Answer:
Friction
Explanation:
In the event that the power is applied toward the path inverse to the bearing of movement, it goes against the movement of the item and henceforth the speed of the article diminishes.
Then, in the event that the thing continues to move one way, grinding will dominate and go about as the moving variable.
So, the moving factor would be friction.
I really need help with this question
In order to determine the speed of an object, what measurements must be made?
Answer:
You need to have the distance traveled and the time it took to travel that distance.
Explanation:
A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant of 35 N/m. What is the greatest vertical distance below the bridge surface that the bungee jumper will reach? Enter your answer as a positive number in meters, but do not enter units.
Answer:
11.78meters
Explanation:
Given data
Mass m = 100kg
Length of cord= 10m
Spring constant k= 35N/m
At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy
That is
Us=Ug
Us= 1/2kx^2
Ug= mgh
1/2kx^2= mgh
0.5*35*10^2= 100*9.81*h
0.5*35*100=981h
1750=981h
h= 1750/981
h= 1.78
Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge
Answer:
[tex]X=74.7[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=100kg[/tex]
Length [tex]l=10m[/tex]
Spring constant [tex]\mu=35N/m[/tex]
Generally the equation for potential energy of mass is mathematically given by
[tex]P.E_m=mgh[/tex]
Since
[tex]P.E_m=P.E_s[/tex]
Where
P.E_s =potential energy of spring
Therefore
[tex]m*g*(x+10) = 0.5*k*\mu^2[/tex]
[tex]100*9.8*(x+10) = 0.5*35*\mu^2[/tex]
[tex]980*(x+10) = 17.5*\mu^2[/tex]
[tex]980*x+9800 = 17.5*\mu^2[/tex]
[tex]17.5*\mu^2 - 980*\mu - 9800 = 0[/tex]
Comparing the equation above with standard quadratic equation
[tex]17.5*\mu^2 - 980*\mu - 9800 = 0[/tex]
[tex]ax^2+bx+c=0[/tex]
Giving
[tex]a=17.5\\ b=-980\\ c=-9800[/tex]
Solving Quadratic equation the roots of the equation is given as
[tex]\mu_1=64.66[/tex]
[tex]\mu_2=-8.661[/tex]
Since
[tex]\mu[/tex] can not be -ve
Therefore
The vertical distance attained by the bungee jumper is given as
[tex]X=\mu+l[/tex]
[tex]X=64.7+10[/tex]
[tex]X=74.7[/tex]
Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 2180 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
Answer:
[tex]0.84\:\text{s}[/tex]
Explanation:
The impulse-momentum theorem states that the impulse on an object ([tex]F\Delta t[/tex]) is equal to the change in momentum of that object ([tex]\Delta p[/tex]).
Set up the following equation:
[tex]F\Delta t=\Delta p[/tex]
Solving for change in momentum:
The momentum of an object is equal to [tex]p=mv[/tex], where [tex]m[/tex] is the mass of the object and [tex]v[/tex] is the velocity of the object. Since the person's final velocity will be zero, their final momentum will also be zero. Therefore, the person's change in momentum is [tex]68\cdot 27-0=1836\:\text{kgm/s}[/tex].
Solving for time:
[tex]2180\cdot\Delta t = 1836,\\\Delta t =\frac{1836}{2180},\\\Delta t =\boxed{0.84\:\text{s}}[/tex]
Answer:
If the engineers know that the
If the engineers know that themaximum force that a person can safely withstand is 2180 N, approximately, 0.84 second is required to crumple the barrier to safely slow the person
is required to crumple the barrier to safely slow the personwith this force.
PLEASE ANSWER THIS ASAP THIS IS A SCIENCE QUESTION NO LINKS
Answer:
I believe the answer would be kinetic energy to thermal energy.
Explanation:
Thermal energy is the heat of the brakes, and the kinetic energy would be when the car is in motion before stopping.
what is wheel and axle?
Answer:
Wheel and axle consists of two coaxial cylinders of different diameters. Various examples of wheel and axle are used in our daily life. Some examples of such wheel and axles are string-roller, screwdriver, MADANI, ROTE PING, spanners, knobs of a door, steering of vehicles etc. Most of them are used for magnifying effort but some are also used to gain speed like MADANI and ROTE PING. In wheel and axles, usually effort is applied on big cylinder called wheel and is overcome bya small cylinder called axle.
