What are the odds IN FAVOR of picking a red marble from a bag of 10 green marbles, 10 yellow marbles, and 5 red marbles?

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  lower bound is  [tex]0.0234[/tex]

The  upper bound is  [tex]0.100[/tex]

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

Step-by-step explanation:

From the question we are told that

The  sample size of  individuals who earned in excess of​ $100,000 per​ year is   [tex]n_ 1 = 1205[/tex]

The  number of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

    [tex]w = 712[/tex]

The  sample size  individuals who earned less than​ $100,000 per​ year is [tex]n_2 = 1310[/tex]

The  number of  individuals who earned less than​ $100,000 per​ year that said yes is

       [tex]v= 693[/tex]

The sample proportion of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

           [tex]\r p _ 1 = \frac{w}{n_1 }[/tex]

substituting values

          [tex]\r p _ 1 = \frac{712}{1205}[/tex]

          [tex]\r p _ 1 =0.5909[/tex]

The sample proportion of  individuals who earned less than​ $100,000 per​ year that said yes is

          [tex]\r p _ 1 = \frac{v}{n_2 }[/tex]

substituting values

         [tex]\r p _ 1 = \frac{693 }{1310}[/tex]

        [tex]\r p _ 1 = 0.529[/tex]

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 1 -0.95[/tex]

           [tex]\alpha = 0.05[/tex]

 Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the value is  [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

    Generally the margin of error is  

   [tex]E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p _1 (1- \r p_1 )}{n_1} + \frac{ \r p _2 (1- \r p_2 )}{n_2} } }[/tex]

substituting values

   [tex]E = 1.96 * \sqrt{ \frac{ 0.5909 (1- 0.5909 )}{1205} + \frac{ 0.592 (1- 0.6592 )}{1310} } }[/tex]

    [tex]E =0.03846[/tex]

Generally the 95% confidence interval is  

        [tex](\r p_1 - \r p_2) - E < p_1 - p_2 <( \r p_1 - \r p_2 ) + E[/tex]

substituting values

        [tex](0.5909 - 0.529 ) - 0.03846 < p_1 - p_2 < (0.5909 - 0.529 ) + 0.03846[/tex]

         [tex]0.02344 < p_1 - p_2 < 0.10036[/tex]

The  lower bound is  [tex]0.0234[/tex]

The  upper bound is  [tex]0.100[/tex]

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

The lower bound is 0.0234 and the upper bound is 0.100. Then the 95% confidence interval is (0.0234, 0.100)

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

The research group asked the following question of individuals who earned in excess of​ $100,000 per year and those who earned less than​ $100,000 per​ year.

The sample size of individuals who earned in excess of $100,000 per year will be

[tex]\rm n_1 =1205[/tex]

The sample size of individuals who earned less than $100,000 per year will be

[tex]\rm n_1 =1205[/tex]

The number of individuals who earn an excess of $100,000 per year that said yes will be

[tex]\rm w = 712[/tex]

The number of individuals who earn less than $100,000 per year that said yes will be

[tex]\rm v= 693[/tex]

Then the sample proportion of individuals who earned in excess of $100,000 per year that said yes will be

[tex]\rm \hat{p}_1=\dfrac{w}{n_1}\\\\\hat{p}_1=\dfrac{712}{1205}\\\\\hat{p}_1= 0.5909[/tex]

Then the sample proportion of individuals who earned less than $100,000 per year that said yes will be

[tex]\rm \hat{p}_2=\dfrac{v}{n_2}\\\\\hat{p}_2=\dfrac{693}{1310}\\\\\hat{p}_2= 0.529[/tex]

The confidence level is 95% then the level of significance is mathematically represented as

[tex]\alpha =1-0.95\\\\\alpha =0.05[/tex]

Then the critical value of α/2 from the normal distribution table. Then the value of z is 1.96, then the error of margin will be

[tex]E = z_{\alpha /2} \times \sqrt{\dfrac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \dfrac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\E = 1.96 \times \sqrt{\dfrac{05909(1-0.5909)}{1205} + \dfrac{0.529(1-0529)}{1310}}\\\\E = 0.03846[/tex]

The 95% confidence interval will be

[tex]\begin{aligned} (\hat{p}_1-\hat{p}_2)-E & < p_1-p_2 < (\hat{p}_1-\hat{p}_2) + E\\\\(0.5909 - 0.529) - 0.03846 & < p_1-p_2 < (0.5909 - 0.529) + 0.03846\\\\0.02344 & < p_1-p_2 < 0.10036 \end{aligned}[/tex]

More about the margin of error link is given below.

https://brainly.com/question/6979326

Answer:

fourth option

Step-by-step explanation:

