Answer:
2
5
[tex]\dfrac{4}{5}[/tex]
Step-by-step explanation:
We are given 2 fractional numbers:
[tex]1.\ \dfrac{2}4\\2.\ \dfrac{5}8[/tex]
We have to use fraction strips to compare to the fractional numbers.
Let we are Comparing [tex]\frac{2}{4}[/tex] with the length of [tex]x[/tex] number of [tex]\frac{1}4[/tex] sections.
i.e.
[tex]\dfrac{2}{4} = x \times \dfrac{1}{4}\\\Rightarrow x = \dfrac{2 \times 4}{4}\\\Rightarrow x = 2[/tex]
Let we are Comparing [tex]\frac{5}{8}[/tex] with the length of [tex]y[/tex] number of [tex]\frac{1}8[/tex] sections.
i.e.
[tex]\dfrac{5}{8} = y \times \dfrac{1}{8}\\\Rightarrow y = \dfrac{5 \times 8}{8}\\\Rightarrow y = 5[/tex]
Now, let us have a look at 3rd part of question:
The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8
Let the answer be [tex]z[/tex].
So, the equation becomes:
[tex]\dfrac{2}{4} = z \times \dfrac{5}{8}\\\Rightarrow z = \dfrac{2 \times 8}{4 \times 5}\\\Rightarrow z = \dfrac{2 \times 2}{5}\\\Rightarrow z = \dfrac{4}{5}[/tex]
So, the answers are:
2
5
[tex]\dfrac{4}{5}[/tex]
Please answer this correctly
Answer:
50%
Step-by-step explanation:
The chances of getting either heads or tails on a coin is 50/50. Convert that to probability and that is 1/2. Convert it to percentage of 100 and it is 50%.
Only time a coin isn't 50/50 is if the coin itself is a weighted coin.
Please help me with this math problem
Answer:
-1/4 is the slope and the y intercept is -4
Step-by-step explanation:
Solve for y
x +4y = -16
Subtract x
4y = -x-16
Divide by 4
4y/4 = -x/4 -16/4
y = -1/4 x -4
This is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
-1/4 is the slope and the y intercept is -4
Each of the following is a confidence interval for μ = true average (i.e., population mean) resonance frequency (Hz) for all tennis rackets of a certain type:(111.6, 112.4) (111.4, 112.6)(a) What is the value of the sample mean resonance frequency?
Answer:
The value of the sample mean resonance frequency is 112Hz
Step-by-step explanation:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
In this problem, we have that:
Lower bound: 111.6
Upper bound: 112.4
Sample mean: (111.6 + 112.4)/2 = 112Hz
The value of the sample mean resonance frequency is 112Hz
The value of the sample mean resonance frequency is 112 Hz.
What is the value of the sample mean resonance frequency?The value of the sample mean resonance frequency is equivalent to the average of the upper limit and the lower limit.
The sample mean resonance frequency = (lower limit + upper limit) / 2
(111.6 +112.4) / 2
= 224 / 2
= 112 Hz
To learn more about confidence interval, please check: https://brainly.com/question/15905477
Henrique began to solve a system of linear equations using the linear combination method. His work is shown below: 3(4x – 7y = 28) → 12x – 21y = 84 –2(6x – 5y = 31) → –12x + 10y = –62 12x – 21y = 84 + –12x + 10y = –62 –11y = 22 y = –2 Complete the steps used to solve a system of linear equations by substituting the value of y into one of the original equations to find the value of x. What is the solution to the system? ( , )
Answer:
( 3.5 , -2 )
Step-by-step explanation:
Answer:
( 3.5 , -2)
Explanation:
On edge
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce the following results: 490 mg, 502 mg, 505 mg, 495mg, and 492 mg. The manufacturer claims that the tablet contains 500 mg of vitamin C. Do an appropriate statistical analysis to find out whether the results obtained by the student is consistent with bottle claim.
Answer:
There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.
P-value = 0.166.
Step-by-step explanation:
We start by calculating the mean and standard deviation of the sample:
[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\[/tex]
Then, we can perform the hypothesis t-test for the mean.
The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=500\\\\H_a:\mu< 500[/tex]
The significance level is 0.05.
The sample has a size n=5.
