What are three things that need to be labeled when making a graph?​

Answer: The force does not change.

Explanation:

The force between two charges q₁ and q₂ is:

F = k*(q₁*q₂)/r^2

where:

k is a constant.

r is the distance between the charges.

Now, if we increase the charge of each particle two times, then the new charges will be: 2*q₁ and 2*q₂.

If we also increase the distance between the charges two times, the new distance will be 2*r

Then the new force between them is:

F = k*(2*q₁*2*q₂)/(2*r)^2 = k*(4*q₁*q₂)/(4*r^2) = (4/4)*k*(q₁*q₂)/r^2 = k*(q₁*q₂)/r^2

This is exactly the same as we had at the beginning, then we can conclude that if we increase each of the charges two times and the distance between the charges two times, the force between the charges does not change.

Answer:

1.25 m

Explanation:

This is the vertical height not the distance along the slope.

[tex]K=U\\\frac{1}{2}mv^{2} = mgh\\h = \frac{v^{2}}{2g}=\frac{25}{20}=1.25 m[/tex]

The height the car can reach if the the track starts to climb upwards is 1.2742 meters up.

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or its relation with its surrounding systems.

P.E. = mass × g × height

K.E. = 0.5 × mass × (velocity)²

Given that the toy car has a mass of 0.025 kg and is traveling on a horizontal track with a velocity of 5 m/s. Now, the car starts to climb up vertically, therefore, the kinetic energy will be converted to potential energy.

Kinetic Energy = Potential Energy

0.5 × mass × (velocity)² = mass × g × height

Cancel mass from both the sides,

0.5 × (velocity)² = g × height

0.5 × (5 m/s)² = 9.81 m/sec² × height

height = 1.2742 meters

Hence, the car will travel 1.2742 meters up.

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Answer:

1500000 Pa

Explanation:

The formula for pressure is force per unit area.

P=F/A where  F is force and A is area

Given that ;

F= mass * acceleration due to gravity

F= 60 * 9.81 = 588.6 = 589 N

A= area = 4cm² = 0.0004 m²

P= F/A = 589 / 0.0004

P= 1471500

P=1500000 Pa

Answer:

the velocity of the egg the instant before impact is 17.15 m/s.

Explanation:

Given;

mass of the egg, m = 80 g = 0.08 kg

height through which the egg was dropped, h = 15 m

The velocity of the egg before impact will be maximum, and the final velocity is given by the following kinematic equation;

v² = u² + 2gh

where;

u is the initial velocity of the egg = 0

v is the final velocity of the egg before impact

v² = 0 + 2 x 9.8 x 15

v² = 294

v = √294

v = 17.15 m/s

Therefore, the velocity of the egg the instant before impact is 17.15 m/s.

Doppler ultrasound would be most useful in detecting a blockage in a heart artery.

By monitoring the rate of change in pitch, a Doppler ultrasound may calculate how quickly blood flows (frequency). A sonographer with training in ultrasound imaging applies pressure to your skin with a tiny, hand-held instrument (transducer) roughly the size of a bar of soap across the area of your body being scanned, moving from one place to another as required.

As an alternative to more invasive treatments like angiography, which involves injecting dye into the blood arteries to make them visible on X-ray images, this test may be performed.

Your doctor may use a Doppler ultrasound to assess for artery damage or to keep track of specific vein and artery therapies.

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Answer:

The answer is below

Explanation:

a) Impulse is the total effect of force which has been acting on a body over a period of time. Impulse is the product of the force and the period of time applied. It is given by:

Impulse = force × time

Given that during 2 seconds, the impulse is 4 Ns, we can calculate the force applied.

Impulse = force × change in time

4 = force * 2

force = 4 / 2 = 2 N.

Hence the impulse applied during the following 3 seconds is:

Impulse = force × change in time = 2 * (2 + 3) = 2 * 5 = 10 Ns

The impulse applied during the following 3 seconds is 10 Ns not 6 Ns

b) In perfectly elastic collision, there is no loss in kinetic energy while in an inelastic collision there is loss in kinetic energy due to energy conversion or transfer.

