling conflicting forces. The two methods that the majority of effective compositions attain balance are either symmetrically or asymmetrically.
What design tenet is characterized by the distribution of visual weight on either side of the vertical axis?
Balance. Both sides of the visual field's weight distribution are equal.
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A liquid of constant density rho and constant viscosity μ flows down a wide, long inclined flat plate. The plate makes an angle θ with the horizontal. The velocity components do not change in the direction of the plate, and the fluid depth, h, normal to the plate is constant. There is negligible shear stress by the air on the fluid. Find the velocity profile u(y), where u is the velocity parallel to the plate and y is measured perpendicular to the plate. Write an expression for the volume flow rate per unit width of the plate.
The velocity profile u(y) is defined as V = (alpha)*g*sin(alpha)*h^3/3M, where u is the velocity measured parallel to the plate and y is measured perpendicular to the plate. The air just slightly shear stresses the fluid.
Velocity is a vector measurement of an object's rate of motion and direction of motion. The magnitude and direction must therefore be understood in order to calculate the velocity according to this criterion. It is possible to describe shearing stress, also known as shear stress, as "a type of stress that acts coplanar with cross section of material." Shear forces resulted in shear stress. They are a pair of forces that have the same magnitude and are directed in the opposite direction and operate on opposite sides of a body. A vector quantity is shear stress.
Alpha = g*sin(alpha)*h2/2M [y - y^3/3h^2]
V = (alpha)*g*sin(alpha)*h2/2M
Alpha = g*sin(alpha)*h^3/3M
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a skydiver leaps from a plane and accelerates toward the surface of the earth. earth’s acceleration toward the skydiver is: group of answer choices equal to the acceleration of the skydiver due to newton’s 3rd law much smaller than the acceleration of the skydiver zero cannot be determined
Earth’s acceleration toward the skydiver is much smaller than the acceleration of the skydiver
Define acceleration
Acceleration is the rate at which velocity, both in terms of speed and direction, varies over time. When anything moves faster or slower in a straight line, it is said to have been accelerated.
Your descent to the ground quickens as you plummet. This acceleration will keep going until the drag from her falling speed due to wind resistance equals the acceleration caused by gravity. He should keep accelerating downward because air resistance, also known as drag force, is usually far smaller than the normal force of a body. She will reach "terminal velocity" when these forces balance each other out, at which point she will stop accelerating.
He will thereafter fall at the same rate until he activates his chute, however his initial acceleration is brought on by acceleration due to gravity.
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a gust of wind creates ripples on the ocean that have a wavelength of 4.7\;\mathrm{cm}4.7cm and propagate at a speed of 6.5\;\mathrm{cm/s}6.5cm/s. what is the frequency of these ocean waves?
A gust of wind creates ripples in the ocean, then the frequency of these ocean waves will be 1.4 Hz.
What is Frequency?The percentage of waves that transfer a fixed point in a unit of time is known as the frequency in physics. It is the frequency or vibrations that a body in periodic motion perceptions in a unit of time. When a body in periodic motion moves through a sequence of incidents or positions before returning to its initial state, it is believed to have experienced one cycle or one vibration.
As per the given data mentioned in the question,
Frequency = speed/wavelength
Speed = 6.65 cm/s
Wavelength = 4.7 cm
F = (6.5 × 10⁻²)/(4.7 × 10⁻²)
F = 1.4 Hz
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a constant magnetic field of 7 7 t passes through a square with side 3 3 m at an angle of 55 ∘ 55∘ from the surface. calculate the magnetic flux that passes through the square. round your answer to two decimal places
The magnetic flux that passes through the square is 51.60wb.
What is magnetic flux?
The total magnetic field that flows through a specific area is measured by magnetic flux. It serves as a useful tool for describing the effects of the magnetic force on objects occupying a specific space.
The total magnetic flux through a closed surface is equal to zero, according to Gauss's law of magnetism, one of the four Maxwell's equations. (A "closed surface" is a surface that completely and without any openings encloses a volume or volumes.)
