Answer:
The electric force acting at a distance can be observed when someone rubs a glass rod with something woolen then the rod is taken away from the woolen material. The piece of paper leaps into air and sticks on to the rod. This is due to the electrostatic force of attraction that the paper sticks on the glass rod.
Explanation:
Answer:
Pam rubs a glass rod with wool, then moves the rod over a pile of small paper scraps. The scraps leap into the air and stick to the rod.
Assign oxidation numbers to the element in each of the following compounds. Remember an oxidation number is for one atom of the element.
a. HgO
b. Al4C3
c. CrF2
d. Fe2S3
Answer:
a. x = + 2
b. x = + 3
c. x = + 2
d. x = + 3
Explanation:
The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.
a.
HgO
The oxidation number of Hg in HgO is:
x + (-2) = 0
x = +2
b.
Al₄C₃
The oxidation number of Al in Al₄C₃ is:
4x +(3 × -4) = 0
4x - 12 = 0
4x = +12
x = 12/4
x = +3
c. CrF₂
x + ( 2 × - 1) = 0
x - 2 = 0
x = + 2
d. Fe₂S₃
2x + ( 3 × - 2) = 0
2x + (-6) = 0
2x = 6
x = 6/2
x = +3
Decide whether the compound is ionic or molecular, if you can.
Compound is a soft waxy white solid that can be easily shaped and molded by hand. When the flame of an ordinary laboratory burner is held about away from the solid, it rapidly and extensively melts into a clear liquid.
Answer:
Molecular solid
Explanation:
Molecular solids have a very low melting point. This is because, they are composed of weak intermolecular forces hence the layers of the solid easily fall apart as the solid melts.
We can see here that the solid being considered melts easily. Hence we can conclude that it is actually a molecular solid.
Can anybody answer this question of chemistry?
Answer:
Answer:A
Answer:AExplanation:
Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol
= 180g/molNumber of moles of Glucose = Mass/Molar Mass
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55
Answer:
Answer:A
Answer:AExplanation:
Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol
= 180g/molNumber of moles of Glucose = Mass/Molar Mass
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55
Which constants would most likely be filled in the first row of the table?
O temperature and moles of gas
O volume and temperature
O
pressure and volume
pressure and moles of gas
Answer:
A
Explanation:
Correct on edge
The temperature and moles of gas constants would most likely be filled in the first row of the table. Therefore, option A is correct.
What is gas constant ?The gas constant, denoted by R, is a physical constant that is expressed in terms of units of energy per temperature increment per mole. It's also referred to as the ideal gas constant, the molar gas constant, or the universal gas constant.
A general constant in the equation of state of gases that is equal to the product of the pressure and volume of one mole divided by the absolute temperature in the case of an ideal gas see gas law sense c.
All gases adapt an equation of state known as the ideal gas law: PV = nRT, where n is the number of moles of the gas and R is the universal gas constant.
Thus, option A is correct.
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Your question is incomplete, most probably your question was
The incomplete table below shows selected characteristics of gas laws.
Name
Variables
Constants
Equation
?
?
?
PV = k
Charles's law
?
?
V = kT
?
Temperature, pressure
?
P = kT
Combined gas law
Pressure, temperature, volume
?
?
Which constants would most likely be filled in the first row of the table?
temperature and moles of gas
volume and temperature
pressure and volume
pressure and moles of gas
Which of the following represents a compound made of five molecules
OCOS
OC205
Осо
5002
all organisms begins life as a ________ cell.
Answer:
All organisms begin life as a single cell
Explanation:
Single cell also did you know 15 minutes can save you 15% more on car insurance
12. Which gas has the greatest kinetic energy at STP?
a. He
b. Ne
c. Ar
d. none of the above (all have the same kinetic energy)
Answer:
d. none of the above (all have the same kinetic energy)
Explanation:
The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.
At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.
The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.
Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where, K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Chromuate found inside which of the following structures of a eukaryotic cell?
Answer:
Chromuates are found in the chromosomes of the eukaryotic cells!!!!
Explanation:
I learned this in 7th grade!!!!
Mark Me Brainliest plzz
For the reaction of hydrogen with iodine
H2(g) + I2(g) rightarrow 2HI(g)
relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide.