In perfectly elastic collision the object does not stick together while in an inelastic collision the object stick together.

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

Answer:

a) the frequency of the wave is 0.2 Hz

b) the speed of the wave 4 m/s

Explanation:

Given that;

time period = to complete one cycle t = 5 sec

frequency f = 1/t

frequency f = 1 / 5sec

f = 0.2 Hz

Therefore the frequency of the wave is 0.2 Hz

b)

speed of wave V = λf

given that our wavelength is 20.0 m

we substitute

speed of wave V = 20.0 × 0.2

speed of wave V = 4 m/s

Therefore, the speed of the wave 4 m/s

Answer:

Explanation:

Note the charge balls on the top and bottom row are identical. So those charges cancel each other out. The only charges in the net electric field are the two in the middle row.

Electric field strength = k*Q/r^2

= (8.99 *10^9) * (3-(-3)) * 5*10^(-6) / (2*0.5)^2

= 269700 N/C

Answer:

Explanation:

(b) cuz the 1st n 3nd row cancel out, net electric field will go from +3Q to -3Q. the direction is right.

Answer:

45

Explanation:

Answer:

F = 5.17 N

Explanation:

       [tex]F =\sqrt{F_{1} ^{2} +F_{2} ^{2} + 2*F_{1} * F_{2} * cos \theta} (1)[/tex]

       [tex]F =\sqrt{2.81 N ^{2} +2.81 N ^{2} + 2*2.81N* 2.81N* cos 46} = 5.17 N (2)[/tex]

Answer:

a) [tex]v=1.102122995 \approx 1.10m/s[/tex]

b) [tex]x=0.0451m[/tex]

c) [tex]v_m=1.75m/s[/tex]

Explanation:

From the question we are told that

Mass of soft rubber[tex]M_r= 5.26g=>0.00526kg[/tex]

Spring compression [tex]d_C= 4.93 cm=>0.0493m[/tex]

Stiffness constant [tex]k= 7.90 N/m[/tex]

Ball Distance [tex]d=14.6=>0.146[/tex]

Frictional force [tex]f=0.0328 N[/tex]

a)Generally the equation for motion of the second ball according to Newton's law is given by

[tex]\frac{1}{2}kc^2-f\triangle x=\frac{1}{2} mv^2[/tex]

[tex]v=\sqrt{\frac{k*d_c^2-2f\triangle x}{m}}[/tex]

[tex]v=\sqrt{\frac{(7.90 )(0.0493)^2-2*(0.0328)(0.0493+0.146)}{0.00526}}[/tex]

[tex]v=1.102122995 \approx 1.10m/s[/tex]

b)Generally for speed to be at maximum spring force must equal frictional force

At distance

[tex]f=kc'[/tex]

[tex]d_c'=f/k[/tex]

[tex]d_c'=0.0328 /7.90[/tex]

[tex]d_c'=0.004151898734=>0.0042m[/tex]

Therefore

Ball is at maximum speed at

[tex]x=d_c-d_c'[/tex]

[tex]x=0.0493-0.0042[/tex]

[tex]x=0.0451m[/tex]

c)Generally maximum velocity is represented mathematically as

[tex]\frac{1}{2}kc^2-f\triangle x'=\frac{1}{2} mv'^2+\frac{1}{2}kc'^2[/tex]

[tex]\frac{1}{2} mv'^2 = \frac{1}{2}kc^2-f\triangle x'-\frac{1}{2}kc'^2\\[/tex]

[tex]v=\sqrt{\frac{k*d_c^2-2*f*x-kd_c'^2}{m}}[/tex]

[tex]v=\sqrt{\frac{7.90 *0.0493^2-2*(0.0328)*(0.0451)-7.90(0.0042)^2}{0.00526}}[/tex]

[tex]v=1.749685197m/s[/tex]

[tex]v_m=1.75m/s[/tex]

Answer:

A, B, D, and H

Explanation:

Statements A, B, D and H are all correct except the following:

Statement C is incorrect. The name of [tex] AlF_3 [/tex] is aluminium fluoride NOT "trialuminium fluoride".

