Answer:
pH = 5.37
Explanation:
We'll begin by obtaining the concentration of the hydrogen ion in the solution. This can be obtained as follow:
HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)
From the balanced equation above,
1 mole of HNO₃ produced 1 mole of H⁺.
Therefore, 4.3×10¯⁶ M HNO₃ will also produce 4.3×10¯⁶ M H⁺.
Finally, we shall determine the pH of the solution. This can be obtained as follow:
Concentration of Hydrogen ion [H⁺] = 4.3×10¯⁶ M
pH =?
pH = –Log [H⁺]
pH = –Log 4.3×10¯⁶
pH = 5.37
Therefore, the pH of the solution is 5.37
A gas diffuses 1/6 times faster than hydrogen gas (H2).
What is the molar mass of the gas? (5 points)
a
59.95 g/mol
b
66.54 g/mol
c
68.68 g/mol
d
72.58 g/mol
Answer:
72.58 g/mol
Explanation:
mark me brainless if I am ✅
The relationship between the rate of diffusion and the molar mass is given by Graham's law. A gas diffusing 1/6 times faster than hydrogen will have a molar mass of 72.58 g/mol. Thus, option d is correct.
What is Graham's law?Graham's law states the inverse relationship between the rate of diffusion and the square root of the molar mass of the gas. It is given as,
Rate = 1 ÷ √M
The molar mass of the gas that diffuses 1/6 times faster than hydrogen is calculated as,
R₁ ÷ R₂ = √ (M₂ ÷ M₁)
Here,
The molar mass of hydrogen = M₁
The molar mass of unknown gas = M₂
Rate of diffusion of hydrogen gas = R₁
Rate of diffusion of unknown gas = R₂ = 1 / 6 R₁
Substituting values:
R₁ ÷ 1/6 R₁ = √M₂ ÷ 2
6 × 1.414
= 8.485
= 84.85 g/mol ≈ 72.58 g/mol
Therefore, option d. 72.58 g/mol is the molar mass of unkown gas.
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2C2H2 + 5O2 → 4CO2 + 2H2O
Which of the following statements would be correct if one mole of C2H2 was used in this reaction? (5 points)
a
One mole of oxygen was used in this reaction.
b
Five moles of oxygen were used in this reaction.
c
Four moles of carbon dioxide were produced from this reaction.
d
Two moles of carbon dioxide were produced from this reaction.
Answer:
d. Two moles of carbon dioxide were produced from this reaction
Explanation:
The given chemical reaction can be written as follows;
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
From the above chemical reaction, we have;
Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O
We have;
One mole of C₂H₂ will react with two and half moles of O₂ to produce two moles of CO₂ and one mole of H₂O
Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.
Need help on this question asap pleasee
Answer:
9.0 moles of CaO
Explanation:
We have the reaction equation as follows;
Fe2O3 + Ca3(PO4)2 -------> 2FePO4 + 3CaO
Now we know from the equation that;
1 mole of iron III oxide yields 3 moles of CaO
Therefore;
3 moles of iron III oxide yields 3 * 3/1
= 9.0 moles of CaO
A Chemist reacted magnesium and aluminum oxide. A reaction takes place. Explain why
Explanation:
when Magnesium is reacted with Aluminum oxide, Aluminum being a less reactive metal than magnesium, is replaced by magnesium
Al2O3 + 3Mg - 3MgO + 2Al
hence reaction takes place
Two reasons that a plant from a rain forest would not survive in a desert home?
Answer: A planet from a rain forest would not survive in a desert home, for the fact they depend on water and as these live from water, without it, this leads to dehydration and with loss of water with plants, nothing is able to survive when it comes to a rain forest plant being in a desert home. Another reason is the high trees and leaves that are providing the plants enough sunlight or shade to grow, it guarantees to help keep the temperature normal. Being in a deserted area would mean that there would be a temperature change, something the plant is not used to. Without that needed shade and avoiding the scorching sun, they will die out from how different the temperature is, and how hot it is.
