Let the speed of one rider = x
The speed of the second rider would e 2x ( twice as fast)
The total speed of the two riders would be x + 2x = 3x
Speed = Distance / time
Using the numbers:
3x = 72/3
Simplify:
3x = 24
Divide both sides by 3:
x = 8
The speed of one rider is 8 miles per hour
The speed of the second rider is 2(8) = 16 miles per hour.
In 120 spins, about how often can you expect to get a number less than 6?
Answer:
is is 35
Step-by-step explanation:
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The hundred students took a survey. They were asked, "What is your favorite kind of sandwich?" Turkey was chosen by 25% of the
students.
What number of students chose turkey?
O A 5
B. 50
Ο Ο
ООО
C. 100
D. 175
E 500
Answer:
Step-by-step explanation:
Answer:
its A because 25% is equal to 25 out of a hundred
Step-by-step explanation:
Solve for X.
X-9
2/36
Dustin got four-fifths of the answers correct on his math test. If there was 20 questions , how many did he get right ?
Answer:
= 16
Step-by-step explanation:
1/5 of 20 = 4
so,
4/5 of 20 = 16
Two boats started to move towards each other from two docks, located 30 miles apart. One boat moved at a speed of 3 miles per hour, the other moved twice as fast. How soon will the boats meet?
Answer:
3.333 hours
Step-by-step explanation:
Given the total distance is 30 miles, and boat 1 travels at 3 mph and boat 2 travels at 6 mph, and the time for both is the same. Distance is speed S times time T so
30 = D(boat 1) + D(boat 2)
30 = (S1 * T) + (S2 * T)
30 = 3T + 6T
30 = 9T
3.333 = T
Derivative using direct definition of derivative 2-x/2+x
Let f(x) = (2 - x)/(2 + x). By definition of the derivative,
[tex]\displaystyle f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]
[tex]\displaystyle f'(x)=\lim_{h\to0}\frac{\frac{2-(x+h)}{2+(x+h)}-\frac{2-x}{2+x}}h[/tex]
[tex]\displaystyle f'(x)=\lim_{h\to0}\frac{\frac{(2-x-h)(2+x)-(2-x)(2+x+h)}{(2+x+h)(2+x)}}h[/tex]
[tex]\displaystyle f'(x)=\lim_{h\to0}\frac{-4h}{h(2+x+h)(2+x)}[/tex]
[tex]\displaystyle f'(x)=-4\lim_{h\to0}\frac1{(2+x+h)(2+x)}=\boxed{-\frac4{(2+x)^2}}[/tex]
A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $70.00. a. Develop a 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls (to 2 decimals).
Answer:
The 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls is ($234.96, $269.94).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
T interval
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 64 - 1 = 63
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 63 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.9983
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.9983\frac{70}{\sqrt{64}} = 17.49[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 252.45 - 17.49 = $234.96.
The upper end of the interval is the sample mean added to M. So it is 252.45 + 17.49 = $269.94.
The 95% confidence interval estimate of the mean amount spent per day by a family of four visiting Niagara Falls is ($234.96, $269.94).
Trey invested $15,000 into a savings account for five years at 7% interest. How much is in the account if the interest is compounded monthly?
Multipuly po ba (15;000 7%)
The horizontal distance of the ramp is 12 ft. And the vertical height of the ramp is 5 ft. Round answers to the nearest whole number.
a) what is the length of the ramp?
b) Find measure of the angle incline.
Answer:
a) 13 feet
b) 22.6º
Step-by-step explanation:
c² = 12² + 5²
c² = 144 + 25
c² = 169
Take the square root of both sides
c = 13 Feet
----------------------------
tan = opp/adj
∅ = arctan5/12
∅ = 22.619864948040426
∅ = 22.6º
The Histogram is a graphic which is: A. Bar Chart useful for showing the distribution of data B. 80-20 principle C. A complex timeline D. A simple history
Answer: Flow Chart. B - Fishbone Diagram. C - Scatterplot. D - 80-20 principle; used to identify the ... The Histogram is a graphic which is: A - Bar Chart useful for showing the distribution of data. B. 80-20 principle. C. A complex timeline. D. A simple history
Step-by-step explanation: Hope this helped :)
Which statement is NOT true?
All squares are rhombuses.
All rhombuses are parallelograms.
The diagonals bisect each other in squares, rhombuses, and rectangles.
The diagonals are perpendicular in squares, rhombuses, and rectangles.
Answer:
D
Step-by-step explanation:
Rectangles haven’t perpendicular diagonals
Multiply. Simplify and write your answer as a mixed number.
A prism has three rectangular faces. It's other faces are in the shape of a _____.
Answer:
Rectangle or parallelogram
If you place a 35-foot ladder against the top of a 31-foot building, how many feet will the bottom of the ladder be from the bottom of the building? Round to the nearest tenth of a foot.
Answer:
4ft
Step-by-step explanation:
The bottom of the ladder will be 16.25 feet from the bottom of the building.
