The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.
Less than
15
1515 minutes
15
1515-
29
2929 minutes
30
3030-
44
4444 minutes
45
4545-
59
5959 minutes
60
6060 or more minutes Total
Private vehicle
636
636636
908
908908
590
590590
257
257257
256
256256
2647
26472647
Public Transportation
9
99
54
5454
96
9696
62
6262
108
108108
329
329329
Other
115
115115
70
7070
23
2323
7
77
7
77
222
222222
Total
760
760760
1032
10321032
709
709709
326
326326
371
371371
3198
31983198
Given that the commuter used public transportation, find the probability that the commuter had a commute of
60
6060 or more minutes.
P
(
60
+
minutes

public transportation
)
=
P(60+ minutes ∣ public transportation)=

Answers

Answer 1

Answer:

36

Explanation:

Step review


Related Questions

A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis through its center, how large is the torque acting on the cylinder? With work please

Answers

Answer:

0.011 N-m

Explanation:

Given that

The mass of a solid cylinder, m = 30 kg

The radius of the cylinder, r = 0.18 m

The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]

It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :

[tex]\tau=I\alpha[/tex]

Where

I is the moment of inertia of the cylinder,

For cylinder,

[tex]I=\dfrac{mr^2}{2}[/tex]

So,

[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]

So, the required torque on the cylinder is 0.011 N-m.

Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You may assume the slab is much longer and wider than it is thick. Write the reduced form of the governing equation for the slab. Clearly identify your coordinate system on a sketch and state your assumptions identifying which terms you are eliminating and why.

Answers

Answer:

Explanation:

The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.

Which equation will tell you the acceleration of the object?

Answers

Answer:

In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2

Explanation:

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answers

This question is incomplete, the complete question is;

A positive charge of magnitude Q1 = 6.5 nC is located at the origin.

A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answer:

the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C    

Explanation:

Given the data in the question;

Q1 = 6.5 nC, Q2 = -3.5 nC

from the image below, to get our angle ∅

tan∅ = opp/adj

tan∅ = 10.5 / 16.5

tan∅ = 0.636363

∅ = tan⁻¹( 0.636363 )

∅ = 32.47°

also, r1 = √( 16.5² + 10.5²)

r1 = √( 272.25 + 110.25 )

r1 = √382.5

r1 = 19.55 cm = 0.1955 m

Now, the x-component of the electric field at point P due to charge Q1 will be;

Ex = E2cos32.47°

= (kQ1/r1²)cos32.47°

we know that;  k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²

Q1 = 6.5 nC = 6.5 × 10⁻⁹ C

so we substitute

= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°

= (58.5 / 0.03822025) × 0.843672

= 1291.33 N/C

Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C

4) Snowman melting in the sun​

Answers

Answer:

is there more information for the question

Mikey got shocked when he touches a wire. How was the energy transferred to Mikey's fingers?
a. Convection b. Conduction c. Radiation d. Radioaction

Answers

Answer:

Conduction

Explanation:

Conduction is when heat or electricity is transmitted throughout a substance.

The energy transfer taking place through our body is called conduction. Our body is conductive and which make the electrical shock.

What is conduction?

There are three different modes of energy transfer namely, conduction, convection and radiation. Conduction is the energy transfer mode on solids and convection is taking place in gases and liquids.

Radiation is the energy transfer mode through vacuum. In conduction the energy transfers easily through the chain of  closely packed molecules. Whereas in convection, the molecule which obtained an energy travels across the space and transfers to other molecules.

Our body transfers energy inside through conduction process. Skin is very conductive and the electrons from the wire can be passed through our body that's why we gets electrically shocked.

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A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest

Answers

Answer:

[tex]m=90.1kg[/tex]

Explanation:

From the question we are told that

Force F=39400

Initial speed [tex]V_1=35m/s[/tex]

Distance[tex]d=1.4m[/tex]

Generally the equation for acceleration is mathematically given by

[tex]a=\frac{V^2-U^2}{2d}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=-437.5m/sec^2[/tex]

Generally the equation for mass is mathematically given by

[tex]F=ma\\m=F/a[/tex]

[tex]m=\frac{-39400}{-437.5}[/tex]

[tex]m=90.1kg[/tex]

The speed limit on suburban roads is 50 km/h. You are traveling at the limit when an empty bag blows onto the road from behind a parked car 5.0m in front of you. If you maintain your speed how long will it be before you hit?