The sample mean is M=496.8.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=5-1=4[/tex]
This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-1.1)=0.166[/tex]
As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.
GIVING BRAIN AND 30pointsWhat is the solution to the system of equations below?
y=-3x+2 and 3y =-
3
4
X-6
no solution
infinitely many solutions
(-16, 6)
O (-16, -2)
Answer:
No solution
Step-by-step explanation:
Using substitution, we get to the answer 12=0, which is untrue meaning no solution.
Hope this helps! Please give Brainliest!!
Answer:
no solution
Step-by-step explanation:
y= -1/4x+2
3y = - 3/4x-6 ⇒ y= - 1/4x - 2
These are parallel lines as have same slope of -1/4, so there is no solution
If Jack borrowed $200 and repaid $226 altogether at the end of 2 years, what was the interest rate? Hint: Find the amount of interest from the repaid amount.
Answer: 6.5%
Step-by-step explanation:
Interest = Amount repaid - Amount borrowed
= 226 - 200
Interest = 26
Si = ( prt) / 100
26 = (200 x r x 2) / 100
26 = 4r
r = 6.5%
Triangle L M N is cut by line segment O P. Line segment O P goes from side M L to side M N. The length of O L is 14, the length of O M is 28, the length of M P is y, and the length of P N is 18.
Which value of y would make O P is parallel to L N?
16
24
32
36
Answer:
The value of y that would make O P parallel to L N = 36
Step-by-step explanation:
This is a question on similar triangles. Find attached the diagram obtained from the given information.
Given:
The length of O L = 14
the length of O M = 28
the length of M P = y
the length of P N = 18
Length MN = MP + PN = y + 18
Length ML = MO + OL = 28+14 = 42
For OP to be parallel to LN,
MO/ML = MP/PN
MO/ML = 28/42
MP/PN= y/(y+18)
28/42 = y/(y+18)
42y = 28(y+18)
42y = 28y + 18(28)
42y-28y = 504
14y = 504
y = 504/14 = 36
The value of y that would make O P parallel to L N = 36
Answer:
D-36
Step-by-step explanation:
The percentage of households that include at least one frequent gamer is 58%. A gaming magazine is interested in studying this further to see how it impacts their magazine advertisements. For what sample size, n, will the sampling distribution of sample proportions have a standard deviation of 0.02
Answer:
For a sample size of n = 609.
Step-by-step explanation:
Central limit theorem for proportions:
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this question:
We have that p = 0.58.
We have to find n for which s = 0.02. So
[tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
[tex]0.02 = \sqrt{\frac{0.58*0.42}{n}}[/tex]
[tex]0.02\sqrt{n} = \sqrt{0.58*0.42}[/tex]
[tex]\sqrt{n} = \frac{\sqrt{0.58*0.42}}{0.02}[/tex]
[tex](\sqrt{n})^{2} = (\frac{\sqrt{0.58*0.42}}{0.02})^{2}[/tex]
[tex]n = 609[/tex]
For a sample size of n = 609.
segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segment AB dilated by?
1/2
2
3
4
Answer:
the answer is 3
Step-by-step explanation:
i took the test
The mean annual tuition and fees for a sample of 15 private colleges was with a standard deviation of . A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from 32,500 a) state the null and alternate hypotheses b) calculate the standard error c) calculate the test statistic d) find the p - value .
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
The mean annual tuition and fees for a sample of 15 private colleges was $35,500 with a standard deviation of $6500. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $32,500. State the null and alternate hypotheses. A) H0: 4 = 32,500, H:4=35,500 C) H: 4 = 35,500, H7:35,500 B) H: 4 = 32,500, H : 4 # 32,500 D) H0:41 # 32,500, H : 4 = 32,500
Solution
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ = 32500
For the alternative hypothesis,
Ha: µ ≠ 32500
This is a two tailed test.
Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.
Since n = 15,
Degrees of freedom, df = n - 1 = 15 - 1 = 14
t = (x - µ)/(s/√n)
Where
x = sample mean = 35500
µ = population mean = 32500
s = samples standard deviation = 6500
t = (35500 - 32500)/(6500/√15) = 1.79
We would determine the p value using the t test calculator. It becomes
p = 0.095
Assuming alpha = 0.05
Since alpha, 0.05 < than the p value, 0.095, then we would fail to reject the null hypothesis.