Explanation: I hope this helped you.
okay, the answer should be simple and easy, plants from a rainforest would not survive in a desert because the plants in the rainforest do get water, sunlight and air whereas the plants in the desert have Sunlight which is very hot. so if a plant in the rainforest was transferred to the desert it will hard to survive and it will eventually die because they will not get water that will be needed and the plant can get sunburns with the too hot temperature.
Answer is C
Zeke is attempting to react a piece of magnesium metal with sulfuric acid. The sulfuric acid is a 5M solution. What could Zeke do
to slow down the rate at which the magnesium will react with the acid?
A)
increase the temperature
B)
add a 10M sulfuric acid solution
9)
add water to the acid to decrease its molarity
D)
add more of the 5M sulfuric acid to the reaction
Answer:
c)
Explanation:
add water to the acid to decrease its molarity
In a neutral solution, the concentration of H+ is
Group of answer choices
Answer:
equal to [OH-]
Hydrogen ion concentration is more conveniently expressed as pH, which is the logarithm of the reciprocal of the hydrogen ion concentration in gram moles per liter. Thus, in a neutral solution the hydrogen ion (H+) and the hydroxyl ion (OH−)
Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)
How many moles of Iron (11) Oxide would be produced by complete reaction of 0.15
moles of iron? (Be sure to show your work including the mole ratio you used)
Answer:
0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.
Explanation:
The balanced reaction is:
4 Fe + 3 O₂ → 2 Fe₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe: 4 molesO₂: 3 molesFe₂O₃: 2 molesYou can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?
[tex]moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}[/tex]
moles of Fe₂O₃= 0.075
0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.
Which of the following are physical properties?
Radioactivity
Color
Temperature
Flammability
Texture
Reactivity
Answer:
Explanation:
The properties that are observed or measured without changing the composition of matter are called physical properties.
color, Temperature, Texture are the physical properties as the composition of matter remains the same.
On the other hand, Radioactivity, Flammability and Reactivity comes under chemical property as during the chemical reactions there might be some changes in the properties.
18. How many grams are in 563 mL of chlorine gas at STP?
Answer:
[tex]at \: stp : \\ 22400 \: ml \: are \: occupied \: by \: 71 \: g \: of \: chlorine \\ 563 \: ml \: will \: be \: occupied \: by \: ( \frac{563}{22400} \times 71) \:g \\ = 1.78 \: g[/tex]
What is the number of moles in a sample of gas that has a volume of 3.5 L, a
pressure of 200 kPa, and a temperature of 300 K?
Explanation:
[tex]PV = nRT \\ (200000 \times 3.5 \times {10}^{ - 6} ) = n \times 8.314 \times 300 \\ n = \frac{0.07}{2494.2 } \\ n = 2.81 \times {10}^{ - 5} [/tex]
[tex] \small{ \star{ \underline{ \blue{ becker}}}}[/tex]
Which is true for a substance that releases energy?
OA. The energy release decreases the molecular motion and the kinetic energy of the substance.
B. The energy release decreases the molecular motion but increases the kinetic energy of the substance.
C. The energy release increases the molecular motion and the kinetic energy of the substance.
D. The energy release increases the molecular motion but decreases the kinetic energy of the substance.
E. The energy release is used only to change the state of the substance.
-Carbon and Oxygen combine to from carbon dioxide
Answer:
Carbon and oxygen combine to form two oxides, carbon monoxide and carbon dioxide in which the ratio of the weights of carbon and oxygen is respectively 12:16 and 12:32.
20 mL of hydrogen measured at 15° C is heated to 35°C.
What is the new volume at the same pressure?
V2 = 21.4 ml
Explanation:
Note: When dealing with gases, make sure that you change the units from °C to K.
T1 = 15°C + 273 = 288K
T2 = 35°C + 273 = 308K
V1 = 20 ml
V2 = ?