According to the given information:
Side length [tex]$=a=3 \mathrm{~m}$[/tex]
Area [tex]$=A=a^2=(3)^2=9 m^2$[/tex]
Magnetic field [tex]$B=7 \mathrm{~T}$[/tex]
Angle [tex]$\theta=55^{\circ}$[/tex]
[tex]$\Rightarrow$[/tex] Angle with area vector [tex]$=\alpha=90^{\circ}-55^{\circ}=35^{\circ}$[/tex]
Now, magnetic flux is given as
[tex]$$\begin{aligned}\phi & =B \cdot A=B A \cos \alpha \\& =7 \times 9 \times \cos 35^{\circ} \\& =51.60 \mathrm{\omega b} .\end{aligned}$$[/tex]
Magnetic flux [tex]$\phi=51.60 \mathrm{wb}$[/tex]
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calculate the moment of inertia of a thin, uniform rod of length l and mass m that rotates about a pivot at distance l/3 from one end.
The mass moment of inertia (ML²/9) is a measurement of a body's degree of inertia for rotational motion.
Explain about the moment of inertia?In physics, the term "moment of inertia" refers to the quantitative measurement of a body's inertia with respect to rotation, or the resistance that a body shows when a torque is applied to change its speed of rotation around an axis (turning force).
An engine's flywheel is a large mass that is positioned on the crankshaft. The flywheel's MOI is extremely high and aids in energy storage. In comparison to a solid shaft, a hollow shaft transmits more power (both of same mass). Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.
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jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. time-lapse photography shows that the ball was in contact with the racket for 40 ms. (a) what average force did the ball exert on the racket? (b) what is the ratio of this force to the weight of the ball?
The average force the ball exerts on the racket is 200 N and the ratio of this force to the weight of the ball is 102.04.
What do you mean by force?
A force is a push or pull that an object feels as a result of interacting with another thing. Each time two things come into contact, a force is applied to each one of them. When the interaction is finished, the force is no longer sensed by the two objects.
As given in the question,
The weight of the ball = 0.200 kg
Initial velocity = 40 m/s
Time in contact = 40 ms = 0.04 s
a) From the formula of impulse, we can write as:
Impulse (J) = The change in momentum
{since, Impulse (J) = Ft}
Ft = P
Ft = mv
Here, F = force, t = time, P = momentum, m = mass, v = velocity
So, the average force was exerted on the racket can be calculated as:
F(avg) = mv/t
putting the value from the question,
F(avg) = (0.200 kg)(40 m/s)/(0.04 s)
F (average) = 200 N
b) The weight of the ball can be calculated as:
W = mg
Here, W = weight, m = mass, g = gravitational constant
W = (0.200 kg)(9.8 m/s2)
W = 1.96 N
The ratio between the force and weight of the ball can calculated as: F(avg)/W = 200 N/1.96 N
= 102.04
Hence, the answers for a and b are 200 N and 102.04 respectively.
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The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is _______________ the momentum of the bullet it fires.
a. less than
b. more than
c. the same as
d. not equal to
The recoil (springing or flying back of the gun when shots are fired) momentum of a gun is the same as the momentum of the bullet it fires.
option C is the correct answer.
What is the principle of conservation of linear momentum?
The principle of conservation of linear momentum states that in an isolated system, the sum of the initial momentum of the system is equal to the sum of the final momentum of the system.
Mathematically, the principle of conservation of linear momentum is written as;
Pi = Pf
where;
Pi is the sum of the initial momentum of the systemPf is the sum of the final momentum of the systemm₁u₁ = m₂u₂
where;
m₁ is the mass of the gunu₁ is the initial speed of the gunm₂ is the mass of the bulletu₂ is the final speed of the bulletThus, based on the principle of conservation of linear momentum the final momentum of the gun will always be equal to the final momentum of the bullet.
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Suppose we replacebothhover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment thesame. Compared to the pucks in the video, this pair of pucks will rotateHint 1.How to approach the problemThis question asks you to relate the mass of a rotating object to the object’s angular speed(rate of rotation).You can do that using angular momentum:. In this equation, the moment of inertiais the "mass" term, equivalent toin the equation forlinear momentum.So, how does the pucks moment of inertiarelate to their mass? Is the relationship linear ()? Or is it quadratic () or inverse square()? To see the answer, try writing the general equation that defines.Now, how will doubling the mass of the pucks affect,, and?