Statement E is incorrect. The name of [tex] Li_2Se [/tex] is lithium selenide NOT "lithium selenate".

Statement F is incorrect. Dinitrigen monoxide, also known as nitrous oxide has a formula of [tex] N_2O [/tex] NOT [tex] NO_2 [/tex].

Statement G is incorrect. Sulfur trioxide formula is [tex] SO_3 [/tex].

Answer:

Number of revolutions = 20.71 rev.

Explanation:

Given the following data;

Initial speed, u = 0m/s

Final speed, v = 9.9m/s

Time, t = 11.4secs

Diameter = 86.9cm to meters = 86.9/100 = 0.869m

To find the acceleration;

Acceleration, a = (v - u)/t

Acceleration, a = (9.9 - 0)/11.4

Acceleration, a = 9.9/11.4

Acceleration, a = 0.87m/s²

Now we would find the distance covered by the tire using the second equation of motion.

S = ut + ½at²

S = 0(11.4) + ½*0.87*11.4²

S = 0 + 0.435*129.96

S = 56.53m

The circumference of the tire is calculated using the formula;

Circumference = 3.142 * diameter

Circumference = 3.142 * 0.869

Circumference = 2.73m

Number of revolutions = distance/circumference

Number of revolutions = 56.53/2.73

Number of revolutions = 20.71 rev.

Therefore, the number of revolutions the tire makes during this motion is 20.71 revolutions.

Answer:

1225kg

Explanation:

Given parameters:

Velocity of the car  = 20m/s

Momentum = 24500kgm/s

Unknown:

Mass of the car  = ?

Solution:

To solve this problem, we must understand that the momentum of a body is the quantity of motion that it possess.

So;

  Momentum  = mass x velocity

    Mass of the car  = [tex]\frac{Momentum }{velocity}[/tex]   = [tex]\frac{24500}{20}[/tex]   = 1225kg

Answer:

Explanation:

Where is the remaining part of the question? This is a very easy one

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).

Hope this helped

Answer:

a) The ideal speed = 16.21 m/s

b) Minimum co-efficient of friction = 0.216

Explanation:

From the given information:

The ideal speed can be determined by considering the centrifugal force component and the gravity component.

[tex]\dfrac{mv^2}{r}cos \theta = mg sin \theta[/tex]

[tex]v = \sqrt {gr \ tan \theta}[/tex]

[tex]= \sqrt{(9.8 \ m/s^2) (100) \ tan 15^0}[/tex]

= 16.21 m/s

(b)

Let assume that it requires 25 km/h to take the same curve.

Then, using the equilibrium conditions;

[tex]mg \ sin \theta = \dfrac{mv^2}{r} cos \theta + \mu ((\dfrac{mv^2}{r}) sin \theta + mg cos \theta)[/tex]

[tex]\mu = \dfrac{mg sin \theta - \dfrac{mv^2}{r} cos \theta }{((\dfrac{mv^2}{r}) sin \theta + mg cos \theta) }[/tex]

[tex]\mu = \dfrac{g sin \theta - \dfrac{ v^2}{r} cos \theta }{((\dfrac{v^2}{r}) sin \theta + g cos \theta) }[/tex]

[tex]\mu = \dfrac{(9.8 \ m/s^2 ) sin (15^0) - \dfrac{ \dfrac{(25 \times 10^3}{3600} \ m/s)^2 }{100 \ m } cos (15^0) }{((\dfrac{(\dfrac{25 \times 10^3}{3600} )^2}{100}) sin 15^0 + (9.8 \ m/s^2) cos 15^0 ) }[/tex]

[tex]\mathbf{\mu = 0.216}[/tex]

Answer:

the distance between the two point charges will be reduced by a factor of  [tex]\frac{1}{\sqrt{5} } = 0.447[/tex]

Explanation:

The force between two point charges is given by Coulomb's law;

[tex]F = \frac{kQ_1Q_2}{r^2}[/tex]

where;

k is Coulomb's constant

Q₁ and Q₂ are two point charges

r is the distance between the two charges

From the equation above, the following relationship between force and distance can be deduced;

