Answer:
D. Both distributions are skewed left, so the interquartile range is the best measure to compare variability.
Step-by-step explanation:
Plotting the data roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.
In such a scenario, interquartile range is normally the best measure to compare variations of data.
Therefore, the last option is the best for the data provided.
please mark me brainliest :)
Thursday is ladies night at the slurp in Burt bar and Grill. All adult beverages are $1.25 for women and $2.50 for men. A total of 211 adult beverages were sold last Thursday night. If the slip and burp sold a total of $365.00 in adult beverages last Thursday night, how many adult beverages were sold to women?
Answer:
130 women
Step-by-step explanation:
First set up a system of equations:
1.23W+2.50M=365.00
W+M=211
Using substitution you get:
1.25W+2.50(211-W)=365.00
Simplify:
-1.25W=-162.5
Divide:
W=130
Consider the following sets of sample data: A: 431, 447, 306, 413, 315, 432, 312, 387, 295, 327, 323, 296, 441, 312 B: $1.35, $1.82, $1.82, $2.72, $1.07, $1.86, $2.71, $2.61, $1.13, $1.20, $1.41 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
Answer:
Dataset A
We have the following results:
[tex] \bar X_A = 359.786[/tex]
[tex]s_A= 60.904[/tex]
[tex] CV_A = \frac{60.904}{359.786}= 0.169 \approx 0.2[/tex]
Dataset B
We have the following results:
[tex] \bar X_B = 1.791[/tex]
[tex]s_B= 0.635[/tex]
[tex] CV_B = \frac{0.635}{1.791}= 0.355 \approx 0.4[/tex]
Step-by-step explanation:
For this case we have the following info given:
A: 431, 447, 306, 413, 315, 432, 312, 387, 295, 327, 323, 296, 441, 312
B: $1.35, $1.82, $1.82, $2.72, $1.07, $1.86, $2.71, $2.61, $1.13, $1.20, $1.41
We need to remember that the coeffcient of variation is given by this formula:
[tex] CV= \frac{s}{\bar X}[/tex]
Where the sample mean is given by:
[tex] \bar X= \frac{\sum_{i=1}^n X_i}{n}[/tex]
And the sample deviation given by:
[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
Dataset A
We have the following results:
[tex] \bar X_A = 359.786[/tex]
[tex]s_A= 60.904[/tex]
[tex] CV_A = \frac{60.904}{359.786}= 0.169 \approx 0.2[/tex]
Dataset B
We have the following results:
[tex] \bar X_B = 1.791[/tex]
[tex]s_B= 0.635[/tex]
[tex] CV_B = \frac{0.635}{1.791}= 0.355 \approx 0.4[/tex]
What is the end behavior of the graph of the polynomial function f(x) = 2x3 – 26x – 24?
Answer:
Step-by-step explanation:
Answer:
its b on edge
Step-by-step explanation:
HELP PLZ!! I NEED HELP!
Answer:
yes£18Step-by-step explanation:
The amount Lila and Wassim plan to save is ...
(£13 +13)(9) = £234
__
The charges they expect to incur are a per-person charge and a tent pitch charge. Since they expect to stay 10 nights, the special rate means they will only be charged for 8 nights.
per-person charge
per-person-per-night charge = (2 persons)(8 nights)(£6 per person-night)
= £96
tent pitch charge
To determine the tent pitch area required, we need to find the area of the tent:
A = LW = (4.2 m)(2.3 m) = 9.66 m²
This is less than 10 square meters, so we can expect the pitch charge to be £15 per night for 8 nights.
tent pitch charge = (£15/night)(8 nights) = £120
So, the total of camp site charges is expected to be ...
person charge + pitch charge = £96 +120 = £216
__
The expected savings exceeds the expected charges by ...
£234 -216 = £18
Lila and Wassim will have enough saved, with £18 extra.