Any help would be great
Answer:
-8 * 5 = -40
a⁵ * a = a⁶
b⁶ * b³ = b⁹
Answer is -40a⁶b⁹
Does the graph represent a function. Explain
Answer:
Yes
Step-by-step explanation:
functions include parabolas so yes!
from what area of the world is the earliest dated inscription with a symbol for zero?
Answer:
india
Step-by-step explanation:
An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, the corresponding 95% confidence interval for the mean jumping distance is (8.8104, 11.1248)cm. What is the corresponding 98% confidence interval for the mean jumping distance?
Answer:
[tex] 9.9676 - 2.326*0.5904 =8.594[/tex]
[tex] 9.9676 + 2.326*0.5904 =11.341[/tex]
Step-by-step explanation:
Notation
[tex]\bar X[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
For this case the 9% confidence interval is given by:
[tex] 8.8104 \leq \mu \leq 11.1248[/tex]
We can calculate the mean with the following:
[tex]\bar X = \frac{8.8104 +11.1248}{2}= 9.9676[/tex]
And we can find the margin of error with:
[tex] ME= \frac{11.1248- 8.8104}{2}= 1.1572[/tex]
The margin of error for this case is given by:
[tex] ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE[/tex]
And we can solve for the standard error:
[tex] SE = \frac{ME}{t_{\alpha/2}}[/tex]
The critical value for 95% confidence using the normal standard distribution is approximately 1.96 and replacing we got:
[tex] SE = \frac{1.1572}{1.96}= 0.5904[/tex]
Now for the 98% confidence interval the significance is [tex]\alpha=1-0.98= 0.02[/tex] and [tex]\alpha/2 = 0.01[/tex] the critical value would be 2.326 and then the confidence interval would be:
[tex] 9.9676 - 2.326*0.5904 =8.594[/tex]
[tex] 9.9676 + 2.326*0.5904 =11.341[/tex]
what is the length of the line?
Answer:
root 61
Step-by-step explanation:
You can use the distance formula or draw a triangle with sides 5 and 6
Can someone please help me??
Answer : The value of x is 4.1 cm.
Step-by-step explanation :
As we know that the perpendicular dropped from the center divides the chord into two equal parts.
That means,
AB = CB = [tex]\frac{15.6cm}{2}=7.8cm[/tex]
Now we have o calculate the value of x by using Pythagoras theorem.
Using Pythagoras theorem in ΔOBA :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](OA)^2=(OB)^2+(BA)^2[/tex]
Now put all the values in the above expression, we get the value of side OB.
[tex](8.8)^2=(x)^2+(7.8)^2[/tex]
[tex]x=\sqrt{(8.8)^2-(7.8)^2}[/tex]
[tex]x=\sqrt{77.44-60.84}[/tex]
[tex]x=\sqrt{16.6}[/tex]
[tex]x=4.074\approx 4.1[/tex]
Therefore, the value of x is 4.1 cm.
5/a - 4/b as a single fraction
Answer:
I'm not completely sure what you mean by a, "single fraction," but I'm pretty sure the answer you are looking for is [tex]\frac{5-4}{a-b}[/tex]
Step-by-step explanation:
Which transformations could have occurred to map AABC
to AA"B"C"?
O a rotation and a dilation
O a rotation and a reflection
O a reflection and a dilation
O a translation and a dilation
Answer:
A reflection and a dialation
Step-by-step explanation:
Reflection is when you flip a figure over a line. Rotation is when you rotate a figure a certain degree around a point. Dilation is when you enlarge or reduce a figure.In this case a rotation is not nessasary, so I would suggest a reflection in the y-axis and a dialation to shrink the triangle to A'B'C'
So for the transformations that could have occurred to map ABC to A'B'C' you should choose the answer
a reflection and a dialation
The transformations that occurred to map ABC to A'B'C are: C. a reflection and a dilation
Key Facts on TransformationsReflection is simply flipping a shape over an axis.Dilation means enlarging a figure or reducing the size of a figure.Rotation simply involves rotating a figure around a given point while maintaining same size.Translation is shifting the points of a figure to move it to another position.Thus, in the transformation shown, figure ABC was reflected over the y-axis and then dilated to give A'B'C'.
