Answer and Explanation:
Suppression: refers to an allele of a gene that can annul the expression of the other gene. The suppressor gene might be associated with its own particular phenotype (such as color) or it might not have any detectable effect other than suppressing the other gene expression.
Available data:
Two true-breeding white strains of the plant Illegitimati noncarborundum were mated the F1 progeny were all white the F1 plants were allowed to self-fertilize 126 white-flowered and 33 purple-flowered F2 plants grew.a. Using the ratio of these offspring, determine how flower color is inherited?
There are two genes involved in the color expression, we might define them as C gene for color, and W gene for suppression of the color. So, W inhibits the expression of C. The dominant C allele expresses purple, while the recessive allele does not express color.
As there are two genes interacting, there are 16 possible offspring produced. So, if the total individuals in the F2 are 159 (126 + 33), then:
159 individuals in the F2 ------------ 100% progeny ---- 16
126 white-flowered individuals------79.25% -----------12.68
33 purple-flowered individuals -----3.32 % ------------ 3.32
These proportions approximate to the proportion 13:3, corresponding to the genetic interaction "suppression".
b. Define allele symbols. Indicate (using these symbols) the genotypic classes and the corresponding phenotypic ratios of the F2.
As we mentioned before, the proposed symbols for these genes are C for the color gene and W for the suppressor gene. The dominant allele C expresses purple, while the recessive allele c does not express any color. W allele inhibits C, and w allele does not inhibit c.
1st Cross:
Parental) WWCC x wwcc
Gametes) WC WC WC WC
wc wc wc wc
Punnet square) WC WC WC WC
wc WwCc WwCc WwCc WwCc
wc WwCc WwCc WwCc WwCc
wc WwCc WwCc WwCc WwCc
wc WwCc WwCc WwCc WwCc
F1) 100% WwCc
2nd Cross:
Parental) WwCc x WwCc
Gametes) WC Wc wC cc
WC Wc wC cc
Punnet square) WC Wc wC wc
WC WWCC WWCc WwCC WwCc
Wc WWCc WWcc WwCc Wwcc
wC WwCC WwCc wwCc wwCc
wc WwCc Wwcc wwCc wwcc
F2) White-flowered plants 13/16 = 9/16 + 3/16 + 1/16
W-C- 9/16
W-cc 3/16
wwcc 1/16
Purple-flowered plants 3/16
wwC-
c. A white F2 plant is allowed to self-fertilize. Of the progeny ¾ are white-flowered, and ¼ are purple-flowered. What is the genotype of the white F2 plant? Briefly explain how you determined your answer.
3/4 = 12/16 white
1/4 = 4/16 purple
To get the proportion 3:1 we should self-fertilize and individual that is heterozygous for one of the genes and homozygote for the other gene. As we have 1/4 of purple-flowered plants, we can assume that there must be present the dominant allele C for purple color. So, the homozygote dominant allele should belong to the C gene, and the W gene should be heterozygous one needed to get the required proportion. The cross would be like:
Parental) WwCC x WwCC
Gametes) WC wC WC wC
WC wC WC wC
Punnet square)
WC wC WC wC
WC WWCC WwCC WWCC WwCC
wC WwCC wwCC WwCC wwCC
WC WWCC WwCC WWCC WwCC
wC WwCC wwCC WwCC wwCC
F3) White-flowered plants
4/16 WWCC
8/16 WwCC
Purple-flowered plants
4/16 wwCC
The flower white trait is inherited as an epistatic trait because it resembles a 13:3 phenotypic ratio.
Epistasis, also called dominant suppression, is a type of gene interaction that deviates from 9:3:3:1 phenotypic proportions due to the presence of a single allele that suppresses the expression of another gene.In this case, the C can be defined as the color gene and S the suppressor gene.Parental P line >> SsCc x SsCcGametes >> SC Sc sC ccF1 Punnet squareSC Sc sC sc
SC SSCC SSCc SsCC SsCc
Sc SSCc SScc SsCc Sscc
sC SsCC SsCc ssCc ssCc
sc SsCc Sscc ssCc sscc
F2 White plants = S-C- 9/16 + S-cc 3/16 + sscc 1/16 >> F2 White plants = 9/16 + 3/16 + 1/16 = 13/16 The genotype of the white F2 plant is SsCC (it give us a phenotypic rate of 3:1 after auto pollination).In conclusion, the flower white trait is inherited as an epistatic trait because it resembles a 13:3 phenotypic ratio.