What is the right triangle?A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.
As per the situation, we create a right triangle as shown.
Let x be the distance from the bottom of the building to the bottom of the ladder.
Using Pythagoras's theorem, then, we have:
x² + 31² = 35²
Simplifying this equation, we get:
x² = 35² - 31²
x² = 264
x = 16.25 (rounded to the nearest tenth of a foot).
Therefore, the bottom of the ladder will be 16.25 feet from the bottom of the building.
Learn more about Pythagoras's theorem here:
brainly.com/question/343682
#SPJ6
I'm getting ripped tonight r.i.p. that (mmm) ayeeeeee
Answer:
Di.ck by doja cat andStep-by-step explanation:
MARK ME BRAINLIEST PLZZZZZZZZZZZWhat is have of the number 21?
Answer:
21
Step-by-step explanation:
you now aswer to that question yes or no
What value of a will make the following equation true?
(x + a)(x – a) = x2 – 16
a = 2
a= 16
a=4
a = 8
Find the length of the third side. If necessary, round to the nearest tenth.
24
28
Answer:
h²=p²+b²
28²=p²+24²
p²=784-576
p²=208
p=√208
p=14.42 cm
hope it helps
stay safe healthy and happy.Which two discontinuities does the graph show?
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Answer:
Discontinuities can be classified as jump, infinite, removable, endpoint, or mixed. Removable discontinuities are characterized by the fact that the limit exists. Removable discontinuities can be "fixed" by re-defining the function.
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Answer:
jump discontinuity at x = –2; infinite discontinuity at x = 0
Step-by-step explanation:
For Edge 2021
how do you find 25% of 92
Answer:
23
Step-by-step explanation:
please I really really need help Find the equation of the straight line that passes through these points: (-1, -3) and (2, 3)
Step-by-step explanation:
m = (3+3)/(2+1)=6/3=2
equation :
y-y1=m(x-x1)
y+1= 2(x+3)
y+1=2x+6
y=2x+6-1
y=2x+5 or 2x-y+5=0
Answer:
y=2x+b
Step-by-step explanation:
m=y2-y1/x2-x1
=3--3/2--1
=6/3
=2
In BCD, the measure of
Answer:
is this yr new questions but still it's blank
stay safe healthy and happy.Since an instant replay system for tennis was introduced a a major tournament, men challenged 1390 referee calls, with the result that 411 of the calls were overturned. Women challenged 753 referee calls, and 213 of the calls were overturned. Use a .05 significance level to test the claim that men and women have equal success in challenging calls.
Required:
a. Test the claim using a hypothesis test.
b. Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for the hypothesis test?
c. What is the conclusion based on the hypothesis test?
Answer:
H0: μm − μw = 0
against the claim
Ha: μm − μw ≠ 0
Since the calculated value of z= 0.6177 does not lie in the critical region the null hypothesis is accepted that men and women have equal success in challenging calls.
Step-by-step explanation:
1) Let the null and alternate hypothesis be
H0: μm − μw = 0
against the claim
Ha: μm − μw ≠ 0
2) The significance level is set at 0.05
3) The critical region is z > + 1.96 and z< -1.96
4) The test statistic
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
Here p1= 411/ 1390= 0.2956 and p2= 213/753=0.2829
pc = 411+ 213/1390+753
pc=624/2143
pc= 0.2912
qc= 1-pc= 1-0.2912=0.7088
5) Calculations
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
z= 0.2956-0.2829/√ 0.2912*0.7088( 1/1390+ 1/753)
z= 0.0127/ √0.2064 (0.00204)
z= 0.0127/0.02056
z= 0.6177
6) Conclusion
Since the calculated value of z= 0.6177 does not lie in the critical region the null hypothesis is accepted that men and women have equal success in challenging calls.
Pleas help me am going to fail
Answer:
20 × 9= 180
...............................
Hi there!
[tex]\large\boxed{180 u^2}[/tex]
Use the following formula to solve for the area:
A = b × h
Plug in the given numbers:
A = 20 × 9 = 180 units²
HELP PLEASE!!!!
Which expression is equivalent to:
1.2y +4.5 -3.4y - 6.3?
5.5y - 10.2
-2.2y - 1.8
4.6y - 1.8
-2.2y + 11.1
Answer:
-2.2y-1.8
Step-by-step explanation:
1.2y+4.5-3.4y-6.3
1.2y-3.4y+4.5-6.3
-2.2y+4.5-6.3
-2.2y-1.8
if a circle is split into 5 parts what is the percentage of each piece
Answer:
20%
Step-by-step explanation:
If we think of the circle as 1, and each piece 1/5, and since we know that 1/5 = 20%, we can conclude that each piece takes up 20% of the circle.
An elementary school is creating a rectangular garden on the side of the school building. The school has raised money to purchase 1000 feet of fence. In order to maximize the area they are using the building for one side and therefore need to use the fencing for the other three sides of the garden. Find the dimensions the school should use to maximize the area of the garden.
Answer:
[tex]Length = 500ft[/tex]
[tex]Width = 250ft[/tex]
Step-by-step explanation:
Given
[tex]P = 1000[/tex] --- perimeter
Required
The dimensions that maximize the area
Let
[tex]L \to Length[/tex]
[tex]W \to Width[/tex]
Such that:
[tex]P = L + 2W[/tex] ---- Because one side is from the school building
This gives:
[tex]L + 2W = 1000[/tex]
Make L the subject
[tex]L = 1000 - 2W[/tex]
The area is then calculated as:
[tex]A= L * W[/tex]
Substitute: [tex]L = 1000 - 2W[/tex]
[tex]A= (1000 - 2W) * W[/tex]
Open bracket, then set A to 0
[tex]A = 1000W - 2W^2[/tex]
[tex]1000W- 2W^2 = 0[/tex]
Rewrite as:
[tex]-2W^2 + 1000W = 0[/tex]
Assume the form of the above equation is: [tex]aW^2 + bW + c = 0[/tex]
The value of W that maximizes it is:
[tex]W = -\frac{b}{2a}[/tex]
Where
[tex]a = -2[/tex]
[tex]b = 1000[/tex]
[tex]c = 0[/tex]
So:
[tex]W = -\frac{1000}{2*-2}[/tex]
[tex]W = \frac{1000}{2*2}[/tex]
[tex]W = \frac{1000}{4}[/tex]
[tex]W = 250[/tex]
Recall that:
[tex]L = 1000 - 2W[/tex]
[tex]L =1000 - 2 * 250[/tex]
[tex]L =1000 - 500[/tex]
[tex]L = 500[/tex]
So, the dimensions that maximize the area is:
[tex]Length = 500ft[/tex]
[tex]Width = 250ft[/tex]
Laz had a hard time with this problem on his homework. Help him figure out what went wrong in his process. (Read Picture)
Answer:
x = 6/√3
y = 3/√3
Step-by-step explanation:
For a triangle rectangle with a known angle θ, we have the relations:
Sin(θ) = (opposite cathetus)/(hypotenuse)
Cos(θ) = (adjacent cathetus)/(hypotenuse)
Tan(θ) = (opposite cathetus)/(adjacent cathetus)
For this triangle, we know an angle:
θ = 60°
And the opposite cathetus measures 3 units.
The adjacent cathetus is y.
The hypotenuse is x.
To find the value of x, we can use the Sin equation:
Sin(60°) = 3/x
x = 3/sin(60°) = 3.46 = 3*2/√3 = 6/√3
And we can use the Tan relation to find the value of y.
Tan(60°) = 3/y
y = 3/Tan(60°) = 1.73 = 3/√3
For x he didn't divide by √3, while for y he multiplied by √3 instead of dividing by √3.
A two-state system is in an environment at temperature 500 K. The energy of state 1 is 4.1e-20 J, and the energy of state 2 is 5.7e-20 J. Let be the probability of finding the system in state 1, and be the probability of finding the system in state 2. What is the ratio
Complete Question
A two-state system is in an environment at temperature 500 K. The energy of state 1 is[tex]E_1=4.1e-20 J[/tex], and the energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]. Let P(1) be the probability of finding the system in state 1, and be the probability of finding the system in state 2. What is the ratio P(2)/P(1)
Answer:
[tex]X=0.0984[/tex]
Step-by-step explanation:
From the question we are told that:
Temperature T=500 K
Energy of state 1 [tex]E_1=4.1e-20 J[/tex],
Energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]
Generally the equation for Probability of finding the system in state is mathematically given by
[tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]
Therefore
For Probability of finding the system in state 1 [tex]P(1)[/tex]
[tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]
Where
K is Boltzmann constant
[tex]K=1.38*10^{-23}[/tex]
[tex]P(1)=e ^{\frac{-(4.1e-20 J)}{1.38*10^{-23}*500}}[/tex]
For Probability of finding the system in state 1 [tex]P(2)[/tex]
[tex]P(2)=e ^{\frac{-(5.7e-20 J)}{1.38*10^{-23}*500}}[/tex]
Generally the equation for The Ratio of [tex]P(2)[/tex] and [tex]P(2)[/tex] is mathematically given by
[tex]X=\frac{P(2)}{p(1)}[/tex]
[tex]X=e ^{\frac{E_1-E_2}{KT}}[/tex]
[tex]X=e ^{\frac{-(4.1-5.7)e-20 J)}{1.38*10^{-23}*500}}[/tex]
[tex]X=0.0984[/tex]
PLEASE HELP I WILL MAKE YOU BRAINLIEST IF IT LETS ME
NO FAKE LINKS OR YOU WILL BE REPORTED
Answer:
Jeffery because the other dude go the 2 numbers wrong (he put the x coordinates on y and y on x)