Answer:
Explanation: The wheel and axle
a machine consisting of a wheel attached to a smaller axle so that these two parts rotate together in which a force is transferred from one to the other.
A parachute on a racing dragster opens and changes the speed of the car from 93 m/s to 45 m/s in a period of 5.3 seconds. What is the acceleration of the dragster?
Answer:
[tex]-9.06\:\mathrm{m/s^2}[/tex]
Explanation:
We can use the following kinematics equation to solve for acceleration:
[tex]v_f=v_f+at[/tex].
Solving for [tex]a[/tex]:
[tex]45=93+5.3a,\\-48=5.3a,\\a\approx \boxed{-9.06\mathrm{m/s^2}}[/tex]
*Note: Since acceleration is a vector quantity, it has both magnitude and direction. The negative sign implies that the acceleration is in the opposite direction of the racing dragster's movement.
Fill in the blank: Friction applies to all states of matter in the gas state it is called ________ resistance and in a liquid it's called ___________ resistance. Air resistance can be used to slow the fall of an object. Parachutes are usually made out of light, strong fabric, originally silk, now most commonly nylon. They are typically dome-shaped, but vary, with rectangles, inverted domes, and others found
Answer:
Drag; water.
Explanation:
Friction can be defined as a force that resists the relative motion of two objects when there surface comes in contact. Thus, it prevents two surface from easily sliding over or slipping across one another. Also, friction usually reduces the efficiency and mechanical advantage of machines but can be reduced through lubrication.
Generally, there are four (4) main types of friction and these includes;
I. Static friction.
II. Rolling friction.
III. Sliding friction.
IV. Fluid friction.
Fluid friction can be defined as a type of friction that acts on physical objects moving through a liquid or gas. A fluid refers to any physical substance that can flow and is able to take the shape of a container.
In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.
Basically, matter exists in three (3) distinct or classical phases and these are; solid, liquid and gas.
Generally, friction applies to all states of matter; in the gaseous state, it is called drag resistance and in a liquid it's called water resistance.
could sum1 explain this for 17 points please?
Answer:
If the potential energy change of each cart is the same, then the total mechanical energy change is the same for each cart
Explanation:
Hills look steeper when standing back from the edge so that gaze is nearly parallel to the surface of the hill. When optical slant (the angle between the center of gaze and the surface) is small, surface orientation is pulled toward the direction of gaze
Infrared technology can be used to do which of the following?
A. Locate tumors in the body
B. Monitor human activity at night
C. Photograph through solid objects
O D. Communicate across long distances
Answer:
human activity at night
Explanation:
just did it
factorise the following - 6x³ + 3x² + 8x + 4 ?
p(1) = -16 x (1)³ + 3 x (1)² + 8 x 1 + 4
= -16 + 3 + 8 + 4
= -16 +16
=0
what is her mass pls help
Answer:
B
Explanation:
Why does the static electricity in an object not constantly shock us?
Answer:Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.
Explanation:
hope this helped D:
If a 20 N force acts on a 10 kg object for 0.5 seconds. If the object starts at rest, what would it’s new p (momentum) and v (velocity) be?
Answer:
[tex]p=10\:\text{kgm/s}},\\v_f=1\:\text{m/s}[/tex]
Explanation:
From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. We can use this to find the acceleration of object after 20 N (force) is applied to the 10 kg object.
Substituting given values, we have:
[tex]\Sigma F=ma, \\20=10a,\\a=\frac{20}{10}=2\:\mathrm{m/s^2}[/tex]
Now that we have acceleration, we can find the final velocity of object (after 0.5 seconds) using the following kinematics equation:
[tex]v_f=v_i+at[/tex], where [tex]v_f[/tex] is final velocity, [tex]v_i[/tex] is initial velocity, [tex]a[/tex] is acceleration, and [tex]t[/tex] is time.
Solving for final velocity:
[tex]v_f=0+2\cdot 0.5,\\v_f=\boxed{1\:\text{m/s}}[/tex]
The momentum of an object is given as [tex]p=mv[/tex]. Since we've found the final velocity and mass stays constant, we have:
[tex]p=10\cdot 1=\boxed{10\:\text{kgm/s}}[/tex]
Do you think the mass of an object greatly affects the coefficient of friction?