Answer:
[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]
Explanation:
Hello!
In this case, considering the given chemical reaction:
[tex]H_2(g) + I_2(g) \rightarrow 2HI(g)[/tex]
Thus, by applying the law of rate proportions, we can write:
[tex]\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}[/tex]
Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:
[tex]r_{H_2} = \frac{-1}{2} r_{HI}[/tex]
Best regards!
A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?
Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure
Explanation:
Answer:
12.49 ml
Explanation:
Density = mass / volume
Volume = mass / density
Volume of zinc = 2.54/7.14
Volume of zinc = 0.3557
Initial volume = 12.13 ml
Total volume = initial volume+ volume of zinc
Total volume = 12.13 + 0.3557
Total volume = 12.4857 = 12.49 ml
How to change 5 % W/V of NaCl to ppm , M ? molar mass = 58.5
please clear explain
Answer:
50000ppm and 0.855M.
Explanation:
ppm is an unit of chemistry defined as the ratio between mg of solute (NaCl) and Liters of solution. Molarity, M, is the ratio between moles of NaCl and liters
A 5% (w/v) NaCl contains 5g of NaCl in 100mL of solution.
To solve the ppm of this solution we need to find the mg of NaCl and the L of solution:
mg NaCl:
5g * (1000mg / 1g) = 5000mg
L Solution:
100mL * (1L / 1000mL) = 0.100L
ppm:
5000mg / 0.100L = 50000ppm
To find molarity we need to obtain the moles of NaCl in 5g using its molar mass:
5g * (1mol / 58.5g) = 0.0855moles NaCl
Molarity:
0.0855mol NaCl / 0.100L = 0.855M
Conclusion
In this activity, thermal energy was transferred ( into / out of the hand warmer while it changed from
liquid to solid.
whats the question?
is water vapor only found in hot water?
the number that go before symbols and formulas in a chemicql equation are
A.SuperScripts
B.Subscripts
C.Catalysts
D.Coefficients
HELP PLEASE
Instantaneous speed is the rate of motion at an instant in time. Based on this statement, a reasonable conclusion is that if and object's instantaneous speed does not chang over time then,________.
•the object is quickly speeding up
•the object is very gradually slowing down
•the object is moving at a constant speed
•the object has returned to its beginning position
Answer:
The object is moving at a constant speed.
What is the mass of 1.0 × 10^9 molecules of aspartame?
Answer:
294.3 g/mol b.
The mass of 1.0*10^9 molecules of aspartame is 2.943*10^11 g/mol
ASPARTAME
Aspartame is used as an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages.
CALCULATION
mass of one molecule of aspartame = 294.3g/mol
mass of 1.0*10^9 molecules of aspartame =294.3*(1.0*10^9) g/mol
=2.943*10^11 g/mol
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1. How many moles of CO2 can be produced from a reaction of 10.0 moles CzHg?
2C₂H6 + 702 4 CO2 + 6H₂O
Answer:
[tex]20[/tex] moles of CO2 can be produced from a reaction of 10.0 moles C2H6
Explanation:
In this reaction -
2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)
So 1 mole of C₂H6 will produce [tex]\frac{4}{2} = 2[/tex] moles of Carbon dioxide (CO2)
Thus, 10 moles of C₂H6 will produce [tex]2 * 10 = 20[/tex] moles of Carbon dioxide (CO2)
Suppose 7.17g of barium acetate is dissolved in 350mL of a 79.0mM aqueous solution of sodium chromate. Calculate the final molarity of barium cation in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Round your answer to 1 significant digit.
Answer:
0.0802 M.
Explanation:
Hello!
In this case, since the barium acetate has the following formula:
[tex]Ba(CH_3COO)_2[/tex]
So its molar mass is 255.43 g/mol, in order to compute the molarity of the barium cation, we first need the moles in 7.17 g:
[tex]n_{Ba(CH_3COO)_2} = 7.17g*\frac{1molBa(CH_3COO)_2}{255.43g} =0.0281molBa(CH_3COO)_2[/tex]
Now, since one mole of barium acetate contains one mole of barium cations, we infer there are 0.0281 moles of barium cations. Moreover, since the molarity is computed by dividing the moles of those ones by the volume of the solution in liters, 350 mL (0.350 L) as it does not change, it turns out:
[tex]M=\frac{0.0281molBa^{2+}}{0.350L}\\\\M=0.0802M[/tex]
Best regards!