Answers

I don’t know the anser to this whuejenewkkaksj

If a 6-kg bowling ball is rolled down the bowling lane with a force of 12 N, what is the acceleration of the ball?

Answers

Since F = ma, you can use this to find the acceleration. Plug in the values:

12N = 6kg * a

And solve for a.

2 m/s/s = a.

The acceleration is 2 m/s^2

1) The cause of magnetism is
A. atoms forming “domains” that are arranged randomly
B. atoms forming "domains” that are arranged uniformly
C. atoms forming "dolomites” that are arranged randomly
D. atoms forming “dolomites” that are arranged uniformly

Answers

Answer:

I think it's A, I'm not sure though

3. An ecosystem is different from all of
the other groups because it contains
things.
O only living
O only nonliving
O both living and nonliving

Answers

Answer:

I think it is O only nonliving

i believe it’s only nonliving

If Angle "a" is 25°, Angle "b" is:
equal to 25°
less than 25°
greater than 25°

Answers

Answer:

less than 25°

Explanation:

I did this question for school and when I put this answer it was correct.

An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5.0 m. What is its velocity?

Answers

Answer:

v = 7.74 m/s

Explanation:

Given that,

The acceleration of the object, a = 12 m/s²

The radius of the circle, r = 5 m

We need to find the velocity of the object. The centripetal acceleration act on the object that is given by :

[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{12\times 5} \\\\v=7.74\ m/s[/tex]

So, the velocity of the car is 7.74 m/s.

1. Two boxes stacked on top of one another weigh 100 kg total. They apply
a friction force of 250N. You apply a force of 300N in the right direction.
What is the total net force and direction of the box?

Answers

Answer:

150

Explanation:

What is the most common grip used in racket sports?

Answers

The continental ...........

If you double the compression of a spring it’s elastic potential energy will do what

Answers

Answer:

When you stretch or compress a spring you work against the restoring force of the spring. This work is stored as elastic potential energy in the spring. The more you stretch or compress the spring, the more work is done by you and more energy is stored.

This is also evident from the expression of the potential energy ( U ) -

U=(1/2)kx2

Where x is the displacement from the unstretched position of the spring. Greater is the x. more is the energy stored.

why is the galaxy when me is the no galaxy so not galaxy but is galaxy so why is thee aliens is the yes but is the no but should not be the ok but when the yes 20 lashes

Answers

Answer:

they are in imaginary world in this every thing is possible

When the starter motor on a car is engaged, there is a 320 A current in the wires between the battery and the motor. Suppose the wires are made of copper and have a total length of 1.5 m . For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. What minimum diameter can the wires have if the voltage drop along the wires is to be less than 0.50 V?

Answers

Answer:

0.5

Explanation:

because it is V uwbsusvegwjosnfvehdbuxbdusndgdghqbwbwbbeuehdbdhdhdhdudhdhdudhdnskowoqllqlqlqnebe

What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?

Answers

Answer:

Uhm thags hsed

Explanation:

Dkrr

Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 mm apart and are emitting 1700-HzHz sound waves into a room where the speed of sound is 340 m/sm/s . Consider a point 4.0 mm in front of speaker 1, which lies along a line from speaker 1, that is perpendicular to a line between the two speakers. Is this a point of maximum constructive interference, a point of perfect destructive interference, or something in between

Answers

Answer:

The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

Explanation:

Given data in the question;

first we find the wavelength of the sound λ

Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.

wavelength λ  = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m

L1 = 4 m

L2 = √(4² +2² ) m

delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m

x = deltaL / λ

If the result is nearly an integer, the waves reinforce at the point.

If it is nearly an integer + 0.5, the waves interfere destructively at the point.

If it is neither, the point is "something in between".

so we solve for  x

x = 0.472 m / 0.2m

x = 2.36

since its not an integer, it is not point maximum constructive interference

delta L = ( 2x + 1 ).λ/2

x = ((2deltaL/λ) - 1)/2

x = (((2×0.472)/0.2) - 1)/2

x = 3.72 / 2

x = 1.86

Here also, it is not an integer, so it is not a point perfect destructive interference.

Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

A 0.160 pF parallel-plate capacitor is charged to a potential difference of 10.0 V and then disconnected from the battery. A cosmic ray burst creates 1.00 x 106 electrons and 1.00 x 106 positive charges between the plates. If the charges do not recombine, but reach the oppositely charged plates, by how much is the potential difference between the capacitor plates reduced

Answers

Answer:

1.0 volts

Explanation:

Given that:

The potential difference between the plate V = 10 V

C = 0.160 pF = 0.160 × 10⁻¹² F

The charge on the capacitor

Q = CV

Q = 0.160 × 10⁻¹² × 10

Q = 1.6 × 10⁻¹² C

It implies that the positive plate of capacitor has +1.6 × 10⁻¹² C charge while the negative plate has -1.6 × 10⁻¹² C

The number of excess electrons on the negative plate is:

[tex]n = \dfrac{q}{e}[/tex]

[tex]n = \dfrac{-1.6\times 10^{-12}}{-1.6\times 10^{-19}}[/tex]

[tex]n = 1.0 \times 10^7[/tex]

Thus, electron deficiency on the positive plate is [tex]1.0 \times 10^7[/tex]

The net negative charge that moves towards the positive plate is :

q = number of electrons moved × e

[tex]q = 1\times 10^6 \times (-1.6 \times 10^{-19})[/tex]

[tex]q = -1.6 \times 10^{-13} \ C[/tex]

Now, the net charge on the positive plate is:

[tex]q_{net} = q +q' \\ \\ q_{net} = (1.6 \times 10^{-12}) + (-1.6 \times 10^{-13})[/tex]

[tex]q_{net} =1.44 \times 10^{-12} \ C[/tex]

The potential difference between the plate;

[tex]V_{new} = \dfrac{q_{net} }{c}[/tex]

[tex]V_{new} = \dfrac{1.44 \times 10^{-12} }{0.16 \times 10^{-12}}[/tex]

[tex]V_{new} = 9.0 V[/tex]

The reduction in potential difference

[tex]\Delta V = V - V_{new}[/tex]

[tex]\Delta V = 10 - 9.0[/tex]

[tex]\mathbf{\Delta V = 1.0 \ volts}[/tex]

Trevor is charting the motion of his pet tortoise across the floor. The diagram below shows its position every 60 seconds.

A.The tortoise is moving at a constant speed
B. The tortoise’s speed is decreasing through time
C. The tortoise’s speed is increasing through time
D. The tortoise’s position is not changing through time

Answers

Answer:

A.The tortoise is moving at a constant speed

Explanation:

The chart shows the tortoise covering a distance of 0.5 meters every 60.0 seconds. Since this rate of motion is not changing, the tortoise is moving at a constant speed.

The diagram shows the tortoise moving at a constant speed. Thus the correct option is option A.

What is speed?

Speed is defined as how far the object travels. It is also defined as the rate of change of distance per unit of time. Speed is the scalar quantity and the unit of speed is m/s.

Speed is denoted by the letter v. v = s/t, where s is the distance traveled along the path and t is the time taken by the object to move along the path.   The SI unit of distance is meter and the unit of time is seconds.

When the object covers an equal distance at equal intervals of time is called uniform speed. When the object covers unequal distance with equal intervals of time or equal distance with unequal intervals of time is called Non-uniform speed.

The graph shows the Tortoise covers 0.5 m in 60 seconds is called uniform speed. Thus, option A is correct.

To learn more about Speed:

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a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the car traveled?

Answers

Answer:

the average speed of the car is 170 mph.

Explanation:

Given;

initial speed, u = 70 mph

time of motion, t₁ = 3 hours

final speed, v = 20 mph

time of motion, t₂ = 2 hours

The average speed of the car is calculated as;

[tex]v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph[/tex]

Therefore, the average speed of the car is 170 mph.

the angular speed of an automobile engine is increased at a constant rate from 1300rev/min to 2000rev/min in 3s (a) what is its angular acceleration in revolutions per minute squared ​

Answers

Answer:

please find attached pdf

Explanation:

Milk with a density of 1020 kg/m3 is transported on a level road in a 9-m-long, 3-m-diameter cylindrical tanker. The tanker is completely filled with milk (no air space), and it accelerates at 4 m/s . If the minimum pressure in the tanker is 100 kPa, determine the maximum pressure difference and the location of the maximum pressure. Answer: 66.7 kPa

Answers

Solution :

Given data is :

Density of the milk in the tank, [tex]$\rho = 1020 \ kg/m^3$[/tex]

Length of the tank, x = 9 m

Height of the tank, z = 3 m

Acceleration of the tank, [tex]$a_x = 2.5 \ m/s^2$[/tex]

Therefore, the pressure difference between the two points is given by :

[tex]$P_2-P_1 = -\rho a_x x - \rho(g+a)z$[/tex]

Since the tank is completely filled with milk, the vertical acceleration is [tex]$a_z = 0$[/tex]

[tex]$P_2-P_1 = -\rho a_x x- \rho g z$[/tex]

Therefore substituting, we get

[tex]$P_2-P_1=-(1020 \times 2.5 \times 7) - (1020 \times 9.81 \times 3)$[/tex]

           [tex]$=-17850 - 30018.6$[/tex]

           [tex]$=-47868.6 \ Pa$[/tex]

           [tex]$=-47.868 \ kPa$[/tex]

Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.

         


Minimum interplanar spacing required for Bragg's diffraction is:​

Answers

Answer:

Explanation:

\frac{\lambda }{2} is the minimum interplanar spacing which is required for Bragg's diffraction to occur.

A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the air pressure and temperature inside the vessel are 20 atm and 300K, respectively: What is the mass of air stored in the vessel

Answers

Answer:

The mass of air stored in the vessel is 235.34 kilograms.

Explanation:

Let supossed that air inside pressure vessel is an ideal gas, The density of the air ([tex]\rho[/tex]), measured in kilograms per cubic meter, is defined by following equation:

[tex]\rho = \frac{P\cdot M}{R_{u}\cdot T}[/tex] (1)

Where:

[tex]P[/tex] - Pressure, measured in kilopascals.

[tex]M[/tex] - Molar mass, measured in kilomoles per kilogram.

[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.

[tex]T[/tex] - Temperature, measured in Kelvin.

If we know that [tex]P = 2026.5\,kPa[/tex], [tex]M = 28.965\,\frac{kg}{kmol}[/tex], [tex]R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K}[/tex] and [tex]T = 300\,K[/tex], then the density of air is:

[tex]\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}[/tex]

[tex]\rho = 23.534\,\frac{kg}{m^{3}}[/tex]

The mass of air stored in the vessel is derived from definition of density. That is:

[tex]m = \rho \cdot V[/tex] (2)

Where [tex]m[/tex] is the mass, measured in kilograms.

If we know that [tex]\rho = 23.534\,\frac{kg}{m^{3}}[/tex] and [tex]V = 10\,m^{3}[/tex], then the mass of air stored in the vessel is:

[tex]m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})[/tex]

[tex]m = 235.34\,kg[/tex]

The mass of air stored in the vessel is 235.34 kilograms.

1. How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car
has an average acceleration of 3.2 m/s2 ?
Solving for:
Formula:
Substitute known values:
Number answer:
Unit answer

Answers

Answer:

I have no clue I'm really really really really really but like really sorry this is so hard

I have no clue I just need more questions to ask
19273)2
Woman
9272

How much thermal energy is needed to boil 2.65 kg of water at its boiling
point?
Use Q = mass x latent heat of vaporization.
A. 265 kJ
B. 11.1 kJ
C. 5990 kJ
D. 882 kJ

Answers

Answer: 5990 kJ :)

Explanation: a p e x <3

The amount of thermal energy needed to boil 2.65 kg of water at its boiling point is 5990 kJ. So, the correct answer is option C.

What is thermal energy?

Thermal energy is the energy that is generated by the movement of particles within a substance or system. It is a type of internal energy and is directly related to the temperature of the system. The faster the particles are moving, the more thermal energy the system has. Thermal energy can be transferred from one system to another through the processes of conduction, convection, and radiation. It is a form of energy that is used in many different applications, such as heating homes and buildings, powering engines, and cooking food.

Here in the Question,

To calculate the thermal energy needed to boil the water, we can use the formula,

Q = m x L

where Q is the thermal energy, m is the mass of the water, and L is the latent heat of the vaporization of water.

Q = m x L

Q = 2.65 kg x 2260 kJ/kg

Q = 5990 kJ

Therefore, 2.65 kg of water will require 5990 kJ of thermal energy to reach its boiling point.

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Is altitude abiotic or biotic or neither SCIENCE WORK NEEDED BY 11:59 HELP HELP HLEP

Answers

Answer:

abiotic

Explanation:

goggle:)))))))

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