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Fur color in mice is affected by a single gene. The gene for fur color has two alleles: B that causes dark brown fur, and b that causes light brown fur. In a mouse with dark brown fur, the genotype could be BB or:_________
Answer:
The genotype could be BB or Bb
Explanation:
The genotype could be Bb which means it has heterozygous alleles.
The B which is allele for dark brown fur is dorminant and b for light brown is recessive. In this case, the dorminant allele masked the effect of the recessive allele b which make the dorminant allele B to be expressed phenotypically.
Complete this sentence. The CNS communicates with the body proper through ________. View Available Hint(s) Complete this sentence. The CNS communicates with the body proper through ________. some cranial nerves, some spinal nerves, and some additional nerves that were mentioned but not discussed in the tutorial the spinal nerves but not specifically through the cranial nerves the cranial nerves but not specifically through the spinal nerves some (but not all) of the cranial nerves and some (but not all) of the spinal nerves the cranial nerves and the spinal nerves
Answer:
The correct answer is - The cranial nerves and the spinal nerves.
Explanation:
The central nervous system or CNS includes the brain and the spinal cord of the nervous system where it takes sensory information, integrates, and responds accordingly. The spinal cord acts as a conduit for signals between the brain and the rest of the body.
Spinal nerves and crania; both play an essential role in taking sensory information and respond accordingly. Spinal nerves are nerves that help in sending motor, sensory, and autonomic signals between the CNS and the body. The cranial nerves supply information to the CNS and then from the CNS to the body.
Thus, the correct answer is - The cranial nerves and the spinal nerves.
What type of enzyme can activate another enzyme by adding a phosphate from ATP?
Answer:
Here my answer goes.......
Explanation:
In biochemistry, a kinase is an enzyme that catalyzes the transfer of phosphate groups from high-energy, phosphate-donating molecules to specific substrates. This process is known as phosphorylation, where the substrate gains a phosphate group and the high-energy ATP molecule donates a phosphate group.
You inject an antibody against the protein tubulin into a living animal cell. After the injection, the cell begins mitosis, but the chromosomes do not become attached to the spindle; in fact, there is no spindle. The contractile ring does, however, form. What do these results mean?
Answer:
The mitotic spindle was “ blocked ” by the action of the antibodies that bind to tubulin.
Explanation:
The tubulin heterodimers consist of α- or β-tubulin structures that form the microtubules, which represent the cytoskeletal of eukaryotic cells. During mitosis, the microtubules are arranged in order to form the mitotic spindle, this structure is critical for the segregation of homologous chromosomes during Anaphase.
Interphase microtubules are required for attaching chromosomes in the middle of the cell during its division, thereby it is expected that the antibodies bind to these microtubules during this process.
The contractile ring is formed by approx. 20 actin filaments that encircle the middle of dividing cells, thereby it is expected that these antibodies are specific of tubulin heterodimers.
If two genes are found on different chromosomes, or if they are far enough apart on the same chromosome that the chance of a crossover between them is very high, the genes are considered to be unlinked. Unlinked genes follow Mendel’s law of independent assortment. If, however, two genes tend to "travel together" because they are near one another on the same chromosome, they are said to be linked. Linked genes do not follow Mendel’s law of independent assortment. In this tutorial, you will compare the inheritance patterns of unlinked and linked genes.
Part A - Independent assortment of three genes
A wild-type tomato plant (Plant 1) is homozygous dominant for three traits: solid leaves (MM), normal height (DD), and smooth skin (PP).