WHICH ONE IS TRUE WHICH ONE IS FALSE?
The number of valence electrons decreases from left to right across each period.
The number of valence electrons increases from top to bottom within each group.
All of the elements in group 9 have nine valence electrons.
Elements with the most valence electrons are in group 18.
Answer:
The number of valence electrons increases from top to bottom within each group.
Explanation:
The valence electrons are the outermost shell electrons.
Therefore, the number of valence electrons does not increase from top to bottom within each of the group.
Down a group, the number of valence electrons remains the same.
For group I elements, the number of electrons is 1.
The group is the vertical arrangement of elements.
From left to right across a period, the number of valence electrons increases because you move from group to group.
Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 225 mL of insulin at a concentration of 20.0 mg/mL . What is the total mass of insulin in the bottle?
The total mass of insulin in the bottle : m = 4500 mg
Further explanationGiven
225 ml of insulin
The concentration 20 mg/ml
Required
The total mass of insulin
Solution
Density is the ratio of mass per unit volume
Can be formulated
ρ = m / V
m = ρ x V
Input the value :
m = 20 mg/ml x 225 ml
m = 4500 mg
Which two elements have similar characteristics?
Answer:
The two elements are FLUORINE AND CHLORINE. These two elements have similar characteristics because they belong to the same group in the periodic table. On the periodic table, elements with similar properties are grouped together in the same group. Both chlorine and fluorine belongs to the halogen group.
Explanation:
Hope it helps, some how.
11. A 4.175 gram sample of a certain hydrate of copper (II) sulfate, CuSO,• xH,O, is heated until all
the water is driven off. The resulting anhydrous compound weighs 3.120 grams. What is the
formula of the hydrate?
The formula of the hydrate = CuSO₄• 3H₂O
Further explanationGiven
4.175 grams sample CuSO₄• xH₂O
3.120 grams anhydrous compound CuSO₄
Required
The formula
Solution
mass of H₂O driven off :
= 4.175 - 3.12
= 1.055 g
MW CuSO₄ = 159.5 g/mol
MW H₂O = 18 g/mol
mol ratio of CuSO₄ : H₂O :
= 3.12/159.5 : 1.055/18
= 0.01956 : 0.05861
= 1 : 3
Based on the data provided, the formula of the hydrated salt is CuSO4.3H20
What is the formula of the hydrate?The formula of the hydrate is determined from the mole ratio of the anhydrous saltand water.
Mass of water = 4.175 - 3.120
mass of water = 1.055 g
Mole ratio= mass/molar mass
molar mass of CuSO4 = 160 g/mol
molar mass of H2O = 18 g/mol
CuSO4 = 3.120/160 = 0.0195
H2O = 1.055/18 = 0.0586
CuSO4 = 0.0195/0.0195 = 1
H2O = 0.0586/0.0195 = 3
Therefore, the formula of the hydrated salt is CuSO4.3H20
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A 175 g piece of iron and a 175 g piece of aluminum are placed in a hot water bath so that they are warmed to 99.7 o C. The metal samples are removed and cooled to 21.5 o C. Which sample undergoes the greater heat change
Answer:
The Aluminium sample
Explanation:
From the question,
ΔQ of the iron = Cm(t₂-t₁)........................ Equation 1
Given: C = specific heat capacity of iron, m = mass of iron, t₁ and t₂ = initial and final temperature respectively.
Given: m = 175 g = 0.175 kg, t₂ = 21.5°C, t₁ = 99.7°C
Constant: C = 444 J/kgK.
Substitute into equation 1
ΔQ = 0.175(444)(21.5-99.7)
ΔQ = -6076.14 J
Similarly, for aluminium,
ΔQ' = c'm'(t₂-t₁)...................... Equation 2
Given: m' = 175 g = 0.175 kg,
Constant: 900 J/kgK
ΔQ' = 0.175(900)(21.5-99.7)
ΔQ' = -12316.5 J
Hence the aluminium sample undergoes the greater heat change
PLSSS HELP!! In the demonstration, Iron reacted with the oxygen in the air. Which one ran out
first? How do you know?
