A dwari planet is a:

small rocky object that orbits the Sun and is usualy found in a bet beiween me orbits of Mars and Jupiter.

small object made of ice and dust thai orbits the Sun and forms a coma as i approaches the Sun.

round object that orbits the Sun but lacks the abity to clear the neghborhood around is orbit.

meteoroid thai bums up in Earth's amosphere, producing a streak of light.​

Answers

Answer 1

Answer:

round object that orbits the Sun but lacks the ability to clear the neighborhood around is orbit.

Explanation:

It is true that a dwarf planet is a round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit.

Due to the size of a dwarf planet, it does not possess enough gravitational attraction or force to clear the orbit around it or other bodies.

One of the notable dwarf planets is Pluto. It was formerly thought to be planet but it has since been delisted.

Pluto's orbit lies beyond that of Neptune.


Related Questions

What is the wavelength of a wave that has a speed of 350 meters second and a frequency of 140 hert??

Answers

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).

Hope this helped

A Discuss the possibility of fracture of two leg bones that have a length of about 70cm and an average area of

about 4cm

2 when a 80kg person jump from a height of 300cm.

Noting: The breaking stress of the bone ϬB =1.5×108 N/m2 , and

Young’s modulus for the bone is Y=1.5×1010 N/m2

Answers

Answer: The bones won't fracture.

Explanation: Stress, in Physics, is a quantity describing forces that can cause deformation. Strain is the measure of how muc an object can be stretched or deformed. The ratio between stress and strain is called Young's modulus or elastic modulus

Breaking Stress of Bone is the maximum stress a bone can take before a rupture occur.

To determine if a person will break his/her bones by jumping from a height, we determine the energy necessary for that jump and compare it with the energy necessary to break a bone.

The energy for breaking a bone is calculated as

[tex]E=\frac{Al_{0}\sigma_{B}^{2}}{2Y}[/tex]

A is the area in m²

l₀ is length in m

[tex]\sigma_{B}[/tex] is breaking stress in N/m²

Y is Young's modulus in N/m²

Calculating energy to break a bone:

[tex]E=\frac{4.10^{-4}.7.10^{-1}.(1.5.10^{8})^{2}}{2.(1.5.10^{10})}[/tex]

[tex]E=210[/tex] J

This is the energy necessary to break one leg bone, so as there are 2, energy will be 420 Joules.

Potential energy gained by jumping is calculated as

E = m.g.h

m is mass in kg

g is acceleration due to gravity in m/s²

h is height in m

Calculating

E = 80.(9.8)(0.3)

E = 235.2 J

Comparing the two energies, potential energy for jumping is less than maximum energy a bone can absorve without breaking, so the leg bones won't suffer a fracture.

A car with mass 1141 kg, moving at 16 m/s, strikes a(n) 2916 kg car at rest. If the two cars stick together, with what speed do they move

Answers

Answer:

V = 4.49 m/s

Explanation:

Given that,

Mass of the car 1, m₁ = 1141 kg

Initial speed of car 1, u₁ = 16 m/s

Mass of car 2, m₂ = 2916 kg

Initial speed of car 2, u₂ = 0

We need to find the speed of the cars if they stick together. Let the speed be V. The momentum will remain conserved in the process. Using the conservation of momentum to find it.

m₁u₁ + m₂u₂ = (m₁+m₂)V

[tex]V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\=\dfrac{1141\times 16+2916 \times 0}{(1141 +2916 )}\\\\=4.49\ m/s[/tex]

So, the required speed of the two cars is 4.49 m/s.

In which three ways does the pattern seen on the screen during a double-slit
experiment support the wave model of light?
O A. All of the light that enters the slits passes through them.
B. The light bends around the edges of the slit.
C. There are bands of dimmer light.
D. There are bands of brighter light.

Answers

Answer:

b,c,d

Explanation:

the light bends around the edges of the slit

there are bands of brigter light

there are bands of dimmer light

( just took the quiz )

Option B,C and D shows the three ways does the pattern seen on the screen during a double-slit experiment.

What is double-slit experiment?

The double-slit experiment shows that light and matter may have properties that are both conventionally defined waves and particles, as well as the essentially probabilistic nature of quantum mechanical processes.

The three ways does the pattern seen on the screen during a double-slit experiment support the wave model of light;

B. The light bends around the edges of the slit.

C. There are bands of dimmer light.

D. There are bands of brighter light.

Hence, B,C and D are the three ways does the pattern seen on the screen during a double-slit experiment.

