Chemistry College

What does the esophagus connect?
the intestine to the colon
the intestine to the mouth
The stomach to the intestine
the mouth to the stomach

Answers

Answer 1

Answer: it think it would be last one.  the mouth to the stomach is the answer.

Explanation:

Answer 2

Answer:

The correct answer is D! The esophagus connects the mouth to the stomach.

Explanation:

The mouth is connected to the esophagus, which in turn is connected to the throat. The throat, in turn, connects the mouth to the stomach.

I had this on a science test and I got it right :D

I hope this helps! ;)

Related Questions

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed? (4 points)

Answers

Answer:

0.917 L

Explanation:

Step 1: Given data

Molar concentration of the solution (M): 0.530 M (0.530 mol/L)Mass of Ca(OH)₂ (solute): 36.0 g

Step 2: Calculate the moles corresponding to 36.0 g of Ca(OH)₂

The molar mass of Ca(OH)₂ is 74.09 g/mol.

36.0 g × 1 mol/74.09 g = 0.486 mol

Step 3: Calculate the volume of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

liters of solution = moles of solute / M

liters of solution = 0.486 mol / (0.530 mol/L) = 0.917 L

Answer:

0.917 liters

Hope this helps! :D

Explanation:

5.

(08.02 MC)

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed? (4 points)

Water pollution has severely impacted animals and plants in New York's Hudson

Answers

Yeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeet

difference between vegetative and reproductive part​

Answers

Answer:

The vegetative parts includes the roots, stems,leaves and the reproductive parts include flowers. ... The vegetative parts can reproduce new plants by the process of vegetative propagation but the reproductive parts cannot produce new plants directly instead they produce precursor of new plants that are seeds or fruits.

Quinine in a 1.664-g antimalarial tablet was dissolved in sufficient 0.10 M to give 500 mL of solution. A 15.00-mL aliquot was then diluted to 100.0 mL with the acid. The fluorescence intensity for the diluted sample at 347.5 nm provided a reading of 327 on an arbitrary scale. A standard 100 ppm quinine solution registered 180 when measured under conditions identical to those for the diluted sample. Calculate the mass of quinine in milligrams in the tablet.

Answers

Answer:

605.6mg of quinine

Explanation:

Based on Lambert-Beer's law, the intensity of an optical measurement is directely proportional to its concentration.

Unknown concentration gives a reading of 327

100 ppm gives 180 of intensity

The concentration of the diluted quinine tablet is:

327 * (100ppm / 180) = 181.67 ppm. The final dilution

The concentration of the first diluted solution is:

181.67 ppm * (100.0mL / 15mL) = 1211ppm

ppm could be defined as mass of solute (In this case of quinine) in mg per liter of solution. That is:

1211mg / L

As the tablet was diluted to 500mL = 0.5L, the mass of the quinine is:

0.5L * (1211mg / L) =

605.6mg of quinine

Help please I’ll mark as brainiliest

Answers

Answer:

         B             B

W      BW          BW        

W       BW          BW

Explanation:

Hope this helps

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