Another tomato plant (Plant 2) is homozygous recessive for the same three traits: mottled leaves (mm), dwarf height (dd), and peach skin (pp)
Leaves Height Fruit Plant 1 solid normal Smooth (PP) (MM) (DD) Plant 2 mottled (mm) dwarf peach (Pp) (dd)
In a cross between these two plants (ADOPPx mmddpp), all offspring in the F, generasion are wild type and heterozygous for all three traits (AmDdPp)
Now suppose you perform a testcross on one of the F, plants (mOoPpx mmodpp). The F, generation can include piants with these eight possible phanotypes
a) solid normal, smooth
b) solid norma peach
c) solid dwarf smoom
d) solid dvarf, peach
a) motted nomal, amooth
b) motted, normal pesch
c) mottied, dwad smooth
d) moted dwaf peach
Assuming that the three genes undergo independent assortment, predict the phenotypio ratio of the offspring in the F, generation.
Complete question:
A wild-type tomato plant (Plant 1) is homozygous dominant for three traits: solid leaves (MM), normal height (DD), and smooth skin (PP).
Another tomato plant (Plant 2) is homozygous recessive for the same three traits: mottled leaves (mm), dwarf height(dd), and peach skin (pp).
In a cross between these two plants (MMDDPP x mmddpp), all offspring in the F1 generation are wild type and heterozygous for all three traits(MmDdPp).
Now suppose you perform a testcross on one of the F1plants (MmDdPp x mmddpp). The F2 generation can include plants with these eight possible phenotypes:
solid, normal, smooth
solid, normal, peach
solid, dwarf, smooth
solid, dwarf, peach
mottled, normal, smooth
mottled, normal, peach
mottled, dwarf, smooth
mottled, dwarf, peach
Assuming that the three genes undergo independent assortment, predict the phenotypic ratio of the offspring in the F2 generation.
Answer and Explanation:
Cross 1:
Parental) MMDDPP x mmddpp
F1) MmDdPp
Cross 2: Testcross
Parental) MmDdPp x mmddpp
Gametes) MDP MdP MDp Mdp mDP mdP mDp mdp
mdp mdp mdp mdp mdp mdp mdp mdp
Punnet Square)
mdp
MDP MmDdPp
MdP MmddPp
MDp MmDdpp
Mdp Mmddpp
mDP mmDdPp
mdP mmddPp
mDp mmDdpp
mdp mmddpp
F2) 8/64 = 1/8 MmDdPp, solid leaves, normal height, smooth skin
8/64 = 1/8 MmddPp, solid leaves, dwarf height, smooth skin
8/64 = 1/8 MmDdpp, solid leaves, normal height, peach skin
8/64 = 1/8 Mmddpp, solid leaves, dwarf height, peach skin
8/64 = 1/8 mmDdPp, mottled leaves, normal height, smooth skin
8/64 = 1/8 mmddPp, mottled leaves, dwarf height, smooth skin
8/64 = 1/8 mmDdpp, mottled leaves, normal height, peach skin
8/64 = 1/8 mmddpp, mottled leaves, dwarf height, peach skin
Another way of predicting the phenotypic ratio of the offspring in the F2 generation is by performing a testcross for each gene by separately and then multiplying their genotypic proportions. This is:
Leaves Gene
Parental) Mm x mm
Gamtes) M m m m
Punnet Square) M m
m Mm mm
m Mm mm
F2) 1/2 Mm
1/2 mm
High Gene
Parental) Dd x dd
Gamtes) D d d d
Punnet Square) D d
d Dd dd
d Dd dd
F2) 1/2 Dd
1/2 dd
Skin Gene
Parental) Pp x pp
Gamtes) P p p p
Punnet Square) P p
p Pp pp
p Pp pp
F2) 1/2 Pp
1/2 pp
To get the phenotypic ratio of the offspring we multiply the genotypic proportion for each trait by the genotypic proportions of the other two traits, like this:
For plants with solid leaves, normal height, smooth skinsolid leaves ratio -> 1/2
normal height ratio -> 1/2
smooth skin ratio -> 1/2
MmDdPp ratio: 1/2 x 1/2 x 1/2 = 1/8
For plants with solid leaves, dwarf height, smooth skinMmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with solid leaves, normal height, peach skinMmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with solid leaves, dwarf height, peach skinMmddpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with mottled leaves, normal height, smooth skinmmDdPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with mottled leaves, dwarf height, smooth skinmmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with mottled leaves, normal height, peach skinmmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
For plants with mottled leaves, dwarf height, peach skinmmddpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8
Given the behavior and ecology of this insect, what are some factors that could cause the incidence of Chagas disease to increase in Central and South America in areas like the banana plantation, and why
Answer and Explanation:
There are many physical elements such as temperature, precipitation, humidity, altitude, vegetation, among others, that influence the presence of the insects that transmit the Chagas diseases. Its transmission seems to be enhanced by other social elements, such as the deficiency in basic services, lack of planning, the socio-economical conditions, cultural conditions. Altogether, these factors intervene in the presence of the Chagas disease, a systemic infection caused by the protozoa Trypanosoma cruzi. This protozoan is hosted by different wild and domestic mammals, transmitted to the human by hematophagous insects. The transmission occurs through dejections deposited on skin or mucose during or after the feeding process.