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You want to build a snowman, so you accelerate a 2kg snowball across your yard at a rate of 0.5m/s2. Calculate the amount of force you applied to your friend.

Answers

Answer:

4

Units:

Newtons

a car traveled at 100 km h for 3 hours how far did it travel

100 km

300 km/h

300 km

3 km/h

Answers

Answer:

300km

Explanation:

Given parameters:

Speed of the car  = 100km/h

Time taken for the travel  = 3hrs

Unknown:

How far did it travel  = ?

Solution:

To solve this problem, we must understand that;

        Speed  = [tex]\frac{distance}{time}[/tex]  

 Distance  = speed x time

 Distance  = 100km/hr x 3hr = 300km

Exercise 3 In an equation y mx+c; y and x have dimensions of length and c is constant. What are the dimensions of m'
A. Mass
B. Length
C. Time
D. m is Dimensionless

Answers

Answer:

D. m is Dimensionless

Explanation:

The equation of a straight line is given as:

        y  = mx + c

Dimension of y = l

                       x = l

                       c has no dimension

 So;

if we do a dimensional analysis:

            L  = m L + 0

              m  = 1

So, m has no dimension

Which statements correctly describe the formula or name of a compound? Select all that apply.
OA. The formula of nitrogen trifluoride is NF 3
B. The formula of ammonia is NH3.
C. The name of AlF, is trialuminum fluoride.
D. The formula of calcium chloride is CaCl2
E. The name of Li, Se is lithium selenate.
OF. The formula of dinitrogen monoxide is NO
2
Results
G. The formula of sulfur trioxide is 30.
Cho
Аа
H. The formula of magnesium hydroxide is Mg(OH)2
G.

Answers

Answer:

A, B, D, and H

Explanation:

Statements A, B, D and H are all correct except the following:

Statement C is incorrect. The name of [tex] AlF_3 [/tex] is aluminium fluoride NOT "trialuminium fluoride".

Statement E is incorrect. The name of [tex] Li_2Se [/tex] is lithium selenide NOT "lithium selenate".

Statement F is incorrect. Dinitrigen monoxide, also known as nitrous oxide has a formula of [tex] N_2O [/tex] NOT [tex] NO_2 [/tex].

Statement G is incorrect. Sulfur trioxide formula is [tex] SO_3 [/tex].

A 5kg box is sliding down a ramp with a rough surface as seen below. The height of the ramp is 20m and the distance the box travels down the ramp (from A to B) is 15m. At point A the velocity of the box is 8 m/s. If the velocity at point B is 3m/s, what was the impulse caused by friction? If the force of friction is 5N, how long did it take the box to slide the 15 m?

Answers

Answer:

A Impulse = – 25 Ns

B. Time = 5 s

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

Time (t) =?

A. Determination of the Impulse.

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

I = Ft = M(v – u)

I = M(v – u)

I = 5 (3 – 8)

I = 5 × – 5

I = – 25 Ns

NOTE: the negative sign indicates that the net force is acting in the negative direction.

B. Determination of the time.

Impulse (I) = 25 Ns

Force (F) = 5 N

Time (t) =?

I = Ft

25 = 5 × t

Divide both side by 5

t = 25 / 5

t = 5 s

Thus, it will take 5 s for the box to slide through the 15 m long ramp.

A car accelerates uniformly from rest and reaches a speed of 9.9 m/s in 11.4 s. The diameter of a tire is 86.9 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev.

Answers

Answer:

Number of revolutions = 20.71 rev.

Explanation:

Given the following data;

Initial speed, u = 0m/s

Final speed, v = 9.9m/s

Time, t = 11.4secs

Diameter = 86.9cm to meters = 86.9/100 = 0.869m

To find the acceleration;

Acceleration, a = (v - u)/t

Acceleration, a = (9.9 - 0)/11.4

Acceleration, a = 9.9/11.4

Acceleration, a = 0.87m/s²

Now we would find the distance covered by the tire using the second equation of motion.

S = ut + ½at²

S = 0(11.4) + ½*0.87*11.4²

S = 0 + 0.435*129.96

S = 56.53m

The circumference of the tire is calculated using the formula;

Circumference = 3.142 * diameter

Circumference = 3.142 * 0.869

Circumference = 2.73m

Number of revolutions = distance/circumference

Number of revolutions = 56.53/2.73

Number of revolutions = 20.71 rev.