We use Charles's law to solve V2:
V1/T1 = V2/T2
or
V2 = (T2/T1)V1
= (308K/288K)(20 ml)
= 21.4 ml
Convert 22 grams of copper Il chloride (Cucl2) to moles.
with work please
What two things combine with oxygen to form ground-level ozone?
A) NOx and ODS
B) CFCs and halons
C) NOx and VOC
D) HFCs and HCFCs
Answer:
c) NOx and VOC
oxides of nitrogen (NOx) and volatile organic compounds (VOC)
Explanation:
-
What volume of 15.9 M Nitric acid would be required to make 7.2 L of 6.00 M nitric acid? (hint: dilution problem) will mark brainliest if correct
a. 2.72 L
b. 686.88 L
c. .075 L
d. 272
Answer:
d
Explanation:
Methane, a highly flammable gas, is placed in a piston that has a volume of 2.1
L at STP. The piston then compresses the gas to 125 mL. What is the pressure
inside of the piston?
Can animals and plants adapt to climate changes?
Answer:
Yes but will take a very very long time for them to adapt most will die but as gemeration passes they will get used to it
What percentage of a substance remains after 7 half-lives have passed?
A. 0.39
B. 2.5
C. 1.25
D. 0.78
Answer:
Not really sure, buts its either B or C.
Which is the correct chemical formula for Pentacarbon Tetraphosphide
Answer:
C5P4
Explanation:
the answer is C5P4 because penta is 5 and tetra is 4
The reaction between solid aluminum and liquid bromine is exothermic. This reaction creates
the product aluminum bromide.
What equation includes the correct formulas and demonstrates conservation of mass?
A Al(s) + Br2(1) - AlBr3(s)
B Al(s) + Br(l) - AlBr(s)
C Al(s) + 3Br(1) - AlBr3(s)
D
2Al(s) + 3Br2(1) - 2AlBr3(s)
Answer:
correct answer is d)
Explanation:
This answer demonstrates law of conservation of mass because the mass of the products is equal to the mass of reactants with the help of the coefficients which is the process known as balancing. This answer also includes the correct formulas, as Br is a gas so it MUST be written as Br2. hope this helps:)
2Al(s) + 3Br2(1) - 2AlBr3(s) is the correct formulas and demonstrates conservation of mass.
What is Conservation of Mass?Every action has an equal and opposite response, states Newton's Third Law. This indicates that any force applied to an item will have an equal and opposite-directed response force of the same magnitude. A force pair is the collective name for these connected forces.
Each individual object will have a different force pair with each other object in systems of numerous objects where all things interact. In the case of charged particles, the charge of each object will dictate the direction of each force in the force pair.
Similar charges will cause particles to repel one another by directing their forces away from one another. With their forces pointing in the same direction, particles with opposing charges attract one another.
Therefore, 2Al(s) + 3Br2(1) - 2AlBr3(s) is the correct formulas and demonstrates conservation of mass.
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Mendel crossed tall pea plants with short pea plants. the offspring were all tall plants.
1. Which allele is recessive?
2. Which allele is dominant?

please hurry

Answer:
1. Allele for shortness (t)
2. Allele for tallness (T)
Explanation:
Gregor Mendel performed numerous experiments using pea plants (Pisium sativum). He tested the height traits of pea plants by crossing tall pea plants (TT) and short pea plants (tt) to obtain offsprings that were all tall (Tt) in the first filial generation (F1).
This is possible because the allele for tallness is DOMINANT while the allele for shortness is RECESSIVE. This means that tallness allele (T) will mask the phenotypic expression of shortness allele (t) when in an heterozygous state (Tt) as in the F1 generation.
Structures and Forces - What is force and external forces.
Question 1) Jacob and Ravleen are moving furniture. They need to move the filing cabinet over 6 feet and it is very heavy. Jacob wants to apply force and push it by putting his hands on point A because he thinks it would be easier to move it from the top as there is less weight on the top. Ravleen says it's better to push at point B because the center of gravity is lower. Which person is correct and EXPLAIN why and what may happen if it is pushed in the wrong spot.
