Answer:
No, it is not necessary for them to have same mass.
Explanation:
Let both bodies have a density d1 and d2 respectively.
Since their volumes are equal V1 = V2
we know that, https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D
Hence, d1 = and d2 =
Taking the ratio of densities,we get
This implies that unless the bodies have same densities, the mass of the two bodies will not be same.
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
You can learn more about potential energy here: https://brainly.com/question/15813853?referrer=searchResults
I hope it helps you!
4. Determine the net force for the free-body
diagram
Fnorm = 40N
Ffrict =28N
Fapp =44N
Fgrav = 40N
Answer:
Fapp =44N is the correct answer
Explanation:
Please mark brainliest
which of these is NOT a metamorphic rock?
Basalt
Slate
Marble
Explanation:
Basalt is not a metamorphic rocks
. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
Please help me, I'm not good in physics.
You press your physics textbook flat against a vertical wall with your hand. What is the direction of the friction force exerted by the wall on the book? (a) downward (b) upward (c) out from the wall (d) into the wall. (Serway and Jewett, 2009) What type of friction is present?
Answer:
Upward direction.
The friction is kinetic friction
How could you measure the strength of static electricity compared to the strength of an
electromagnet?
Answer:
Lines of Force around an ElectromagnetExplanation:
The magnetic field strength of an electromagnet is therefore determined by the ampere turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic fieldWhich one of the following best describes a fuse?
4. Premature wrinkling due to overexposure to the Sun, what am I?
Premature Aging
Mark as brainlist
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)
A human cannonball act uses springy bungee cords instead of gunpowder to launch a person through a long cylindrical tube into the air. If a cannon is capable of launching a 55 kg test dummy 11 m into the air when launched straight up, how much energy is stored in the bungee cords? *
A. 539J
B. 605 J
C. 2965J
D. 5929 J
Answer:
Energy stored, E = 5929 J
Explanation:
Given that,
The mass of a test dummy, m = 55 kg
It is launched 11 m into the air.
We need to find the energy stored in the bungee cords. It can be calculated as follows :
[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]
So, 5929 J of energy is stored in the bungee cords.
1. A plane mirror has a
surface
Answer:
A plane mirror is a mirror with a flat (planar) reflective surface. For light rays striking a plane mirror, the angle of reflection equals the angle of incidence. The angle of the incidence is the angle between the incident ray and the surface normal (an imaginary line perpendicular to the surface).
A student wants to make an analogy to help her remember the characteristics of the planets. Which analogy makes the most sense?
The inner planets are like cotton candy and the outer planets are like hard butterscotch candy.
The outer planets are like bowling balls and the inner planets are like basketballs.
The inner planets are like hard butterscotch candy and the outer planets are like cotton candy.
The outer planets are like roses and the inner planets are like daisies.
Answer:
The last one makes the most sense as they combine two like things that are easy to visualize
Explanation:
Answer:
C. The inner planets are like hard butterscotch candy and the outer planets are like cotton candy.
Explanation:
Right on ED2021, goodluck!
34 Which of these human characteristics shows discontinuous variation?
A blood group
B hair color
C height
D weight
Answer:
Blood group
Explanation:
Answer:
A. Blood group.
Explanation:
They could purely random genetic changes.
in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?
Answer:
[tex]1.2\times 10^{10}\ kg[/tex]
Explanation:
Given that,
The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]
We need to find how much mass wast lost.
The relation between energy and mass is given by :
[tex]E=mc^2[/tex]
Where
c is speed of light
[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]
So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.
Which of the following determines the identity of an atom?
A. atomic mass
B. mass number
C. atomic number
D. charge
The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?
Answer:
10m/s
Explanation:
Vf=v0+at
30m/s=v0+2.5m/s^2*8s
Solve for v0=10m/s
Sorry for the vague explanation I'm on my phone right now. Hope this still helps!
Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.
To find the initial velocity of the car, we can use the kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).
Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:
30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).
Now, solve for the initial velocity (u):
30 m/s = u + 20 m/s.
Subtract 20 m/s from both sides:
u = 30 m/s - 20 m/s = 10 m/s.
Therefore, the initial velocity of the car is 10 m/s.
To know more about Initial velocity, here
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How do longitudinal waves differ from transverse waves? Give examples of both.
Answer:
Explanation:
Longitudinal
The medium moves in the same direction of the wave
It acts in one dimension
The wave cannot be polarized or aligned
This wave can be produced in any medium such as gas, liquid or solid
The earthquake P wave is an example
It is made of rarefactions and compressions
Transverse
The medium is moving perpendicular to the direction of wave
It acts in two dimension
The wave can be polarized or aligned
This wave can be produced in solid and liquid’s surface
Earthquake S wave is an example
It is made of troughs and crests
how important is it to have an emergency plan
Answer:
The actions taken in the initial moments after a crisis matter. These steps can determine how disruptive the aftermath will be. With this in mind, companies need to plan for any potential incidents that could occur. In this blog post, we discuss the importance of emergency planning, the impact it has on a crisis and how to prepare for the worst.