Therefore, the number of revolutions the tire makes during this motion is 20.71 revolutions.

A toy car, mass of 0.025 kg, is traveling on a horizontal track with a velocity of 5 m/s. If
the track then starts to climb upwards, how high up the track can the car reach?

Answers

Answer:

1.25 m

Explanation:

This is the vertical height not the distance along the slope.

[tex]K=U\\\frac{1}{2}mv^{2} = mgh\\h = \frac{v^{2}}{2g}=\frac{25}{20}=1.25 m[/tex]

The height the car can reach if the the track starts to climb upwards is 1.2742 meters up.

What is kinetic and potential energy?

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or its relation with its surrounding systems.

P.E. = mass × g × height

K.E. = 0.5 × mass × (velocity)²

Given that the toy car has a mass of 0.025 kg and is traveling on a horizontal track with a velocity of 5 m/s. Now, the car starts to climb up vertically, therefore, the kinetic energy will be converted to potential energy.

Kinetic Energy = Potential Energy

0.5 × mass × (velocity)² = mass × g × height

Cancel mass from both the sides,

0.5 × (velocity)² = g × height

0.5 × (5 m/s)² = 9.81 m/sec² × height

height = 1.2742 meters

Hence, the car will travel 1.2742 meters up.

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A 5kg box is sliding down a ramp with a rough surface as seen below. The height of the ramp is 20m and the distance the box travels down the ramp (from A to B) is 15m. At point A the velocity of the box is 8 m/s. If the velocity at point B is 3m/s, what was the impulse caused by friction? If the force of friction is 5N, how long did it take the box to slide the 15 m?

Answers

Answer:

the answer is b luv .

Explanation:

Two force vectors are oriented such that the angle between their directions is 46 degrees and they have the same magnitude. If their magnitudes are 2.81 newtons, then what is the magnitude of their sum

Answers

Answer:

F = 5.17 N

Explanation:

If we know the magnitudes of both vectors, and the angle between them, we can find the magnitude of their sum, applying the cosine theorem, as follows:

       [tex]F =\sqrt{F_{1} ^{2} +F_{2} ^{2} + 2*F_{1} * F_{2} * cos \theta} (1)[/tex]

Replacing by the givens, F₁ = F₂ = 2.81 N, θ = 46º, we get:

       [tex]F =\sqrt{2.81 N ^{2} +2.81 N ^{2} + 2*2.81N* 2.81N* cos 46} = 5.17 N (2)[/tex]

A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.

Answers

Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

[tex]P=F/A[/tex]

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

[tex]A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }[/tex]

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

[tex]w = m*g[/tex]

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]w = 60*9.81\\w = 588.6[N][/tex]

And the pressure:

[tex]P=588.6/0.0004\\P=1471500 [Pa][/tex]

Because 1 [Pa] = 1 [N/m²]

You have to deliver some 5.0-kg packages from your home to two locations. You drive for 2.0 h at 30 mi/h due east (call this segment 1 of your trip), then turn around and drive due west for 30 min at 28 mi/h (segment 2). Use a coordinate system with the positive x axis aimed toward the east and the origin at your home.
A. What is your position vector at the instant you reach the end of segment 1?
B. What is your position vector at the instant you reach the end of segment 2?
C. Calculate your displacement during segment 2.

Answers

Answer:

A. 60 mi.

B. 46 mi.

C. -14 mi.

Explanation:

A)

Assuming that we use a coordinate system with the positive x-axis aimed toward the east, and the origin at the start point, we can find the position vector at the end of the segment 1, applying the definition of average velocity, as follows:

       [tex]v_{avg1} = \frac{x_{1f} -x_{1o}}{t} (1)[/tex]

where x₁f = final position at the end of segment 1, x₁₀ = initial position at the start of the segment 1 = 0, t = time traveled during segment 1 = 2.0 h, and v₁, average velocity during segment 1 = 30 mi/h due east.Replacing by the givens, and solving for x₁f, we get:

        [tex]x_{1f} = v_{1avg} * t =30 mi/h * 2.0 h = 60 mi due east. (2)[/tex]

B)

In order to find the position at the end of the segment 2, we can use the same equation (1), but taking into account that the initial position will not be zero, but the final position at the end of the segment 1, i.e., 60 mi due east.Replacing by the givens, and solving for x₂f, we get:

       [tex]x_{2f} = x_{1f} + v_{2avg} * t = (-28 mi/h) * 0.5 h = 60 mi - 14 mi = 46 mi (3)[/tex]

C)  

The displacement during the segment two, is simply the difference between the final and initial positions for this segment.Since x₂₀= x₁f = 60 mi, and x₂f = 46 mi, we find that the displacement is as follows:Δx = x₂f - x₂₀ = 46 mi - 60 mi = - 14 mi.