Answer:
no it doesn't
Explanation:
What best describes an impulse acting on an object?
the net force on an object divided by the time of impact
the velocity of an object divided by its mass
the product of an object's mass and the time of force impact
the product of an object's mass and its change in velocity
it
Answer:
D
Explanation:
What can be the maximum size of a black hole?
Answer:
hello! your answer is fifty billion M
Kicks and throws are examples of
A. friction
B. force
C. both friction and force
B.
force is the example of kicks and throws
Consider a day in the physics lab room with room temperature of 20 0C and pressure of 1.0 atm. A container of 3.5 L is left open to the air for a long time. The container is then sealed and place on a Bunsen burner until its temperature reaches 95 0C. It is then open. How many moles of air escape?
Answer:
The number of moles of air that escape is approximately 0.027 moles
Explanation:
The room temperature, T₁ = 20 °C = 298.15 K
Atmospheric pressure, P₁ = 1.0 atm
The volume of the container, V₁ = 3.5 L
The final temperature of the air in the container after heating on the Bunsen burner, T₂ = 95 °C = 368.15 K
The container opened finally
The ideal gas equation is P·V = n·R·T
∴ n = P·V/(R·T)
Where;
R = The universal gas constant = 0.08205 L·atm/(mol·K)
Therefore, we get;
n₁ = 1.0 × 3.5/(0.08205 × 298.15) ≈ 0.143
The number of moles, n₁ ≈ 0.143 moles
When the gas is heated to 95 °C, the number of moles becomes
n₂ = P₂·V₂/(R·T₂)
P₂ = 1.0 atm atmospheric pressure, V₂ = 3.5 L, the volume of the container, T₂ =
∴ n₂ = 1.0 × 3.5/(0.08205 × 368.15) ≈ 0.116
The number of moles of air remaining in the container, n₂ ≈ 0.116 moles
The number of moles of air that escape, n = n₁ - n₂
∴ n = 0.143 - 0.116 = 0.027
The number of moles of air that escape, n ≈ 0.027 moles
[tex] \bigstar[/tex] A uniform resistance wire is stretched till it's length becomes four times.What happens to the resistance ?
*Plagiarised / Irrelevant answers will be reported!
Answer:
if a uniform resistance wire is stretched till it's length becomes four times the the resistance of wire multiples by sixteen times as resistance is directly proportional to the
length of wire.
hope it helps.
stay safe healthy and happyAnswer:
we have:
At unit length
Resistance [R]=[tex] \frac{pL}{A} [/tex].....i
where
p: resistivity
L:length
A:area
when
length is strength 4 times
length will be 4L
Now
new equation becomes
Resistance[R] =[tex] \frac{p4L}{A} [/tex]=4[tex] \frac{pL}{A} [/tex]=4R
so
when A uniform resistance wire is stretched till it's length becomes four times. the resistance increases by four times of its original resistance.
what is 7/3 because it wont work for me pls help
Answer:
7/3 = 2 1/3
Explanation:
If the numerator is greater than or equal to the denominator of a fraction, then it is called an improper fraction. In that case, you could convert it into a whole number or mixed number fraction. 7/3 = 2 1/3.
Answer:
2.3333 (3-repeating) hope that helps
Plisssss you can help me pliss
helpppppppppppp.......!
Explanation:
m = 66 kg
a = 2 m/s²
F = .....?
F = m . a= 66 . 2
= 132 N
#CMIIWAll students except one are cheating on a test. The one student who is not cheating on the test is exhibiting abnormal behavior. Based on the information provided in the article, explain the conclusion of this scenario. Which definition for abnormal behavior would apply to this scenario? (Site 1)
Answer: See explanation
Explanation:
According to clinical psychology, an abnormal behavior is when an act results in a significant distress and is deviant from the normal practice.
In this case, while the whole class is cheating, one student isn't. This shows that the student is deviating from what every other person is doing. Since the student deviates from the norm, it's an abnormal behavior.