Different rural areas in Central and South America are characterized by a mountain relief (temperatures between 15 and 30ºC - relative humidity between 50 and 90%), as well as by a plane relief associated with alluvial plain (temperature between 20 and 35ºC - media relative humidity of 75%). Vegetation in the mountain area provides a natural habitat to the triatomines, the insects that transmit the Chagas disease.
Constant deforestation in mountains, soil move, the cutting down, firing, have destroyed the natural habitat of the insects, becomming the cause of their arrival to populated centers. As their environment is destroyed, insects migrate to new areas and find refuge in precarious houses that surround the affected areas. Most of these houses have clay walls, a roof made of branches, and no floor. People that live in these conditions do not have economic resources. Indexes of infestation in these houses are high due to the material used for their construction. Insects tend to establish near a source of food, such as domestic animals or even humans. It is also common that these houses have chicken coops and farmyards that also offer good conditions for the insects to live in.
Economic activities are important variables to consider, as these define the way of living in a population.
Agriculture activities are performed with no control or planning. People deforest to plant, getting in contact with the insects' natural habitat, producing environmental changes, and getting in touch with them, enhancing the risks of being infected and of transportin the insects.
Rank each of the following in terms of their appearance in the cell during carbohydrate catabolism. 1 represents the first to appear, and 6 represents the last. (Assume only a single round of carbohydrate catabolism took place.)
(6 items)
(Drag and drop into the appropriate area)
First
1. Glucose
2. Fructose-1,6- bisphosphate
3. Glyceraldehyde-3. phosphate
4. Pyruvate
5. Succinyl-CoA
6. Citric acid
Answer:
Explanation:
The correct order of above question is -
1. Glucose
2. Fructose - 1,6 - biphosphate
3. Glyceraldehyde - 3 - phosphate
4. Pyruvate
5. Citric acid
6. Succinyl co- A
Explanation - These all are the step of carbohydrate metabolism in a cell. The carbohydrate is catabolise and successively into smaller forms.
First four steps show the glycolysis process in which by use of ATP glucose molecule breakdown into simpler one.
Last two steps show the kerb's cycle in which citric acid (six carbon compound) is converted into succinyl co - A ( four carbon compound) .
What is meant by the following statement about the cell membrane?
The cell membrane is said to be semipermeable.
O A. It will not allow any molecules to pass through.
oso
O B. It does not contain any membrane proteins.
O C. It is very selective about what it allows to pass through.
D. It allows all polar molecules into the cell.
describe some other kinds of activities that would benefit the most from each molecule n the table
Answer:
The macromolecules; protein helps to gain muscle, fat helps provide stored energy for longer period, carbohydrates provide immediate energy.
Explanation:
Proteins are the macromolecules that help on the muscle building and storage. Bodybuilders utilize proteins to build their body and muscle protein. Protein has equal energy value as carbohydrates.
Fat help in providing energy when there is no carbohydrate provided energy to utilize. In the winters some animals hibernate they utilize the fat provided energy during the hibernation period.
Carbohydrate gives energy immediately for the cellular process and also help athletes to provide energy immediately. Runners drink carbohydrates based drinks to get energy before the race.
Which is an example of foraging as a benefit of social behavior?
