Use the distributive property to identify the equivalent expression.

8x + 10

Answer:

Step-by-step explanation:

surface area = 2πrh + 2πr²

where r = 7 m radius

           h = 2 m

plugin values into the formula

surface area = 2πrh + 2πr²

                     = 2π (7) 2  +  2π (7)²

                     = 87.965  +  307.867

                     = 395.841 m²

Answer:

395.841 m²

Step-by-step explanation:

surface area = 2πrh + 2πr² and r = 7 m radius

h = 2 m

Plugin

 2π (7) 2  +  2π (7)²

multiply into itself than add

87.965  +  307.867

add

395.841 m²

Therefore your answer would be 395.841 m²

Answer:

6543

Step-by-step explanation:

Not much to explain lol

Here,

Odd numbers are 3 and 5.

The largest odd number =6543

Answer: 8m ^ 4n ^ 5

Answer:

Angle 8

Step-by-step explanation:

Angle 8 is the corresponding angle to angle 4. Corresponding angles are angles that are in the same relative position at each intersection. Since the lines are parallel they are also congruent. If you look at the lines both angle 8 and 4 are on the bottom right side of the intersection, therefore they are corresponding angles.

Answer:

Her brother is 10 years old

Step-by-step explanation:

14 ÷ 2 = 7

7 + 3 = 10

The answer is 10

Answer:

5.38516480713

Step-by-step explanation:

a^2+b^2=c^2

5^2+2^2=c^2

25+4=c^2

c^2=square root of 29

c=5.38516480713

Answer:

what chap is this

Step-by-step explanation:

Answer:

0.75

Step-by-step explanation:

To find the slope of the graph, you have to find the rise and the run by any two points on the graph. (I'm going to calculate using the two blue dots as shown in the picture)

[tex]\frac{rise}{run}[/tex] = [tex]\frac{(-2)-(-5)}{4-0}[/tex]

           = [tex]\frac{-2+5}{4}[/tex]

           = [tex]\frac{3}{4}[/tex]

           = 0.75

Answer:

6 eggs per chicken

Step-by-step explanation:

hdjdjidbdudbddjow0s

Answer:

6

Step-by-step explanation:

Answer:

Ax=6

Y=12

Therefore a=6, x=1, y=12

Answer:

{([tex]\frac{6}{a}[/tex],12)}

Step-by-step explanation:

[tex]\left \{ {{ax+y=18} \atop {4ax-y=12}} \right.[/tex]

[tex]5ax = 30[/tex]

[tex]x = \frac{6}{a}[/tex]

[tex]a(\frac{6}{a}) + y = 18[/tex]

6 + y =18→y=12

[tex]4a(\frac{6}{a}) - 12 = 12[/tex]

6 - 12 = 12 → 12 = 12 true  x=[tex]\frac{6}{a}[/tex]  y=12

Answer:

$12.55

Step-by-step explanation:

25-6.75=18.25

18.25-3.70=14.55

14.55-2=12.55

Miguel has $12.55 left

Answer:

0.75

0.7205882

25.5

Result is significant at α = 0.01 and α = 0.05

Model improved

Step-by-step explanation:

Given that:

Number of observations (n) = 20

Total sum of squares (SST) = 1000

Model sum of squares (SSR) = 750

1) R² = SSR / SST = 750 / 1000 = 0.75

2.)

Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))

k = number of regressors = 2

Adj R² = 1 - ((1000 - 750) / (20-2-1)) / (1000 / (20 - 1))

1 - 0.2794117 = 0.7205882

3.) Fstat = (SSR / k) / ((SST - SSR) / (n - k-1))

= (750 /2) / ((1000 - 750) / (20 - 2 - 1))

= 25.5

4.) At α = 0.05

Fα,k,(n - k-1) = F0.05, 2, (20 - 2 - 1) = F0.05,2, 17 = 3.5915 (f distribution calculator)

Fstat > F0.05, 2, (20 - 2 - 1)

25.5 > 3.5915 (Hence result is significant at α = 0.05

At α = 0.01

Fα,k,(n - k-1) = F0.01, 2, (20 - 2 - 1) = F0.01,2, 17 = 6.112 (f distribution calculator)

Fstat > F0.01, 2, (20 - 2 - 1)

25.5 > 6.112 (Hence result is significant at α = 0.01

Adjusted R² if a 3rd regressors is added : k = 3

Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))

k = number of regressors = 3

SSR = 785

Adj R² = 1 - ((1000 - 785) / (20-3-1)) / (1000 / (20 - 1))

1 - 0.2553125 = 0.7446875

Adjusted R² value is now 0.7446875 which is greater than with 2 regressors,. Hence, adding a third regressors improved the model.