Explanation:
hope you like it
On which factor does the inertia of a body depend?
Answer:
The moment of inertia depends on the following factors, The density of the material. Shape and size of the body. Axis of rotation (distribution of mass relative to the axis)
HELP please!!!!!!!!!!!!!!!
What is the direction of the force of an object moving in a circle?
1.toward the center of the circle
2.toward the outside of the circle
3.straight up
4.45 degree angle
Answer:
The answer is 45 degree angle
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
The speed of a 1200 kg car increases from 5 to 29 m/s in 12 s.
What force accelerated the car?
Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m
Explanation:
It just makes sense
Anyone able to help with these questions, will give brainliest to first correct anwser
Answer:
b
Explanation:
I did this question earlier
A 45-kg child sits on a 3.2-kg tire swing. What is the tension in the rope that hangs from a tree branch?
Answer:
472.36 N
Explanation:
The total mass with the tire and child would be 45 kg + 3.2 kg = 48.2 kg
Ft = force tension
Fg = force of gravity
Fnet=0 (because child is motionless and not accelerating)
0 = Ft - Fg
Ft = Fg
Ft = m*g
Ft = 48.2 kg * 9.8 m/s^2
Ft = 472.36 N
Hope this helps!!
A 45-kg child sits on a 3.2-kg tire swing. The tension of the rope is 472.36 N.
The parameters given in the question is
Mass of the child= 45 kg
Mass of the tire swing attached to the tree= 3.2 kg
What is Tension?Tension can be defined as the force that can gets transmitted through a rope, string or wire when they are pulled through any forces that should acting from opposite sides.The tension force can be directed throughout the length of the wire and also it pulls the energy equally on the bodies at the ends.All the physical object which will be in contact exerts some force on one another.The first step is to calculate the total mass. The total mass can be calculated as follows;
= Mass of the child + mass of the tire swing
= 45 + 3.2
= 48.2 kg
The tension can be calculated as follows,
= mass × acceleration
= 48.2 × 9.8
= 472.36
Hence, A 45-kg child sits on a 3.2-kg tire swing. The tension of the rope is 472.36 N.
Learn more about Tension,
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1. Electrons spinning around the nucleus of an atom cause the atom to
a. be a tiny magnet.
b. have north and south poles.
c. have a magnetic field.
d. all of the above
Answer:
Answer:answer is C
is the magnetic field
1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.
Answer:
The answer is "0.047".
Explanation:
Given value:
[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]
Calculating the capacitance:
[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]
In this, the t = time, which is taken to calculates its maximum voltage.
[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]
4. A substance is cut into several piece and compared to the density of the
original sample. The density of each piece will be:-
areater
bl the same
Answer:
The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change
HELP ASAP PLS
A locomotive with a rocket engine is being tested on a smooth horizontal track. The mass of the
locomotive is unknown. Starting from rest, the engines are fired for 20 s. During this time
they expel 500 kg of oxidized kerosene. The kerosene particles are expelled at an average
velocity of 1200 m/s. At the end of the 20-s period the speed of the locomotive is 50 m/s.
What is its mass?
Answer:
The mass of the locomotive is 288,000 kg
Explanation:
The question relates to the law of conservation of energy
The given parameters are;
The form of engine on the locomotive = Rocket engine
The mass of the locomotive = m
The initial velocity of the locomotive, v = 0 m/s
The duration at which the engine is fired = 20 s
The mass of the kerosene expelled, m₁ = 500 kg
The average speed with which the kerosene is expelled, v₁ = 1,200 m/s
The final speed of the locomotive engine after 20-s, v₂ = 50 m/s
Kinetic energy, K.E. = 1/2·m·v²
The total kinetic energy of the kerosene particles, K.E.[tex]_k[/tex] = 1/2 × 500 × 1,200² = 360,000,000
∴ K.E.[tex]_k[/tex] = 360,000,000 J
By the conservation of energy, the kinetic energy of the expelled kerosene particles is equal to the kinetic energy gained by the moving locomotive
Therefore, we have;
K.E.[tex]_L[/tex] = K.E.[tex]_k[/tex]
K.E.[tex]_L[/tex] = 1/2 × m × v₂² = 1/2 × m × 50²
∴ K.E.[tex]_L[/tex] = 1/2 × m × 50² = K.E.[tex]_k[/tex] = 360,000,000 J
1/2 × m × 50² = 360,000,000 J
m = 360,000,000 J/(1/2 × (50 m/s)²) = 288,000 kg
m = 288,000 kg
The mass of the locomotive, m = 288,000 kg