Therefore, the transformations that occurred to map ABC to A'B'C are: C. a reflection and a dilation
Learn more about transformation on:
https://brainly.com/question/1462871
If a square with a width of 30 feet a length of 72 feet, and the diagonal is 78 feet, would the square have right angles. Yes or No answer please explain
It is known that 4% of children carry a certain virus, but a leading health researcher suspects that the percentage is actually higher. Which of the following provides the most convincing evidence to support the researcher's suspicion?
A. Out of 5,000 randomly chosen children, 210 children carry the virus.
B. Out of 60 randomly chosen children, 3 children carry the virus.
C. Out of 5,000 randomly chosen children, 250 children carry the virus.
D. Out of 20 randomly chosen children, 1 child carries the virus.
Answer:
(C)Out of 5,000 randomly chosen children, 250 children carry the virus.
Step-by-step explanation:
[tex]\text{Option A}: \dfrac{210}{5000}=0.042=4.2\% \\\text{Option B}: \dfrac{3}{60}=0.05=5\% \\\text{Option C}: \dfrac{250}{5000}=0.05=5\% \\\text{Option D}: \dfrac{1}{20}=0.05=5\%[/tex]
The higher the research sample, the more credible the results. In options A and C, the research sample was 5000. However, since the relative frequency of children carrying the virus is 5% in both, we take the result with a higher number of positives.
Option C is the correct option.
Before a researcher specified the relationship among variables he must have a (an): A: Inventory of variables B: Inventory of propositions C: Arrangement of propositions D: Schematic diagram
Answer:
Option B
Step-by-step explanation:
Before a researcher specifies the relationship among variables he must have an inventory of propositions/constructs which are mostly stated in a declarative form. These are then tested by examining the relationships between measurable variables of this constructs/propositions.
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 900 voters in the town and found that 60% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 56%. Determine the P-value of the test statistic. Round your answer to four decimal places.
Answer:
Test statistic z = 2.3839.
P-value = 0.0086.
At a signficance level of 0.05, there is enough evidence to support the claim that the percentage of residents who favor construction is above 56%.
Step-by-step explanation:
This is a hypothesis test for a proportion.
The claim is that the percentage of residents who favor construction is above 56%.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.56\\\\H_a:\pi>0.56[/tex]
The significance level is 0.05.
The sample has a size n=900.
The sample proportion is p=0.6.
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.56*0.44}{900}}\\\\\\ \sigma_p=\sqrt{0.000274}=0.017[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.6-0.56-0.5/900}{0.017}=\dfrac{0.039}{0.017}=2.3839[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z>2.3839)=0.0086[/tex]
As the P-value (0.0086) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the percentage of residents who favor construction is above 56%.
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at random from the box and is then removed from the box. (After this first step, there are 14 chips left in the box. ) (2) Then, a chip is selected at random from the box (that is, from the remaining 14 chips) . Let B 1 be the event that the chip removed from the box at the first step of the experi- ment is red. Let B 2 be the event that the chip removed from the box at the first step of the experiment is blue. Let A be the event that the chip selected from the box at the second step of the experiment is red.Find P(B1), P(B2), P(A), P(B1|A), and P(B2|A).
Answer:
P(B1) = (11/15)
P(B2) = (4/15)
P(A) = (11/15)
P(B1|A) = (5/7)
P(B2|A) = (2/7)
Step-by-step explanation:
There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.
B1 is the event that the chip removed from the box at the first step of the experiment is red.
B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.
Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.
P(E) = n(E) ÷ n(S)
P(B1) = probability that the first chip selected is a red chip = (11/15)
P(B2) = probability that the first chip selected is a blue chip = (4/15)
P(A) = probability that the second chip selected is a red chip
P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)
P(B1 n A) = (11/15) × (10/14) = (11/21)
P(B2 n A) = (4/15) × (11/14) = (22/105)
P(A) = (11/21) + (22/105) = (77/105) = (11/15)
P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip
The conditional probability, P(X|Y) is given mathematically as
P(X|Y) = P(X n Y) ÷ P(Y)
So, P(B1|A) = P(B1 n A) ÷ P(A)
P(B1 n A) = (11/15) × (10/14) = (11/21)
P(A) = (11/15)
P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)
P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip
P(B2|A) = P(B2 n A) ÷ P(A)
P(B2 n A) = (4/15) × (11/14) = (22/105)
P(A) = (11/15)
P(B2|A) = (22/105) ÷ (11/15) = (2/7)
Hope this Helps!!!
