the table below shows some inputs and outputs of the invertible function f etc ​

Answer:

1057.89 feet

Step-by-step explanation:

Trig time! Start with a diagram and listing out your trig functions, either mentally or on paper. SOH CAH TOA

The best trig function for this problem is likely tan:

tan84.6 = height / 100

100 * tan 84.6 = height

height = 1057.89 feet

Answer: A, C, D

Step-by-step explanation:

A is correct because Audrey reads 40 pages a day, and David reads 20. When you divide 40 by 20, you get 2. This means that 2 times 20 would be 40, and anything multiplied by 2 is "twice".

40 ÷ 20 = 2

2 × 20 = 40

B is not correct because after 6 days, Audrey reads 240 pages, and David reads only 120. We can figure this out by multiplying the pages read by 6.

Audrey: 40 × 6 = 240

David: 20 × 6 = 120

C is correct because when you subtract 20 from 40, you get 20. Since Audrey reads 40 pages a day and David reads 20, you can use this equation: 40-20 to figure the answer out. Audrey reads 20 more pages every day.

[tex]40-20=20[/tex]

D is correct because after 2 days, Audrey will have read 80 pages, and David will have read 40 pages. When you subtract 40 from 80, you get 40 pages.

40 × 2 = 80

20 × 2 = 40

80 - 40 = 40

E is not correct because, after 3 days, Audrey will have read 120 pages, and David will have read 60 pages. One-third of 120 is 40, not 60. Three times 60 would be 180, not 120. So, This answer is incorrect.

Answer:

B

Step-by-step explanation:

multiply each coordinate by 5

Answer:

55 in²

Step-by-step explanation:

Base x Height

Answer:64

Step-by-Step

Image

Answer:

$11.20 + 2 = 1122  1050 +3 = 1053 hope this help .

Answer:

17.5 is going to be your answer

Answer:

The answer is Gerald R. Ford, Jimmy Carter, Ronald Reagan, and lastly George H.W Bush

Step-by-step explanation:

Answer:

5/100

Step-by-step explanation:

each penny = 1/100

Answer:

[tex]10 > 1.85 + 0.5m[/tex]

Step-by-step explanation:

Price of the scooter:

Fixed price of $1.85 to activate plus $0.50 for each mile. This situation can be represented by a linear function, and it is given by:

[tex]P(m) = 1.85 + 0.5m[/tex]

Mikael has a gift card for $10 and he can not spend more on the scooter.

The spendings have to be less than 10. So

[tex]10 > P(m)[/tex]

[tex]10 > 1.85 + 0.5m[/tex]

Answer:

33.3 cm²

Step-by-step explanation:

Recall: Area Scale Factor = (Linear Scale Factor)²

Area scale factor = surface area of bigger cone/surface area of smaller cone

Let the surface area of the smaller cone be represented as x

Therefore,

Area scale factor = 75/x

Linear scale factor = radius of bigger cone/radius of smaller cone = 3/2

Thus:

75/x = (3/2)²

75/x = 9/4

Cross multiply

x*9 = 75*4

9x = 300

Divide both sides by 9

x = 300/9

x = 33.3 cm² (nearest tenth)

Answer:

x = 2

Step-by-step explanation:

From the data, we obtain the slope :

-1, 8 ; 3, - 4

Slope = Rise / run

Rise = y2 - y1 = (-4 - 8) = - 12

Run = x2 - x1 = (3 - (-1)) = 4

Slope, m = - 12 / 4 = - 3

Recall:

Equation of line :

y - y1 = m(x - x1)

y - 8 = - 3(x + 1)

y - 8 = - 3x - 3

y = - 3x - 3 + 8

y = - 3x + 5

Substituting y = - 3x + 5 into the equation 2x+4y= 0

2x + 4(-3x + 5) = 0

2x - 12x + 20 = 0

-10x = - 20

x = 2

Answer:

Yes; That what I got In my studies and lessons

Answer:

[tex]\theta=36.43^{\circ}[/tex]

Step-by-step explanation:

Given that,

Base = 42

Perpendicular height = 31

We need to find the value of [tex]\theta[/tex]. It can be calculated using trigonometry as follows :

[tex]\tan\theta=\dfrac{P}{B}\\\\\theta=\tan^{-1}(\dfrac{P}{B})[/tex]

Put all the values,

[tex]\theta=\tan^{-1}(\dfrac{31}{42})\\\\\theta=36.43^{\circ}[/tex]

So, the value of [tex]\theta=36.43^{\circ}[/tex].