Find f(-11/5) if f(n) = 5n + 6
Answer:
f(-11/5) = -5
Step-by-step explanation:
f(n) = 5n + 6
Let x = -11/5
f(-11/5) = 5*-11/5 +6
= -11 +6
= -5
add or subtract negative numbers
[tex]9+(-2)\\9-2\\=7[/tex]
[tex]-6+(-3)\\-6-3\\=-9[/tex]
[tex]4+(-9)\\4-9\\=-5[/tex]
Answer:
see below
Step-by-step explanation:
9 + -2 =
9 -2 = 7
-6 + -3
-6 - 3 =-9
4 + - 9
-9 +4 = -5
All applicants for admission to graduate study in business are given a standardized test. Scores are normally distributed with a mean of 460 and standard deviation of 80. What fraction of applicants would you expect to have scores of 600 or above
Answer:
The probability that applicants would you expect to have scores of 600 or above = 0.0401 or 4%
Step-by-step explanation:
Explanation:-
Let "x" Scores are normally distributed
Given mean of the Population = 460
standard deviation of the population = 80
Let X = 600
[tex]Z = \frac{x -mean}{S.D} = \frac{600-460}{80} =1.75[/tex]
The probability that applicants would you expect to have scores of 600 or above
P( X≥600) = P( Z≥ 1.75)
= 1- P( Z≤1.75)
= 1- ( 0.5 + A(1.75)
= 1- 0.5 - A(1.75)
= 0.5 - 0.4599 (from Normal table)
= 0.0401
The probability that applicants would you expect to have scores of 600 or above = 0.0401 or 4%
Based on his roommate’s behavior in other similar games, roommate A believes that there is a 0.28 probability that his roommate will choose rock and a 0.55 probability that his roommate will choose scissors. The probabilities are assigned using the . Suppose that roommate A’s probability assignments are correct. What can you say about P( PBPB ), the probability that roommate B chooses paper? Check all that apply. P( PBPB ) = 0.31 0 ≤ P( PBPB ) ≤ 0.1 P( PBPB ) = 0.17 1 ≤ P( PBPB ) ≤ 2 0 ≤ P( PBPB ) ≤ 1
Answer:
[tex]0 \leq P( P_B) \leq 1[/tex]
[tex]P(P_B) = 0.17[/tex]
Step-by-step explanation:
From the given question:
The probabilities are assigned using the Subjective method.
Let the probability that his roommate will choose rock be [tex]P(R_B) = 0.28[/tex]
Let the probability that his roommate will choose scissors be [tex]P(S_B) = 0.55[/tex]
∴
[tex]P(R_B) + P(S_B) +P(P_B) = 1[/tex]
[tex]0.28+ 0.55 + P(P_B) =1[/tex]
[tex]0.83 + P(P_B) = 1[/tex]
[tex]P(P_B) = 1 - 0.83[/tex]
[tex]P(P_B) = 1 -0.83[/tex]
[tex]P(P_B) = 0.17[/tex]
So;
[tex]0 \leq P( P_B) \leq 1[/tex]
[tex]P(P_B) = 0.17[/tex]
In the diagram below, $RT:TS = 1:2$ and $SR = PQ = 20$. Find $UV$.
It's pretty easy not college levlel just some simple high school geomerty.
Answer: 12
Step-by-step explanation: Because $\overline{PQ}$, $\overline{UV}$, and $\overline{SR}$ are all perpendicular to $\overline{QR}$, we have $\overline{PQ} \parallel \overline{UV} \parallel \overline{SR}$. Therefore, we have $\angle UPQ = \angle UTS$ and $\angle UQP = \angle UST$, which means that $\triangle UPQ \sim \triangle UTS$. So, we have $UQ/US = PQ/ST$.
Because $ST/SR = 2/3$ and $PQ = SR$, we have
\[\frac{UQ}{US} = \frac{PQ}{ST} = \frac{SR}{ST} = \frac{3}{2}.\]Since $UQ/US = 3/2$, we have $UQ/QS = 3/5$.
We have $\triangle UQV \sim \triangle SQR$ by AA Similarity, so $UV/SR = UQ/QS = 3/5$. Therefore, we have $UV = (3/5)SR = \boxed{12}$.
Marie plants 12 packages of vegetable seeds in a community garden. Each package costs $1.97. What is the total cost of the seeds?