Answer:
kinda like foraging a signature
Explanation: if I'm wrong go randonauting
An elephant and a tree are both living things. According to cell theory, what can you conclude about these two very different organisms?
Answer:
An elephant and a tree are both living things. According to cell theory, what can you conclude about these two very different organisms?
which statement describes abiotic factors in an environment ?
Which of the following statements is true?A. An isolated system cannot exchange either matter or energy with its surroundings. B. Organisms are open systems when they are out of their habitats. C. Organisms are isolated systems because they have their own machineries in the cells to supply all the matter and energy they need. D. Open systems are called as such because they do not absorb energy, but just openly release the energy to their surroundings.
Answer:
A
Explanation:
An isolated system can NOT exchange energy or matter with it's surroundings. This is why it is isolated.
Which sentence best describes what happens after sunlight hits photosystem
II?
A. Solar energy changes ADP into ATP.
B. NADPH turns into NADP+.
C. Glucose forms from carbon dioxide molecules.
O D. Electrons in the third protein gain new energy from light.
Answer:
A. Solar energy changes ADP into ATP.
Explanation:
The phase of the photosynthesis is based on the light that reacts as the pigment molecule absorbs energy from the sunlight and the photons strike the photosystem to initiate the photosynthesis. Energy transports through the electron that pumps hydrogen ions and forms an electrochemical gradient. The ADP is a combination of phosphate to form the ATP in the reaction i.e ADP +energy to ATP plus water. This usually takes place by the storage of high energy to ATP as sugar molecules that are sent phase of photosynthesis.Answer:
A. Solar energy changes ADP into ATP
Explanation:
Photosynthesis is the process in which plants make there own food by utilizing sunlight that converts water and oxygen into carbon dioxide and energy.
There are two systems in photosynthesis: Photosystem II and Photosystem I.
In photosystem II ADP + P is converted into ATP driven by electron gradients formed in the thylakoid membrane.
Hence, the correct answer is A.
After getting their results in, a group of scientists went back and looked at their study. As planned, their experiment consisted of three groups. The first group received a new medicine at a normal dose, the second group received the medicine at half the dose, and the third group received the medicine at twice the dose. Which of the following best describes what went wrong with the scientists’ study?
Answer:
Their experimental design lacks control group
Explanation:
Based on what I read, the scientists don't have a control group as one of the main groups thus they cannot, in scientific sense, say that the medicine is better or worse. You always need a control group receiving no intervention because then we can compare groups and assess the effectiveness of that intervention (in our case if we had control group vs people who received the medicine, we could see if the people who received the medicine had improved condition etc when compared to participants who did not receive anything)
There is no control group in their experimental design. According to what I've read, the scientists don't have a control group as one of the primary groups. Thus, option C is correct.
What is control group?To determine if the treatment is better or worse in a formal scientific sense. You should always have a control group that does not receive any treatment because this allows us.
To compare the groups and evaluate the effectiveness of the intervention. In our case, if we had a control group and participants who did not receive any treatment, we could see if those participants had better health overall.
By focusing on the impact of a single independent variable, a cause-and-effect link can be established.
The independent variable is altered in the treatment group while being held constant in the control group by researchers. The findings of these groups are then compared.
Therefore, no control group in their experimental design.
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In your own words, explain why the geological structures in Florida are less complex than the geological structures in Colorado.
Answer:
the primordial sea. Colorado is just higher in elevation, prior to be driven up. More of the earths crust is exposed in Colorado than in Florida.
. g Determine the number of moles in 0.05 µg of a 300 bp insert DNA. There are 660 g/mol-bp. What is the molar ratio of insert to vector if you have 10 ng of vector that is 2686 bp?
Answer:
a. 2.4 x 10^-24 mol
b. 5.4 x 10^4
Explanation:
a. Mass of DNA (of 0.05µg)= 0.05µg x number of base pairs x 650Da
=0.05x300x650Da
(1 Da=1.67x10-24g)
=9750 x 1.67 x 10^-24
=16282.5 x 10^-19µg =1.62 x10^-21 g
No. of moles of insert DNA=mass of DNA(in g)/mass of one mole in g/mol
=1.6 x 10^-21g/660 g/mol
=2.4 x 10^-24 mol
Hence, moles of the insert DNA is calculated as 2.4 x 10^-24
b.