When the mass of an object is doubled, the moment of inertia of the object is also doubled. This is because the moment of inertia of an object is proportional to the mass of the object. In the equation for angular momentum, $L = I\omega$, the moment of inertia $I$ is the "mass" term, and it is proportional to the mass of the object.
If we double the mass of the pucks in the experiment, the moment of inertia of the pucks will also be doubled. This means that the angular momentum of the pucks will be doubled, since $L = I\omega$.
However, the angular speed $\omega$ of the pucks will remain the same, since it is not directly affected by the mass of the pucks.
Therefore, the pair of pucks that are twice as massive as the original pucks will have the same angular speed but a higher angular momentum. This means that the pucks will rotate at the same rate but with more momentum, making them harder to stop or change direction.
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a linear, ideal spring that is stretched by 8.0 cm has an elastic potential energy of 20 j. what is the elastic potential energy of the same spring when it is stretched by 12 cm?
The elastic potential energy of the same spring when it is stretched by 12 cm is 180 J.
What is elastic?
Elasticity in physics and material science refers to a body's capacity to withstand a force that causes distortion and to recover its original dimensions after the force has been removed. When sufficient loads are applied, solid objects will deform; if the substance is elastic, this same object will revert to its original size and shape after the loads have been removed. Unlike plasticity, which prevents this from happening and causes the object to stay deformed, For various materials, the physical causes of elastic behaviour can vary greatly. When forces are applied, the atomic lattice in metals changes in size and shape. The lattice returns to its initial lower energy state when forces are removed.
The elastic potential energy of a spring is given by the equation:
PE = 1/2 kx^2
Where k is the spring constant and x is the amount of stretching. In this case, k is a constant since it is the same spring and x is the amount of stretching, which is 12cm. Substituting these values into the equation gives:
PE = 1/2 (20 J/8cm^2)(12cm)^2
= 180 J
Therefore, the elastic potential energy of the same spring when it is stretched by 12 cm is 180 J.
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Two power lines run parallel for a distance of 270 m and are separated by a distance of 40.0 cm. If the current in each of the two lines is 140 A and if they run in opposite directions, determine the magnitude and direction of the force each wire exerts on the other.
Answers:
magnitude: _____ N
direction: towards eachother, or away from eachother
The force exerted by each wire on the other is 2.646N and it is away from each other.
The distance between the parallel power lines is 40cm and they are of a length of 270m each.
The current in the power line is 140A.
The force on each power line due to another can be given by,
F = uI₁I₂L/2πr
Where,
I₁ and I₂ are the current in the line,
L is the length of the wire,
r is the distance between them,
Putting values,
F = 4 x π x 10⁻⁷ x 140 x 140 x 270/2 x π x 0.4
Solving further,
F = 2.646 N.
The force will be away from each other because the current is in same direction. The magnitude of the force will remain same, whatever direction of the current may be.
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imura lifts a box by bending at the knees, then slowly standing up and holding the box away from her body. is this an effective and safe lifting technique?
No, as she kept the box a safe distance from her body. As closely as you can, hug the load to your body.
Which three safe lifting methods are there?Lift gradually by extending your hips and knees (not your back). As you raise, keep your back straight and avoid twisting. Hold the load at the level of your belly button, as near to your body as you can.
Safe lifting technique?Keep the burden as near to your body as you can, if at all possible. Perhaps this is preferable to fiercely clutching it in your hands. As opposed to either entirely flexing your back (stooping) or fully flexing your hips and knees (full/deep squatting), it is ideal to slightly bend your back, hips, and knees at the beginning of the lift.
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barium metal (d = 3.51 g/cm³) has a body-centered cubic structure. calculate the edge length of a unit cell in pm. (1 m = 10¹² pm)
The edge length of a unit cell is calculated to be 50,600 pm if the barium metal has a body-centered cubic structure.
The edge length of a unit cell can be determined by using the formula of density as follows;
ρ = (Z × M) / Avogadro's number × a³
In this equation ρ represents density, M represents the atomic mass, a illustrates the edge length of a unit cell and Z represents the number of atoms in a unit cell which is equal to 2.