Padded dashboards in cars are safer in an accident than nonpadded ones because an occupant hitting the dash has:________.
(a) increased time of impact.
(b) decreased impulse.
(c) decreased impact force.
(d) a and b above.
(e) a and c above.

Answers

Answer:

(e) a and c above.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = Mass * Velocity [/tex]

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

Padded dashboards in cars are safer in an accident than non-padded ones because an occupant hitting the dashboard of an automobile car has an increased time of impact and a decreased impact force because the force or shock experienced is high and happens rapidly over a short period of time, thus, the occupant has less time and velocity while absorbing the momentum of the car in the course of the collision.

Two charged particles attract each other with a force of magnitude F. If the distance between the charges is made 3.5 times as large and the charge on one of the particles is made 4 times as big, what is the ratio of the new F to the old one

Answers

Answer:

The ratio between the forces is:

[tex]\frac{F_{new}}{F_{old}}=0.33[/tex]

Explanation:

The electrostatic force equation is:

[tex]F_{old}=k\frac{q_{1}q_{2}}{d^{2}}[/tex]

Where:

q1 and q2 are the electric charges

d is the distance between them

k is the electrostatic constant

Now, the distance is 3.5 times as large and q1 is 4 times as big, then the new force will be:

[tex]F_{new}=k\frac{4q_{1}q_{2}}{(3.5d)^{2}}[/tex]

[tex]F_{new}=\frac{4}{3.5^{2}}k\frac{q_{1}q_{2}}{d^{2}}[/tex]

We can rewrite this equation in terms of F(old)

[tex]F_{new}=\frac{4}{3.5^{2}}F_{old}[/tex]

Therefore, the ratio between the forces is:

[tex]\frac{F_{new}}{F_{old}}=\frac{4}{3.5^{2}}[/tex]

[tex]\frac{F_{new}}{F_{old}}=0.33[/tex]

I hope it helps you!

A dog sees a flowerpot sail up and then back past a window H high. If the total time the pot is in sight is t seconds, find the height above the window that the pot rises. (Let H = 2 m and t = 1.0 s, find the height above the window-- after you have found an algebraic solution.)

Answers

Answer:

maximum height = 0.1225 m

Explanation:

given data

H = 2m

t = 1 sec

solution

we consider here velocity of pot at lower side is u

and final velocity is v with acceleration a

time take is t/2

so

height h = u × [tex]\frac{t}{2}[/tex]  - 0.5 × g × [tex](\frac{t}{2})^2[/tex]     .................1

here

u = [tex]\frac{2}{t} \times ( h + \frac{gt^2}{8} )[/tex]

and

v = u +a t/2      .........................2

v = u + g t/2

v = [tex]\frac{2h}{t} + \frac{gt}{4} - \frac{gt}{2}[/tex]

v = [tex]\frac{2h}{t} - \frac{gt}{4}[/tex]

so that

maximum height is  = [tex]\frac{v^2}{2g}[/tex]

maximum height = [tex]\frac{(\frac{2h}{t} - \frac{gt}{4})^2}{2g}[/tex]

put here value of h and t

maximum height =  [tex]\frac{(\frac{2(2)}{1} - \frac{g(1)}{4})^2}{2g}[/tex]

maximum height = 0.1225 m

The velocity of a Froghopper flea, which is represented by a vector, has a direction and a magnitude. If a coordinate system is oriented where the x-axis is horizontal, and the y-axis is vertical, is it possible to write expressions for the x and y components of the velocity vector in terms of the vector's magnitude and direction.

Answers

Answer:

Explanation:

The solution of the question cab e found in attachment below:

PLEASE ANSWER-Why are loose electrons needed for heat conduction?