F₁r₁² = F₂r₂²

F₁r₁² = (5F₁)r₂²

r₁² = 5r₂²

[tex]r_2^2 = \frac{r_1^2}{5} \\\\r_2 = \sqrt{\frac{r_1^2}{5}} \\\\r_2 = \frac{r_1}{\sqrt{5} } \\\\r_2 = \frac{1}{\sqrt{5} } \ r_1\\\\r_2 = 0.447( r_1)[/tex]

Thus, the distance between the two point charges will be reduced by a factor of  [tex]\frac{1}{\sqrt{5} } = 0.447[/tex]

To increase the force between two point charges by a factor of 5, you have to change the distance between them by a factor of 0.447.

Coulomb law states that the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the distance between them. It is given by:

F = kq₁q₂/r²

q₁, q₂ are charges, k is a constant and r is the distance between them.

Let us assume that:

F = kq₁q₂/r²

[tex]r=\sqrt{\frac{kq_1q_2}{F} }[/tex]

To increase the force by a factor of 5:

[tex]r=\sqrt{\frac{kq_1q_2}{5F} }\\\\r=0.447 \sqrt{\frac{kq_1q_2}{F} }[/tex]

Hence to increase the force between two point charges by a factor of 5, you have to change the distance between them by a factor of 0.447.

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The work done by the force of 50 N for a displacement of 10000 m is 500000 J. Then the power is 250 × 10⁷ W.

Work done in physics is the product of force and displacement of an object. If a force applied on an object results in a displacement the force is said to be done some work on the object.

Work done W = F.ds

Given F = 50 N

displacement = 10000 m

Then w = 50 N × 10000 m = 500000 J

Power is the rate of energy or work needed to bring a displacement in an object. It is the product of work done and time.

w = 500000 J

time = 500 s

then power = w. t

p = 500000 J × 500 s = 250 × 10⁷ W

Therefore, the power of the action is 250 × 10⁷ W.

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Answer:

The steam gives what is known as the LATENT HEAT OF VAPORIZATION TO THE ROOM

Explanation:

The term known as " latent heat if vaporization" deals with changes in a specific phase of matter to another one, that is from liquid to vapor. It can be defined as the quantity or the amount of heat required to change the liquid into vapor.

Therefore, when the system send the steam into radiators in each room of the house the steam gives what is known as the LATENT HEAT OF VAPORIZATION TO THE ROOM.

The steam which Is first of all condensed In order to produce the latent heat of vaporization is then sent back into the system and then comes out again to repeat the process in the paragraph above.

Answer:

The carbon dioxide levels have increased due to burning fossil fuels

Explanation:

Correct on edge 2021 hope this helps!✌️

The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.

Global warming is defined as the phenomenon of heating up of the earth's surface in a long term due to the increased amount of emission of green house gases in the earth's atmosphere.

Here,

When more fossil fuels and the materials like coal are burned for the purpose of energy production, it will result to the production of an increased amount of carbon dioxide. This leads to the emission of huge amount of carbon dioxide in the earth's atmosphere. Since, carbon dioxide is a green house gas, the release of higher amount of carbon dioxide will lead to an increased concentration of green house gases. This causes an increase in the temperature of the atmosphere, resulting in the increased heating of the surface of earth. This uneven heating up of  earth's surface is called global warming. This is the result of higher release of carbon dioxide in the earth's atmosphere.

Hence,

The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.

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I'm going to assume that, judging by the fact that the coefficient of friction and angle of the incline seem to be intentionally left out, the point A refers to a point at the bottom of the incline, and the point B is located 19 m away from A on a horizontal surface. If this is not the case, please be sure to correct me!

Let v denote the speed of the box at point A, x the distance the box slides (without friction) down the incline, and θ the angle of the incline.

Recall that

v ² - v₀² = 2 a ∆x

where

v = final speed

v₀ = initial speed

a = acceleration

∆x = displacement

While on the incline, the box starts at rest (v₀ = 0) and slides a distance x from the starting point to point A with acceleration a to attain some speed v.