First of all, let us determine number of moles of vector to calculate the molar ratio.
No. of moles of vector=10 x 10^-9 x 2686 x 650 x 1.67 x 10-24/660
=2.68x6.5x1.67x10-27/660
=4.4 x 10^-29 mol
Molar ratio of insert to vector=2.4 x 10^-24/4.4x10^-29
=5.4 x 10^4
So, the molar ratio of the vector and insert as per the data is calculated as 5.4 x 10^4
Why do processes and activities suddenly change the global temperature?
Answer:
hey mate here is your answer
Answer:
Earth's temperature depends on the balance between energy entering and leaving the planet’s system. When incoming energy from the sun is absorbed by the Earth system, Earth warms. When the sun’s energy is reflected back into space, Earth avoids warming. When absorbed energy is released back into space, Earth cools. Many factors, both natural and human, can cause changes in Earth’s energy balance, including:
Explanation:
Variations in the sun's energy reaching Earth
Changes in the reflectivity of Earth’s atmosphere and surface
Changes in the greenhouse effect, which affects the amount of heat retained by Earth’s atmosphere
Which statement best explains why water is essential for all living things?
A) Water makes up 65% of human beings.
B) Water is an essential component of blood.
C) Water covers 7596 of Earth's surface.
D) Water is necessary for cellular functions.
Answer:
d) Water is necessary for cellular functions.
Explanation:
if we cant work on a cellular level, we wont work at all!
hope i helped!
Answer:
the answer is d) in edge 2021
Explanation:
water is necessary for cellular functions
HOPE THIS HELPS
Which environmental change is considered short term?
forest fire
ice age
mountain building
solar energy changes
Edunuity
Answer:
forest fires
Explanation:
An environmental change that occurs quickly and affects organisms immediately (causing behavioral adaptations).
floods, forest fires, blizzards, volcanic eruptions,
Answer: Forest fires[A]
Explanation:
got 100% on the edge2020 Unit Test
have a good day:)
Correctly order the production and transport of sperm through the male reproductive system. Semen is released from the penis. Sperm are produced in the testes. Sperm leave the testes through the semen duct. In the semen duct, fluids from the glands are added to the sperm.
Answer:
sperm are produced in testes. sperm leaves through the semen duct. In the semen duct,fluids from the glands are added to the sperm. semenis releasedfrom the penis
Answer:
4 semen is realeased through the penis
1 sperm is produced in the testes
2 sper leaves the semen duct
3 fluids from the glands add to the sperm
Explanation:
Each of the following occurs during apoptosis of a cell except:__________. a. bleb formation. b. formation of apoptotic bodies. c. rupture of the cell, releasing cytoplasmic contents. d. DNase fragmentation of DNA flipping phosphatidylserine to the outer leaflet of the plasma membrane.
Explanation:
The process of programmed cell death, or apoptosis, is generally characterized by distinct morphological characteristics and energy-dependent biochemical mechanisms.
Each of the following statements is either true or false.
1. The microscope lens may be cleaned with any soft tissue.
A. True
B. False
2. The microscope should be stored with the ail immersion lens in position over the stage.
A. True
B. False
3. When beginning to focus, use the ssanning objective lens.
A. True
B. False
4. When focusing on high power, always use the coarse adjustment knob to focus.
A. True
B. False
5. A coverslip should always be used with wet mounts.
A. True
B. False
Answer:
1.false.
There are special lense tissues for this which will not scratch the lense so that the focal power will nit be affected. Grit -free lens paper,Kimwipes or Kodak lens are ideal cleaning materials.
2.This is also false. Microscope should be covered with dust cover, and even in the cabinet,It should never be left without am eyepiece.
3.True.
This gives he lowest magnification, which allows for wide view of the specimen in order get the specific spot to focus on.It has magnification power of 10x eyepiece lens.Thus a 4x scanning objective lens therefore gives total magnification of 40x.