Substituting the values in this equation to determine the edge length of a unit cell as follows;
3.51 = 2 × 137.33 / (6.022 × 10^23) × (a³)
3.51 = 274.66 / (6.022 × 10^23) × (a³)
3.51 × (6.022 × 10^23) / 274.66 = a³
a = 5.06 × 10^-8 m
Converting m to pm as follows;
as 1 m = 1 × 10^12
Therefore; 5.06 × 10^-8 m = 50,600 pm
Hence 50,600 pm is the edge length of a unit cell.
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Lucy is a witness in a criminal trial. She replies to one question from the prosecutor by saying, "I refuse to answer that question on the
grounds that it might incriminate me."
What protection provided for in the Bill of Rights has Lucy invoked?
the right to a speedy and public trial
the right not to testify against herself
the right not to be put in double jeopardy
the right to confront witnesses against her
Answer:
C) The right not to be put in double jeopardy.
Explanation:
There was other sources that stated that too, I just chose the image below to make you more confident with ""C" being the right answer.
The kuratomi family lives in hillville. They drive 160 miles due south to visit relatives in southville. Then they drive 120 miles due west to visit some friends in franklinville. Finally, they take a direct route from franklinville back to their home. How many miles is the entire trip?.
The entire trip is 480 miles.
How many miles is the entire trip?
Using Pythagoras theorem,
160²+120²= √40000 = 200
What is Pythagoras theorem?
In mathematics, the Pythagorean Theorem or Pythagorean Theorem is the fundamental relationship in Euclidean geometry between the three sides of a right triangle. It states that the area of a square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation for the lengths of sides a, b and hypotenuse c and is often called the Pythagorean equation.
This theorem is named after the Greek philosopher Pythagoras, who lived around 570 BC. he was born This theorem has been proven countless times in many different ways. The proofs vary and include both geometric and algebraic proofs, some thousands of years old.
If the Euclidean space is expressed in the Cartesian coordinate system of analytic geometry, the Euclidean distance satisfies the Pythagorean relation. That is, the square of the distance between two points is equal to the sum of the squares of the differences in each coordinate between the points.
Therefore, The entire trip is of 480 miles.
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The flow waveform pattern that provides the shortest inspiratory time (TI) of all the available flow patterns with an equivalent peak flow rate setting is which of the following?
a. Sine
b. Constant
c. Ascending ramp
d. Descending ramp
The flow waveform pattern that provides the shortest inspiratory time (TI) of all the available flow patterns with an equivalent peak flow rate setting is Constant.
A wave is the predictable, planned movement of disturbances from one place to another. The most well-known waves are those that flow across the surface of water, but there are also waves in sound, light, and the motion of subatomic particles. In the simplest waves, the disturbance oscillates periodically (see periodic motion) with a defined frequency and wavelength. Mechanical waves, like sound, need a medium to flow through, in contrast to electromagnetic waves, which need not and can move in a vacuum (see electromagnetic radiation). How a wave moves across a medium depends on its properties.
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if a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) calculate the ideal speed to take a 85 m radius curve banked at 15 degrees.
The ideal speed is 14.71 m/s. The result is obtained by using the trigonometric formula for tan θ.
What is tan θ when a car takes a banked curve?When a car takes a banked curve, the value of tan θ would be
[tex]tan \: \theta = \frac{v_{i}^{2} }{r \times g}[/tex]
Where
θ = bangking anglevi = ideal speed (m/s)r = radius of the curve (m)g = acceleration due to gravity (9.8 m/s²)If the car takes a banked curve below the ideal speed, the friction is needed to hold it from sliding inwards of the curve. We have
radius of the curve banked, r = 85 mbanking angle, θ = 15°To find the ideal speed, we use the trigonometric formula for tan θ.
[tex]tan \: \theta = \frac{v_{i}^{2} }{r \times g}[/tex]
[tex]v_{i}^{2} = r g \times tan \: \theta[/tex]
[tex]v_{i} = \sqrt{r g \times tan \: \theta}[/tex]
[tex]v_{i} = \sqrt{85 \times 9.8 \times tan \: 15}[/tex]
[tex]v_{i} = \sqrt{223.2}[/tex]
vi = 14.94 m/s
Hence, the ideal speed to take a 85 m radius of the curve banked at 15 degrees is 14.94 m/s.
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how much current will flow through a 10-v battery with a 100-ω resistor connected across its terminals?