Common difference is given by difference of two consecutive term

d = nth term - (n-1)th term

______________________________________

for all the  series lets take second term as nth term

and first term as (n-1)th term

_________________________________________

for first series

n th term = -3 1/2 = -3.5

(n-1)th term = -5

therefore

d= -3.5 -(-5) = -3.5 +5 = 1.5

______________________________________

for second series

n th term = 4 1/2 = 4.5

(n-1)th term = 2 1/2 = 2.5

therefore

d= 4.5 -(2.5) =2

_________________________

for third series

n th term = 3

(n-1)th term =1.5

therefore

d= 3 - 1.5 = 1.5

__________________________________

for fourth series

n th term = -1.5

(n-1)th term = -4

therefore

d= -1.5 -(-4) = -1.5 + 4 = 2.5 = 2 1/2

___________________________________

Thus, based on above solution option four has common difference of 2 1/2

Question

In a study of 100 new cars, 29 are white. Find p and q , where p is the proportion of new cars that are white.

Answer:

p = 0.29  and q = 0.71

Step-by-step explanation:

Given

Total new cars =  100

White new cars = 29

Required

Determine p and q

From the question;

p represents white new cars

Hence;

[tex]p = 29[/tex]

Note that;

[tex]p + q = 100[/tex]

Substitute 29 for p

[tex]29 + q = 100[/tex]

[tex]29 - 29 + q = 100 - 29[/tex]

[tex]q = 100 - 29[/tex]

[tex]q = 71[/tex]

The proportion of p is calculate by dividing p by the total number of new cars (Same process is done for q)

For proportion of p

[tex]Proportion,\ p = \frac{p}{new\ cars}[/tex]

[tex]Proportion,\ p = \frac{29}{100}[/tex]

[tex]Proportion,\ p = 0.29[/tex]

For proportion of q

[tex]Proportion,\ q = \frac{q}{new\ cars}[/tex]

[tex]Proportion,\ q = \frac{71}{100}[/tex]

[tex]Proportion,\ q = 0.71[/tex]

Answer:

Below

Step-by-step explanation:

● (3.5× 10^8) × (4×10^(-12))

● (3.5×4) × (10^8 × 10^(-12) )

● 14 × 10^ (-12+8)

● 14 × 10^(-4)

● 14/10^4

Answer:

1/13

Step-by-step explanation:

There are 52 cards in a deck of cards and 13 of them are hears

P(heart) = hearts / total

              = 13/52 = 1/13

Answer:

-5-9i

Step-by-step explanation:

-1-8i-4-i

-1-4-8i-i

-5-9i

Answer:

1/8 is less than

Step-by-step explanation:

i dont see any fractions below gona have to edit your answer

Answer:

C

Step-by-step explanation:

[tex] \sin( 5 ^{o} ) = \frac{33}{ab} \\ ab = 378.63[/tex]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

[tex]2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30[/tex]

It can be written as

[tex]2(\ln 2x)-(\ln 10x)=\ln 30[/tex]         [tex][\because \ln e^a=a][/tex]

[tex]\ln (2x)^2-(\ln 10x)=\ln 30[/tex]        [tex][\because \ln a^b=b\ln a][/tex]

[tex]\ln \dfrac{4x^2}{10x}=\ln 30[/tex]        [tex][\because \ln \dfrac{a}{b}=\ln a-\ln b][/tex]

[tex]\ln \dfrac{2x}{5}=\ln 30[/tex]

On comparing both sides, we get

[tex]\dfrac{2x}{5}=30[/tex]

Multiply both sides by 5.

[tex]2x=150[/tex]

Divide both sides by 2.

[tex]x=75[/tex]

Therefore, the correct option is B.

Answer:

b x=75

Step-by-step explanation:

Answer:

AB = 16 Units

Step-by-step explanation:

In the given figure, CD is the diameter and AB is the chord of the circle.

Since, diameter of the circle bisects the chord at right angle.

Therefore, AE = 1/2 AB

Or AB = 2AE...(1)

Let the center of the circle be given by O. Join OA.

OA = OD = 10 (Radii of same circle)

Triangle OAE is right triangle.

Now, by Pythagoras theorem:

[tex] OA^2 = AE^2 + OE^2 \\

10^2 = AE^2 + 6^2 \\

100= AE^2 + 36\\

100-36 = AE^2 \\

64= AE^2 \\

AE = \sqrt{64}\\

AE = 8 \\

\because AB = 2AE..[From \: equation\: (1)] \\

\therefore AB = 2\times 8\\

\huge \purple {\boxed {AB = 16 \: Units}} [/tex]

Answer:

12 days

Step-by-step explanation:

The answer of the problem is the LCM of 3 and 4=12. Hence the answer is 12 days

On 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

It is defined as the common number of two integers, which is the lowest number that is a multiple of two or more numbers. The full name of LCM is the least common multiple.