4.False,
This will break the objective lens.Fine adjustment knob should be use.This will gives the sharpest focus,using a coarse knob will crack the lens because the working distance for focusing will be too small, and suing this will damage the objective lens,
5.False,only the wet mount should be used.High power and oil lens should not be used as this will reduce the efficiency of the microscope.
What caWhat can be known about Mendel’s five-part hypothesis?n be known about Mendel’s five-part hypothesis?
Answer:
It is an answer to a scientific question and is based mostly on research.
Explanation:
Mendel five part hypothesis was also known as the law of segregation. This law explain the how traits are inherited in living organisms. Mendel's theory discovered that there are two alleles for a single gene and that one of these alleles is inherited from each parent, which forms the basis of the trait in the progeny(offspring).
Mendel’s hypothesis was considered true after various experiments and analysis and also answer the question of how the different traits are passed on from parent to progeny. This validates it being an answer to a scientific question and it being based mostly on research.
Answer:
A) It is an answer to a scientific question and is based mostly on his research.
Explanation:
Edgnty
Type the correct answer in the box. Spell all words correctly. Which training does Michael need to work as a veterinarian in a zoo? Michael loves animals, so he studied to become a veterinarian. However, he wishes to work for a well-known zoo in Ohio. He would probably need to acquire training in zoo to be hired.
Answer:
The correct answer yo get a degree in veterinary medicine.
Explanation:
In U. S. a veterinarian needs to have the proper training and degree to practice at any place like zoo or clinics. Michael needs a Doctor of Veterinary Medicine degree known as D.V.M. or V.M.D. from an accredited veterinary medicine college. It is a four years program that includes classroom studies, laboratory experience, and clinical work.
Answer:
The right answer is zoo MEDICINE
Explanation:
Large zoos often seek veterinarians who possess additional training in zoological medicine.
(For Plato users, I got it right on the test)
Identify which type of study the following example describes.
Severing the connections between visual regions and the rest of the brain in animals, and observing the animals failure to recognize objects,
Answer:
They are training animals in a maze and recording physiological changes in their brains, Stimulating a brain structure and recording subsequent changes in movement, Introducing two adults that are potentially attracted to each other, and then measuring their sex hormone levels, Measuring the brain volumes and intelligences of people in a group, Observing enlarged cerebral ventricles in the brains of many people with schizophrenia, Severing the connections between visual regions and the rest of the brain in animals, and observing the animals’ failure to recognize an object, and Studying the relationship between a sex hormone treatment and strength of an animal’s mating behavior.
Explanation:
Which statement about venation is INCORRECT?
Some flowering plants have leaves that lack venation even though the stems and roots have vascular bundles.
Venation is important for delivering water to leaf cells and taking sugars to the stem.
Venation refers to arrangement of the veins within a leaf.
Venation patterns include pinnate, palmate and dichotomous.
In general, monocots exhibit parallel venation.
Answer:
Some flowering plants have leaves that lack venation even though the stems and roots have vascular bundles.
Explanation:
Venation refers to the arrangement of the veins in the leaf of a plant which are involved in the transport of material in the plants.
The xylem present in leaves transports water to the leaf whereas phloem transports sugar from the leaves to different parts of the plants. In angiosperms, no plants are known whose leaves lack the veins but stem and root possess the vascular bundles.
Monocot is characterised by their parallel veins whereas dicots possess reticulate veins. Also, the compound leaves possess one of the three types of venation that are palmate, pinnate and dichotomous.
Since no angiosperm posses, veinless leaves, therefore, is the correct answer.
Using the key choices choose all responses that apply to the following descriptions. Some terms may be used more than once.
Key:
a. stratum basale
b. stratum corneum
c. stratum granulosum
d. stratum lucidum
e. stratum spinosum
f. papillary layer
g. reticular layer
h. epidermis as a whole
i. dermis as a whole
_____________1. layer of translucent cells in thick skin containing dead keratinocytes
_____________2. two layers containing dead cells.
_____________3. dermal layer responsible for fingeiprints.
_____________4. epidermal layer exhibiting the most rapid cell division.
_____________5. layer including scalelike dead cells, full of keratin, that constantly slough off.
_____________6. layer named for the numerous granules present.
_____________7. location of melanocytes and tactile epithelial cells.
_____________8. area where weblike pre-keratin filaments first appear.
_____________9. deep layer of the dermis
_____________10. layer that secretes a glycolipid that prevents water loss from the skin
Answer and Explanation:
b. stratum corneum: 5. layer including scalelike dead cells, full of keratin, that constantly slough off.