Answers

Answer:

Why do metals conduct heat so well? The electrons in metal are delocalised electrons and are free moving electrons so when they gain energy (heat) they vibrate more quickly and can move around, this means that they can pass on the energy more quickly.

g A box of mass 10 kg attached to a spring is pulled to a maximum of 44 cm. The box is released. What is the speed when the box reaches a point 10 cm from the equilibrium position

Answers

Answer:

The speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

Explanation:

Mass attached to the spring, m = 10 kg

maximum displacement of the spring, A = 0.44 m

The spring constant is calculated from Hook's law;

F = kx

mg = kx

k = (mg) / x

k = (10 x 9.8) / 0.44

k = 222.73 N/m

The angular speed of the spring is calculated as;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega =\sqrt{\frac{222.73}{10} } \\\\\omega = 4.72 \ rad/s[/tex]

The speed when the box reaches a point 10 cm from the equilibrium position is calculated as;

[tex]v = \omega \sqrt{A^2-x^2} \\\\v = 4.72\sqrt{0.44^2-0.1^2}\\\\v = 2.02 \ m/s[/tex]

Therefore, the speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

3.
A person drives north 6 blocks, then drives west 6 blocks.
The displacement is a straight line from the starting point to the finish in a
direction
O A northwesterly
O B southwesterly
O c northeasterly
OD southeasterly

Answers

The answer is c northeasterly because it goes through the middle of those two

An athlete runs on track at a constant speed of 75 meters/min for 15 s. What is the total distance he covered during that time?

Answers

Answer:

45

Explanation:

A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fast!!!)

Answers

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

For which medical procedure would Doppler ultrasound be most useful?

A.
Finding a lung tumor
B.
Fixing a pulled muscle
C.
Locating a broken bone in a finger
D.
Detecting a blockage in a heart artery

Answers

The answer is d.

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Doppler ultrasound would be most useful in detecting a blockage in a heart artery.

What are the clinical uses of Doppler ultrasound?

By monitoring the rate of change in pitch, a Doppler ultrasound may calculate how quickly blood flows (frequency). A sonographer with training in ultrasound imaging applies pressure to your skin with a tiny, hand-held instrument (transducer) roughly the size of a bar of soap across the area of your body being scanned, moving from one place to another as required.

As an alternative to more invasive treatments like angiography, which involves injecting dye into the blood arteries to make them visible on X-ray images, this test may be performed.

Your doctor may use a Doppler ultrasound to assess for artery damage or to keep track of specific vein and artery therapies.

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The Earth (geosphere) comprises several major layers, differing in chemical and mineral composition, material strength, and other physical properties. Which of the layers listed below constitutes the largest proportion of Earth's volume?
a) Lithosphere
b) Crust
c) Outer core ·
d) Inner core
e) Mantle

Answers

Answer:

Option E:

The mantle

Explanation:

The earth's mantle is the mushy, semi-solid portion of the earth that makes up most of the earth's volume. The mantle extends for a depth of about 2800km downwards into the earth, making it the largest internal portion of the earth.  It makes up about 84 percent of the earth's structure, leaving the core and the crust with 15 percent and 1 percent respectively.

Due its nature, convection currents are set up predominantly in the mantle of the earth, which leads to movements in the upper layers of the earth (the crust).

The mantle is large enough for the lighter crust to float on its surface.

100 POINTS. PLEASE EXPLAIN

Answers

Answer:

Explanation:

Note the charge balls on the top and bottom row are identical. So those charges cancel each other out. The only charges in the net electric field are the two in the middle row.

Electric field strength = k*Q/r^2

= (8.99 *10^9) * (3-(-3)) * 5*10^(-6) / (2*0.5)^2

= 269700 N/C

Answer:

Explanation:

(b) cuz the 1st n 3nd row cancel out, net electric field will go from +3Q to -3Q. the direction is right.

A child is twirling a 0.0113-kg ball on a string in a horizontal circle whose radius is 0.147 m. The ball travels once around the circle in 0.388 s. (a) Determine the centripetal force acting on the ball. (b) If the speed is doubled, by what factor does the centripetal force increase

Answers

Answer:

0.435 N

The centripetal force increases by a factor of 4

Explanation:

Let the centripetal force be F

F =mv^2/r

m= mass of the object

v = linear velocity of the object

r = radius of the circular path

but v = 2πr/T = 2 * 3.142 * 0.147 / 0.388

v = 2.38 m/s

F = 0.0113 * (2.38)^2/0.147

F= 0.435 N

if v= 2v

Then;

F = m(2v)^2/r

F = m4v^2/r

F= 4mv^2/r

The centripetal force increases by a factor of 4

A jumbo egg (80 grams) is dropped from a height of 15 meters onto a 1 inch of foam. Using kinematics, determine the velocity of the egg the instant before impact.