Identify the types of information that are necessary to communicate with emergency responders. Select one or more: Any chemicals involved in an incident Any other hazards present in the lab The history of safety incidents in the lab How the incident happened
Answer:
How the incident happened
Any chemicals involved in an incident
Any other hazards present in the lab
Explanation:
Above are the types of information that are necessary to communicate with emergency responders. The emergency responders ask the first question that how the incident happened. After that they ask that is there any harmful chemicals are present in the laboratory or what types of chemicals present in the laboratory. These questions were asked by the emergency responders in order to give the patient a suitable treatment.
The emergency responders are persons that helps in the case of emergency to deal with hazardous conditions. The information provided to the emergency responders helps in dealing with the condition.
The information that has to be provided to the emergency responder in case of a laboratory incident helps them to handle the situation. The questions about how the incident occurs, the presence of hazardous chemicals in the laboratory will help in avoiding the further hazard. The involvement of the chemical in the hazard will help to deal with the situation.
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The water solution of which of the following
substances is the best conductor of electricity?
A) CO2
C) CO
B) KC1
D) C6H1206
The water solution of KCl is the BEST conductor of electricity (Option B).
Potassium is an alkali metal that has free electrons and therefore it is an excellent conductor of electricity.Potassium chloride (formula KCl) is a metal halide salt consisting of potassium and chlorine.In solution, KCl is a good conductor of electricity because potassium ions (K+) and chloride (CL-) ions become completely dissociated in the water.In conclusion, the water solution of KCl is the BEST conductor of electricity (Option B).
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The Question A 1.80 x 10-2 kg block of metal has the following dimensions: 0.4981 inches by 0.531 inches, by 0.5839 inches. Determine the density of the block in g/mL. Using the provided list of metals and their respective densities, what is the metal's identity
Answer:
Zinc
Explanation:
m = Mass of block [tex]1.8\times 10^{-2}\ \text{kg}=18\ \text{g}[/tex]
Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches
[tex]1\ \text{inch}^3=16.3871\ \text{mL}[/tex]
Volume of block
[tex]V=0.4981\times 0.531\times 0.5839\times 16.3871\ \text{mL}[/tex]
Density is given by
[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{18}{0.4981\times 0.531\times 0.5839\times 16.3871}\\\Rightarrow \rho=7.112\ \text{g/mL}[/tex]
The density of the metal is [tex]7.112\ \text{g/mL}[/tex]. The metal here is zinc.
< Progress: 19/21 groups Due Jan 15 at 11:55 PM Use the References to access important values if needed for this question. The compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of the hydrate
Answer:
CoSO4.7H2O
Cobalt II tetraoxosulphate VI heptahydrate
Explanation:
According to IUPAC nomenclature, compounds are named systematically.
We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O
According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.
Classify each of the compounds as an ionic compound, a covalent compound or an acid.a. BaCl2______________________d. CH4______________________b. MnO2______________________e. H2S*______________________c. H3AsO4______________________f. CH3OH
Answer:
a. BaCl2 is ionic compound.
b. CH4 is covalent compound.
b. MnO2 is ionic compound.
e. H2S is covalent compound.
c. H3AsO4 is ionic compound.
f. CH3OH is covalent compound.
Explanation:
BaCl2, MnO2 and H3AsO4 are ionic compounds due to the presence of ionic bond between the atoms while on the other hand, CH4, H2S and CH3OH are covalent compounds due to the presence of covalent bond between their atoms. In covalent bonds, sharing of electrons occur whereas in ionic bonds, complete transfer of electrons occur from one atom to another atom.
if you know an object's distance from the sun in kilometers,how can you find the distance in AU?
Answer:
We divide our value by 1.5×10⁸
Explanation:
AU is a unit to determine distance in the space.
We know that AU means astronomic unit.
The value for conversion is 1.5×10⁸ Km
1 AU = 1.5×10⁸ Km
Let's see the example:
One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:
3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU