To draw a Lewis structure for a polyatomic ion, begin by calculating A, the available electrons, and N, the needed electrons. What is N for CIO3-, the chlorate ion?​

Answers

Answer 1

Answer:

N for chlorate ion is one

Explanation:

Because N is the number of electrons needed to form octet structure causing a negative charge of one, since it already has 25valence electrons

Answer 2

Answer: 26

Correct Answer


Related Questions

The products of a reaction are NaCl and H2O. What does the law of conservation of matter reveal about the reactants in the reaction? A. At least some of the reactants will include NaCl and H2O. B. The reactants will contain only Na, Cl, O, and H in some amounts. C. Na, Cl, O, H, and three other elements were the reactant elements. D. The reactants will have one Na, one Cl, one O, and two H atoms.

Answers

Answer:

D

Explanation:

total mass should be equal on both sides

it's a double do displacement reaction

HCl + NaOH --> NaCl + H2O

How many molecules are in each sample?
A. 4.9 g H2O
B. 54.4 g N^2
C. 89 g CCI4
D. 11 g C6H12O6

Answers

Answer:

To find the number of molecules first find the number of moles.

number of moles (n) = mass / molar mass (M)

then use the formula

N = n × L

where n = number of moles

N = number of entities

L = Avogadro's constant = 6.02 × 10^23entities to find the number of molecules

A. 4.9 g H2O

m = 4.9g

M = (2*1)+(16×1) = 2 + 16 = 18g/mol

n = 4.9/18 = 0.272mol

N = 0.272 × 6.02 × 10^23

= 1.6374*10^23 molecules of H2O

B. 54.4g of N2

m = 54.4g

M(N2) = 14×2 = 28g/mol

n = 54.4/28 = 1.942mol

N = 1.942 * 6.02*10^23

= 1.1690*10^24 molecules of N2

C. 89 g CCI4

m = 89g

M(CCl4) = 12 + (35.5 × 4) = 154g/mol

n = 89/154 = 0.577mol

N = 0.577 × 6.02 × 10^23

= 3.473*10^23 molecules of CCl4

D. 11 g C6H12O6

m = 11g

M(C6H12O6) = (12×6)+(12×1)+(16×6) =

180g/mol

n = 11/180 = 0.0611mol

N = 0.0611 × 6.02×10^23

= 3.678*10^22 molecules of C6H12O6

Hope this helps

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