Answers

Answer:

the velocity of the egg the instant before impact is 17.15 m/s.

Explanation:

Given;

mass of the egg, m = 80 g = 0.08 kg

height through which the egg was dropped, h = 15 m

The velocity of the egg before impact will be maximum, and the final velocity is given by the following kinematic equation;

v² = u² + 2gh

where;

u is the initial velocity of the egg = 0

v is the final velocity of the egg before impact

v² = 0 + 2 x 9.8 x 15

v² = 294

v = √294

v = 17.15 m/s

Therefore, the velocity of the egg the instant before impact is 17.15 m/s.

Two charges q1 and q2 are separated by a distance r and apply a force F to each other. If both charges are doubled, and the distance between them is halved, the new force between them is

Answers

Answer:

The new force between them is increased by a factor of 16.

Explanation:

According to Coulombs law, the force of attraction between two (2) charges is given by the formula;

F = Kq1q2/r²

Given the following data;

q1 = 2q1

q2 = 2q2

r = r/2

Substituting into the equation, we have;

F = 2q1*2q2/(r/2)²

F = 4q1q2/r²/4

F = 4q1q2 * 4/r²

F = 16q1q2/r²

Therefore, the new force between them is increased by a factor of 16.

Other Questions
I would appretate it if somebody would correct theses sentences PLZ !1. "The image that I get when I think of Jay is when I think of him as a small child, when he could rattle off the names of nearly every species of whale known to man. (Context: A grandfather describes his grandson.)"2. Only then did I realize how annoyed a cat must have got when it couldnt catch the mouse, and eventually how happy a cat can get when the mouse dies without it trying. (Context: A mouse dies from fright under a couch while a mom, her son, and their cat try to coax it to come out.) plz some body correct the 2 sentences PLZ and TY! Write an equation of a line with slope -3/2 and x-intercept (4,0) Read the sentence.Jada was completely fearless. She jumped over eachhurdle without worry.Based on the context clue in the sentence, what is thebest definition of the word fearless?O daringO tiredO worriedaloneMark this and returnSave and ExitSub Tipu Sultan, The tiger of mysore, was a symbol of resistance for the british in the subcontinent. Explain why? Ethan was able to save 220.00 in 5 days, spending only 25.50 of the allowance given him daily. How much allowance is he given a day? The unit price of a shirt is $12. The cost, c, of n shirts is represented by the equation c = 12n. Select the value that belongs in the highlighted box.$2$3$18$48$60$72 (8, -1) and slope m= -3 for slope intercept What is the relationship between Reeve and the audience? How were the actions of the Little Rock 9 important in the fight for equality (in your answer make sure you explain what might have happened if the Little Rock 9 had not volunteered to do what they did)? A. 28.26cmB. 37.68cmC. 18.84cmD. 56.52cm The farmer down the street has an orchard with both orange and grapefruit trees. Over the weekend, she collected 49 oranges and 84 grapefruits. She wanted to make baskets to sell at the local farmer's market with an equal number of oranges and grapefruits in each basket. What is the greatest number of baskets she can make. Number of baskets she can make with an equal number of fruits in each basket? Number of oranges in each basket? Number of grapefruits in each basket? HELP PLEASE ILL GIEV CORRECT ANSWER BRAINLY! Noah and his dad went out to lunch thier meal cost $34.56 Noah dad left a 15% tip on the table what is the amount of the tip he left for the meal what is the amount of lunch including tip What is the volume of the rectangular prism Science: Write a letter of appreciation for your mother who take of you in her womb for nine months Which statement best supports the fact that earlyhumans needed to migrate from place to placefrequently? and no boxes were removed, all the boxes in the warehouse were arranged in stacks of 14 boxes each, with no boxes left over. How many boxes were in the warehouse before the 60 additional boxes arrived Anna recently moved to Boston in order for her husband Joe to begin a new job as an economics professor at Harvard. Anna is an experienced surgeon who is currently interviewing with several different hospitals in Boston. Anna is currently: * 10 points A. seasonally unemployed. B. structurally unemployed. C. cyclically unemployed. D. counted as employed since she is likely to receive a job offer soon. E. frictionally unemployed. Find the slope 1. (4,7) (-2,-5)2. (-10,8) (-5,4)3. (1,2) (3,9) What system uses letters of the alphabet and Arabic numeralsto provide different classification possibilities? ASAP please