Answer:
The reason he might be exhibiting abnormal behavior is the fact that everyone except him is cheating on a test. He is the odd one out and due to this he might be anxious/nervous. Perhaps he thinks that since he is the only one not cheating that he might get a bad grade cause the teacher will assume he is cheating aswell. Another might be that he does not like being singled out. It's out of the norm and he does not particularly like it.
Explanation:
Take this and alter it to your liking. It got me a 100%!
007 (part 1 of 2) 1.0 points
Light moves from flint glass (n = 1.66) into
water at an angle of incidence of 27.2º.
a) What is the angle of refraction?
Answer in units of".
008 (part 2 of 2) 1.0 points
b) At what angle would the light have to be
incident to give an angle of refraction of 90.0°
Answer in units of
Answer:
a) The angle of refraction is approximately 34.7
b) The angle the light have to be incident to give an angle of refraction of 90° is approximately 53.42°
Explanation:
According to Snell's law, we have;
[tex]\dfrac{n_1}{n_2} = \dfrac{sin (\theta_2)}{sin (\theta_1)}[/tex]
The refractive index of the glass, n₁ = 1.66
The angle of incident of the light as it moves into water, θ₁ = 27.2°
a) The refractive index of water, n₂ = 1.333
Let θ₂ represent the angle of refraction of the light in water
By plugging in the values of the variables in Snell's Law equation gives;
[tex]\dfrac{1.66}{1.333} = \dfrac{sin (\theta_2)}{sin (27.2^{\circ})}[/tex]
[tex]sin (\theta_2) = sin (27.2^{\circ}) \times \dfrac{1.66}{1.333} \approx 0.5692292265[/tex]
θ₂ = arcsin(0.5692292265) ≈ 34.7°
The angle of refraction of the light in water, θ₂ ≈ 34.7°
b) When the angle of refraction, θ₂ = 90°, we have;
[tex]\dfrac{1.66}{1.333} = \dfrac{sin (90^{\circ})}{sin (\theta_1)}[/tex]
[tex]sin (\theta_1) = \dfrac{sin (90^{\circ})}{\left( \dfrac{1.66}{1.333}\right)} = sin (90^{\circ}) \times \dfrac{1.333}{1.66} \approx 0.803[/tex]
θ₁ ≈ arcsin(0.803) ≈ 53.42°
The angle of incident, θ₁, that would give an angle of refraction of 90° is θ₁ ≈ 53.42°
The application of a force that causes an object to move in the direction of the force is ______.
Power
Work
Kinetic energy
Distance
Answer:
work is the answer because work is said to be done if an object is displaced by the application of force
what is the answer to bliky got sticky yuh all over mickey
Answer:
huh
Explanation:
Answer:
whaaaaaaaa
Explanation:
Atoms in group 18 are inert (chemicalally unreactive) because
Answer:
They have a full shell of valence electrons and are very stable .
Explanation:
Answer
atoms in group 18 are chemically inert because they are stable and do not take part in any chemical reaction.
Explanation:
Calcular la cantidad de solucion que se encuentra en un recipiente con 670 g de solvente y 22 g de soluto
Answer:
692 g
Explanation:
La fórmula para encontrar la solución de una mezcla química es agregar el soluto y el solvente juntos. Esto significa
Solución = solvente + soluto
Solución = 670 g + 22 g
Solución = 692 g
es así de simple, y espero que lo entiendas
9) An object with a height of 18 cm is placed in front of a converging lens. The image has a
height of –9.0 cm.
a) What is the magnification of the lens?
b) If the focal length of the lens is 6.0 cm, how far in front of the lens is the object?
c) Where does the image appear?
Answer:
Explanation:
a) Magnification = image height / object height = -9 / 18 = -0.5
b) Magnification = - image distance / object distance = -0.5
so image distance = 0.5 object distance
1/focal length = 1/image distance + 1/object distance
1/6 = 1/(0.5 object distance) + 1/object distance
object distance = 18.0 cm
c) Image appears behind the lens.
Answer:
Explanation:
mag = ht i/ht o = -9/18 = -1/2
mag = -1/2 = -di/do
do = 2di
put in eqn
1/f = 1/di + 1/do
1/6 = 1/di + 1/2di
2di = 18
do = 18cm
image is behind lens