Answer:

false

Step-by-step explanation:

Answer:

141.4

Step-by-step explanation:

i think

Step-by-step explanation:

With the quadratic equation in this form: [tex]ax^2+bx+c=0[/tex]

Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Example: 2x^2 + 7x + 3

ac is 2×3 = 6 and b is 7

So we want two numbers that multiply together to make 6, and add up to 7

In fact 6 and 1 do that (6×1=6, and 6+1=7)

How do we find 6 and 1?

It helps to list the factors of ac=6, and then try adding some to get b=7.

Factors of 6 include 1, 2, 3 and 6.

1 and 6 add to 7, and 6×1=6.

Step 2: Rewrite the middle with those numbers:

Rewrite 7x with 6x and 1x:

2x^2 + 6x + x + 3

Step 3: Factor the first two and last two terms separately:

The first two terms 2x^2 + 6x factor into 2x(x+3)

The last two terms x+3 don't actually change in this case

So we get:

2x(x+3) + (x+3)

Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.

In this case we can see that (x+3) is common to both terms, so we can go:

Start with: 2x(x+3) + (x+3)

Which is: 2x(x+3) + 1(x+3)

And so: (2x+1)(x+3)

Done!

Check: (2x+1)(x+3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 (Yes)

Please Mark As Brainliest

Answer:

ok

Step-by-step explanation:

Answer:

The length is 8.

Step-by-step explanation:

If you know the formula for area is LxW. Use this but reverse it. The area is 24 and the width is 3. Now divide 24/3=8. Simple as that!

Formula: A/W=L or A/L= W use this if you need more help! Hope it helps (:(:

6/16 = 3/8

hope this helps

Answer:

3 / 4

Step-by-step explanation:

We can realize that both the numerator and denominator have a common factor of 9. We can divide them both by 9 to get:

3 / 4

This fraction is in simplest form.

Answer:

3/4

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

[tex]a =7[/tex]   [tex]b = 2[/tex]  [tex]c = -4[/tex]

Step-by-step explanation:

Given

[tex]\frac{3x}{x + 2} + \frac{4x}{x - 2} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Required

Find a, b and c

[tex]\frac{3x}{x + 2} + \frac{4x}{x - 2} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Take LCM

[tex]\frac{3x(x -2) + 4x(x+2)}{(x + 2)(x - 2)} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Expand

[tex]\frac{3x^2 -6x + 4x^2+8x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

Collect like terms

[tex]\frac{3x^2 + 4x^2-6x+8x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

[tex]\frac{7x^2+2x}{x^2 - 4} = \frac{ax^2 + bx}{x^2 + c}[/tex]

By direct comparison:

[tex]ax^2= 7x^2 \to a = 7[/tex]

[tex]bx = 2x \to b = 2[/tex]

[tex]-4 = c \to c = -4[/tex]

Answer:

Probability of getting all three correct answer =  [tex]\frac{1}{64}[/tex]

Step-by-step explanation:

Given - A multiple choice test contains questions  with four options each: A, B, C, or D. If  Natalie randomly guesses on the last three  questions.

To find - what is the probability that she  gets all three correct.

Proof -

Given that,  question has 4 options.

And 1 option can be correct,

Let

x be that Natalie gives correct answer.

So,

Probability of getting, correct answer, P(x) = [tex]\frac{1}{4}[/tex]

So,

Probability of getting, incorrect answer, P(x') = 1 -  [tex]\frac{1}{4}[/tex] = [tex]\frac{3}{4}[/tex]

Now,

Given that, she guess the 3 questions.

All correct means,

first, second, third question answer is correct.

So,

Probability of getting all three correct answer = [tex]\frac{1}{4}[/tex]×[tex]\frac{1}{4}[/tex]×[tex]\frac{1}{4}[/tex] = [tex]\frac{1}{64}[/tex]

Given:

The stem-and-leaf plot or a date set.

To find:

The mode of data set.

Solution:

From the given stem-and-leaf plot, we get the numbers of the data set.

64, 67, 70, 70, 71, 75, 76, 78, 78, 80, 82, 82, 88, 91, 93, 94, 97, 98, 100, 100, 100

Mode of a date set is the most frequent value.

In the given data set the most frequent value is 100 with frequency 3.

Therefore, the mode of data set is 100. Hence, option A is correct.

Answer:it is A: 100

Step-by-step explanation:

i got it right

good luck with your test :)

Answer: [tex]m=\frac{-30}{79},\ y=5.40[/tex]

Step-by-step explanation:

Given

Points are [tex]\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)[/tex]

Convert mixed numeral to fraction

[tex]\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)[/tex]

Slope of the line is

[tex]\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}[/tex]

Equation of line

[tex]\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40[/tex]

Answer:

64 cars

Step-by-step explanation:

total number of cars that the parking lot can hold = 8/3 × 24 = 64 cars

Answer:

x int. (-1,0) and (-2,0).   y-int,(0,10)

Step-by-step explanation:

y-int. it's 10 because the y-int is always the c value.

x-int.

x=-b±√b²-4ac/2a

x=-15±√15²-4(5)(10)/2(5)

x=-15±√225-200/10

x=-15±√25/10

x= -15+5/10.      x=-15-5/10

x=-10/10.           x=-20/10

x=-1.                  x=-2

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ([tex]S_{5}[/tex]) = 250

or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]

or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]

or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

Answer:

(a) Name: Multinomial distribution

Parameters: [tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

(b) Range: [tex]\{(x,y,z)| x + y + z=20\}[/tex]

(c) Name: Binomial distribution

Parameters: [tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

[tex](d)\ E(x) = 1[/tex]   [tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y) = 17[/tex]

Step-by-step explanation:

Given

[tex]p_1 = 5\%[/tex]

[tex]p_2 = 85\%[/tex]

[tex]p_3 = 10\%[/tex]

[tex]n = 20[/tex]

[tex]X \to[/tex] High Slabs

[tex]Y \to[/tex] Medium Slabs

[tex]Z \to[/tex] Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

[tex]X \to[/tex] Number of voids considered as high slabs

[tex]Y \to[/tex] Number of voids considered as medium slabs

[tex]Z \to[/tex] Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

[tex]p_1 = 5\%[/tex]   [tex]p_2 = 85\%[/tex]   [tex]p_3 = 10\%[/tex]  [tex]n = 20[/tex]

And the mass function is:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

[tex]n = 20[/tex]

The number of voids (x, y and z) cannot be negative and they must be integers; So:

[tex]x + y + z = n[/tex]

[tex]x + y + z = 20[/tex]

Hence, the range is:

[tex]\{(x,y,z)| x + y + z=20\}[/tex]

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

[tex]p_1 = 5\%[/tex] and [tex]n = 20[/tex]

[tex]E(x) = p_1* n[/tex]

[tex]E(x) = 5\% * 20[/tex]

[tex]E(x) = 1[/tex]

[tex]Var(x) = E(x) * (1 - p_1)[/tex]

[tex]Var(x) = 1 * (1 - 5\%)[/tex]

[tex]Var(x) = 1 * 0.95[/tex]

[tex]Var(x) = 0.95[/tex]

[tex](e)\ P(X = 1, Y = 17, Z = 3)[/tex]

In (b), we have: [tex]x + y + z = 20[/tex]

However, the given values of x in this question implies that:

[tex]x + y + z = 1 + 17 + 3[/tex]

[tex]x + y + z = 21[/tex]

Hence:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

[tex](f)\ P{X \le 1, Y = 17, Z = 3)[/tex]

This question implies that:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)[/tex]

Because

[tex]0, 1 \le 1[/tex] --- for x

In (e), we have:

[tex]P(X = 1, Y = 17, Z = 3) = 0[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

In (a), we have:

[tex]f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z[/tex]

So:

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}[/tex]

Expand

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}[/tex]

[tex]P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}[/tex]

Using a calculator, we have:

[tex]P(X=0; Y=17; Z = 3) = 0.07195[/tex]

So:

[tex]P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)[/tex]

[tex]P(X \le 1, Y = 17, Z = 3) =0.07195[/tex]

[tex](g)\ P(X \le 1)[/tex]

This implies that:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

In (c), we established that X is a binomial distribution with the following parameters:

[tex]p_1 = 5\%[/tex]      [tex]n = 20[/tex]

Such that:

[tex]P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}[/tex]

So:

[tex]P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}[/tex]

[tex]P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}[/tex]

[tex]P(X=0) = 1 * 1 * (95\%)^{20}[/tex]

[tex]P(X=0) = 0.3585[/tex]

[tex]P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}[/tex]

[tex]P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}[/tex]

[tex]P(X=1) = 0.3774[/tex]

So:

[tex]P(X \le 1) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X \le 1) = 0.3585 + 0.3774[/tex]

[tex]P(X \le 1) = 0.7359[/tex]

[tex](h)\ E(Y)[/tex]

Y has the following parameters

[tex]p_2 = 85\%[/tex]  and    [tex]n = 20[/tex]

[tex]E(Y) = p_2 * n[/tex]

[tex]E(Y) = 85\% * 20[/tex]

[tex]E(Y) = 17[/tex]