How do i work out the probability of rolling two sixes
Answer: p = 1/25
Step-by-step explanation:
Ok, you know that the probability of rolling a six is p = 1/5
now, if you want to have two sixes, then you have two events with a probability of 1/5.
And as you know the joint probability for two events is equal to the product of the probabilities, then the probability of rolling two sixes is:
p = (1/5)*(1/5) = 1/25.
Bronson is ordering pizza at a restaurant, and the server tells him that he can have up to three toppings: spinach, bacon, and pepperoni. Since he cannot decide how many of the toppings he wants, he tells the server to surprise him. If the server randomly chooses which toppings to add, what is the probability that Bronson gets just spinach? Express your answer as a fraction or a decimal number rounded to four decimal places.
Answer:
The probability that Bronson gets just spinach is;
P = 1/7
or
P = 0.1429
Step-by-step explanation:
There are three possibilities;
- just one topping
- two topping
- three topping
For just one topping, the number of possible outcomes is;
N1 = 3C1 = 3!/(1!2!) = 3 possible outcomes
For two topping, the number of possible outcomes is;
N2 = 3C2 = 3!/(2!1!) = 3 possible outcomes
For three topping, the number of possible outcomes is;
N3 = 3C3 = 3!/3! = 1 possible outcomes
Total number of possible outcomes;
N = N1+N2+N3
N = 3+3+1 = 7
The probability that Bronson gets just spinach is;
Getting spinach is one out of seven possible outcomes, so;
P = 1/N = 1/7
P = 1/7 or 0.1429
Terry has a number cube that is numbered from 1 to 6. She rolls the cube 50 times. Which equation can be used to predict the number of times that she will roll a number that is greater than 4? P (number greater than 4) = StartFraction 1 over 6 EndFraction (50) P (number greater than 4) = StartFraction 2 over 6 EndFraction (50) P (number greater than 4) = StartFraction 3 over 6 EndFraction (50) P (number greater than 4) = StartFraction 4 over 6 EndFraction (50)
Answer:
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
This table represents a quadratic function with a vertex at (1, 2). What is the
average rate of change for the interval from x = 5 to x = 6?
Answer:
D: 9
Step-by-Step Explanation:
The average rate is synonymous with the slope. Since we want to find the average rate of change from x = 5 to x = 6, we will use the two points (5, 18) and (6, ?). We will need to find ? first.
Since the table represents a quadratic function and we are given the vertex, we can use the vertex form of a quadratic:
[tex]\displaystyle f(x)=a(x-h)^2+k[/tex]
Where (h, k) is the vertex.
The vertex is (1, 2). Hence:
[tex]f(x)=a(x-1)^2+2[/tex]
To determine a, pick a sample point from the table and solve for a. We can use (2, 3). Hence:
[tex](3)=a((2)-1)^2+2[/tex]
Solve for a:
[tex]1=a(1)^2\Rightarrow a=1[/tex]
Hence, our function is:
[tex]f(x)=(x-1)^2+2[/tex]
Evaluate the function when x = 6:
[tex]\displaystyle f(6)=(6-1)^2+2=27[/tex]
So, our two points are (5, 18) and (6, 27).
Again, to find the average rate of change between x= 5 and x = 6, find the slope between their two points. Hence:
[tex]\displaystyle m=\frac{27-18}{6-5}=9[/tex]
Our answer is D.
The sum of a number and twice the number is 24 what is the number?
Answer:
x = 8
Step-by-step explanation:
Step 1: Write out the expression
x + 2x = 24
Step 2: Combine like terms
3x = 24
Step 3: Isolate x
x = 8
And we have our final answer!
Answer:
X=8
Step-by-step explanation:
Please answer this correctly
Answer:
0
Step-by-step explanation:
The sorted data set is ...
1 2 3 3 5 7 8 9
The median is the average of the middle two numbers: (3+5)/2 = 4.
Replacing one of the 3s with a 1 makes the data set be ...
1 1 2 3 5 7 8 9
The average of the middle two numbers is (3+5)/2 = 4.
The median increases by 4 - 4 = 0.