We have:

Amira starts an exercise program on the 3rd of March.

She will swim every 3 days and cycle every 4 days.

Total days =3 + 4 = 7 days = 1 week

The day she swims and cycles on the same day = LCM of 3 and 4

= 3, 6, 9, 12, 15

= 4, 8, 12, 16

= 12

Thus, on 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

Learn more about the LCM here:

brainly.com/question/20739723

#SPJ2

Answer:

we have a right triangle and to get the internal angle of the right triangle formed at the helicopter we subtract 62 degrees from 90 which equals 28 degrees

we now use the cosine to find the distance (d) from the helicopter

cosine 28 = 85/d

d = 85 / cosine 28 = 85 / 0.8829 = 96.2736 = 96 feet

Answer:

B. The mean is less than the median.

Step-by-step explanation:

Say there was 20 kids: 10 kids(half) scored 86's, 3 kids(a few) scored 45's, and 7 kids(the remaining) scored 77's.

The median would be- 81.5 (chronological order, find the middle number)

The mean would be- 76.85 (sum of all the scores divided by the number of scores)

The mode would be- 86 (most frequent number)

The mean(76.85) is less than(<) the median(81.5)

Answer:

x=(n+12)π, y=mπ∴x=n+12π, y=mπ and z = rπ where n∈I, m∈I, r∈I

Step-by-step explanation:

∴ LHS ≤ 2 and RHS ≥ 2

So, sin2 x = 1, cos2 y = 1 and sec2 z = 1

∴x=(n+12)π, y=mπ∴x=n+12π, y=mπ and z = rπ where n∈I, m∈I, r∈I

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

Answer:

Step-by-step explanation:

I'm having difficulty reading your input:  25, y, + 18, 25.  Please clarify your meaning.

5x3 – 6x2 is a polynomial expression with two terms.

The term  is a ratio.  False.   See above.

The entire expression is a difference.  True.

There are four terms.  False.   See above.

Two statements B and C are true for the expression 5x3 – 6x2 25y+ 18

A. The term is a ratio. False

B. There are three terms.terms. True

C. The entire expression is a difference. True

D. There are four terms. False

Learn more about linear equation here: brainly.com/question/1884491

#SPJ2

Answer:

Here is the answer i got-

Step-by-step explanation:

325823-250823=75000

325823’s 244367250percent is 75000

Answer:

0.14

Step-by-step explanation:

The z score is a score used in statistics to determine by how many standard deviations ti the raw score above or below the mean. If the raw score is above the mean then the z score is positive while If the raw score is below the mean then the z score is negative, It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

From the normal distribution table, The area under the curve shaded is 1 to 2 = P(1 < z < 2) = P(z < 2) - P(z < 1) = 0.9772 - 0.8413 = 0.1359 ≈ 0.14

The area under the curve shaded is 1 to 2 is 0.14

Probabilities are used to determine the chances of an event

The shaded region represents the probability of the z-scores

The shaded region 1 to 2 is represented as:

P(1 < z < 2) =

Using the probability of z-score, we have the formula

P(1 < z < 2) = P(z < 2) - P(z < 1)

From the given standard normal table:

P(z < 2) = 0.9772

P(z < 1) = 0.8413

So, we have:

P(1 < z < 2) = 0.9772 - 0.8413

P(1 < z < 2) = 0.1359

Approximate

P(1 < z < 2) = 0.14

Hence, the area under the curve shaded is 1 to 2 is 0.14

Read more about normal distribution at:

https://brainly.com/question/4079902

Answer:

∠NMC  = 50°

Step-by-step explanation:

The interpretation of the information given in the question can be seen in the attached images below.

In ΔABC;

∠ A + ∠ B + ∠ C = 180°    (sum of angles in a triangle)

∠ A + 70°  + 50°  = 180°

∠ A = 180° - 70° - 50°

∠ A =  180° - 120°

∠ A =  60°

In ΔAMN ; the base angle are equal , let the base angles be x and y

So; x = y   (base angle of an equilateral  triangle)