The most superficial epidermal layer conformed of squamous, plane, thin cells with keratin in their cytoplasm, that are continuously released. These cells are replaced by new cells that have the same destiny.
d. stratum lucidum
: 1. layer of translucent cells in thick skin containing dead keratinocytes
Also known as the transparent layer, is only located in the thicker parts of the skin, such as the hands´ palms and the feets´ soles. This layer is so thin that the cells´ edges and some ties their nucleus can not be identified. Keratinocytes are diaphanous and are grouped together. They lack a nucleus and the cytoplasm is filled with a gelatinous substance, eleidin, which will transform into keratin.
b. stratum corneum and d. stratum lucidum 2. two layers containing dead cells.
c. stratum granulosum: 6. layer named for the numerous granules present.
These layer cells contain granules filled with keratohyalin that is needed for keratin production. These cells are arranged in two to four layers, and they begin to degenerate. This is why they show high lysosomes enzymes concentration. This is also the layer where it begins keratinization.
e. stratum spinosum: 10. layer that secretes a glycolipid that prevents water loss from the skin.
8 to 10 irregular cell layers. These cells are rich in DNA necessary for proteinic synthesis that ends in keratin production, and Langerhans cells that belong to the immunity system. This stratus is also known as "Malpigio stratum". It also produces a glycoprotein that helps to prevent water loss.
a. stratum basale 4. epidermal layer exhibiting the most rapid cell division.
7. location of melanocytes and tactile epithelial cells.
Stratum basale is the innermost germinative, single, basal layer of the epidermis composed of basal cuboidal-shaped cells. These cells are the precursor of keratinocytes, this is why this layer is also called germinativum. In this basal layer, there are also Merkel cells as well as melanocytes. The former associated with nerve fibers, transmit part of the touch, and the latter, form the pigment responsible for skin coloring and tanning, melanin.
f. papillary layer: 3. dermal layer responsible for fingerprints.
This stratum is a thin superior layer in the dermis. It has conjunctive tissues and blood vessels that nourish the skin and helps to control the temperature. It´s surface forms papilla that increases the mechanical union between dermis and epidermis.
g. reticular layer: 9. deep layer of the dermis
The inner and thicker layer of the dermis. It is characterized by it´s thick, irregular bundles of collagen fibers and elastic fibers. These are not randomly oriented but forming the regular skin tightening lines known as Langer lines.
h. epidermis as a whole: 7. location of melanocytes and tactile epithelial cells.
Composed of a plane stratified keratinized epithelium that constantly grows and maintains a normal thickness by the process of peeling. The Epidermis is made up of five cell layers, which have different functions: Stratum basale, stratum spinosum, stratum granulosum, stratum lucidum, and stratum corneum.
i. dermis as a whole: composed of conjunctive dense tissue that provides support, resistance, and thickness to the skin.
A species of spruce tree occupies the same niche at the mouth of a river that a species of pine tree occupies further upstream. One year, several pinecones fall into the river and are carried to the mouth, where they take root and grow amongst the spruce trees. What will be the most likely result of this occurrence
Answer:
The correct option is: "Either the pine trees or the spruce trees will eventually evolve into a new species."
Explanation:
There will be a competition between spruce trees and pine trees for nutrition and other resources from the environment to grow and spread since they are now occupying the same niche. Overtime, one specie will outlive the other by evolving into a specie that gives it an advantage over the other.
Answer: bears
Explanation: it’s the answer
Can someone help me I don’t know which goes with which it’s different structures of the cell membranes
Answer:
I hoped I helped :))))
Explanation:
A. Extracellular Fluid
B. Hydrophilic Heads
C. Integral Protein
D. Hydrophobic Tails
E. Cytoplasm
F. Carbohydrate