A 10-v battery with just a 100- resistor placed across its terminals will conduct 0.1 A of current.
What are current and a circuit?When a patterns is made to enable continuous movement of electric charge, a circuit is produced. A current seems to be the continuous passage of an electric charge thru the electrodes of a circuit; it is frequently referred to as a "flow," like a liquid might travel through with a straight tube.
Briefing:Use Ohm's law
V = IR
where voltage (V), current (I), and resistance (R)
so,
I = V / R
I = 10 / 100
I = 0.1 A
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The complete question is-
How much current will flow through a 10-V battery with a 100Ω resistor connected across its terminals?
A. 0.1A
B. 1.0A
C. 0
D. 1000A
you are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.8 × 107 m and its rotation period to be 22.3 hours. you have previously determined that the planet orbits 8.6 × 1011 m from its star with a period of 402 earth days. once on the surface you find that the acceleration due to gravity is 63.6 m/s2. what are the mass of (a) the planet and (b) the star? (g
The mass of the star of the distant solar system is 82 * 10²² kg and the mass of the planet of the distant solar system is 8.58 * 10²⁵ kg
g = G M / r
g = Acceleration due to gravity
G = Gravitational constant
M = Mass of star
r = Distance between both bodies
g = 63.6 m / s²
G = 6.67 * 10⁻¹¹ N m² / kg²
r = 8.6 * 10¹¹ m
Ms = 63.6 * 8.6 * 10¹¹ / ( 6.67 * 10⁻¹¹ )
Ms = 82 * 10²² kg
F = G M m / r²
F = m g
Equating,
m g = G M m / r²
With the above equation, we can find the mass as:
Mp = g r² / G
Mp = 63.6 * ( 1.8 * 10⁷ / 2 )² / 6.67 * 10⁻¹¹
Mass of particle = 8.58 * 10²⁵ kg
Therefore the mass will be equal to 8.58 * 10²⁵ kg
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when 70. g of lun(s) (molar mass 35g per mil) reacts with excess h2(g). 8.0% of lih (s) is priduced . tge percent yield is closey to:______.
According to the given statement the percent yield is closest to 17%
Do molar mass and weight correspond?Additionally, the primary distinction between the two would be that molar mass provides the mass of the a mole of a certain material. In contrast, molecular weight refers to a substance's molecule's mass. While molar mass as well as molecular weight have distinct definitions and measurement systems, their values are equivalent.
Briefing:
How to calculate the percentage yield
The reaction between Li3N(s) and LiH(s) is given as:
Calculate the moles of Li3N
Moles = Mass/Molar mass
Moles = 70/35
Moles = 2 moles
You can see from the reaction the 1 mole of Li3N produces 3 moles of LiH, making the total amount of LiH 6 moles.
Determine the mass of LiH (theoretical yield)
Mass of LiH = 6 * 7.95
Mass of LiH = 47.7g
%yield = actual/theoretical * 100
%yield = 8/47.7 * 100
%yields = 16.77%
Hence the percent yield is closest to 17%
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a 3000 kg truck travelling at 50 km/hr strikes a stationary 1000 kg car, locking the two vehicles together. a) what is the final velocity of the two vehicles?) b) how much of the initial kinetic energy is lost to the
The final velocity of the two vehicles is 37.5 kph and the initial kinetic energy lost is 0.25Joule
a) Prior to and following the impact, momentum is preserved as follows:
3000×50 = 4000×X
X = 37.5 kph
afterward, 37.5km/h is 10.4166m/s so it’s 4000*10.4166²/2 or about 217000 Joule
so 73000 Joule were lost in the collision
b) The portion lost is calculated as the difference between the kinetic energy before and after the collision, divided by the initial energy:
(1/2×3000×50² - 1/2×4000×37.5²) / (1/2 × 3000 × 50²) = 0.25 Joule
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What happens to the gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer?.
Option C is correct because moving one of the objects closer by 3 m increases the gravitational force between two objects that are 15 m apart by 1.
What is referred to as gravity?All material objects in the universe are subject to the force of gravity, also known as gravitation. The force of gravity tends to draw any two non-zero mass objects or particles toward one another. Subatomic particles and galaxy clusters are both affected by gravity, as are objects of all sizes.