Answer:
The restoring force that prevents the furniture from tipping over when pushing the furniture towards the right, F= W × D
Where;
W = The weight of the furniture
D = The horizontal distance from the center of gravity of the furniture, CG and the to the lower right corner of the furniture
Given that A > D, for the furniture to tip over when pushing above the CG, we have;
F1 × A ≤ W × D
∴ F1 << W or for a force much smaller than W, the weight of the furniture applied above the center of gravity, the furniture will tip over
However when the force F2 is applied, where C < D, we have for no tipping over;
F2 × C ≤ W × D, therefore, given that C < D, when a force much higher than the weight, W, is applied at F2, the furniture will remain upright
Therefore, it is better push at a point lower than or equal to the center of gravity, whereby the point B is lower than the center of gravity, it is better to push at point B, Ravleen is correct and it is better to push at point B because the center of gravity is lower
If the furniture is pushed at the wrong spot it may tip over
Please see attached drawing
Explanation:
Calculate how many grams of sodium chloride we would need to make a solution with the same molarity of seawater, which is about 0.598 M.
Answer:
34.92 grams NaCl (in 1 L of solution)
Explanation:
The chemical formula of sodium chloride is NaCl. From the formula, we can calculate the molar mass of NaCl:
MM(NaCl)= MM(Na) + MM(Cl) = 23 g/mol + 35.4 g/mol = 58.4 g/mol
A solution of NaCl with a molarity of 0.598 M has 0.598 moles of NaCl per liter of solution. So, we multiply the moles by the molar mass of NaCl to calculate the mass we need:
mass of NaCl = 0.598 mol x 58.4 g/mol = 34.92 g NaCl
Therefore, we need 34.92 grams of NaCl to prepare 1 liter of a solution with a molarity of 0.598 M.
URGENT!!!
Which statement explains why an increase in molality increases the boiling point of a solution? The addition of solute decreases the solvent’s vapor pressure. A higher temperature must then be applied to overcome the change. The addition of solute increases the solvent’s vapor pressure. A higher temperature must then be applied to overcome the change. The addition of solute increases the solvent’s ability to boil. The solute’s molecules repel the solvent’s molecules, giving them higher binding energy and hence the need for higher temperature.
Answer:
the addition to solute decreases the solvent's vapor pressure. a temperature must then be applied to overcome the change
Explanation:
Answer:
long story short: A
Explanation:
If two half lives have passed since a scientist collected a 1.00- gram sample of a U-235, how much U-235 is left now?
answers for most finals chem test questions (10th)
Answer:
one quarter of the original amount, so 0.25 g
Explanation:
Answer:
C
Explanation:
Whilst Et₃CCl is unreactive towards water even at elevated temperatures, Et₃SiCl is hydrolyzed rapidly. Explain the origin of these differences and provide a reaction scheme with mechanistic details for the hydrolysis of Et₃SiCl.
Answer:
See Explanation
Explanation:
In discussing the reason why Et₃SiCl is more easily hydrolysed than Et₃CCl, we must remember that the electronegativity difference between silicon and chlorine is much higher than the electronegativity difference between carbon and chlorine.
As a result of this, the Si-Cl bond in Et₃SiCl is more polar and hence susceptible to attack by water than the C-Cl bond in Et₃CCl.
Also, it is postulated that the presence of vacant d orbitals on silicon assists hydrolysis in Et₃SiCl. Such vacant orbitals are absent in carbon hence Et₃CCl does not undergo hydrolysis.
The reaction scheme is shown in the image attached to this answer.
MgCl2 + NaOH → Mg(OH)2 +Naci
Balance
Please help this will determine my grade so I beg help me out and my grade
Answer:
C: checking your email
Explanation:
I believe that C would be impossible, as you cannot use wireless networks without radio waves