Use the free body diagram to determine the acceleration. By Newton's second law, the net force on the object acting parallel to the incline

∑ F = m g sin(θ) = m a   →   a = g sin(θ)

where m = 9.0 kg and g = 9.8 m/s².

Write the distance x in terms of θ with some trigonometry:

sin(θ) = (5.0 m) / x   →   x = (5.0 m) / sin(θ)

Now plug a and x into the formula above to solve for v :

v ² = 2 g sin(θ) ((5.0 m) / sin(θ))

v ² = (10.0 m) g

v ≈ 9.9 m/s

Answer:

1.06 h

Explanation:

Assuming that the airplane is traveling through the air, moving at a sites relative to the ground. The airplane is expected to make a displacement of 675 km due North.

Let north y be positive, and west x also be positive, then

With the wind blowing at 33 km/h due South. We then say,

The northern component of the velocity of the airplane you the ground is

669 km/h - 33 km/h = 636 km/h

Then, the time interval taken by the airplane to travel 675 km is

675 / 636 = 1.06 h

Therefore, we can conclude that the answer is 1.06 h

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

The correct expression for the number of hours it takes Planet B to complete one revolution around the star is [tex]\frac{T}{\sqrt{8} }[/tex].

The given parameters;

From Kepler's law, the period of planet is related to radius as follows;

[tex]\frac{T_1^2}{R_1^3} = \frac{T_2^2}{R_2^3} \\\\T_2 ^2 = \frac{T_1^2 \times R_2^3}{R_1^3} \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} } \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} }\\\\T_2 = T_1 \sqrt{\frac{ R_2^3}{(2R_2)^3} }\\\\T_2 = T_1 \sqrt{\frac{R_2^3}{8R_2^3} } \\\\T_2 = T_1 \sqrt{\frac{1}{8} } \\\\T_2 = \frac{T_1}{\sqrt{8} }\\\\T_B = \frac{T_A}{\sqrt{8} } = \frac{T}{\sqrt{8} }[/tex]

Thus, the correct expression for the number of hours it takes Planet B to complete one revolution around the star is [tex]\frac{T}{\sqrt{8} }[/tex].

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Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

[tex]P=F/A[/tex]

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

[tex]A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }[/tex]

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

[tex]w = m*g[/tex]

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]w = 60*9.81\\w = 588.6[N][/tex]

And the pressure:

[tex]P=588.6/0.0004\\P=1471500 [Pa][/tex]

Because 1 [Pa] = 1 [N/m²]

Answer:

the acceleration of the girl is 8 m/s² in opposite direction.

Explanation:

Given;

mass of the girl, m₁ = 30kg

mass of the boy, m₂ = 40 kg

acceleration of the boy, a₂ = 6 m/s²

let acceleration of the girl = a₁

Apply Newton's third law of motion;

the force exerted by the girl is equal  in magnitude  to the force exerted by the boy but in opposite direction.

F₁ = -F₂

m₁a₁ = -m₂a₂

30a₁ = -(40 x 6)

30a₁ = -240

a₁ = -240 / 30

a₁ = -8 m/s² (the negative sign shows that the acceleration is in opposite direction)

Thus, the acceleration of the girl is 8 m/s² in opposite direction.

Recall the equation for Kinetic Energy: = m

Knowing this, we know that there are only two factors that can alter Kinetic Energy: mass and velocity. Looking at the equation, we can deduce that an increase in either mass or velocity would increase the overall Kinetic Energy as long as everything else stays constant.

a) He can let Ivan off at the next stop - Wrong. By letting Ivan off, mass decreases. Assuming Paul maintains the same speed as before, Kinetic Energy decreases.

b) He can pedal harder to increase the speed to 10 meters per second - Correct. By speeding up, "v" increases and the overall Kinetic Energy increases.

c) He could reduce the speed to 3 meters per second - Wrong. Looking at the equation, we know reducing speed would reduce Kinetic Energy

d) He can pick up a third rider - Correct, assuming they keep the same speed after picking up the third rider: if mass increases and velocity stays the same, then Kinetic Energy will increase.

Answers - B, D

If there's anything you don't understand here, just let me know :)