Then;

x + x + 60° = 180°

2x +  60° = 180°

2x = 180° - 60°

2x = 120°

x = 120°/2

x = 60°

∴ x = 60° , y = 60°

In ΔBQC

∠a + ∠e + ∠b = 180°

50° + ∠e + 40° = 180°

∠e = 180° - 50° - 40°

∠e = 180° - 90°

∠e = 90°

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

∠i  = 50° - 40° = 10°

In ΔNQC

∠f + ∠i   + ∠j = 180°

90° + 10° + ∠j = 180°

∠j  = 180° - 90°-10°

∠j  = 180° - 100°

∠j  = 80°

From  line AC , at point N , ∠y + ∠c + ∠j = 180°   (sum of angles on a straight line)

60° + ∠c + ∠80° = 180°

∠c  = 180° - 60°-80°

∠c  = 180° - 140°

∠c  = 40°

Recall that :

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

Then In Δ NMC ;

∠d + ∠h + ∠c = 180°   (sum of angles in a triangle)

∠d + 90° + 40° = 180°

∠d  = 180° - 90° -40°

∠d  = 180° - 130°

∠d  = 50°

Therefore, ∠NMC = ∠d  = 50°

Answer:

612,300

600,000

10,000

2,000

300

00

0

Answer:  3.79 litres

Step-by-step explanation:

1 litre is equivalent to about ‭1.05668821‬ American quarts.

4 quarts would therefore be;

= 4/‭1.05668821‬

= 3.78541178

= 3.79 litres

Answer:

86.28 ft²

Step-by-step explanation:

The figure given consists of a rectangle and a semicircle.

The area of the figure = area of rectangle + area of semicircle

Area of rectangle = [tex] l*w [/tex]

Where,

l = 10 ft

w = 8 ft

[tex] area = l*w = 10*8 = 80 ft^2 [/tex]

Area of semicircle:

Area of semicircle = ½ of area of a circle = ½(πr²)

Where,

π = 3.14

r = ½ of 8 = 4 ft

Area of semi-circle = ½(3.14*4) = 6.28 ft²

Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)

Answer:

the area of the figrue is 105.12

Step-by-step explanation:

Answer:

Option C - Reject H0. We have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.

Step-by-step explanation:

First of all let's define the hypothesis;

Null hypothesis;H0; μ = $48,722

Alternative hypothesis;Ha; μ > $48,722

Now, let's find the test statistic for the z-score. Formula is;

z = (x' - μ)/(σ/√n)

We are given;

x' = 48,722

μ = 49,870

σ = 3900

n = 50

Thus;

z = (49870- 48722)/(3900/√50)

z = 2.08

So from online p-value calculator as attached, using z = 2.08 and α = 0.05 ,we have p = 0.037526

This p-value of 0.037526 is less than the significance value of 0.05,thus, we reject the claim that that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722

9514 1404 393

Answer:

Step-by-step explanation:

The sum of side lengths of a rectangle is half the perimeter, so is 15 inches for this brochure. If x is one of the side lengths, then (15 -x) is the other one, and the area is ...

  x(15 -x) = 52

  x^2 -15x = -52 . . . . multiply by -1 and expand

  (x -7.5)^2 = -52 +56.25 = 4.25 . . .  complete the square

  x = 7.5 ±√4.25 ≈ {5.438, 9.562} . . . inches

The longer side is 7+√4.25 ≈ 9.562 inches; the shorter side is 7-√4.25 ≈ 5.438 inches.

Answer:

Step-by-step explanation:

a. table

x = 100,y = 20*100+3000 = 2000+3000 = 5000

x = 200,y = 20*200+3000 = 4000+3000 = 7000

x = 300,y = 20*300+3000 = 6000+3000 = 9000

b：

y = 4300

4300 = 20x+3000

20x = 4300-3000

20x = 1300

x = 1300/20

x  = 65

so 65 computer desks can be produced.

Answer:

Yes, Rolle's theorem can be applied

There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)

Step-by-step explanation:

Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable  in the open interval, and f(a) = f(b) given that:

[tex]f(0)=-0^2+3\,(0)=0\\f(3)=-3^2+3\,(3)=-9+9=0[/tex]

Then there must be a c in the open interval for which f'(c) =0

In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:

[tex]f(x)=-x^2+3\,x\\f'(x)=-2\,x+3\\f'(c)=-2\,c+3\\0=-2\,c+3\\2\,c=3\\c=\frac{3}{2} =1.5[/tex]

There is a unique answer for c, and that is c = 1.5

Rolle's theorem is applicable if [tex]f(a)=f(b)[/tex] and $f$ is differentiable in $(a,b)$

since it's polynomial function, it's always continuous and differentiable..

and you can easily check that $f(0)=f(-3)=0$

so it is applicable.

now, $f'(x)=-2x+3=0 \implies x=\frac32$

there is only once value (as you can imagine, the graph will be downward parabola)

Answer:

(a^3/b^7)^2 = (a^6/b^14)