Give an illustration of what gravity is?The earth's gravitational pull on a body is known as gravitational force. As an illustration, consider how the gravitational attraction of a tree causes its leaves and fruit to fall to the earth.
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What intermolecular force is present for ne to form a liquid at low temperatures?.
For ne to form a liquid at low temperatures, an intermolecular force known as London dispersion forces must be present.
What are intermolecular forces ?
Different sections of a molecule may have a positive or negative charge, which can lead them to arrange into particular forms in a solid. These intermolecular forces are what draw molecules together. The melting and boiling points of a substance depend on the strength of intermolecular forces.
Neon is a noble gas, an inert gas. The London dispersion force exists between them as an intermolecular force. Think of two Ne atoms that are close to one another. Due to their rapid speed, electrons eventually become asymmetrical in their distribution. London dispersion forces, which are transient dipoles caused by unequal electron distributions, are the only intermolecular forces it is capable of showing. The ensuing London dispersion forces can provide weak attractions between neon atoms because neon has electrons. Neon is a monatomic gas that exists. In other words, each neon atom is self-contained and does not interact chemically with any other atoms. As a result, neon's electron distribution can be said to be symmetrically undisturbed, making it nonpolar.
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question 3 if you are on earth and you would like to send a space probe to an asteroid that is in a circular orbit with a radius of 7 au, how many years would the journey take using the minimum energy direct trajectory?
It would take the probe minimum 8.5 years to reach a distance of 7 AU (1 AU = 150 million km).
The answer to this question depends on many factors, such as the probe's speed, the asteroid's mass, and the asteroid's size. Assuming that the probe is traveling at a speed of 10 km/s and that the asteroid's mass is 5x10^15 kg, the journey will take approximately 8.5 years.
However, this assumes a minimum energy direct trajectory, meaning that the probe would need to make a few course corrections to ensure it stays on the correct trajectory. This could cause the journey to take much longer than 8.5 years. Additionally, the size of the asteroid could impact the journey time, as a larger asteroid could cause the probe to need to make more course corrections.
In conclusion, the journey time for a space probe to travel to an asteroid with a radius of 7 AU using a minimum energy direct trajectory will depend on several factors. However, the journey time could be significantly increased if the probe requires more course corrections or if the asteroid is larger.
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There are two reasonable approximations to consider for the pencil in this problem: a cylinder and a thin rod. However, in this problem we will treat the pencil as a uniform thin rod of length 15.0 cm and mass 10.0 g . The pencil rotates about an axis perpendicular to the plane of the figure. Which of the labeled points is the point that the axis of rotation passes through?
The point that the axis of rotation passes through in the pencil of length 15.0 cm and mass 10.0 g is point B.
The free body diagram of the pencil that rotates about an axis perpendicular to the plane of the figure is shown in the image attached below.
N = Normal force
mg = Weight
C = Center of mass point
f = Frictional force
The weight of the pencil acts in vertically downward direction at the center of mass of the pencil, that is, at point C. Since, the pencil touches the surface at point B, the force due to weight of the pencil produces a torque and makes the pencil rotate about point B.
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Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena kevin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, what can you infer?.
Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena kelvin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, then Kevin’s circular path has a bigger radius than Linda’s path.
What is speed?Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number.
Given that,
Linda, a biker, is moving along a circular path at a constant speed of 10 km/h.
kelvin, another biker, is moving along a circular path at a constant speed of 12 km/h.
As we know,
acceleration (a) = V²/r
For Linda, a₁ = (10)²/r₁
For Kelvin, a₂ = (12)² /r₂
So, a₁/a₂ = [(10)²/r₁] × [r₂/(12)²]
or, a₁/a₂ = 0.694 r₂/r₁
or, r₁ = 0.694 r₂ [ As, acceleration is same]
Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.
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The complete question is as follows:
Linda, a biker, is moving along a circular path at a constant speed of 10 km/h. In a neighboring arena Kevin, another biker, is moving along a circular path at a constant speed of 12 km/h. If the acceleration of the two bikers is the same, what can you infer?
A) The centripetal force on Kevin is higher than that on Linda.
B) The centripetal force on Linda is higher than that on Kevin.
C) Kevin’s circular path has a bigger radius than Linda’s path.
D) Linda’s circular path has a bigger radius than Kevin’s path