Answer:

[tex]t=\dfrac{9\pm 3}{6}[/tex]

[tex]1\ \text{hour}[/tex]

[tex]2\ \text{hour}[/tex]

Step-by-step explanation:

s = Speed of Emile = 6 miles/hour

d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]

Time taken to find the minimum and maximum time Emile ran for is

[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]

The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]

The time taken is

[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]

The minimum number of hours Emile runs is 1 hour.

[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]

The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].

Answer:

|6x – 9| = 3

1 Hour

2 Hours

Step-by-step explanation:

The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.

Answer:

Your answer is: ↓

If your converting in Logarithmic Form then your answer is: [tex]log_{i}(-1)=2[/tex]

If you are trying to figure if that equation is determined T/F: The answer is T.

If you are trying to evaluate (expand) the question your answer is:[tex]-1=-1[/tex]

Step-by-step explanation:

Hope this helped : )

Answer:

C. 30 is the correct answer.

Step-by-step explanation:

Answer:

The equations have one solution at (5, -5).

Step-by-step explanation:

We are given a system of equations:

[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]

This system of equations can be solved in three different ways:

Graphing the Equations

We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].

Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.

[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]

Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].

Equation 2 also needs y to be isolated.

[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]

Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].

Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.

The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]

Now, we can place these values in our table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.

For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.

[tex]\bullet \ \text{For x = 0,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]

[tex]\bullet \ \text{For x = 1,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]

[tex]\bullet \ \text{For x = 2,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]

[tex]\bullet \ \text{For x = 3,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]

[tex]\bullet \ \text{For x = 4,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]

[tex]\bullet \ \text{For x = 5,}[/tex]

[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]

And now, we place these values into the table.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.

Equation 1                  Equation 2

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]                 [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]

Therefore, using this data, we have one solution at (5, -5).

Answer: 3 numbers

Step-by-step explanation:

For this questions to be solved, we need to write the multiples of both 3 abd 5 that are less than 50. This will be:

Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48

Multiples of 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45.

Common multiples = 15, 30 and 45

Therefore, the numbers that is less than 50 that are multiples of both 3 and 5 are 3 numbers

Answer:

Slope = -69, y-intercept is (0, -346)

Step-by-step explanation:

y=-69x-346

x=0

y= -69(0)-346

y=0-346

y=0

sople -69 coefficient of x

Answer:

c

Step-by-step explanation:

Answer:

[tex] - \bigg(3a - \frac{5}{2} b) \bigg)^{2} [/tex]

Step-by-step explanation:

[tex]15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2} [/tex]

Answer:

2 and 2/5

Step-by-step explanation:

Trust me on this, also can I have brainlest please? Hope you do well!

2 and two fifths i took the test 6 years ago

Answer:

36

Step-by-step explanation:

4 benches in 1 hour

? benches in 9 hours

36 benches

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

Answer:

36 is the answer :)

Step-by-step explanation:

Answer:

62

Step-by-step explanation:

Answer:

238.328

Step-by-step explanation:

The product of 0.62 x 10 is 6.2. So, I did 6.2 to the power of 3, which is 238.328.

Answer: 3

Step-by-step explanation:

Answer:

300 shirts

Step-by-step explanation:

You can divide 12% by itself to find one percent, then divide the 36 shirts by 12 as well.

What you do to one side, you need to do to the other.

Now that we have our numbers after dividing (you should have 1% and 3 shirts) you can see what 100% would be. To do this you would multiply 1% by 100 and multiply 3 shirts by 100.

Now we know that 12% of 300 shirts is 36 shirts.

Answer:

2

4/.5 = 2

Therefore, your answer is 2, or A. Hope this helped!

Answer:

the answer is B) 8

Step-by-step explanation:

hope this helped sorry if it didn't and if it's wrong sorry for that also.

Answer:

$11.83

Step-by-step explanation:

1 gallon = 3.785 litres

0.5(1/2gallon) = x liters

x = 0.5 × 3.785 liters

x = 1.89271 liters

0.8 liter = 100 pesos

1.89271 liters = x pesos

x = 1.89271 × 100/0.8

x = 236.58875 pesos

Converting to dollars

1 mexican peso = $0.050

236.58875 pesos = x

x = 236.58875 × $0.050

x = $11.8294375

Approximately = $11.83

A half gallon jug of the same wine cost in dollars $11.83