Answer:
$23.64
Step-by-step explanation:
Each package of seeds cost $1.97, and Maire bought and planted 12 packages. You would do 12 x 1.97 to get 23.64
Answer:
$23.64
Step-by-step explanation:
$1.97 × 12
$23.64
Hope this helps...
f(x)={(x^(2)+4 x 1):}
Answer:
Substitute the given value into the function and evaluate:
f(x)=6x
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the mean of the prime factors of 24 is
Answer:
bad words
Step-by-step explanation:
it is your shet
Answer:
2.25
Step-by-step explanation:
Prime Factors of 24 is 2 x 2 x 2 x 3
2 + 2 + 2 + 3 = 9
9/4 = 2.25
Suppose that 45% of students in a college have a smart phone. If you select three students at random, what is the probability that all three have a smart phone? Give your answer as a decimal (to at least 3 places) or fraction
Answer:
[tex] P(X=3)[/tex]
And we can use the probability mass function and we got:
[tex]P(X=3)=(3C3)(0.45)^3 (1-0.45)^{3-3}=0.091[/tex]
Then the probability that all three have a smart phone is 0.091
Step-by-step explanation:
Let X the random variable of interest "number of students with smartphone", on this case we now that:
[tex]X \sim Binom(n=3, p=0452)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
And we want to find this probability:
[tex] P(X=3)[/tex]
And we can use the probability mass function and we got:
[tex]P(X=3)=(3C3)(0.45)^3 (1-0.45)^{3-3}=0.091[/tex]
Then the probability that all three have a smart phone is 0.091
Preciso de ajudaa! Resolução também! - Considere as funções f e g tais que f(x)= x³+1 e g(x)= x-2 Determine: a)(fog)(0) b)(gof)(0) c)(fof)(1) d)(gog)(1)
Answer:
(fog)(x) means that we have the function f(x) evaluated in the function g(x), or f(g(x)).
So, if f(x) = x^3 + 1 and g(x) = x - 2.
we have:
a) (fog)(0) = f(g(0)) = (0 - 2)^3 + 1 = -8 + 1 = -7
b) (gof)(0) = g(f(0)) = (0^3 + 1) - 2 = -1
c) (fof)(1) = f(f(1)) = (1^3 + 1)^3 + 1 = 2^3 + 1 = 8 + 1 = 9
d) (gog)(1) = g(g(1)) = (1 - 2) - 2 = -1 -2 = -3
Consider the next 1000 98% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on which the intervals are based are selected independently of one another. How many of these 1000 intervals do you expect to capture the corresponding value of μ?
Answer:
980 intervals.
Step-by-step explanation:
For each interval, there are only two possible outcomes. Either it captures the population mean, or it does not. One interval is independent of other intervals. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
98% confidence interval
Has a 98% probability of capturing the population mean, so [tex]p = 0.98[/tex]
1000 intervals
This means that [tex]n = 1000[/tex]
How many of these 1000 intervals do you expect to capture the corresponding value of μ?
[tex]E(X) = np = 1000*0.98 = 980[/tex]
980 intervals.
What is the probability that 4 randomly selected people all have different birthdays? Ignore leap years, and round your final answer to four decimal places.
0.9729
0.9918
0.9891
0.9836
Answer:
(D)0.9836
Step-by-step explanation:
There are 365 days in a year.
Since each person has a different birthday:
We can choose a birthday for the first person 365 out of 365 days.We can choose a birthday for the second person 364 out of 365 days.We can choose a birthday for the third person 363 out of 365 days.We can choose a birthday for the fourth person 362 out of 365 days.Therefore,
P(4 randomly selected people all have different birthdays)
[tex]=\dfrac{365}{365} \times \dfrac{364}{365} \times \dfrac{363}{365} \times \dfrac{362}{365}\\\\=0.9836[/tex]
A newspaper report says that a company made £700’000 profit last year. It’s says this was 12% more than the year before. How much profit did the company make the year before
Answer: £625,000
Step-by-step explanation:
Previous year's profit can be calculated as:
700000 / 1.12 = 625000
The profit that should make a year before should be £625,000.
Given that
The profit made last year should be £700,000.And, there is 12% more than the year before.So the profit that should make a year before should be
[tex]= \frac{700,000}{(1 + 0.12)} \\\\= \frac{700,000}{(1.12)}[/tex]
= £625,000
Therefore we can conclude that The profit that should make a year before should be £625,000.
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If I use my debit card at the gas pump, I get a five-cent discount. Which of the following statements is
accurate?
(a) The absolute change in price is the same for all grades ofgas; the relative change in price for Regular (the cheapest) is the greatest.
(b) The absolute change in price is the same for all grades ofgas; the relative change in price for Premium (the most expensive) is the greatest.
(c) The relative change in price is the same for all grades ofgas; the absolute change in price for Regular (the cheapest) is the greatest.
(d) The relative change in price is the same for all grades of gas; the absolute change in price for Premium (the most expensive) is the greatest.
Answer:
(d) The relative change in price is the same for all grades of gas; the absolute change in price for premium (the most expensive) is the greatest.
Step-by-step explanation:
The debit card holders are offered discount if they use debit card for a payment. When the gas pump offers the discount the relative change in price is same. The banks offers discounts to its customers to encourage cashless payments.
The point (-7,1) when reflected across the origin maps onto
Answer:
(7,-1)
Step-by-step explanation:
common rule for reflections across the origin; im guessing you meant a reflection across the line y=x since it goes through the origin too.
for this make sure to add this transformation:
(x,y) --> (-x,-y)
Help meeeee and thank u so much god bless u haha
Answer:
[See Below]
Step-by-step explanation:
For Point Slope Form:Point slope form is: [tex]y-y_1=m(x-x_1)[/tex]
'm' is the slope
(x1, y1) is a coordinate point.
Slope:Slope is rise over run. [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
We are given the points (-1,5) and (3,-3).
[tex]\frac{-3-5}{3-(-1)}=\frac{-8}{4}= -2[/tex]
The slope of the line is -2.
I will use (-1,5) as the point:
[tex]y-y_1=m(x-x_1)\rightarrow\boxed{y-5=-2(x+1)}[/tex]
For Slope Intercept:Slope intercept is: [tex]y=mx+b[/tex]
'm' - Slope
'b' - y-intercept
We can use the point slope equation to convert it into slope intercept form:
[tex]y-5=-2(x+1)\\\\y-5=-2x-2\\\\y-5+5=-2x-2+5\\\\\boxed{y=-2x+3}[/tex]
For Standard Form:Standard form is [tex]Ax+By=C[/tex]
Using out slope intercept form equation:
[tex]y=-2x+3\\\\y+2x=-2x+2x+3\\\\1y+2x=3\\\\\boxed{2x+1y=3}[/tex]
A sequence is defined recursively using the formula . If the first term of the sequence is 120, what is f(5)? −15 −7.5 7.5 15
Answer:
C. 7.5
Step-by-step explanation:
I took the quiz on EDGE
If the first term of the sequence is 120, then f(5) will be 7.5
What is recursively sequence?In mathematics and theoretical computer science, a constant-recursive sequence is an infinite sequence of numbers satisfying a linear recurrence relation: each number in the sequence is equal to a fixed linear combination of one or more of its immediate predecessors. A recursive sequence is a sequence of numbers formed by using previous terms to find the next terms, such as the Fibonacci sequence.How to solve this problem?The steps are as follow:
From the given conditions We knew the sequence is defined by the formula f(n + 1) = - 0.5f(n) and we know f(1) = 120So f(1 + 1) = f(2) = - 0.5f(1) = - 0.5 * 120 = f(2) = - 60Then f(2+1) = f(3) = -0,5 f(2) = -0,5x-60 f(3)=30f(3 + 1) = f(4) = - 0.5f(3) = - 0.5 * 30 = f(4)= -15f(4 + 1) = f(5) = - 0.5f(4) = - 0.5x - 15 = f(5) = 7.5So, f(5) = 7.5So if the first term of the sequence is 120, then f(5) will be 7.5
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The diameter of a sphere is 4 centimeters, which represents the volume of the sphere?
Answer:
10 2/3π or 33.51
Step-by-step explanation:
the volume of a sphere is 4/3πr^3
if the sphere has a diameter of 4 the radius is half the diameter so it would be 2. 2^3 = 8 now multiply 8 by 4/3 to get 10 2/3. now multiply by pi to get 10 2/3 π or 33.5103 which rounds to 33.51
Answer:
32π/3 cubic cm
Step-by-step explanation:
Paolo is buying salad and pizza for a company lunch. Suppose that a bowl of salad costs $5.00, and slice of costs $2.00.Let E be the amount in dollars that Paolo spends on salad and pizza. If Paolo buys S bowls of salad and P slices of pizza, then the total amount of money he spends E can be represented by the equation _____.Now rearrange the equation you wrote above so that P is written in terms of E and S. The quantity of pizza he buys can be represented by the equation _____.Suppose Paolo has $40.00 to spend on salad and pizza; that is E = $40.00Complete the following table with values of S or P that make the equation true.To complete the first row, determine the number of pizza slices Paolo can purchase with $40.00, when the number of salad bowls he purchases is 0.Budget (Dollars) Salad (Bowls) Pizza (Slice)40.00 0 _____40.00 4 _____40.00 _____ 0
Answer:
E=5S+2PP=0.5(E-5S)[tex]\left|\begin{array}{c|c|c}$Budget (Dollars)& $Salad (Bowls) &$Pizza (Slice)\\40.00&0&20\\40.00&4&10\\40.00&8&0\end{array}\right|[/tex]
Step-by-step explanation:
Cost of a bowl of salad = $5.00
Cost of a slice of pizza = $2.00
If Paolo buys S bowls of salad and P slices of pizza, then the total amount of money he spends E can be represented by the equation:
E=5S+2PNext, we make P the subject of the equation above.
2P=E-5S
[tex]P=\dfrac{E-5S}{2} \\P=0.5(E-5S)[/tex]
Therefore, The quantity of pizza he buys can be represented by the equation:
P=0.5(E-5S)When E=$40, we are required to complete the table below.
[tex]\left|\begin{array}{c|c|c}$Budget (Dollars)& $Salad (Bowls) &$Pizza (Slice)\\40.00&0&\\40.00&4&\\40.00&&0\end{array}\right|[/tex]
When S=0, E=$40
From P=0.5(E-5S)
P=0.5(40-5(0))=20
When S=4, E=$40
P=0.5(40-5(4))
=0.5(40-20)
=0.5*20
=10
When P=0, E=$40
P=0.5(E-5S)
0=0.5(40-5S)
40-5S=0
5S=40
S=8
Therefore, the completed table is:
[tex]\left|\begin{array}{c|c|c}$Budget (Dollars)& $Salad (Bowls) &$Pizza (Slice)\\40.00&0&20\\40.00&4&10\\40.00&8&0\end{array}\right|[/tex]
4. Factor the expression.
4b2 + 28b + 49
QA (2b + 7)2
OB (2b - 72
C (-2b + 7)2
OD 2(b - 7)2
Answer:
A. [tex](2b+7)^2[/tex]
Step-by-step explanation:
[tex]4b^2 +28b + 49\\=(2b)^2 + 2\times 2b\times 7 + (7)^2\\=(2b+7)^2[/tex]
A random sample of n observations is selected from a normal population to test the null hypothesis that muμequals=10. Specify the rejection region for each of the following combinations of HSubscript aa, alphaα, and n. a. HSubscript aa: muμnot equals≠10; alphaαequals=0.010.01; nequals=1313 b. HSubscript aa: muμgreater than>10; alphaαequals=0.100.10; nequals=2323 c. HSubscript aa: muμgreater than>10; alphaαequals=0.050.05; nequals=99 d. HSubscript aa: muμless than<10; alphaαequals=0.100.10; nequals=1111 e. HSubscript aa: muμnot equals≠10; alphaα equals=0.050.05; nequals=2020 f. HSubscript aa: muμless than<10; alphaαequals=0.010.01; nequals=77 a. Select the correct choice below and fill in the answer box within your choice.
Answer:
Step-by-step explanation:
a) H0: μ = 10
Ha: μ ≠ 10
This is a two tailed test
n = 13
Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a two tailed test. Therefore, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.
1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995
The critical value is 3.012
The rejection region is area > 3.012
b) Ha: μ > 10
This is a right tailed test
n = 23
α = 0.1
We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α
1 - α = 1 - 0.1 = 0.9
The critical value is 1.319
The rejection region is area > 1.319
c) Ha: μ > 10
This is a right tailed test
n = 99
α = 0.05
We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α
1 - α = 1 - 0.05 = 0.95
The critical value is 1.66
The rejection region is area > 1.66
d) Ha: μ < 10
This is a left tailed test
n = 11
α = 0.1
We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α
1 - α = 1 - 0.1 = 0.9
The critical value is 1.363
The rejection region is area < 1.363
e) H0: μ = 10
Ha: μ ≠ 10
This is a two tailed test
n = 20
Since α = 0.05, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.
1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975
The critical value is 2.086
The rejection region is area > 2.086
f) Ha: μ < 10
This is a left tailed test
n = 77
α = 0.01
We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α
1 - α = 1 - 0.01 = 0.99
The critical value is 2.376
The rejection region is area < 2.376
What is the solution for this inequality? 5x ≤ 45
A. x ≥ -9
B. x ≤ 9
C. x ≤ -9
D. x ≥ 9
Answer:
[tex]x\le \:9[/tex]
Step-by-step explanation:
[tex]5x\le 45[/tex]
[tex]\frac{5x}{5}\le \frac{45}{5}[/tex]
[tex]x\le \:9[/tex]
Answer:
B
Step-by-step explanation:
We divide the entire inequality by 5 to get rid of the coefficient of x. The ≤ stays the same so we get x ≤ 9.
A restaurant borrows from a local bank for months. The local bank charges simple interest at an annual rate of for this loan. Assume each month is of a year. Answer each part below.Do not round any intermediate computations, and round your final answers to the nearest cent. If necessary, refer to the list of financial formulas.
(a) Find the interest that will be owed after 4 months
(b) Assuming the restaurant doesn't make any payments, find the amount owed after 4 months
Complete Question:
A restaurant borrows $16,100 from a local bank for 4 months. The local bank charges simple interest at an annual rate of 2.45% for this loan. Assume each month is 1/12 of a year.
Answer each part below.Do not round any intermediate computations, and round your final answers to the nearest cent. If necessary, refer to the list of financial formulas.
(a) Find the interest that will be owed after 4 months
(b) Assuming the restaurant doesn't make any payments, find the amount owed after 4 months
Answer:
a) Interest that will be owed after 4 months , I = $131.48
b) Amount owed by the restaurant after 4 months = $16231.48
Step-by-step explanation:
Note that the question instructs not to round any intermediate computations except the final answer.
Annual rate = 2.45%
Monthly rate, [tex]R = \frac{2.45\%}{12}[/tex]
R = 0.20416666666%
Time, T = 4 months
Interest, [tex]I = \frac{PRT}{100}[/tex]
[tex]I = \frac{16100 * 0.20416666666 * 4}{100} \\I = 161 * 0.20416666666 * 4\\I = \$131.483333333\\I = \$131.48[/tex]
b) If the restaurant doesn't make any payments, that means after four months, they will be owing both the capital and the interest ( i.e the amount)
Amount owed by the restaurant after 4 months = (Amount borrowed + Interest)
Amount owed by the restaurant after 4 months = 16100 + 131.48
Amount owed by the restaurant after 4 months = $16231.48
-12.48 -(-2.99)-5.62
Answer:
[tex]-15.11[/tex]
Step-by-step explanation:
[tex]-12.48-(-2.99)-5.62=\\-12.48+2.99-5.62=\\-9.49-5.62=\\-15.11[/tex]
Answer:
-15.11
Step-by-step explanation:
-12.48+2.99-5.62=
-9.49 - 5.62= - (9.49+5.62)=-15.11
The next 3 options are:
A: x=1 or x= -3
A: x= -1 or x=3
B: Since the quadratic equation has two real solutions, the graph of the quadratic equation intercepts the x axis at (-1,0) and (3,0)
please please help. Thank you so much.
Answer:
A: x= -1 or x=3
B: Since the quadratic equation has two real solutions, the graph of the quadratic equation intercepts the x axis at (-1,0) and (3,0)
Step-by-step explanation:
x^2 -2x -3 =0
Factor
(x-3 )(x+1) =0
Using the zero product property
x-3 =0 x+1 =0
x=3 x=-1
The zeros are
(3,0) (-1,0)
It intersects the x axis at (3,0) (-1,0)
Kong made a scale drawing of a fish tank.The tank which is 24 feet long in real life, is 12 inches long in the drawing. What scale did Kong use for the drawing? 1 inch = feet.
Answer:
[tex]1\ inch = 2\ feet[/tex]
Step-by-step explanation:
Given:
[tex]Real\ tank\ measurement\ = 24\ feet[/tex]
[tex]Scale\ measurement\ = 12\ inches[/tex]
Required:
Scale Ratio.
To get the scale ratio, we simply divide the actual measurement by the scale measurement
This is done as follows:
[tex]Scale\ Ratio = \frac{Actual\ Measurement}{Scale\ Measurement}[/tex]
[tex]Scale\ Ratio\ = \frac{24\ feet}{12\ inches}[/tex]
[Divide numerator and denominator by 12]
[tex]Scale\ Ratio\ = \frac{2\ feet}{1\ inch}[/tex]
[Convert the above expression to ratio]
[tex]Scale\ Ratio = 2\ feet : 1\ inch[/tex]
The interpretation of this is that 1 inch on the scale measurement represent 2 feet on the actual measurements